This question already has answers here:
How to display a float with two decimal places?
(13 answers)
How to format a floating number to fixed width in Python
(10 answers)
Closed 2 years ago.
When we round off using python is there a way we get answer in 2 decimal place incase if:
round(10.3,2)
It will give 10.3.Is there way so that we get 10.30?
10.3 is the same number as 10.30 so rounding has nothing to do with it. Try string formatting.
n = 10.3
"{:.2f}".format(n) # classic str.format
f"{n:.2f}" # f-strings in 3.6+
Related
This question already has answers here:
How to get numbers after decimal point?
(37 answers)
Closed 3 years ago.
If I print 5/4 I get 1.25. How do I just get the .25 part.
print(5/4)
1.25
Not the most elegant solution but this will work
print(5/4-5//4)
This question already has answers here:
python3: How to get logical complement (negation) of a binary number, eg. '010' => '101'?
(5 answers)
Two Complement's Python (with as least bits as possible)
(1 answer)
Closed 4 years ago.
I need to convert negative number to binary in python.
How can I do it ?
EDIT: I need to use twos complement
bin(-2)
#'-0b10'
Use the built in binfunction to get a binary representation.
This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 5 years ago.
https://i.imgur.com/YYNhvNv.png
Its adding in 1 at the end of that console log output. Why?
Answer is suppose to be only 13.37
Likely because it is adding to numbers of type double (I am not a huge Python expert though, so I could be wrong). The doubletype, much like single does not have perfect precission. Hence some decimal errors can occur...
This question already has answers here:
Limiting floats to two decimal points
(35 answers)
Closed 7 years ago.
So I was surprised I didn't find anything regarding this.
I have a python script which is testing a C++ program. It needs to format a float in the same way std::setprecision does. That is a float like 1.265 should be rounded UP to 1.27 (2 dp).
Now I have the following code:
"{:.2f}".format(myFloat)
The issue is that numbers like 1.265 are rounded to 1.26 and my tests fail. setprecision rounds 1.265 to 1.27.
What is the best way to fix this issue?
You can use double rounding to overcome the inability of binary arithmetic to exactly represent a decimal value.
round(round(1.265, 3) + 0.0005, 2)
This question already has answers here:
Change default float print format
(8 answers)
Closed 8 years ago.
In c++, there exists the cout.precision() to set the number of decimal digits I want to see when I print out a floating point number. Is there any equivalent solution in Python so that every time I want to print out a float I don't get those 11 extra digits that I don't actually need?
In Python you can use the format() function your floats explicitly:
print format(floatvalue, '.5f')
to output a float with 5 digits after the decimal. See the Format Specification Mini-Language for details on the formatting options.
You can also use the str.format() method to control how a float value is interpolated into a larger string, using the same formatting parameters.