How to add prefix value in model for two columns...? - python

I am trying to add a Prefix(CLI, CID) into the two columns in one table but its working for me only the Primary Key but other field is not generating the CID00001 like this....
this is my model.py
class Prefix(models.Model):
cdClientID = models.CharField(primary_key=True, editable=False, max_length=200)
cdClientNumber = models.CharField(editable=False, max_length=200)
class Meta:
unique_together = (('cdClientID', 'cdClientNumber'),)
def save(self, *args, **kwargs):
if not self.cdClientID:
prefix = 'ATT{}'.format('')
prev_instances = self.__class__.objects.filter(cdClientID__contains=prefix)
if prev_instances.exists():
last_instance_id = prev_instances.last().cdClientID[-4:]
self.cdClientID = prefix + '{0:08d}'.format(int(last_instance_id) + 1)
else:
self.cdClientID = prefix + '{0:08d}'.format(1)
super(Prefix, self).save(*args, **kwargs)
here its genrating the only clientID its PK and how can i generate the clientnumber also CLN00001 with autoIncrement
tnx in advance...

Not sure how this is going to work in actual web servers, but it seems to work in Django shell. Take your code:
class Prefix(models.Model):
cdClientID = models.CharField(primary_key=True, max_length=200)
The reason why I removed editable=False is because you need to do something like the following:
>>> str = 'CLN' + 1
>>> p = Prefix.objects.create(cdClientID=str)
You need to parse number formats later on to get the leading zeros, but this is briefly how you do this.
Reference

Related

How to make more than one fields primary key and remove auto generated id in django models

Suppose in a relational database schema we have a student, a subject and a teacher which connect to each other with a relation teaches. Also, the relation has an attribute time that stores the time of the lesson. This is the most complete yet simplified example I can think to describe my case. Now, the most pythonic and django-wise way I can think of trying to reach a correct solution is, after creating a model class for student, subject and teacher, to create a new class Teaches, which has the foreign keys for the three other classes; also it has the property date field for time. This class would look something like this:
class Teaches(models.Model):
teachers = models.ForeignKey(Teacher, on_delete_models.CASCADE)
subjects = models.ForeignKey(Subject, on_delete_models.CASCADE)
students = models.ForeignKey(Student, on_delete_models.CASCADE)
time = models.DateField
class Meta:
constraints = [
fields=['teachers', 'subjects', 'students']
name='teacher_subject_student_triplet'
]
I added the Meta class because this is what this answer recommends as the correct approach.
The problem is that that in the migrations file I can still see the id field. The only way I've seen there is to remove it is to set another field as Primary Key, but in my case I cannot do that, having more than one keys. Any suggestions?
=========== model.py =============
from django.db import models
class TeacherModel(models.Model):
teacher_code = models.CharField(max_length=255)
def __str__(self):
return self.teacher_code
class SubjectModel(models.Model):
subject_code = models.CharField(max_length=255)
def __str__(self):
return self.subject_code
class StudentModel(models.Model):
student_code = models.CharField(max_length=255)
def __str__(self):
return self.student_code
class Teaches(models.Model):
custom_primary_key = models.SlugField(primary_key=True,blank=True)
teacher = models.ForeignKey(TeacherModel, on_delete=models.CASCADE)
subject = models.ForeignKey(SubjectModel, on_delete=models.CASCADE)
student = models.ForeignKey(StudentModel, on_delete=models.CASCADE)
time = models.DateField
#property
def make_key(self):
new_key = str(self.teacher.teacher_code + self.subject.subject_code + self.student.student_code)
return new_key
def save(self, *args, **kwargs):
self.custom_primary_key = self.make_key
super(Teaches, self).save(*args, **kwargs)
========= Output ==============
You can remove autogenerated id by adding primary_key=True, see below code:
class Person(models.Model):
username = CharField(primary_key=True, max_length=100)
first_name = CharField(null=True, blank=True, max_length=100)
setting a field to primary_key=True automatically makes it unique and not null.
In settings.py:
DEFAULT_AUTO_FIELD = 'django.db.models.BigAutoField'
Controls the automatic generation of primary keys of each model if defined in settings.
Read this article:
Set AutoField or BigAutoField on a per model basis

What is the "instance" being passed to the to_representation function of my ListSerializer?

The goal of this project is to create an API that refreshes hourly with the most up to date betting odds for a list of games that I'll be scraping hourly from the internet. The goal structure for the JSON returned will be each game as the parent object and the nested children will be the top 1 record for each of linesmakers being scraped by updated date. My understanding is that the best way to accomplish this is to modify the to_representation function within the ListSerializer to return the appropriate queryset.
Because I need the game_id of the parent element to grab the children of the appropriate game, I've attempted to pull the game_id out of the data that gets passed. The issue is that this line looks to be populated correctly when I see what it contains through an exception, but when I let the full code run, I get a list index is out of range exception.
For ex.
class OddsMakerListSerializer(serializers.ListSerializer):
def to_representation(self, data):
game = data.all()[0].game_id
#if I put this here it evaluates to 1 which should run the raw sql below correctly
raise Exception(game)
data = OddsMaker.objects.filter(odds_id__in = RawSQL(''' SELECT o.odds_id
FROM gamesbackend_oddsmaker o
INNER JOIN (
SELECT game_id
, oddsmaker
, max(updated_datetime) as last_updated
FROM gamesbackend_oddsmaker
WHERE game_id = %s
GROUP BY game_id
, oddsmaker
) l on o.game_id = l.game_id
and o.oddsmaker = l.oddsmaker
and o.updated_datetime = l.last_updated
''', [game]))
#if I put this here the data appears to be populated correctly and contain the right data
raise Exception(data)
data = [game for game in data]
return data
Now, if I remove these raise Exceptions, I get the list index is out of range. My initial thought was that there's something else that depends on "data" being returned as a list, so I created the list comprehension snippet, but that doesn't resolve the issue.
So, my question is 1) Is there an easier way to accomplish what I'm going for? I'm not using a postgres backend so distinct on isn't available to me. and 2) If not, its not clear to me what instance is that's being passed in or what is expected to be returned. I've consulted the documentation and it looks as though it expects a dictionary and that might be part of the issue, but again the error message references a list. https://www.django-rest-framework.org/api-guide/serializers/#overriding-serialization-and-deserialization-behavior
I appreciate any help in understanding what is going on here in advance.
Edit:
The rest of the serializers:
class OddsMakerSerializer(serializers.ModelSerializer):
class Meta:
list_serializer_class = OddsMakerListSerializer
model = OddsMaker
fields = ('odds_id','game_id','oddsmaker','home_ml',
'away_ml','home_spread','home_spread_odds',
'away_spread_odds','total','total_over_odds',
'total_under_odds','updated_datetime')
class GameSerializer(serializers.ModelSerializer):
oddsmaker_set = OddsMakerSerializer(many=True, read_only=True)
class Meta:
model = Game
fields = ('game_id','date','sport', 'home_team',
'away_team','home_score', 'away_score',
'home_win','away_win', 'game_completed',
'oddsmaker_set')
models.py:
class Game(models.Model):
game_id = models.AutoField(primary_key=True)
date = models.DateTimeField(null=True)
sport=models.CharField(max_length=256, null=True)
home_team = models.CharField(max_length=256, null=True)
away_team = models.CharField(max_length=256, null=True)
home_score = models.IntegerField(default=0, null=True)
away_score = models.IntegerField(default=0, null=True)
home_win = models.BooleanField(default=0, null=True)
away_win = models.BooleanField(default=0, null=True)
game_completed = models.BooleanField(default=0, null=True)
class OddsMaker(models.Model):
odds_id = models.AutoField(primary_key=True)
game = models.ForeignKey('Game', on_delete = models.CASCADE)
oddsmaker = models.CharField(max_length=256)
home_ml = models.IntegerField(default=999999)
away_ml = models.IntegerField(default=999999)
home_spread = models.FloatField(default=999)
home_spread_odds = models.IntegerField(default=9999)
away_spread_odds = models.IntegerField(default=9999)
total = models.FloatField(default=999)
total_over_odds = models.IntegerField(default=999)
total_under_odds = models.IntegerField(default=999)
updated_datetime = models.DateTimeField(auto_now=True)
views.py:
class GameView(viewsets.ModelViewSet):
queryset = Game.objects.all()
serializer_class = GameSerializer
Thanks
To answer the question in the title:
The instance being passed to the Serializer.to_representation() is the instance you pass when initializing the serializer
queryset = MyModel.objects.all()
Serializer(queryset, many=True)
instance = MyModel.objects.all().first()
Serializer(data)
Usually you don't have to inherit from ListSerializer per se. You can inherit from BaseSerializer and whenever you pass many=True during initialization, it will automatically 'becomeaListSerializer`. You can see this in action here
To answer your problem
from django.db.models import Max
class OddsMakerListSerializer(serializers.ListSerializer):
def to_representation(self, data): # data passed is a queryset of oddsmaker
# Do your filtering here
latest_date = data.aggregate(
latest_date=Max('updated_datetime')
).get('latest_date').date()
latest_records = data.filter(
updated_date_time__year=latest_date.year,
updated_date_time__month=latest_date.month,
updated_date_time__day=latest_date.day
)
return super().to_representation(latest_records)

Django ForeignKey accept two models

I'm working on this big project with Django and I have to update the database. I have to add another table which will replace another later.
So I want to add in a model the possibility to have a field where I can have either the old model OR the new one.
Here is the code of the old model:
class Harvests(models.Model):
ident_culture = models.IntegerField(primary_key=True)
intitule_culture = models.CharField(max_length=50, blank=True)
nom_fertiweb = models.CharField(max_length=50, blank=True, null = True)
affichage_quintaux_tonne = models.CharField(max_length=1,
choices=RENDEMENT_CHOICES, default = 'T')
type_culture = models.ForeignKey("TypeCulture", null=True)
slug = models.SlugField(null=True, blank=True)
image = models.ImageField(upload_to = 'images_doc_culture/',
null=True, blank = True)
affichage = models.BooleanField(default = True)
class Meta:
verbose_name = "Liste - Culture"
verbose_name_plural = "Liste - Cultures"
ordering = ['intitule_culture']
def __str__(self):
return self.intitule_culture
def label(self):
return self.intitule_culture or ''
#classmethod
def get_choices(cls):
choices = [('', corp.EMPTY_CHOICE_LBL)]
c_category_lbl, c_category = '', []
for item in cls.objects.all():
choices.append((item.pk, item.intitule_culture))
return choices
And there is the code od the new one I created:
class Crops(models.Model):
intitule_culture = models.CharField(max_length=75, blank=True)
affichage_quintaux_tonne = models.CharField(max_length=2,
choices=RENDEMENT_CHOICES, default = 'T')
type_culture = models.ForeignKey("TypeCulture", null=True)
ident_culture = models.IntegerField(primary_key=True)
affichage = models.BooleanField(default = True)
id_marle = models.IntegerField(null=True)
class Meta:
verbose_name = "Liste - Culture 2019"
verbose_name_plural = "Liste - Cultures 2019"
ordering = ['intitule_culture']
def __str__(self):
return self.intitule_culture
def label(self):
return self.intitule_culture or ''
#classmethod
def get_choices(cls):
choices = [('', corp.EMPTY_CHOICE_LBL)]
c_category_lbl, c_category = '', []
for item in cls.objects.all():
choices.append((item.pk, item.intitule_culture))
return choices
I want to accept both models in the field culture in this model:
class CompanyHarvest(models.Model):
company = models.ForeignKey('corp.Company', verbose_name='Exploitation',
related_name ='cultures')
culture = models.ForeignKey(Harvests, verbose_name ='Culture')
precision = models.CharField(max_length=255, blank=True)
saison_culture = models.CharField(max_length=1, choices=SAISON_CHOICES,
default = 'P')
class Meta:
verbose_name = "Expl. - Culture"
verbose_name_plural = "Expl. - Cultures"
unique_together = ('company', 'culture', 'precision', 'saison_culture')
def __str__(self):
return str(self.culture) + ' ' + self.precision + \
' ' + str(self.get_saison_culture_display() )
#property
def slug(self):
return "_".join([slugify(str(self.culture or '')),
slugify(str(self.precision or ''))]
)
I'm new to Django, can anyone help me with this please ? (^-^)
This is not possible - at least not this way. And this is not a Django limitation but a SQL one, a foreign key cannot reference either one table or another.
A possible and simple obvious solution here would be to have two foreign keys in CompanyHarvest - one for each of the old and new model -, each with blank=True et default=None, but it can quickly make a mess of all the client code (all code using CompanyHarvest).
Much better solutions would be to either only keep the existing model (adding any new field/feature to it and eventually hiding obsolete ones) or migrate all old model records to the new model (this can be combined with the naive "two foreign keys" solution so you can keep the old table and records as archives if necessary).
Also - totally unrelated but -, this:
#classmethod
def get_choices(cls):
choices = [('', corp.EMPTY_CHOICE_LBL)]
c_category_lbl, c_category = '', []
for item in cls.objects.all():
choices.append((item.pk, item.intitule_culture))
return choices
1/ should be defined on the manager (cf https://docs.djangoproject.com/en/2.1/topics/db/managers/#adding-extra-manager-methods)
2/ should be written using .values() queryset (which will save on both the db query and building full-blown instances for no good reason):
for item in cls.objects.values("pk", "intitule_culture"):
choices.append(item)
3/ and could very possibly (i'd have to see how it's used) replaced by a ModelChoiceField in the calling code.
Oh and yes: if you allow blanks for text fields, you very probably want to force the empty string as default so you don't two possible (and incompatible) cases (sql NULL and the empty string) when no value is given.

Django generate custom ID

I saw this answer but there is no specific answer yet. I want to create custom id that starts with letter. When a new record comes into database I want to change the id to A00001, .... A00002, .... A00010, ...A10000 etc. The id will be always in range 99999- 00001 so how can I do that?
my model is simple:
class Custom(models.Model):
id = models.AutoField(primary_key=True, editable=False)
The AutoField field is a kind of IntegerField field, so you can't use PKs as A00001 .
So, the possible way to achieve the requirement is to change the AutoField to CharField.
Technically you can use "String PK Field" But, you should be aware of the problems/performance issues if you are going to use that.
Here I found one nice SO post that explains the same - Strings as Primary Keys in SQL Database========================================================================
If you still really wish to migrate to String PKs, read the following
First you need to use the CharField instead of AutoField and override the save() method of model
from django.db.models import Max
class Custom(models.Model):
id = models.CharField(primary_key=True, editable=False, max_length=10)
name = models.CharField(max_length=100)
def save(self, **kwargs):
if not self.id:
max = Custom.objects.aggregate(id_max=Max('id'))['id_max']
self.id = "{}{:05d}".format('A', max if max is not None else 1)
super().save(*kwargs)
string as Primary Key not good idea if you plan to do references to the table, so i recommend you to add a property, for example:
class Custom(models.Model):
id = models.AutoField(primary_key=True, editable=False)
#property
def sid(self):
return "A%05d" % self.id
and to do queries you can do processing the input values, for example:
s_input = "A%05d" % 231 # 'A00231'
number = s_input[1:] # '00231'
input_id = int(number) # 231
I also have another way, That i use in my django project. Here are some code
def ids():
no = Employee.objects.count()
if no == None:
return 1
else:
return no + 1
emp_id = models.IntegerField(('Code'), default=ids, unique=True, editable=False)
id = models.CharField(primary_key=True, editable=False, max_length=30)
def save(self, **kwargs):
if not self.id:
self.id = "{}{:08d}".format('ABC', self.emp_id)
super().save(*kwargs)
It's better to create a new field for the custom id in the models and the process in the backend. You can set that as primary_key with unique=True and editable=False:
class Custom(models.Model):
id = models.Autofield(primary_key=True, editable=False, max_length=10)
uid= models.CharField(max_length=100, unique=True)
def save(self, *args, **kwargs):
super().save(*args, **kwargs)
self.set_uid() # calling the set_uid function
def set_uid(self):
if not self.uid: # if uid of the instance is blank
uid = "CUS" + str(self.id + (10 ** 5)) # generating the uid
customer= Custom.objects.get(id=self.id) # getting the instance
customer.uid = uid # allocating the value
customer.save() # saving the instance
def __str__(self):
return self.uid
Can also merge the set_uid() inside the save() where the function is called:
class Custom(models.Model):
id = models.Autofield(primary_key=True, editable=False, max_length=10)
uid= models.CharField(max_length=100, unique=True)
def save(self, *args, **kwargs):
super().save(*args, **kwargs)
if not self.uid: # if uid of the instance is blank
self.uid = "CUS" + str(self.id + (10 ** 5)) # generating the uid and allocating the value
self.save() # saving the instance
def __str__(self):
return self.uid
I tried to use answer of #JPG, but it has a bug.
The bug is becasue it can't auto increment.
I fixed the bug, and this my resultant code:
def save(self, **kwargs):
if not self.id:
max = YourModel.objects.aggregate(
id_max=models.Max('id'))['id_max']
if max is not None:
max += 1
else:
max = 100
self.id = "{:08d}".format(
max) # id from 100 to start
super().save(*kwargs)

django views, getting request and using it as a parameter

I'm very confused about this right now,
so I know when there's a simple code like the below
def text_detail(request ,course_pk, step_pk):
step = get_object_or_404(Text, course_id = course_pk, pk=step_pk)
course_pk and step_pk from the url, and those requests are set equal to course_id and pk here. but what I don't understand is what is course_id and pk here? I mean, course_id is from Course model which is foreignkey to step. so it's self.Course.id so it's course_id. But then, how about the next one pk? shouldn't it be step_id = step_pk? when it's just pk how does django know which pk it is?
Sorry if the question is very confusing, I'm very confused right now.
Edit
class Step(models.Model):
title = models.CharField(max_length=200)
description = models.CharField()
order = models.IntegerField(default=0)
course = models.ForeignKey(Course)
class Meta:
abstract = True
ordering = ['order',]
def __str__(self):
self.title
class Text(Step):
content = models.TextField(blank=True, default="")
Actually the get_or_404() method doing a similar/exact job as below,
try:
return Text.object.get(pk=step_pk,course_id = course_pk)
except Text.DoesNotExist:
raise Http404
You can read the source code of the same here
What is course_id and pk ?
Both are attributes of your Text model, as the name indicates pk is your Primary Key of Text model and course_id is the id/pk of course field which is a FK.
EDIT
Text is inherited from Step model so, it will show properties of usual python class.Hence, the Text model be like this internally (not-exact)
class Text(models.Model):
content = models.TextField(blank=True, default="")
title = models.CharField(max_length=200)
description = models.CharField()
order = models.IntegerField(default=0)
course = models.ForeignKey(Course)
class Meta:
ordering = ['order', ]
def __str__(self):
return self.title
Example
text = Text.objects.get(id=1) # text instance with id=1
text.course_id # will hold the id of "course" instance which is related to the particular "text" instance
URL assignment and all those stuffs are entirely depends on your choice and logic. So If you need to get a Text instance in your view, do as below,
text = get_object_or_404(Text, pk = pk_of_TEXT_instance)

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