Open a new window with the button - python

I am building a real time monitoring project where information is given in the first window and that's keep on updating in the second window. I am trying to monitor the updated information in parallel from a different window using the same code, but as I pressed the new button and given the new information it is updating in the previous window also but I wanted monitor window to be completely different, so that I can monitor the different information in parallel using the same code. Please have a look at the sample code and help me with the ideas.
The sample code:
import time
import threading
import tkinter.messagebox
from tkinter import ttk
import queue
from tkinter import *
class Demo1:
data=[]
def __init__(self, master):#Python scrollbar on text widget
self.master = master
self.t=tkinter.Text(self.master,height=20,width=50)
self.t.grid(row=1, column=1)
self.button = tkinter.Button(self.master,height=3,width=10, text="OK", command = self.new_window)
self.button.grid(row=2,column=1)
def new_window(self):
self.inputValue=self.t.get("1.0",'end-1c')
Demo1.data1=self.inputValue.split("\n")
self.master.destroy() # close the current window
self.master = tkinter.Toplevel() # create another Tk instance
self.app = Demo2(self.master) # create Demo2 window
self.master.mainloop()
class Demo2:
t1 = []
s1 = True
display = []
display1 = []
i=0
kas = True
num=0
j1=0
def __init__(self, master):
self.master = master
self.button = tkinter.Button(self.master,height=2,width=11, text="new",command=self.new).place(x=0,y=0)
self.label = tkinter.Label(self.master, text="monitor", font=("Arial",20)).grid(row=0, columnspan=3)
cols = ('aa','bb')
self.listBox = ttk.Treeview(self.master, columns=cols)
for col in cols:
self.listBox.heading(col, text=col)
self.listBox.column(col,minwidth=0,width=170)
self.listBox.grid(row=1, column=0)
self.a()
def a(self):
self._img=tkinter.PhotoImage(file="green1.gif")
a=Demo1.data1
for i,(a) in enumerate(a): #here I have some function which runs repeatedlly
self.listBox.insert('', 'end',image=self._img, value=(a))
threading.Timer(1.0, self.a).start()
def new(self):
main()
def main():
root = tkinter.Toplevel()
app = Demo1(root)
root.mainloop()
if __name__ == '__main__':
main()
I have given the pppp information to monitor but as a pressed new button and added the xx information its updating in the previous window also. Please help me with the idea so that the link between these window will be vanished.
Output:

You have some major issues with your program. Including how you are trying to use your classes. The Toplevel() object was giving me issue, so I used Tk(). This should show you how to properly use the classes with the window. Most importantly your second window needs to be created from global not the first window. Also Demo1.data is a reference to your class definition not the actual data you loaded. I hope this example is helpful.
from tkinter import *
# your second window should be created in global
def create_demo2():
global app, app2
root2 = Tk()
app2 = Demo2(root2, app)
class Demo1:
def __init__(self, window):
self.window = window
self.data = ""
self.button = Button(self.window, text="New Window",
command=create_demo2)
self.button.pack()
def set_data(self):
self.data = "data"
class Demo2:
# you could just use app from global scope, but I like to pass so that it is explicit.
def __init__(self, window, app1):
self.window = window
self.button_set = Button(self.window, text="Set", command=app1.set_data)
self.button_use = Button(self.window, text="Use", command=self.use_data)
self.app = app1
self.label = Label(self.window)
self.button_set.pack()
self.button_use.pack()
self.label.pack()
def use_data(self):
self.label.configure(text=self.app.data)
root = Tk()
app = Demo1(root)
app2 = None
root.mainloop()

Related

How to get variable from a class to another Tkinter window

The goal is to pass the variable string1 from class Display to be used in another Tkinter window.
So when the button named Next [in class Display load function] is clicked, it would open a new Tkinter window. And in the new window, the variable string1 from class Display needs to be retrieved for further action. May i know should i create another class Display2, or should i just add a method in the class Display?
Currently the string variable can be passed as reference from class Display to the class Action_Data. But how can it be passed to another Tkinter window when the button Next is clicked?
I am trying to get the variable via the callback function new_window. Just not sure if it's how it's done. Any pointer would be appreciated. Many thanks.
from tkinter import *
import tkinter as tk
#Application window
root = tk.Tk()
#Display Class
class Display (tk.Frame):
def __init__(self, master, display_data):
tk.Frame.__init__(self,master)
self.master = master
#passing data as reference
self.display= display_data
#button
self.load_button = tk.Button(self, text="Load", command=self.load)
self.load_button.pack()
def new_window(self):
self.master = tk.Tk() # create another Tk instance
var_string2 = Label(self, text="<<string1 value>>")
var_string2.pack()
print (var_string2)
def load(self):
#get value
string1='value1'
self.display.action1(string1)
self.acition_button = tk.Button(self, text="Next",
command=self.new_window)
self.acition_button.pack()
#Action_Data Class
class Action_Data(tk.Frame):
def __init__(self, master):
tk.Frame.__init__(self,master)
def action1(self, path1):
var_path1 = path1
print(var_path1)
display= Action_Data(root)
display.pack()
reader = Display(root, display)
reader.pack()
pathlabel2 = Label(root)
root.mainloop()
Issue
Now the new window is blank and cannot retrieve the value of variable string1 from the load function
Error
Use the lambda function to pass the button's command, that way you can pass the needed string as an argument.
You do not need to create two instances of Tk, if you need another window, create a Toplevel.
from tkinter import *
import tkinter as tk
#Application window
root = tk.Tk()
#Display Class
class Display (tk.Frame):
def __init__(self, master, display_data):
tk.Frame.__init__(self,master)
self.master = master
#passing data as reference
self.display= display_data
#button
self.load_button = tk.Button(self, text="Load", command=self.load)
self.load_button.pack()
def new_window(self, string):
#self.master.destroy() # close the current window
new_window = tk.Toplevel() # create toplevel
var_string2 = Label(new_window, text=string)
var_string2.pack()
new_window.focus()
print (var_string2.cget("text"))
def load(self):
#get value
string1='value1'
self.display.action1(string1)
self.acition_button = tk.Button(self, text="Next",
command= lambda : self.new_window(string1))
self.acition_button.pack()
#Action_Data Class
class Action_Data(tk.Frame):
def __init__(self, master):
tk.Frame.__init__(self,master)
def action1(self, path1):
var_path1 = path1
print(var_path1)
display= Action_Data(root)
display.pack()
reader = Display(root, display)
reader.pack()
pathlabel2 = Label(root)
root.mainloop()

Python Tkinter custom msgbox fails during import

I am trying to create a custom text entry box that has a text entry field in the center and can return the user's input. I'm specifically trying to make something that can be imported and re-used in other programs. My current iteration uses an "inputdialog" class that works fine for getting the input when it's in it's own .py file, but if I try to import the module into another script, the "ok" button seemingly does nothing, and the "x" button throws an "ImportError: cannot import name 'inputdialog'" error after closing the pop-up.
The following is my code which currently works if run as a standalone script:
from tkinter import *
class inputdialog:
def __init__(self):
self.value = None
self.root = Tk()
self.root.withdraw()
self.top = Toplevel(self.root)
Label(self.top, text="Value").pack()
self.e = Entry(self.top)
self.e.pack(padx=5)
b = Button(self.top, text="OK", command=self.ok)
b.pack(pady=5, padx=5, side="right")
self.root.mainloop()
def ok(self):
self.value = self.e.get()
self.root.destroy()
if __name__ == "__main__":
test = inputdialog()
print(test.value)
The following is how I've imported this module into another program, which does not currently work:
if __name__ == "__main__":
# These two lines below are needed to make sure that "askopenfilename"
# doesn't show it's top level tkinter window
root = Tk()
root.withdraw()
entdbemp = askopenfilename(title="Please select a file: ")
# Here is my non-working module call
master = inputdialog()
print(master.value)
Why would my "OK" button cease to function when imported? Is there any way I can fix my code to allow it to be imported? Is there a better way of trying to make an importable text entry module using tkinter?
The problem has nothing to do with importing. The problem is that in your second example you call Tk() twice: once in each file. Also, when you call 'destroy' you are only removing the GUI from the screen, you are not exiting the mainloop.
To make this work, you need to remove the lines that create a root in the inputdialog class, move the mainloop() call to a point after starting the class, and then call the quit method for the toplevel window (not the root window):
from tkinter import *
class inputdialog:
def __init__(self, master=None):
self.value = None
self.top = Toplevel(master)
Label(self.top, text="Value").pack()
self.e = Entry(self.top)
self.e.pack(padx=5)
b = Button(self.top, text="OK", command=self.ok)
b.pack(pady=5, padx=5, side="right")
def ok(self):
self.value = self.e.get()
self.top.quit()
if __name__ == "__main__":
root = Tk()
root.withdraw()
master = inputdialog(root)
root.mainloop()
print(master.value)
If you want to be neat and proper: rather than making a class that wraps around a different class, in OOP and GUIs we like to make a subclass:
import tkinter as tk
class inputdialog(tk.Toplevel):
def __init__(self, master=None):
tk.Toplevel.__init__(self, master)
self.value = None
tk.Label(self, text="Value").pack()
self.e = tk.Entry(self)
self.e.pack(padx=5)
b = tk.Button(self, text="OK", command=self.ok)
b.pack(pady=5, padx=5, side="right")
def ok(self):
self.value = self.e.get()
self.quit()
if __name__ == "__main__":
root = tk.Tk()
root.withdraw()
master = inputdialog(root)
root.mainloop()
print(master.value)
Also, wildcard imports (from module import *) are ugly and against PEP8; don't use them.
BTW, the easygui package has done all this already; you may just want to install and use that.

import a python file that create a window when main window button clicks

I am creating 2 window in my program and i am using two class, since the code is complex, i separate it in 2 different python file. After i imported the second window file, how can i make sure it open without having this error which show in this picture
The original result should look like this after the new window button clicked:
Coding for Main Window:
from tkinter import *
import classGUIProgram
class Window(Tk):
def __init__(self, parent):
Tk.__init__(self, parent)
self.parent = parent
self.initialize()
def initialize(self):
self.geometry("600x400+30+30")
self.wButton = Button(self, text='newWindow', command = self.OnButtonClick)
self.wButton.pack()
def OnButtonClick(classGUIProgram):
classGUIProgram.top = Toplevel()
master = Tk()
b = classGUIProgram.HappyButton(master)
master.mainloop()
if __name__ == "__main__":
window = Window(None)
window.title("title")
window.mainloop()
Coding for Second Window:
from tkinter import *
class HappyButton:
def __init__(self, master):
frame = Frame(master)
frame.pack()
self.printButton = Button(frame, text="Print message", command=self.printMessage)
self.printButton.pack(side=LEFT)
self.quitButton = Button(frame, text="Quit", command= quit)
self.quitButton.pack(side=LEFT)
self.downloadHistoryCB=Checkbutton(frame, text="Download History")
self.downloadHistoryCB.pack(side=LEFT)
def printMessage(self):
print("Wow this actually worked!")
master = Tk()
b = HappyButton(master)
master.mainloop()
You're creating extra Tk windows. Here is an example of using Toplevel widgets and another file.
mainWindow.py
import tkinter as tk
import secondWindow as sW
class MainWindow(tk.Tk):
def __init__(self):
super().__init__()
self.title("Main Window")
self.geometry("600x400+30+30")
tk.Button(self, text = "New Window", command = self.new_window).pack()
tk.Button(self, text = "Close Window", command = self.close).pack()
self._second_window = None
def new_window(self):
# This prevents multiple clicks opening multiple windows
if self._second_window is not None:
return
self._second_window = sW.SubWindow(self)
def close(self):
# Destory the 2nd window and reset the value to None
if self._second_window is not None:
self._second_window.destroy()
self._second_window = None
if __name__ == '__main__':
window = MainWindow()
window.mainloop()
secondWindow.py
import tkinter as tk
class SubWindow(tk.Toplevel):
def __init__(self, master):
super().__init__(master)
self.title("Sub Window")
self.geometry("400x300+30+30")
# Change what happens when you click the X button
# This is done so changes also reflect in the main window class
self.protocol('WM_DELETE_WINDOW', master.close)
tk.Button(self, text = "Print", command = self.printMessage).pack()
def printMessage(self):
print("Wow this actually worked!")
When using another file be sure to not have any global code you don't want running. Your classes don't have to inherit from Tk and Toplevel, this is just an example. But you need to ensure you only ever have one instance of Tk otherwise you get the behaviour you encountered

Is it possible to keep the same window for every class in python's tkinter?

I am trying to create a program in tkinter which allows me to open an initial window then to keep it throughout all classes used. For example, if I was to create a button in a window then when I click this button, it would exuecute a method that destroys the widget, and then executes a new class that builds a new screen within the same window, such as text opposed to a button.
from tkinter import *
class Window1:
def __init__(self, master):
self.master = master
self.label = Button(self.master, text = "Example", command = self.load_new)
self.label.pack()
def load_new(self):
self.label.destroy()
## Code to execute next class
class Window2:
def __init__(self, master):
self.master = master
self.label = Label(self.master, text = "Example")
self.label.pack()
def main():
root = Tk()
run = Window1(root)
root.mainloop()
if __name__ == '__main__':
main()
I understand this is less practical, but I am curious. Cheers.
Tk() creates main window and variable root gives you access to this window. You can use root as argument for Window2 and you will have access to main window inside Window2
from tkinter import *
class Window1:
def __init__(self, master):
# keep `root` in `self.master`
self.master = master
self.label = Button(self.master, text="Example", command=self.load_new)
self.label.pack()
def load_new(self):
self.label.destroy()
# use `root` with another class
self.another = Window2(self.master)
class Window2:
def __init__(self, master):
# keep `root` in `self.master`
self.master = master
self.label = Label(self.master, text="Example")
self.label.pack()
root = Tk()
run = Window1(root)
root.mainloop()
--
Probably nobody use another class to create Label in place of Button ;)
--
EDIT: In this example using names Window1 and Windows2 is misleading because there is only one window and two classes which use this window. I would rather use names FirstOwner, SecondOwner
Everything is implemented in one Tk class and in this case there always is only one window.
from tkinter import *
from tkinter import ttk
class MainWindow():
def __init__(self, mainWidget):
self.main_frame = ttk.Frame(mainWidget, width=300, height=150, padding=(0, 0, 0, 0))
self.main_frame.grid(row=0, column=0)
self.some_kind_of_controler = 0
self.main_gui()
def main_gui(self):
root.title('My Window')
self.main_label_1 = ttk.Label(self.main_frame, text='Object_1')
self.main_label_1.grid(row=0, column=0)
self.main_label_2 = ttk.Label(self.main_frame, text='Object_2')
self.main_label_2.grid(row=1, column=0)
self.main_label_3 = ttk.Label(self.main_frame, text='Object_3')
self.main_label_3.grid(row=2, column=0)
self.setings_button = ttk.Button(self.main_frame, text='Setings')
self.setings_button.grid(row=0, column=1)
self.setings_button.bind('<Button-1>', self.setings_gui)
self.gui_elements = [self.main_label_1,
self.main_label_2,
self.main_label_3,
self.setings_button]
def setings_gui(self, event):
self.gui_elements_remove(self.gui_elements)
root.title('Setings')
self.main_label_1 = ttk.Label(self.main_frame, text='Object_1')
self.main_label_1.grid(row=2, column=0)
self.main_menu_button = ttk.Button(self.main_frame, text='Main menu')
self.main_menu_button.grid(row=0, column=1)
self.main_menu_button.bind('<Button-1>', self.back_to_main)
self.some_kind_of_controler = 1
self.gui_elements = [self.main_label_1,
self.main_menu_button]
def back_to_main(self, event):
if self.some_kind_of_controler == 1:
self.gui_elements_remove(self.gui_elements)
else:
pass
self.main_gui()
def gui_elements_remove(self, elements):
for element in elements:
element.destroy()
def main():
global root
root = Tk()
root.geometry('300x150+50+50')
window = MainWindow(root)
root.mainloop()
if __name__ == '__main__':
main()

tkinter variable does not change when changing Checkbutton state

I have a Window wich opens another window askig for the settings. But the BooleanVar I use to get the Checkbutton's state doesn't change. It does however when I call the settingswindow strait from the code without the other window.
This is the minimal code to get the
from tkinter import *
class MainWindow():
def __init__(self, master):
self.root = master
SettingsWindow()
self.root.mainloop()
class SettingsWindow():
def __init__(self):
rootSettings = Tk()
self.rebuild = BooleanVar()
chkRebuild = Checkbutton(rootSettings, text="rebuild", variable=self.rebuild, command=self.testFunc)
chkRebuild.pack()
rootSettings.mainloop()
def testFunc(self):
print(self.rebuild.get())
root = Tk()
mainWindow = MainWindow(root)
The output is always 0 when clicking on the checkbutton, evenso the output of BooleanVar is True or False.
What is the difference in calling SettingsWindow() from insite a class or outside? At least I think that is the reason it is not working.
I am using Pyhton3 in case there is a difference.
You can't have two instances of Tk. For your second window you need to create a Toplevel. You also should never call mainloop more than once in your entire program.
This is a sample example for how to solve the checkbutton's variable not changing issue.
Key: for the second window, should use Toplevel, not use Tk.
from tkinter import *
class MainWindow:
def __init__(self):
self.master = Tk()
self.fun = dict()
def set_ui(self):
Button(self.master, text='SecondWindow', command=self.fun).pack(side=LEFT)
self.master.mainloop()
class SecondWindow:
def __init__(self):
self.root = Toplevel()
self.var = BooleanVar()
self.set_ui()
def printf(self):
print(self.var.get())
def set_ui(self):
Checkbutton(self.root, text='press', variable=self.var, command=self.printf).pack(side=LEFT)
def call_second_window():
second_window = SecondWindow()
main_window = MainWindow()
main_window.fun = call_second_window
main_window.set_ui()

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