How to change time in available line in python [duplicate] - python

This question already has answers here:
How to rewrite output in terminal
(4 answers)
Closed 2 years ago.
Let's assume there is a code which is using with anaconda prompt. While the program flowing, every second is printing to screen. However, here every second is printed the same or next line.
I want to print every second in the same place.
For example, print 30 and after 1 second later, delete 30 and print 29 to the same place.
How can I do that with python?

You can use \r to return to the start of line instead of moving the cursor to the next line (\n). Whether or not this works with your shell is an open question; e.g. IDLE occasionally has problems with this.
import time
for x in range(10):
print(x, end='\r')
time.sleep(1)
print() # to add a newline, finally
print('The end!')

After every second when you have to clear the screen you can use this :
import os
os.system('cls')

Related

Python print statement dependent on lines following it? [duplicate]

This question already has answers here:
Why doesn't print output show up immediately in the terminal when there is no newline at the end?
(1 answer)
Python print immediately?
(1 answer)
Closed 2 years ago.
I have the following code:
for file_name, content in corpus.items():
print('here')
content = [list(filter(lambda index: index not in remove_indices, content))]
corpus[file_name] = np.array(content).astype(np.uint32)
Where corpus is a 800,000 long dictionary with string keys and array values.
Things were taking forever so I decided to check how fast each iteration was by adding in that print statement.
If I comment the last two lines out it prints lots of heres really fast, so there's no problem with my iterator. What's really weird is that when I uncomment the last two lines, here takes a long time to print, even for the first one! It's like the print statement is somehow aware of the lines that follow it.
I guess my question speaks for itself. I'm in Jupyter notebook, if that helps.

How can i print multiple numbers where the next number replaces the previous number? [duplicate]

This question already has answers here:
How to output to the same line overwriting the previous line?
(4 answers)
Closed 2 years ago.
For example:
x=0
while x!=10000:
print(x)
x += 1
this outputs:
0
1
2
3....
but i don't want it to create new lines. I want it to replace the previous number so that only the numbers change without it creating new lines, if that makes sense.
You can use \r instead of \n in print(..., end='\r') to move cursor to beginning of line and then you can write in the same place.
Minimal working code
import time
for x in range(100):
print(x, end='\r')
time.sleep(0.1)
I added time.sleep to slow down it.
If you have to write shorter text in place of longer text then you may have to add spaces at the end of text.
I'm not sure if all terminals/consoles respect \r.
Some terminals may use other codes to move cursor, clear clear, etc. These codes are used by modules like curses, npyscreen, urwid, asciimatics to create widgets in text mode.
BTW: If you want it to draw progress bar then see module tqdm

Overwriting printed statements in the IDLE in Python [duplicate]

This question already has answers here:
How to output to the same line overwriting the previous line?
(4 answers)
Closed 3 years ago.
I am looking for a method so that when something is printed continuously, it overwrite what the previous printed statement says. for example, if I am making a counter, normally the outcome in the IDLE would be: 1 2 3 4...., but however I'm looking to rewrite/overwrite what the previous printed statement says so it say "1" for a second then "2" appears but we can no longer see "1". Any suggestions? Sorry about how wordy this question is, I was having a hard time trying to write this where another person understands.
import time
arr = [1,2,3,4]
for element in arr:
print(element, end='\r')
time.sleep(1)
end='\r' in the print statement does the trick

Is there a function like print that changes based on a variable? [duplicate]

This question already has answers here:
Overwriting/clearing previous console line
(4 answers)
How to clear only last one line in python output console?
(8 answers)
Closed 3 years ago.
I'm writing a python script where I print a variable from a list. At the moment, I am using print("Variable: ", var, "\n") which works but it fills up the terminal. I'd like it to only update the variable and not the text so that it stays on one line.
I tried importing os and adding os.system('clear') to the end of the loop, but I found it flashes and is unreadable. This is somewhat what I have:
import jquery
import os
varList = jquery.loads(open('variables.json').read())
for varCurrent in varList:
print ("Variable: ", varCurrent, "\n")
# Clear the terminal
#os.system('clear')
Although it works, this is completely unreadable due to the flash when the terminal clears.
Desired output: Variable: $var where $var updates and "Variable: " does not. Meaning no new lines and no terminal clearing.
Like on a typewriter, you should do a carriage return with the '\r' symbol:
import time
for x in range(10):
print(f'\rVariable: {x}', end='')
time.sleep(.5)

Using time.sleep() in Python, I'd like to print strings in the same line [duplicate]

This question already has answers here:
Print in one line dynamically [duplicate]
(22 answers)
Closed 3 years ago.
Using time.sleep() method in Python, I've been trying to print strings in a same line.
Result I want is printing five "." in a line one by one every second.
I've tried end='' with print line, but it appeared together 5 seconds later.
Here is my code.
import time
for i in range(5):
print("." , end='')
time.sleep(1)
I expect the output of "....." to be printed separately every second (during 5 seconds), but the actual output appeared altogether after 5 seconds.
Sorry for bad english but if you don't mind, please help me :)
import time
for i in range(5):
print('.', end=' ', flush=True)
time.sleep(1)
So,
try to change your code to this:
import time
for i in range(5):
print("." , end=" ", flush=True)
time.sleep(1)
And look here: https://stackoverflow.com/a/3249539/11578778
Docs: https://docs.python.org/3/library/functions.html#print
Best regards, Brhaka

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