I'm a newbie to Django and I know this probably has been asked alot of times.
So basically what's happening is when I try to create a new project and whenever I'm trying to run my server, by default it's opening http://127.0.0.1:8000/catalog/ and not http://127.0.0.1:8000/.
Even if I run the server with my other projects, I'm facing the same error.
I followed this django basics tutorial on https://developer.mozilla.org/en-US/docs/Learn/Server-side/Django/skeleton_website
Idk but somehow I think it's default address is set to http://127.0.0.1:8000/catalog/.
Here's the link to the repo for the project:
https://github.com/Fanceh/django-404-error
Here's my project's urls.py:
from django.contrib import admin
from django.urls import path, include
from testuapp import urls
urlpatterns = [
path('admin/', admin.site.urls),
path('',include("testuapp.urls"))
]
Here's the code in my testuapp urls.py:
from django.urls import path
from . import views
urlpatterns = [
path('', views.testu),
]
Here's my webapp's views.py file:
from django.shortcuts import render
# Create your views here.
def testu(request):
render(request, 'Greetings!')
Is there any way I can change it?
Regards
From the tutorial link it mentions the redirect.
Any request for the root URL, will redirect you to /catalog.
Screenshot from the tutorial below.
HTH
so i assume you are below url pattern structure in your testuapp project.
urlpatterns = [
path('catalog',include("views.catalog"))
]
views.calalog is the name of the method in your view file.
Ok I think I figured it out, it's just the chrome cache. I cleared it and bam it's working!
Related
I am running a django project on a ubuntu digital ocean droplet with nginx/gunicorn on my own domain. I am using a virtual environment with Django version 3.1.6 and Python 3.8.5
I am trying to follow Corey Shafers Django tutorial to create a blog app and while I can reach the generic django success page on example.com I ran into the following from example.com/blog :
Page not found (404)
Request Method: GET
Request URL: example.com/blog
Using the URLconf defined in website.urls, Django tried these URL patterns, in this order:
admin/
The current path, blog, didn't match any of these.
My current ~/projectdir/website/urls.py (see edit at bottom):
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/',admin.site.urls),
path('', include('blog.urls')),
]
My ~/projectdir/blog/urls.py:
from django.urls import path
from . import views
urlpatterns = [
path('', views.home, name='blog-home'),
path('about/', views.about, name='blog-about'),
]
My ~/projectdir/blog/views.py:
from django.shortcuts import render
from django.http import HttpResponse
def home(request):
return HttpResponse('<h1>Blog Home</h1>')
As far as I can tell everything looks ok syntax-wise but I can't figure out why the URLconf is not seeing the blog path. I have tried reloading nginx and that didn't help.
EDIT
I have edited /projectdir/website/urls.py to look like this:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/',admin.site.urls),
path('blog', include('blog.urls')),
]
I am still getting the same 404 reponse with "The current path, blog, didn't match any of these."
I think you have not included the blog app in your base urls.py, see this django doc.
Your virtual environment may not be enabled in Visual Studio code. Activate venv in vscode or other , then try again
you can activate venv in vscode by ctrl+shift+P -> select interpreter ->Select Interpreter path -> select your python that you want use it.
or you dont run your project in vscode and then run it
and then /polls request after localhost:8000 to the correct address will do
path('', include('blog.urls')) urls paths should written as path('blog/', include('blog.urls')).
This mean include path not be an empty string.
Hello StackOverflow community,
I'm currently learning how to use the library Django combined with Python. However, I've ran into some issues which are somehow strange. My situation is the following. I have a project called "animals" which is the base of the Django application. My app is called "polls". Then I've defined the following views.
polls/views.py
from django.shortcuts import render
from django.http import HttpResponse
def animals(request, animal_id):
return HttpResponse("%s" % animal_id)
def index(request):
return HttpResponse('Hello world')
So far, so good. Unfortunatly I can't say the same about the urlpatterns.
polls/urls.py
from django.urls import path
from . import views
urlpatterns = [
path('',views.index,name='index'),
# Redirects to localhost:8000/polls/<animal_id>
path('<int:animal_id>/',views.animals,name='animals')
]
Whenever I want to navigate to the url "localhost:8000/polls/10/" Django reminds me of the fact, that the url is not accepted by the application and a 404 Error is thrown inside my browser. Am I missing something here?
UPDATE
I've managed to resolve the problem by fixing a rather trivial error. While the polls/urls.py was alright, the problem lay inside the animals/urls.py file. This file looked like this:
animals/urls.py
from django.conf.urls import url
from django.contrib import admin
from django.urls import include,path
urlpatterns = [
url(r'^admin/', admin.site.urls),
path('polls',include('polls.urls')),
]
As one can see, the "polls" path is not finished with a "/" sign. This indicates to Django that my desired route would be localhost:8000/polls where is any integer I add to the url. However, you have to add the slash at the end. Otherwise Django won't work as expected.
#code in urls.py
from django.contrib import admin
from django.urls import path
from . import views
urlpatterns = [
path('admin/', admin.site.urls),
path('', views.index, name= 'index'),
path('about/', views.about, name ='about'),
]
#code in views.py
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello")
def about(request):
return HttpResponse("about harry")
Body
I am doing this while watching a tutorial, and the same thing is working for him. Moreover, if mistakenly I write the wrong code and run, cmd shows the errors and on reloading the browser the server doesn't work more. Then I need to restart CMD and again run manage.py. Please tell me the reason and also the solution, Thanks.
What errors do you get?
Besides there're 2 urls' files: url routes for pages are inside urls.py in the same folder where views.py are. In another urls.py (the one which is in the same folder with manage.py) you may need to write following, assuming that 'polls' is the name of you application:
from django.urls import include, path
urlpatterns = [
path('polls/', include('polls.urls')),
]
According to Django docs: include() function allows referencing other URLconfs. Whenever Django encounters include(), it chops off whatever part of the URL matched up to that point and sends the remaining string to the included URLconf for further processing.
You should always use include() when you include other URL patterns. admin.site.urls is the only exception to this.
If you still get the error: check that you’re going to http://localhost:8000/polls/ and not http://localhost:8000/
I have a problem with my project & I hope that you will help me figure it out.The main problem is that my project is a one-single page template, so I don't have so many views , but I want to know , how to redirect to my homepage
from django.conf.urls import url
from django.contrib import admin
from iubestete import views as iubestete_views
urlpatterns = [
url(r'^$', iubestete_views.index),
url(r'^',iubestete_views.index,name="portal"),
url(r'^admin/', admin.site.urls),
]
here is my urls.py file , which function should I import or what should I do? I mean, I want to know for example, if a person types "http://127.0.0.1:8000/adsnjiwadi/" ,how can I redirect that link to my homepage(index.html)?Thank you so much & I hope that you'll have a great day:) Peace:)
Your code url(r'^',iubestete_views.index,name="portal") in urls.py already catch all URL pattern, it will direct to your home page.
eg: http://127.0.0.1:8000/adsnjiwadi, http://127.0.0.1:8000/sfddasfdfaf/ddfsaf, etc. will go to your home page (index).
In your urls.py
url(r'^(?P<garbage>.*)/$', views.garbage,name='redirect')
In your views.py
from django.core.urlresolvers import reverse
def garbage(request, garbage):
return HttpResponseRedirect(reverse('index'))
This is is a hacky method. Anything other than your root url will return to index url.
I migrated my Django project to an Ubuntu distant server. I'm using mod_wsgi in order to runserver and I have some questions about default page.
I'm really new in this domain and I apologize if my question is bad or useless ..
When I want to connect to my Django application, I have to write something like that :
http://172.XX.XX.XXX/Home/login/
If I write just :
http://172.XX.XX.XXX
I get :
Page not found
Using the URLconf defined in Etat_civil.urls, Django tried these URL patterns, in this order:
^admin/
^BirthCertificate/
^Identity/
^Accueil/
^Home/
^captcha/
^Mairie/
The current URL, , didn't match any of these.
My question is :
How I can define redirected url in order to write http://172.XX.XX.XXX in my browser and go directly to http://172.XX.XX.XXX/Home/login/ for example ?
This is urls.py file from my project :
from django.conf.urls import url, include
from django.contrib import admin
from django.conf.urls.static import static
from django.conf import settings
from BirthCertificate import views
from Identity import views
from Accueil import views
from log import views
from Mairie import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^BirthCertificate/', include('BirthCertificate.urls')),
url(r'^Identity/', include('Identity.urls')),
url(r'^Accueil/', include('Accueil.urls')),
url(r'^Home/', include('log.urls')),
url(r'^captcha/', include('captcha.urls')),
url(r'^Mairie/', include('Mairie.urls')),
]
Because I just want for example, write my IP adress in order to access to my Django application and not write all the time a complete url.
If you need some files (apache2 files, ...) please tell me which one I have to post there.
Include this in views.py file of your any app:
from django.shortcuts import redirect
def some_view(request):
return redirect('/Home/login/')
Suppose the view is in log app then,
Include this in your urls.py:
from log.views import some_view
urlpatterns = [
url(r'^$', some_view,name='index'),
url(r'^admin/', admin.site.urls),
url(r'^BirthCertificate/', include('BirthCertificate.urls')),
url(r'^Identity/', include('Identity.urls')),
url(r'^Accueil/', include('Accueil.urls')),
url(r'^Home/', include('log.urls')),
url(r'^captcha/', include('captcha.urls')),
url(r'^Mairie/', include('Mairie.urls')),
]
One method is to use RedirectView by making the following changes to your urls.py:
from django.views.generic.base import RedirectView
urlpatterns = [
url(r'^$', RedirectView.as_view(url='/Home'), name='home'),
...
]
You can either do this in Django or Configure from your webserver. Django has redirects app go through https://docs.djangoproject.com/en/1.10/ref/contrib/redirects/ for more info. You just add the source and redirect urls in the redirects section of your django admin.