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How to compare and remove second element of a nested list using List comprehensions?

So I have a nested list and would like to compare and remove a list inside a nested list based on the condition match.
Here is my code :
def secondValue(val):
return val[1]
if __name__ == '__main__':
nestedList=[]
for _ in range(int(input())):
name = input()
score = float(input())
nestedList.append([name,score]) # Made a nested list from the input
lowestMarks=min(nestedList,key=secondValue) [1] #Extracting the minimum score
newList=[x for x in nestedList[1] if x!=lowestMarks] # PROBLEM HERE
The last line of my code is where I want to remove the list inside my nested list based on condition match. Sure, I can do this with a nested for loop but if there is a way to do this using list comprehension I'd consider that approach.
Basically I'd appreciate an answer that tells how to remove a list from a nested list based on a condition. In my case the list looks like :
[[test,23],[test2,44],......,[testn,23]]

Problems:
for x in nestedList[1] just iterates over second sublist of the nested list.
x is a sublist and it can never be equal to lowestMarks.
Use a list-comprehension as:
newList = [[x, y] for x, y in nestedList if y != lowestMarks]

Mistake was in the below line and is now fixed.
newList=[x for x in nestedList if x[1] != lowestMarks] # PROBLEM HERE
nestedList[1] fetches the second sub-list. You want to iterate over the entire list.

Extract substrings from a list into a list in Python

I have a Python list like:
['user#gmail.com', 'someone#hotmail.com'...]
And I want to extract only the strings after # into another list directly, such as:
mylist = ['gmail.com', 'hotmail.com'...]
Is it possible? split() doesn't seem to be working with lists.
This is my try:
for x in range(len(mylist)):
mylist[x].split("#",1)[1]
But it didn't give me a list of the output.

You're close, try these small tweaks:
Lists are iterables, which means its easier to use for-loops than you think:
for x in mylist:
#do something
Now, the thing you want to do is 1) split x at '#' and 2) add the result to another list.
#In order to add to another list you need to make another list
newlist = []
for x in mylist:
split_results = x.split('#')
# Now you have a tuple of the results of your split
# add the second item to the new list
newlist.append(split_results[1])
Once you understand that well, you can get fancy and use list comprehension:
newlist = [x.split('#')[1] for x in mylist]

That's my solution with nested for loops:
myl = ['user#gmail.com', 'someone#hotmail.com'...]
results = []
for element in myl:
for x in element:
if x == '#':
x = element.index('#')
results.append(element[x+1:])

remove tuples with only one item -- python

I have a list of tuples and some of the tuples only have one item in it. How do I remove tuples with only one item from the list? I want to keep tuples with two items in it.
The tuples I have contain a string, and then an integer after it
list = ((['text'],1),(['text'],2),((3,))

I may suggest:
filtered_list = [tup for tup in list if len(tup) == 2]
You can also check if tuple length is higher than one or anything else...

What about:
new_list = [x for x in old_list if len(x) > 1]

You want to create a list with squared brackets instead of parentheses, otherwise you'd create a tuple.
Also please don't call your variables like built-in names as EdChum suggested.
The solution here is to filter your list:
l=[(1,2),(3,),(4,5)]
filter(lambda x: len(x)!=1, l)

You could use something like that to rebuild a new tuple with tuple that have a length greater than 1.
new_list = tuple(item for item in your_list if len(item) > 1)

How to check if an element in the list exists in another list

How to check if an element in the list exists in another list?And if it does append it to another list.How Can i make it to get all the values in a list?
common=[]
def findCommon(interActor,interActor1):
for a in interActor:
if a in interActor1:
common.append(a)
return common
interActor=['Rishi Kapoor','kalkidan','Aishwarya']
interActor1=['Aishwarya','Suman Ranganathan','Rishi Kapoor']

You can do it using list comprehensions:
common = [x for x in iter_actor1 if x in iter_actor2]
or using sets:
common = set(iter_actor1).intersection(iter_actor2)

interActor=['Rishi Kapoor','kalkidan','Aishwarya']
interActor1=['Aishwarya','Suman Ranganathan','Rishi Kapoor']
anotherlist = []
for x in interActor:
if x in interActor1:
anotherlist.append(x)

Python - x not in list error

I have a list inside a list and I am trying to remove any values in side the nested list that are equal to -1. I am getting a "ValueError: list.remove(x): x not in list" error when I try to run my code, any idea what I am doing wrong?
for x in list:
for i in x:
if i == -1:
list.remove(x)

You shouldn't mutate a list while iterating over it. You also shouldn't name a variable list, since that name is used by a built-in function. You can achieve what you want via a simple list comprehension:
my_list = [[x for x in v if x != -1] for v in my_list]