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comment model not attached to ticket model

Creating a separate comments app for ticket app. My issue is that when I create and submit my comment on a particle ticket, it creates its own new page of tickets instead of being attached to original ticket. I think the issue has to do with my urls.py file and I feel like i'm close to solving this but i’m not sure how to proceed.
Here is my comment models.py
from django.db import models
from django.utils import timezone
from django.contrib.auth.models import User
from django.urls import reverse
from tickets.models import Ticket
class Comment(models.Model):
ticket = models.ForeignKey(Ticket, related_name='comments', on_delete=models.CASCADE,
null=True)
title = models.CharField(max_length=20)
content = models.TextField()
date_posted = models.DateTimeField(default=timezone.now)
author = models.ForeignKey(User, on_delete=models.CASCADE)
def __str__(self):
return self.title
def get_absolute_url(self):
return reverse('tickets:ticket-detail', kwargs={'pk': self.pk})
Here is my ticket models.py
from django.db import models
from django.utils import timezone
from django.contrib.auth.models import User
from django.urls import reverse
from users.models import Profile
class Ticket(models.Model):
title = models.CharField(max_length=100)
content = models.TextField()
date_posted = models.DateTimeField(default=timezone.now)
author = models.ForeignKey(User, on_delete=models.CASCADE)
assignee = models.ForeignKey(Profile, on_delete=models.SET_NULL, blank=True, null=True)
status = models.BooleanField(choices=MARKED, default=True)
priority = models.TextField(choices=PRIORITIES, default='None', max_length=10)
label = models.CharField(choices=TYPES, default='Misc', max_length=100)
def __str__(self):
return self.title
def get_absolute_url(self):
return reverse('ticket-detail', kwargs={'pk': self.pk})
Here is the main urls.py
from django.conf import settings
from django.contrib import admin
from django.urls import path, include
from django.conf.urls.static import static
app_name = 'tickets'
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('users.urls')),
path('', include(('tickets.urls', 'tickets'), namespace='tickets')),
path('', include('tickets.urls')),
path('', include('comments.urls')),
]
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
Here is the ticket urls.py
from django.conf import settings
from django.contrib import admin
from django.urls import path, include
from django.conf.urls.static import static
app_name = 'tickets'
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('users.urls')),
path('', include(('tickets.urls', 'tickets'), namespace='tickets')),
path('', include('tickets.urls')),
path('', include('comments.urls')),
]
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
Here is my comments urls.py
from django.urls import include, path
from .views import (
CommentListView,
CommentCreateView,
CommentUpdateView,
CommentDeleteView,
)
urlpatterns = [
path('tickets/<int:pk>/', CommentListView.as_view(), name='ticket-detail'),
path('tickets/<int:pk>/comments/new/', CommentCreateView.as_view(), name='comment-create'),
path('tickets/comments/<int:pk>/update/', CommentUpdateView.as_view(), name='comment-update'),
path('tickets/comments/<int:pk>/delete/', CommentDeleteView.as_view(), name='comment-delete'),
]

Django Attribute Error: 'NoneType' object has no attribute 'videofile'

I am following this tutorial to create a video uploader in my Django project and have run into this error:
..src/video/views.py", line 9, in showvideo
videofile= lastvideo.videofile
AttributeError: 'NoneType' object has no attribute 'videofile'
I'm sure I am missing something obvious and have been looking for the answer for a while now. Would be grateful for any help.
views.py
from django.shortcuts import render
from .models import VideoUpload
from .forms import VideoForm
def showvideo(request):
lastvideo= VideoUpload.objects.last()
videofile= lastvideo.videofile
form= VideoForm(request.POST or None, request.FILES or None)
if form.is_valid():
form.save()
context= {'videofile': videofile,
'form': form
}
return render(request, 'video.html', context)
forms.py
from django import forms
from .models import VideoUpload
class VideoForm(forms.ModelForm):
class Meta:
model = VideoUpload
fields = ["name", "videofile"]
models.py
from django.db import models
class VideoUpload(models.Model):
name= models.CharField(max_length=500)
videofile= models.FileField(upload_to='videos/', null=True, verbose_name="")
def __str__(self):
return self.name + ": " + str(self.videofile)
from django.conf import settings
from django.contrib import admin
from django.urls import path
from django.conf.urls.static import static
from video.views import (
showvideo,
)
urlpatterns = [
path('showvideo', showvideo, name='showvideo'),
]
if settings.DEBUG:
urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
FYI I updated the name of the model to 'VideoUpload' vs the tutorial.

There is no last_video record in your database. To prevent this from erroring out in such and instance, you could change the line: videofile= lastvideo.videofile into
videofile = lastvideo.videofile if lastvideo else None
This will prevent an error from being thrown. Alternatively you could put the whole bit in a try/except block.

Is there any way to make a second LOGIN_REDIRECT_URL in settings.py in Django?

I am creating an app in Django which have two external users:
1. Teacher
2. Student
I have to create total of 3 apps, one the base app that contains home.html template, other the student app that contains student.html template and third teacher app that contains teacher.html template.
I have just created two apps for now, base app and student app, I have created login, logout and register pages for student app, now I am successfully able to redirect the user (student) to the student.html whenever the student logs into the system and I did this by putting LOGIN_REDIRECT_URL = 'student' in my settings.py.
I want to do the same for Teacher app as well but I want to redirect teacher to the teacher.html.
Is there any way that I can create the second LOGIN_REDIRECT_URL in settings.py to fulfil this purpose or it will be done any other way?
My Project Structure
django_project
|__esacp(main system)
|_____migrations
|_____templates
|________esacp
|__________base.html
|__________home.html
|__________student.html
|__________teacher.html
|_____apps.py
|_____forms.py
|_____models.py
|_____views.py
|__django_project
|__student
|_____migrations
|_____templates
|________student
|___________login.html
|___________logout.html
|___________register.html
|_____apps.py
|_____forms.py
|_____models.py
|_____views.py
|__teacher
|__db.sqlite3
|__manage.py
Code of models.py of esacp app
from django.db import models
from django.utils import timezone
class StudentType(models.Model):
studenttype_id = models.IntegerField(primary_key=True)
type_title = models.CharField(max_length=50)
def __str__(self):
return self.type_title
class StudentDetails(models.Model):
name = models.CharField(max_length=50)
username = models.CharField(max_length=50, primary_key=True)
password = models.CharField(max_length=50)
email_id = models.CharField(max_length=100)
contact = models.CharField(max_length=100)
studenttype = models.ForeignKey(StudentType, on_delete=models.CASCADE)
registration_date = models.DateTimeField(default=timezone.now)
modify_date = models.DateTimeField(auto_now=True)
def __str__(self):
return self.name
Code of urls.py of esacp app
from django.urls import path
from . import views
urlpatterns = [
path('', views.home, name='esacp-home'),
path('student', views.student, name='student'),
]
Code of urls.py of main project
from django.contrib import admin
from django.contrib.auth import views as auth_views
from django.urls import path, include
from users import views as user_views
urlpatterns = [
path('admin/', admin.site.urls),
path('register/', user_views.register, name='register'),
path('login/', auth_views.LoginView.as_view(template_name='users/login.html'), name='login'),
path('logout/', auth_views.LogoutView.as_view(template_name='users/logout.html'), name='logout'),
path('tlogin/', auth_views.LoginView.as_view(template_name='teacher/tlogin.html'), name='tlogin'),
path('tlogout/', auth_views.LogoutView.as_view(template_name='teacher/tlogout.html'), name='tlogout'),
path('esacp/', include('esacp.urls')),
Code of views.py of teacher app
from django.shortcuts import render
from django.contrib.auth.views import LoginView
class MyLoginView():
def get_success_url(self):
url = self.get_redirect_url()
return url
Code of views.py of esacp app
from django.shortcuts import render
from django.contrib.auth.decorators import login_required
def home(request):
return render(request, 'esacp/home.html')
#login_required
def student(request):
return render(request, 'esacp/student.html')
and below I have the statement in setting.py
LOGIN_REDIRECT_URL = 'student'

You have two login URLs. Therefore you can use a different login view for each one, and override get_success_url so that you are redirected to the correct page after login.
For example, the teacher login view would look something like:
from django.contrib.auth.views import LoginView
class TeacherLoginView(LoginView):
template_name = 'teacher/tlogin.html'
def get_success_url(self):
url = self.get_redirect_url()
return url or '/teacher/' # FIXME use reverse here instead of hardcoding the URL
Then use that view instead of TeacherView in your URL patterns.
path('login/', TeacherLoginView.as_view(), name='login'),

django ImpropertlyConfigured. The included urlsconf does not appear to have any patterns in it

I am using django 2.2.2 . I am trying to include path('api/', include('music.urls')),into my root url but I get an exception thrown from resolvers.py file.
Here is my music/urls.py
urls.py
from django.urls import path
from . import views
app_name = 'music'
urlpatterns = [
path('songs/', ListSongsView.as_view(), name = 'songs-all'),
]
here is my root url file
urls.py
from django.contrib import admin
from django.urls import path,include
urlpatterns = [
path('admin/', admin.site.urls),
path('api/', include('music.urls')),
]
views.py
from django.shortcuts import render
from rest_framework import generics
from .models import Songs
from serializers import SongSerializer
# Create your views here.
class ListSongsView(generics.ListApiView):
queryset = Songs.objects.all()
serializer_class = SongsSerializer
models.py
from django.db import models
# Create your models here.
class Songs(models.Model):
title = models.CharField(max_length=255, null = False)
artist = models.CharField(max_length=50, null= False)
def __str__(self):
return "{} - {}".format(self.title, self.artist)
and my stacktrace
File "/home/brianonchari/Documents/django/drf/myapi/lib/python3.5/site-
packages/django/urls/resolvers.py", line 588, in url_patterns
raise ImproperlyConfigured(msg.format(name=self.urlconf_name))
django.core.exceptions.ImproperlyConfigured: The included URLconf 'rest.urls' does not
appear to have any patterns in it. If you see valid patterns in the file then the issue is
probably caused by a circular import.

music/urls.py
from django.urls import path
from .views import ListSongsView
app_name = 'music'
urlpatterns = [
path('songs/', ListSongsView.as_view(), name='songs-all'),
]
root urls.py:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('api/', include('music.urls')),
]
music/views.py:
from django.shortcuts import render
from rest_framework import generics
from .models import Songs
from .serializers import SongSerializer
# Create your views here.
class ListSongsView(generics.ListAPIView):
queryset = Songs.objects.all()
serializer_class = SongSerializer
music/models.py:
from django.db import models
# Create your models here.
class Songs(models.Model):
title = models.CharField(max_length=255, null=False)
artist = models.CharField(max_length=50, null=False)
def __str__(self):
return "{} - {}".format(self.title, self.artist)
music/serializers.py:
from rest_framework import serializers
from .models import Songs
class SongSerializer(serializers.ModelSerializer):
class Meta:
model = Songs
fields = ('title', 'artist')
run your migration for Songs model:
python manage.py makemigrations
python manage.py migrate

Django "Page not found (404)"

I think I done everything correct but I don't know why it doesn't work. When I try to reach a page I get error "Page not found (404)".
So, this all products page works 127.0.0.1:8000/products/ but when I try to visit single product page 127.0.0.1:8000/products/audi I get error that it's not found...
So, maybe you what's wrong here?
Thank you.
Page not found (404)
Request Method: GET
Request URL: http://link/products/audi
Using the URLconf defined in ecommerce.urls, Django tried these URL patterns, in this order:
^static/(?P<path>.*)$
^media/(?P<path>.*)$
^admin/doc/
^admin/
^products/ ^$ [name='products']
^products/ ^$(?P<slug>.*)/$
^contact/ [name='contact_us']
The current URL, products/audi, didn't match any of these.
Main project urls.py:
from django.conf import settings
from django.conf.urls import patterns, include, url
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
(r'^static/(?P<path>.*)$', 'django.views.static.serve', {
'document_root': settings.STATIC_ROOT
}),
(r'^media/(?P<path>.*)$', 'django.views.static.serve', {
'document_root': settings.MEDIA_ROOT
}),
url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
url(r'^admin/', include(admin.site.urls)),
url(r'^products/', include('products.urls')),
url(r'^contact/', 'contact.views.contact_us', name='contact_us'),
)
Products app urls.py:
from django.conf import settings
from django.conf.urls import patterns, include, url
urlpatterns = patterns('products.views',
url(r'^$', 'all_products', name='products'),
url(r'^$(?P<slug>.*)/$', 'single_product'),
)
views.py
from django.http import HttpResponse, HttpResponseRedirect
from django.shortcuts import render_to_response, RequestContext, get_object_or_404
from .models import Product
def all_products(request):
products = Product.objects.filter(active=True)
return render_to_response('products/all.html', locals(), context_instance=RequestContext(request))
def single_product(request, slug):
product = get_object_or_404(Product, slug=slug)
return render_to_response('products/single.html', locals(), context_instance=RequestContext(request))
models.py
from django.db import models
# Create your models here.
class Product(models.Model):
title = models.CharField(max_length=220)
description = models.CharField(max_length=3000, null=True, blank=True)
price = models.DecimalField(max_digits=1000, decimal_places=2, null=True, blank=True)
slug = models.SlugField()
active = models.BooleanField(default=True)
timestamp = models.DateTimeField(auto_now_add=True, auto_now=False)
updated = models.DateTimeField(auto_now=True, auto_now_add=False)
def __unicode__(self):
return self.title
class Meta:
ordering = ['title',]
class ProductImage(models.Model):
product = models.ForeignKey(Product)
description = models.CharField(max_length=3000, null=True, blank=True)
image = models.ImageField(upload_to='product/images/')
timestamp = models.DateTimeField(auto_now_add=True, auto_now=False)
updated = models.DateTimeField(auto_now=True, auto_now_add=False)
def __unicode__(self):
return self.image

Your URL pattern has an extra $ at the beginning, so it can never match anything:
url(r'^$(?P<slug>.*)/$', 'single_product')
This should be:
url(r'^(?P<slug>.*)/$', 'single_product')
This still requires a trailing slash, which is the normal pattern. With that corrected, your URL should be /products/audi/. You don't show the context in which that URL is created, but this is one example of why it's a good idea to use Django's url reversal to build URLs if at all possible. That would look something like this, in Python code (for instance, possibly in a get_absolute_url method on the model:
reverse('single_product', kwargs={'slug': someproduct.slug})
Or like this, in a template:
Django 1.5:
{% url 'single_product' someproduct.slug %}
Django 1.4 and earlier:
{% url single_product someproduct.slug %}

You have a typo:
url(r'^$(?P<slug>.*)/$', 'single_product'),
Note this $ just after ^, in regexp it states for a string end. Replace with
url(r'^(?P<slug>.*)/$', 'single_product'),