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How can I find an element or his index in a list by a few characters of it? [closed]

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How can I find an element or his index in a list by a few characters of it?
For Example:
x = input()
list = ['alberto', 'kari', 'mino']
#now I want to find the element, which starts or contain x (for exampke x = 'albe')
#the next similir element should be found
#and then remove it

for item in list:
If 'alb' in item:
Item.pop()

Convert list of list into dictionary [closed]

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I have a list of list as follows
my_list = [['val1','12'],['val2', 'disabled'],['apple', 10],['banana', 20]]
i would like to convert my_list into dictionary such that my_dict looks like
my_dict = {'val1':'12','val2':'disabled','apple':10, 'banana:20}

Just issue dict(my_list). The dict constructor accepts any iterable of two-element iterables.

You could write your own code like:
my_dict = {}
for i in my_list:
my_dict[i[0]] = i[1]
print(my_dict)

Coverting a python list into string with comma separated in efficient way [closed]

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I have a list of acc nos:
list1 = ['1234','3456','2345','5543','1344','5679','6433','3243','0089']
Output I need is a string:
print(output): '1234','3456','2345','5543','1344','5679','6433','3243','0089'

You can join all the values with ',' and then adding a ' before and after the string like this:
"'{0}'".format("','".join(list1))

>>> list1 = ['1234','3456','2345','5543','1344','5679','6433','3243','0089']
>>> print(','.join(["'{0}'".format(s) for s in list1]))
'1234','3456','2345','5543','1344','5679','6433','3243','0089'

Efficient way of parsing string [closed]

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How would you turn a string that looks like this
7.11,8,9:00,9:15,14:30,15:00
into this dictionary entry
{7.11 : [8, (9:00, 9:15), (14:30, 15:00)]}?
Suppose that the number of time pairs (such as 9:00,9:15 and 14:30,15:00 is unknown and you want to have them all as tuple pairs.

First split the string at the commas, then zip cluster starting from the 3rd element and put it into a dictionary:
s = "7.11,8,9:00,9:15,14:30,15:00"
ss = s.split(',')
d = {ss[0]: [ss[1]] + list(zip(*[iter(ss[2:])]*2))}
Output:
{'7.11': ['8', ('9:00', '9:15'), ('14:30', '15:00')]}
If you need to convert it from string to appropiate data types (you'll have to adapt it according to your needs), then after getting the ss list:
time_list = [datetime.datetime.strptime(t,'%H:%M').time() for t in ss[2:]]
d = {float(ss[0]): [int(ss[1])] + list(zip(*[iter(time_list)]*2))}

select the characters in after "):" and print it in between? [closed]

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I have a file like this
(E:0.13228,((D:0.08440,A:0.14071):0.29270,(H:0.30329,(B:0.06928,
(F:0.00236,G:0.00010):0.00010):0.44531):0.06201):0.57269,C:0.19183);
I need to generate it as follows:
(E:0.13228,((D:0.08440,A:0.14071)0.29270:0.29270,(H:0.30329,(B:0.06928,
(F:0.00236,G:0.00010)0.00010:0.00010)0.44531:0.44531)0.06201:0.06201)0.57269:0.57269,C:0.19183);

What you should use in this cases are the regular expressions. Check Python re
match_pattern = r'\):(\d(\.\d+)?)'
output_pattern = r')\1:\1'
input_str = """(E:0.13228,((D:0.08440,A:0.14071):0.29270,(H:0.30329,(B:0.06928,
(F:0.00236,G:0.00010):0.00010):0.44531):0.06201):0.57269,C:0.19183);"""
output_str = re.sub(match_pattern, output_pattern, input_str)
print(output_str)
And the result is:
(E:0.13228,((D:0.08440,A:0.14071)0.29270:0.29270,(H:0.30329,(B:0.06928,
(F:0.00236,G:0.00010)0.00010:0.00010)0.44531:0.44531)0.06201:0.06201)0.57269:0.57269,C:0.19183);

I guess you could go with some string manipulation like so if you're not using regular expressions
data = "(E:0.13228,((D:0.08440,A:0.14071):0.29270,(H:0.30329,(B:0.06928,
(F:0.00236,G:0.00010):0.00010):0.44531):0.06201):0.57269,C:0.19183);"
dataParts = data.split("):")
correctedData = dataParts[0]
for dataPart in dataParts[1:]:
number = dataPart[:7]
correctedData = "){}:".format(number).join([correctedData, dataPart])
but that's not clean...