I need to get current Tab's name. I checked this topic. And tried this code:
from kivy.lang import Builder
from kivy.uix.screenmanager import Screen, ScreenManager
from kivy.uix.floatlayout import FloatLayout
from kivymd.uix.tab import MDTabsBase
from kivymd.app import MDApp
kv = Builder.load_string("""
<SM>
P1:
<P1>
BoxLayout:
orientation: 'vertical'
MDToolbar:
title: 'TEST'
MDTabs:
id: toolbar
on_tab_switch: root.give_current_tab_name()
Tab:
text: 'Tab 1'
Tab:
text: 'Tab 2'
Tab:
text: 'Tab 3'
""")
class P1(Screen):
def give_current_tab_name(self):
print(self.ids.toolbar.carousel.current_slide.tab_label.text) #It gives previous tab name...
class Tab(FloatLayout,MDTabsBase):
pass
class SM(ScreenManager):
pass
class MyApp(MDApp):
def build(self):
return SM()
if __name__ == '__main__':
MyApp().run()
But, it gives me previous Tab's name.Should i use schedule_once(testfunc,delay_time) for check current tab's name or is there a any other easy way to do that?
Also, i need to disallow to slide page for change tab.It must be only from top tab's names.Can anyone help me for these problems. Thanks already..
For getting tabs name,
on_tab_switch pass 4 arguments:
instance_tabs, instance_tab, instance_tab_label, tab_text
so you can write something like this:
MDTabs:
id: toolbar
on_tab_switch: root.give_current_tab_name(*args)
...
def give_current_tab_name(self, *args):
tab_name = args[3]
For disallowing sliding,
just add:
MDTabs:
id: toolbar
on_tab_switch: root.give_current_tab_name(*args)
lock_swiping: True
Related
I am trying to make an app out of different .py files. But I don't know how to add them together, I have one main file, and one login file with plans to add a lot more, but with these I'm experimenting right now. They are pretty basic for now until I figure out this "bonding" between them and then I will start adding some more complex stuff. I tried couple of things and they didn't work, but I left them in code for you to see (I tried to make the app to start with MainWindow, and on press of the first button it goes to login page*). Here's the code and please help me.
*Right now when I press the button it gives me this error: OSError: exception: access violation writing 0x0000000080006010
this is main.py:
from kivy.lang import Builder
from kivy.app import App
import login
from kivy.uix.screenmanager import Screen
kv = Builder.load_string('''
<MainWindow>:
GridLayout:
cols:1
GridLayout:
rows:5
Button:
text:"NOVA ROBA"
on_release:
root.call_login()
Button:
text:"KUPCI"
Button:
text:"PRODATO"
Button:
text: "AGRONOMI"
Button:
text: "STANJE U MAGACINU"
''')
class MainWindow(Screen):
def call_login(self):
login.app().run()
pass
class main_app(App):
def build(self):
return MainWindow()
if __name__ == '__main__':
main_app().run()
this is login.py:
from kivy.lang import Builder
from kivy.uix.screenmanager import Screen
from kivy.app import App
class Login(Screen, App):
def build(self):
return
pass
kv = Builder.load_string('''
<Login>:
name:"login"
GridLayout:
rows:2
GridLayout:
cols:2
Label:
text:"Password: "
TextInput:
id:passwd
multiline: False
Button:
text: "Submit"
on_release:
passwd.text = ""
''')
class app(App):
def build(self):
return Login()
if __name__ == "__main__":
app().run()
You are creating 2 apps, which is not needed. Instead of inheriting from both Screen and App in the Loginscreen, inherit only from Screen. Then create a ScreenManager in your main.py's build method and then add the imported loginscreen as a widget, to switch to the new screen, use self.manager.current = "login" in the call_login method of MainWindow
class app(App):
def build(self):
sm = ScreenManager()
sm.add_widget(MainWindow())
sm.add_widget(Login())
return sm
>> BACKGROUND :
I want to update/change the text of a Button in the SecondScreen with a press of a Button in the MainScreen. Well I did some research and did what I want, and when I checked in the terminal the text did change. BUUT, the text shown on the SecondScreen did not.
>> THIS IS WHAT I DID :
((Mind you that I'm only using snippets of code for example, I'm going to post the whole code below.))
Button:
text:"PRESS TO CHANGE TEXT"
on_press:
root.funcself()
## on press it goes to it's root and do the "funcself" function in it
which is :
class MainScreen(Screen):
def funcself(self):
app.second.funcscreen()
## it re-directs to the SecondScreen and do the "funcscreen" function
which is :
class SecondScreen(Screen):
def funcscreen(self):
self.ids["button"].text = "SUPPOSED TO CHANGE TO THIS"
and then I checked if I did it successfully by doing print(self.ids["button"].text), and yes!
It did change, but when I navigated to the next screen, the text shown still didn't change.
Anyone mind helping and explaining?
FULL CODE :
python file :
import kivy
from kivy.app import App
from kivy.lang import Builder
from kivy.uix.label import Label
from kivy.uix.widget import Widget
from kivy.uix.button import Button
from kivy.uix.gridlayout import GridLayout
from kivy.uix.screenmanager import ScreenManager, Screen
class MainScreen(Screen):
def funcself(self):
app.second.funcscreen()
class SecondScreen(Screen):
def funcscreen(self):
value = self.ids["button"]
self.ids["button"].text = "SUPPOSED TO CHANGE TO THIS"
kv = Builder.load_file("reproduce.kv")
class reproduce(App):
second = SecondScreen()
def build(self):
return kv
def change_screen(self, x):
scrnmngr = self.root.ids["sm"]
scrnmngr.current = x
def check(self):
print(self.second.ids["button"].text)
if __name__ == "__main__":
app = reproduce()
app.run()
kivy file :
<MainScreen>:
GridLayout:
rows:2
Label:
text: "PRESS TO GO TO THE NEXT PAGE"
GridLayout:
cols:2
Button:
text:"PRESS TO CHANGE TEXT"
on_press:
root.funcself()
Button:
text:">>>"
on_press:
app.change_screen("second")
root.manager.transition.direction = "left"
<SecondScreen>:
GridLayout:
rows:2
Label:
id:label
text: "PRESS TO CHECK AND RETURN TO PREV PAGE"
Button:
id:button
text:"TEXT BEFORE CHANGE"
on_press:
app.change_screen("first")
root.manager.transition.direction = "right"
app.check()
GridLayout:
cols: 1
ScreenManager:
id:sm
MainScreen:
id:main
name:"first"
SecondScreen:
id:second
name:"second"
Root Cause
It did not change because there are two instances of SecondScreen() i.e. one instantiated in the kv file and the other one instantiated in the App class, reproduce(). The view presented is created from the kv file and the second instance does not has a view associated to it.
Solution
There are two solutions to the problem, and remove second = SecondScreen() from the App class.
Kivy Screen » default property manager
Each screen has by default a property manager that gives you the
instance of the ScreenManager used.
Using get_screen()
class MainScreen(Screen):
def funcself(self):
self.manager.get_screen('second').funcscreen()
Using App.get_running_app() & ids
class MainScreen(Screen):
def funcself(self):
App.get_running_app().root.ids.second.funcscreen()
Example
In the following example, there are two solutions provided but one of it is commented off.
main.py
from kivy.app import App
from kivy.lang import Builder
from kivy.uix.screenmanager import Screen
class MainScreen(Screen):
def funcself(self):
self.manager.get_screen('second').funcscreen()
# App.get_running_app().root.ids.second.funcscreen()
class SecondScreen(Screen):
def funcscreen(self):
value = self.ids["button"]
self.ids["button"].text = "SUPPOSED TO CHANGE TO THIS"
kv = Builder.load_file("reproduce.kv")
class reproduce(App):
def build(self):
return kv
def change_screen(self, x):
scrnmngr = self.root.ids["sm"]
scrnmngr.current = x
def check(self):
print(self.second.ids["button"].text)
if __name__ == "__main__":
reproduce().run()
Output
The second attribute you define in your app class, is a new instantiation of the screen, and not really the instance you got in your screenmanager, which you add in kv. This is why when you check, you see its changed, but not on the right instance. And again when you call app.second.func, from mainscreen, again its the wrong instance.
But your app always has a root. In your case its the gridlayout. And every screen has a manager. There are a couple of ways to acces it. But you can do like this.
In your mainscreen class in kv:
Button:
text:"PRESS TO CHANGE TEXT"
on_press:
root.manager.get_screen("second").ids["button"].text = "Something"
Here it gets the screenmanager, and uses its get_screen() method to get the screen named second, and then the id's of that kv rule.
from kivy.app import App
from kivy.uix.popup import Popup
from kivy.uix.widget import Widget
from kivy.uix.dropdown import DropDown
class MyPracticeApp(App):
def build(self):
return Debit()
class Debit(Widget):
def debit(self):
return Hello()
class Hello(Widget):
pass
if __name__ == "__main__":
MyPracticeApp().run()
kv file...
<Debit>
Button:
text : 'popup'
size_hint : 0.2,0.2
on_press : root.debit()
<Hello>:
Button:
text : 'popup2'
size_hint : 0.2,0.2
# on_press : root.debit()
There is a button popup, and when I press this button I am calling the debit() function. Inside the debit function I am calling Hello(), but I'm unable to get anything from this class. What am I doing wrong?
Whenever I click on a buttton I want a new screen but without screen navigation. How do I do this ?
You can use ScreenManager for this.
A little example:
from kivy.app import App
from kivy.lang import Builder
KV = """
#:import NoTransition kivy.uix.screenmanager.NoTransition
BoxLayout:
orientation: "vertical"
Label:
text: "top"
ScreenManager:
id: sm
transition: NoTransition()
Screen:
name: "screen1"
Button:
text: "screen 2"
on_release: sm.current = "screen2"
Screen:
name: "screen2"
Button:
text: "screen 1"
on_release: sm.current = "screen1"
Label:
text: "bottom"
"""
class TestApp(App):
def build(self):
return Builder.load_string(KV)
TestApp().run()
Question Kivy Factory
what is the concept of Factory in kivy
Answer
When the keyword Factory is used anywhere (e.g. kv file, or Python script) in your project, it will automatically register any class or module and instantiate them.
Example
The following example illustrates the use of Factory in the kv file to register and instantiate Popup widget, Hello. There is no class definition of Hello and no definition for method debit() in Python script.
main.py
from kivy.app import App
from kivy.uix.widget import Widget
from kivy.lang import Builder
Builder.load_string("""
#:import Factory kivy.factory.Factory
<Debit>:
Button:
text : 'popup'
size_hint : 0.2,0.2
on_press : Factory.Hello().open()
<Hello#Popup>:
title: 'Popup2'
auto_dismiss: False
BoxLayout:
orientation: 'vertical'
Label:
text: 'Hello Kivy'
Button:
text : 'Close Popup'
size_hint : 1,0.2
on_press : root.dismiss()
""")
class Debit(Widget):
pass
class MyPracticeApp(App):
def build(self):
return Debit()
if __name__ == "__main__":
MyPracticeApp().run()
References: Kivy » Factory object
Question 1
There is a button popup, and when I press this button I am calling the
debit() function. Inside the debit function I am calling Hello(), but
I'm unable to get anything from this class. What am I doing wrong?
Explanation
The second button is not displayed because the app did not have instructions on what to do with the instantiated object, Hello which contains a child widget, Button.
Solution
One of the solution is to add the new object using add_widget() function.
Snippets - Py
def debit(self):
return self.add_widget(Hello())
Question 2
Whenever I click on a button I want a new screen but without screen
navigation. How do I do this ?
Solution
You could use Kivy Popup widget.
Example
main.py
from kivy.app import App
from kivy.uix.popup import Popup
from kivy.uix.widget import Widget
from kivy.lang import Builder
Builder.load_string("""
<Debit>:
Button:
text : 'popup'
size_hint : 0.2,0.2
on_press : root.debit()
<Hello>:
title: 'Hello Popup2'
auto_dismiss: False
Button:
text : 'Close Popup'
size_hint : 0.2,0.2
on_press : root.dismiss()
""")
class Debit(Widget):
def debit(self):
return Hello().open()
class Hello(Popup):
pass
class MyPracticeApp(App):
def build(self):
return Debit()
if __name__ == "__main__":
MyPracticeApp().run()
Output
i have a simple test program:
main.py
from kivy.app import App
from kivy.uix.button import Button
from kivy.uix.screenmanager import Screen
from kivy.clock import mainthread
class TestScreen(Screen):
#mainthread
def on_pre_enter(self): #Is loaded before kv buttons etc? how make it work
pass
#mainthread
def on_enter(self): #Load after kv buttons etc?
button = Button(text="Work?")
#how now add it to display?
#how control where display it? on end or begin is just about on_pre and on?
class TestApp(App):
pass
if __name__ == '__main__':
TestApp().run()
And test.kv file
#:import NoTransition kivy.uix.screenmanager.NoTransition
<TestScreen>:
name:'try'
GridLayout:
id:'test'
cols:2
Button:
text:'Test'
on_press:app.root.current='Main'
ScreenManager:
transition: NoTransition()
Screen:
name: 'Main'
GridLayout:
cols:1
Button:
text:'1'
Button:
text:'2'
Button:
text:'Test'
on_press:root.current='try'
TestScreen:
Is simple to control kv and python widgets(but i dont know how but is more easy to writes widgets etc in kv file, but still need create some in python for automatic content) or better just create all in python withou kv file? I wanna make somehting like this: App with left menu always displayed and on the right side another screen with dynamic content based on screen(clicked from menu) is maybe another simple solution for this. Anyone can explain me step by step? :)
AttributeError
The solution to AttributeError, please replace "id: 'test'" with "id: test" in test.kv file.
Dynamic Content
It is possible to display screen with dynamic content based on clicked from menu. But remember to remove the widgets that were added when exiting the screen (TestScreen/SettingsScreen). If you do not remove the widgets, you will get duplicates/multiples of each widget added each time you enter the screen (TestScreen/SettingsScreen). I recommend using on_pre_enter and on_leave methods. Please refer to the example below for details.
Example
main.py
from kivy.app import App
from kivy.uix.screenmanager import ScreenManager, Screen
from kivy.uix.button import Button
class MyScreenManager(ScreenManager):
pass
class MenuScreen(Screen):
pass
class SettingsScreen(Screen):
def on_pre_enter(self, *args):
self.ids.test.add_widget(Button(text="Work?"))
def on_leave(self, *args):
self.ids.test.remove_widget(self.ids.test.children[0])
class TestApp(App):
title = "Add & Remove Widgets Dynamically"
def build(self):
return MyScreenManager()
if __name__ == "__main__":
TestApp().run()
test.kv
#:kivy 1.10.0
#:import NoTransition kivy.uix.screenmanager.NoTransition
<MyScreenManager>:
transition: NoTransition()
MenuScreen:
SettingsScreen:
<MenuScreen>:
name: 'menu'
GridLayout:
cols: 1
Button:
text: '1'
Button:
text: '2'
Button:
text: 'Test'
on_press: root.manager.current = 'settings'
<SettingsScreen>:
name:'settings'
GridLayout:
id: test
cols: 2
Button:
text: 'Test'
on_press: root.manager.current = 'menu'
Output
as stated in the title - I'm stuck. I've been playing with the code around and everything works as long as I keep ScreenManager and Popup separate. Once combined - they refuse to cooperate. Anyway, here is the simple app that shows the problem I'm having.
from kivy.lang import Builder
from kivy.app import App
from kivy.uix.gridlayout import GridLayout
from kivy.uix.popup import Popup
from kivy.uix.screenmanager import Screen, ScreenManager
class First(GridLayout,Screen):
def show_popup(self):
Popp().open()
pass
class Second(Screen):
pass
class Popp(Popup):
pass
class ScreenManagement(ScreenManager):
pass
app = Builder.load_file("main.kv")
class MainApp(App):
def build(self):
return app
if __name__ == "__main__":
MainApp().run()
And main.kv file
ScreenManagement:
First:
Second:
<First>:
name:"First"
rows: 2
Button:
text: "FirstButton"
on_release: app.root.current = "Second"
Button:
text: "Show popup"
on_release: root.show_popup()
<Second>:
name:"Second"
Button:
text: "BUTTON"
on_release: app.root.current = "First"
<Popp>:
title: "testing"
text: "Hello world"
size_hint: None,None
size: 400,400
auto_dismiss: False
Button:
text: "Okay"
on_press: root.dismiss()
App starts, first and second screen are working but when trying to get popup up I end up with:
kivy.uix.popup.PopupException: Popup can have only one widget as content
Somehow Screen is seen as a widget inside of Popp? Or am I terribly misinterpreting kivy docs?
It's a bug with loading kv file, it should throw an exception in this case.
What you are doing in the code is loading the kv file twice, what causes some weird behavior. Just delete the Builder.load_file(..) and it will work. The file is going to be loaded automatically.
Also, never do double subclassing of widgets like class First(GridLayout, Screen) as it might lead to some problems. Instead, create a grid layout inside the screen.
Put the elements in the Popup inside a layout, for example: Boxlayout.
Here's what I mean:
<Popp>:
title: "testing"
BoxLayout:
orientation: 'vertical'
size_hint: None,None
size: 400,400
Label:
text: "Hello world"
Button:
text: "Okay"
on_press: root.dismiss()
I have same problem with using kivy Builder.load_file and Popup, they dont work together.
the solution is simple, build popup in python code side. this is a loading popup example:
python:
from kivy.app import App
from kivy.uix.popup import Popup
from kivy.factory import Factory
from kivy.properties import ObjectProperty
from kivy.clock import Clock
from kivy.lang import Builder
from kivy.uix.popup import Popup
from kivy.uix.image import Image
from kivy.uix.label import Label
from kivy.uix.boxlayout import BoxLayout
import time, threading
buildKV = Builder.load_file("example.kv")
class ExampleApp(App):
def show_popup(self):
content = BoxLayout(orientation= "vertical")
image=Image(source= 'files/loading.gif', anim_delay= 0)
label=Label(text= 'Model is Running.\nBe Patient Please.')
content.add_widget(image)
content.add_widget(label)
self.popup = Popup(title='Model is Running.',
size_hint=(.250, .785),
content=content, auto_dismiss=False)
self.popup.open()
def process_button_click(self):
# Open the pop up
self.show_popup()
# Call some method that may take a while to run.
# I'm using a thread to simulate this
mythread = threading.Thread(target=self.something_that_takes_5_seconds_to_run)
mythread.start()
def something_that_takes_5_seconds_to_run(self):
thistime = time.time()
while thistime + 10 > time.time(): # 5 seconds
time.sleep(1)
# Once the long running task is done, close the pop up.
self.pop_up.dismiss()
if __name__ == "__main__":
ExampleApp().run()
kivy:
BoxLayout:
Button:
height: 40
width: 100
size_hint: (None, None)
text: 'Click Me'
on_press: app.process_button_click()