I had some errors on import from top level folderin Python
(version Python 3.6.9)
My folder structure is below:
-topfolder
alltestfunc.py
-subfolder
update_test.py
I am trying to import alltestfunc.py in update_test.py , that's all.
The errors which i had:
ModuleNotFoundError: No module named 'alltestfunc'
ValueError: attempted relative import beyond top-level package
etc..
Thanx a lot
Are you calling the code like this?
python topfolder/subfolder/update_test.py
This would make the update_test.py the __main__ file, or the starting point of your program. From there on out you cannot do an import one level up, only from subdirectories.
If you have some script on the topfolder level that is called and then executes the update_test.py you should be good.
Related
In my working directory, I have python3 files like this
/Path/to/cwd/main.py
/Path/to/cwd/Folder/one.py
/Path/to/cwd/Folder/two.py
So I had a main.py file like this
import Folder.one as one
#Do something
In one.py I had code like this
import two
#Some functions defined locally utilizing functions written in two.py
if __name__ == '__main__':
#Code for testing Functions
When I run one.py, it runs fine. But when I run main.py, it throws an error
ModuleNotFoundError: No module named 'two'
Ideally, I would not be expecting such an error at all.
It worked when I changed the import statement from import two to import Folder.two, which works. But I would like to do this in some other way without affecting such import statements much. How to achieve this?
In order for the python interpreter to know what directories contain code to be loaded, you need to include a __init__.py file.
Have a look at this answer to learn more about how to import packages.
In the case of your second import, to access that method you would need to use this syntax.
from .two import *
I have a program, program1.py, that has this structure:
Program
--program1.py
--__init__.py
--data\
----__init__.py
----helper_data.py
--classes\
----__init__.py
----helper_class.py
In helper_class.py, there is an import statement from data.helper_data import *. When I run program1, this works perfectly.
I have a second program, program2.py. I have put program1.py on my PYTHONPATH. In program2.py, I use import program1. It finds the program, but when running the imports from program1.py, I get the following error stemming from the classes.helper_class: ModuleNotFoundError: No module named 'data.helper_data'.
I think I vaguely understand what's going on, but I can't figure out the fix or the search terms to find the answer. I've tried changing the import in program1 to from ..data.helper_data import * and get an error saying I've tried a relative import beyond the parent-level package. I've also tried from .data.helper_data import * and get the same ModuleNotFoundError.
What can I do?
I think You have to import "sys" package.
import sys
sys.path.append('E:\ToDataScientist') # this is where the "Program" folder exists
from Program.data.helper_data import aa # "aa" is the class or function in helper_data
from Program.data.helper_data import * # include all from helper_data
In python 2 I can create a module like this:
parent
->module
->__init__.py (init calls 'from file import ClassName')
file.py
->class ClassName(obj)
And this works. In python 3 I can do the same thing from the command interpreter and it works (edit: This worked because I was in the same directory running the interpreter). However if I create __ init __.py and do the same thing like this:
"""__init__.py"""
from file import ClassName
"""file.py"""
class ClassName(object): ...etc etc
I get ImportError: cannot import name 'ClassName', it doesn't see 'file' at all. It will do this as soon as I import the module even though I can import everything by referencing it directly (which I don't want to do as it's completely inconsistent with the rest of our codebase). What gives?
In python 3 all imports are absolute unless a relative path is given to perform the import from. You will either need to use an absolute or relative import.
Absolute import:
from parent.file import ClassName
Relative import:
from . file import ClassName
# look for the module file in same directory as the current module
Try import it this way:
from .file import ClassName
See here more info on "Guido's decision" on imports in python 3 and complete example on how to import in python 3.
I have the following project structure:
MainScript.py
ExampleFolder
├ MainImport.py
└ SecondaryImport.py
MainScript.py: import ExampleFolder.MainImport
MainImport.py: Import SecondaryImport
When I try to run MainImport.py it gets no errors, but when I try to run MainScript.py, I get an import error that says No module named 'SecondaryImport'.
My question is simple - is there any way that I can import only MainImport.py from MainScript.py without getting this error, and importing SecondaryImport.py? Thanks in advance!
I have also tried adding a blank file named __init__.py to the ExampleFolder, but the error still appears. I also read Python's official documentation, but I could not find the problem. Am I missing something? (:
I think using the statement import ExampleFolder.SecondaryImport would work.
If it does, the error might be happening because as mentioned in docs, import statements will usually start searching your main project directory where the python interpreter was called if your module is not in python itself.
Another way would be to use relative import statement like this:
import .secondaryimport in order to tell the python interpreter to look in the current directory. Hope this helps!
Taking a look at these links will help, I think (It helped me when I was stuck in a similar problem):
https://docs.python.org/3/library/sys.html#sys.path
https://realpython.com/absolute-vs-relative-python-imports/
I have also tried adding a blank file named __init__.py to the ExampleFolder
That's the way - you're creating a Python package from a directory that way. And with packages you have got namespace directory.file where file is a Python file also known as module in Python world.
Then you can do from mainscript.py:
from examplefolder import mainimport
For importing inside package you may use the following syntax inside mainscript.py:
import secondaryimport
and use it in that mainscript.py as:
sevondaryimport.SomeClass()
or you may just do:
from secondaryimport import SomeClass
and use it like:
SomeClass()
Btw, use lowercase in all the cases except classes names - only they should have CamelCase names.
I have some difficulties constructing my project structure.
This is my project directory structure :
MusicDownloader/
__init__.py
main.py
util.py
chart/
__init__.py
chart_crawler.py
test/
__init__.py
test_chart_crawler.py
These are codes :
1.main.py
from chart.chart_crawler import MelonChartCrawler
crawler = MelonChartCrawler()
2.test_chart_crawler.py
from ..chart.chart_crawler import MelonChartCrawler
def test_melon_chart_crawler():
crawler = MelonChartCrawler()
3.chart_crawler.py
import sys
sys.path.append("/Users/Chois/Desktop/Programming/Project/WebScrape/MusicDownloader")
from .. import util
class MelonChartCrawler:
def __init__(self):
pass
4.util.py
def hi():
print("hi")
In MusicDownloader, when I execute main.py by python main.py, it shows errors:
File "main.py", line 1, in <module>
from chart.chart_crawler import MelonChartCrawler
File "/Users/Chois/Desktop/Programming/Project/WebScrape/MusicDownloader/chart/chart_crawler.py", line 4, in <module>
from .. import util
ValueError: attempted relative import beyond top-level package
But when I execute my test code in test directory by py.test test_chart_crawler.py, it works
When I first faced with absolute, relative imports, it seems like very easy and intuitive. But it drives me crazy now. Need your helps. Thanks
The first problem is MusicDownloader not being a package. Add __init__.py to MusicDownloader along with main.py and your relative import ..chart should work. Relative imports work only inside packages, so you can't .. to non-package folder.
Editing my post to provide you with more accurate answer to your answer edit.
It's all about the __name__. Relative imports use __name__ of the module they are used in and the from .(.) part to form a full package/module name to import. Explaining in simple terms importer's __name__ is concatenated with from part, with dots showing how many components of name to ignore/remove, i.e.:
__name__='packageA.packageB.moduleA' of the file containing line: from .moduleB import something, leads to combined value for import packageA.packageB.moduleB, so roughly from packageA.packageB.moduleB import something(but not absolute import as it would be if typed like that directly).
__name__='packageA.packageB.moduleA' of the file containing line: from ..moduleC import something, leads to combined value for import packageA.moduleC, so roughly from packageA.moduleC import something(but not absolute import as it would be if typed like that directly).
Here if it's a moduleB(C) or a packageB(C) doesn't really matter. What's important is that we still have that packageA part which works as an 'anchor' for relative import in both cases. If there will be no packageA part, relative import won't be resolved, and we'll get an error like "Attempted relative import beyond toplevel package".
One more note here, when a module is run it gets a special __name__ value of __main__, which obviously prevents it from solving any relative imports.
Now regarding your case try adding print(__name__) as the very first line to every file and run your files in different scenarios and see how the output changes.
Namely if you run your main.py directly, you'll get:
__main__
chart.chart_crawler
Traceback (most recent call last):
File "D:\MusicDownloader\main.py", line 2, in <module>
from chart.chart_crawler import MelonChartCrawler
File "D:\MusicDownloader\chart\chart_crawler.py", line 2, in <module>
from .. import util
ValueError: Attempted relative import beyond toplevel package
What happened here is... main.py has no idea about MusicDownloader being a package (even after previous edit with adding __init__.py). In your chart_crawler.py: __name__='chart.chart_crawler' and when running relative import with from .. the combined value for package will need to remove two parts (one for every dot) as explained above, so the result will become '' as there're just two parts and no enclosing package. This leads to exception.
When you import a module the code inside it is run, so it's almost the same as executing it, but without the __name__ becoming __main__ and the enclosing package, if there's any, being 'noticed'.
So, the solution is to import main.py as part of the MusicDownloader package. To accomplish the described above, create a module, say named launcher.py on the same level of hierarchy as MusicDownloader folder (near it, not inside it near main.py) with the following code:
print(__name__)
from MusicDownloader import main
Now run launcher.py and see the changes. The output:
__main__
MusicDownloader.main
MusicDownloader.chart.chart_crawler
MusicDownloader.util
Here __main__ is the __name__ inside launcher.py. Inside chart_crawler.py: __name__='MusicDownloader.chart.chart_crawler' and when running relative import with from .. the combined value for package will need to remove two parts (one for every dot) as explained above, so the result will become 'MusicDownloader' with import becoming from MusicDownloader import util. And as we see on the next line when util.py is imported successfully it prints its __name__='MusicDownloader.util'.
So that's pretty much it - "it's all about that __name__".
P.S. One thing not mentioned is why the part with test package worked. It wasn't launched in common way, you used some additional module/program to lauch it and it probably imported it in some way, so it worked. To understand this it's best to see how that program works.
There's a note in official docs:
Note that relative imports are based on the name of the current module. Since the name of the main module is always "__main__", modules intended for use as the main module of a Python application must always use absolute imports.