How to Change Django Default Page to your Design? - python

I uploaded my site to the live server, but still, I am seeing Django default page, I updated my urls.py file, but still, it's not working. and it's showing me this output. Please let me know where I am Mistaking.
I am trying to access this mydomain.com/dashboard
Using the URLconf defined in yoursite.urls, Django tried these URL patterns, in this order:
admin/
The current path, dashboard, didn't match any of these.
here is my urls.py file...
urlpatterns = [
path('admin/', admin.site.urls),
url(r'^dashboard/', include('dashboard.urls')),
url(r'^accounts/', include('accounts.urls')),
url('', include('frontpanel.urls')),
path('', views.index, name='index'),
]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
And here is my views.py file...
def index(request):
category = Category.objects.all().order_by('created_at')
return render(request, "base.html", {'category':category})

What version of Django are you using?
Try changing url to re_path (remember to import it first). I think url has been deprecated.

After Analyzing the question u never mentioned ur app urls.py you only mentioned project urls.py . As u have url(r'^dashboard/', include('dashboard.urls')), in ur project urls.py, there must be a file in your app also named urls.py which handles urls having prefix /dashboard/ , by default django doesnt make that file you need to manually make it add ur function names to redirect . For example this is my main urls.py file
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path('display_report/', include("display_report.urls"))
]
then u have to make a file named urls.py in ur app also to handle the requests and redirect the the approaite functions , in my display_report app i made a urls.py that looks like this
from django.contrib import admin
from django.urls import path, include
from display_report import views
from django.conf.urls.static import static
from django.conf import settings
urlpatterns = [path('', views.index)]
And then it will redirect to function named index in ur views.py file inside ur app
from django.shortcuts import render, redirect, HttpResponse
# from .models import Employee, Tasks, Report, Fileupload, Fileuploadnext
from django.views.decorators.csrf import csrf_exempt
# Create your views here.
def index(request):
return render(request."index.html")
Here my ur will be mydomain.com/display_report and my index.html file will be inside the template folder

Related

python: Django Page not found (404)

app urls.py
from django.urls import path
from . import views
urlpatterns = [
path('hello', views.index, name='index')
]
project urls.py
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('admin/', admin.site.urls),
path('hello/', include("hello.urls"))
]
views.py
from django.http import HttpResponse
from django.shortcuts import render
# Create your views here.
def index(request):
return HttpResponse("Hello, World!")
I've re-watched the tutorial several times and still can't find the error.
Since your project's urls.py includes hello using the prefix 'hello/' in
path('hello/', include("hello.urls"))
and your app's urls.py also has hello as the path in
path('hello', views.index, name='index')
you will need to access /hello/hello in your browser to get to a view that doesn't 404.
Django's technical 404 page (the one with the yellow background) should show the available paths -- if you don't get the technical 404 page, ensure you have the DEBUG setting turned on.

page not found when making new url / view Django

Hello i am trying to add a basic url called localhost:8000/shop
so that when i am on my homepage, I can click a link called shop and It will lead me to localhost:8000/shop
in my urls.py i added
from django.conf import settings
from django.conf.urls.static import static
from django.contrib import admin
from django.urls import include, path
from homepage import views
urlpatterns = [
path('' , views.home),
path('admin/', admin.site.urls),
path('reviews/' , include('reviews.urls')),
path('shop/' , include('product.urls')),
]
in my folder called product i have a urls.py file with
from django.urls import include, path
from . import views
urlpatterns = [
path('shop/' , views.shop),
]
and in my product folder i have a views.py file with
from django.shortcuts import render
# Create your views here.
def shop(request):
return render(request, 'product/shop.html')
linking It to my html file inside my product folder..
when i run the server, I get this error message
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/shop
Using the URLconf defined in yorleico.urls, Django tried these URL patterns, in this order:
admin/
reviews/
shop/
The current path, shop, didn't match any of these.
What am i doing wrong?!
To register the path /shop, you need to use path('' , views.shop), in the urls.py in your shop app. The /shop prefix is already being defined by the path('shop/' , include('product.urls')), line in your project level urls.py.
All url patterns in the product app already start with shop/, due to the path('shop/', include('product.urls')). Therefore your urls.py for the products app should look like:
# product/urls.py
from django.urls import include, path
from . import views
urlpatterns = [
path('' , views.shop),
]
otherwise the path should be /shop/shop/.

Django can't map url to view using include method

I have the following urls.py in my project dir,
Main project urls.py
from django.contrib import admin
from django.urls import path, include
from . import views
urlpatterns = [
path('', views.render_calculator, name='render_calculator'),
path('calculator/', views.render_calculator, name='render_calculator'),
path('disclaimer/', views.render_disclaimer, name='render_disclaimer'),
path('cookiepolicy/', views.render_cookiepolicy, name='render_cookiepolicy'),
path('privacypolicy/', views.render_privacypolicy, name='render_privacypolicy'),
path('dashboard/', views.render_dashboard, name='render_dashboard'),
path('about/', views.render_about, name='render_about'),
path('admin/', admin.site.urls),
path(r'^', include('accounts.urls'))
]
Now I created a new app accounts (I added it to my apps in settings.py) where I would like to store the urls of that app in its own dir like so:
Accounts app urls.py
from . import views
from django.urls import path
urlpatterns = [
path('register/', views.render_register, name='render_register'),
]
Accounts app views.py:
from django.shortcuts import render
def render_register(request, template="register.html"):
return render(request, template)
However, this configuration throws me this error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/register
Using the URLconf defined in CFD.urls, Django tried these URL patterns, in this order:
[name='render_calculator']
calculator/ [name='render_calculator']
disclaimer/ [name='render_disclaimer']
cookiepolicy/ [name='render_cookiepolicy']
privacypolicy/ [name='render_privacypolicy']
dashboard/ [name='render_dashboard']
about/ [name='render_about']
admin/
^
The current path, register, didn't match any of these.
Where is the missing piece?
You are using path() with the regex r'^' which is causing your problem.
In order to define a path with a regex, you need to use re_path.
So change it to the following line:
re_path(r'^', include('accounts.urls'))
or you can use
path('', include('accounts.urls'))
Change this.
path(r'^', include('accounts.urls')) to
path('', include('accounts.urls'))

Django define default view with IP address

I migrated my Django project to an Ubuntu distant server. I'm using mod_wsgi in order to runserver and I have some questions about default page.
I'm really new in this domain and I apologize if my question is bad or useless ..
When I want to connect to my Django application, I have to write something like that :
http://172.XX.XX.XXX/Home/login/
If I write just :
http://172.XX.XX.XXX
I get :
Page not found
Using the URLconf defined in Etat_civil.urls, Django tried these URL patterns, in this order:
^admin/
^BirthCertificate/
^Identity/
^Accueil/
^Home/
^captcha/
^Mairie/
The current URL, , didn't match any of these.
My question is :
How I can define redirected url in order to write http://172.XX.XX.XXX in my browser and go directly to http://172.XX.XX.XXX/Home/login/ for example ?
This is urls.py file from my project :
from django.conf.urls import url, include
from django.contrib import admin
from django.conf.urls.static import static
from django.conf import settings
from BirthCertificate import views
from Identity import views
from Accueil import views
from log import views
from Mairie import views
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^BirthCertificate/', include('BirthCertificate.urls')),
url(r'^Identity/', include('Identity.urls')),
url(r'^Accueil/', include('Accueil.urls')),
url(r'^Home/', include('log.urls')),
url(r'^captcha/', include('captcha.urls')),
url(r'^Mairie/', include('Mairie.urls')),
]
Because I just want for example, write my IP adress in order to access to my Django application and not write all the time a complete url.
If you need some files (apache2 files, ...) please tell me which one I have to post there.
Include this in views.py file of your any app:
from django.shortcuts import redirect
def some_view(request):
return redirect('/Home/login/')
Suppose the view is in log app then,
Include this in your urls.py:
from log.views import some_view
urlpatterns = [
url(r'^$', some_view,name='index'),
url(r'^admin/', admin.site.urls),
url(r'^BirthCertificate/', include('BirthCertificate.urls')),
url(r'^Identity/', include('Identity.urls')),
url(r'^Accueil/', include('Accueil.urls')),
url(r'^Home/', include('log.urls')),
url(r'^captcha/', include('captcha.urls')),
url(r'^Mairie/', include('Mairie.urls')),
]
One method is to use RedirectView by making the following changes to your urls.py:
from django.views.generic.base import RedirectView
urlpatterns = [
url(r'^$', RedirectView.as_view(url='/Home'), name='home'),
...
]
You can either do this in Django or Configure from your webserver. Django has redirects app go through https://docs.djangoproject.com/en/1.10/ref/contrib/redirects/ for more info. You just add the source and redirect urls in the redirects section of your django admin.

How to setup urls.py to work with app/urls.py and templates in src with Django

Trying to figure out how to setup my own project.
I created a new Django app to make a homepage.
src/home/urls.py:
from django.conf.urls import url
urlpatterns = [
url(r'^$', 'views.index', name='index'),
]
src/home/views.py:
from django.shortcuts import render
# Create your views here.
def index(request):
return render(request, "index.html", {})
src/project/urls.py:
from django.conf.urls import url, include
from django.contrib import admin
urlpatterns = [
url(r'^', include('home.urls')),
url(r'^admin/', admin.site.urls),
]
src/templates/index.html:
<h1>Hello World</h1>
The reason this isn't in a templates folder inside of the home app is because I want to use this as my base template eventually for all apps and pages
Error reads:
ImportError at /
No module named 'views'
Using python 3.5 and django 1.9
EDIT*** changed to home.views.index
ERROR now reads:
TemplateDoesNotExist at /
index.html
In Site-wide Urls.py do the Following:
from app_name import urls as app_name_urls
from django.conf.urls import include
urlpatterns=[
path('',include(app_name_urls)
]
In App/urls.py
from django.urls import path
from .import views
urlpatterns=[
#your paths go here
]
Make sure you home is a package and you have __init__.py there.
You might also need to change views.index to home.views.index in your urls.py

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