I am trying to write python script for copy and renaming the files [closed] - python

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What approach should be for below scenario?
I have multiple files and want to copy all files from one directory to other directory and also rename the files like below.
Source Directory: A
example1.txt
example2.txt
example3.txt
Destination Directory:B
example1_19930221.txt
example2_19930221.txt
example3_19930221.txt
command: hadoop distcp /A/* /B/

Use this:
shutil.move(source_path , destination_path.replace(filename, filename + "_19930221"))

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how do i move or separate 1000 files to another folder from 80000 files in a folder [closed]

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i have a text file (.txt) having 1000 files details that are to be separated from the folder contains 80000 files using bash scripting.
the file names are as follows:
20070130064823.IN.PUR.mseed
20070201032214.IN.PUR.mseed
20070206091658.IN.PUR.mseed
20070211045116.IN.PUR.mseed
20070214114510.IN.PUR.mseed
to separate 1000 files that in text file from 80000 files using bash scripting

I can't even create file on the VS Code [closed]

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Unable to write file 'c:\Users\himan.vscode\extensions\ms-python.python-2022.16.1\pythonFiles\lib\python\debugpy\launcher.vscode\launch.json' (Error: Unable to create folder 'c:\Users\himan.vscode\extensions\ms-python.python-2022.16.1\pythonFiles\lib\python\debugpy\launcher' that already exists but is not a directory)
I tried everything even reinstalling VS Code twice.

Python. Copy Files and Folders to existing directory [closed]

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How can I copy all contents (including folders) from folder A to the existing folder B with Python?
You can use the copytree function from the shutil package https://docs.python.org/3/library/shutil.html#shutil.copytree.
from shutil import copytree
src_path = "path/of/your/source/dir"
dest_path = "path/of/your/destination/dir"
copytree(src_path, dest_path, dirs_exist_ok=True)
The dirs_exist_ok=True parameter is useful if the dest_path already exists, and you want to overwrite the existing files.

What is the equivalent of Batch file syntax (*.* or *.csv) for python? [closed]

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I am trying to open a file with python where the filename is 2018_01_25_(filename).csv.
In batch files i used C:*.csv to open the csv file. I have tried this in python 2.7 but it doesnt work.
a = pd.read_csv("filename.csv")
i want to use, a = pd.read_csv("*.csv")
Is there a python equivalent to this?
As far as I know there isn't a one-liner for this, but you can get around it with the os package.
import os
for f in os.scandir():
if '.csv' == f[-4:]:
a = pd.read_csv(f)
break
This code will read the first .csv file into a.

Amazon S3 Python Bulk File Transfer through Python [closed]

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I want to tranfer files in around 1000 directories to an Amazon S3 bucket using Pythons S3 package.
How could I do it ?
I like boto,
http://code.google.com/p/boto/

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