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This code:
a = 10
b = 20
print(f "The variable a is {a} and the variable b is {b}.")
returns this error:
File "main.py", line 3
print (f "The variable a is {a} and the variable b is {b}")
^
SyntaxError: invalid syntax
The version I'm using is after 3.6, so it should work. I'm using Anaconda's prompt, if that's a problem.
you have a space between f and the string. Remove it and everything will work.
The syntax error points to the end of the string. If it pointed to the beginning of the string it would give you a better hint at the problem: after the f, which is interpreted as a variable in this case, a string is unexpected.
You need this:
a = 1
b = 2
test_str = f"{'The variable a is'} {a} {'and the variable b is '}{b}"
print(test_str)
Between the curly braces, string interpolation takes place. The variables for a and b are within two of the curly brace sets and hard-coded strings are within the other two.
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I'm trying to run
word = "where's"
os.popen(f"grep -ow '{word.replace("'", """'"'"'""")}' /texts/*.txt | wc -l").read()
I get:
File "<stdin>", line 1
os.popen(f"grep -ow '{word.replace("'", """'"'"'""")}' /texts/*.txt | wc -l").read()
^
SyntaxError: invalid syntax
Why would this be happening and how can I fix it?
If I escape the asterisk \* I get "Unexpected error after line continuation character" with the arrow pointing at the end of the line (after read())
You're trying to do too much complicated quoting all at once.
Instead, do it in two steps so the quoting doesn't conflict.
word = "where's"
word = word.replace("'", """'"'"'""")
os.popen(f"grep -ow '{word}' /texts/*.txt | wc -l").read()
To explain your error, it's because pairs of quotes do not nest in Python strings.
For example, you can't do this:
s = "alpha 'beta "gamma" delta' omega"
The double quote preceding alpha does not match up with the one following omega. It matches up with the very next double quote it sees, the one preceding gamma. The single quotes do not "protect" the double quotes.
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I want to solve this error.
i tried for almost half hours, but I couldn't find the answer..
This is my error
File "sampling_fun.py", line 71
def average(self) :
^
SyntaxError: invalid syntax
and full code
import csv
class fun :
def __init__(self, rowList, num) :
list = []
listLen = len(self.rowlist)-1
for i in range(listLen) :
list.append(self.rowList[i+1][num] # num = Header 1~4
def average(self) :
ave = sum(self.list)/self.lestLen
print("average : %0.2f" %ave)
return ave
testlist = cssRead('Data_2', 1)
test1 = fun(testlist, 1)
test1.average()
When you encounter such error, check the line before it.
You have a non-matching paranthesis, the closing brace for append is missing.
list.append(self.rowList[i+1][num])
def errors happen when python is not expecting a function definition. As #Siong Thye Goh notes, a missing ) is your issue. For the future, the only time python does not expect a function definition is after an incomplete code-block.
That can happen when you forget to close parentheses or brackets, but also when you forget to put a statement after a colon or don't indent correctly.
Rarely, it can happen due to incompatible space characters when copy-pasting from external sources.
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When executing with Python it shows error:
return (x * (1.0 — x))
^
SyntaxError: invalid character in identifier
How do I correct it?
Use the correct character for you minus operator: -. You are using some other 'dash' character that the interpreter is considering just a name like y or x. But it is invalid!
>>> bad_minus = "—"
>>> good_minus = "-"
>>> bad_minus == good_minus
False
>>> ord(good_minus)
45
>>> ord(bad_minus)
8212
>>>
Assuming the character between 1.0 and x is supposed to be a minus sign, replace it with an actual minus sign.
Your minus is not a minus. It's a "em dash".
Try replacing this '—' with '-'.
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import random
for i in range(1,21):
print("%10d" %(random.randrange(1,7)),
if (i % 5 == 0):
print ("")
What is wrong in this code ?
I know basic python (almost), but i am not able to figure out what could be error in this program.
it is showing this error:
Syntax Error: invalid syntax at line 6 (if statement)
The fourth line is missing bracket .. Thanks all of you
You missed a right bracket )
print("%10d" %(random.randrange(1,7))),
would be correct
You're missing a ) before the last comma on line 4.
Your parenthesis on line 4 don't match. Because you have an unclosed paren, python doesn't report this syntax error until the colon on line 6 (python ignores line breaks as long as you are inside an enclosing set of parenthesis, brackets, or braces).
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I am just getting started with python. I have experience with some other languages I was just curious what the correct syntax would be to print the output of multiple variables in a string. or even the same variable multiple times in a string.
arg1 = 1
arg2 = 2
print ("arg1 =",arg1) # <---------------------------this works
arg1 = 1
print ("arg1 =",arg1 "arg2",arg2) # <----------------why not this ?
SyntaxError: invalid syntax
As #Wooble points out, you have a syntax error. But let's clarify how this works in Python.
print(a, b, c, d,....)
is basically the same as
output = " ".join(a, b, c, d)
print(output)
If you want to output the same variable multiple times, sometimes format is better. http://docs.python.org/3/library/string.html#format-string-syntax
The second argument would be arg1 "arg2" which is not a valid expression. If you want to print both arg1 and "arg2", you should separate it by another comma:
print("arg1 =", arg1, "arg2 =", arg2)