'The requested URL was not found on the server' - python

from flask import Flask
app = Flask(__name__)
#app.route('/hello')
def hello_world():
return "Hello world"
if __name__ == '__main__':
app.run(host='0.0.0.0',port=8000, debug=True)
While clicking the link http://0.0.0.0:8000/, it is showing:
> The requested URL was not found on the server If you entered the URL
> manually please check your spelling and try again.

The only URL you have defined is /hello, so when you request /, there is nothing to be served, so you get the Not Found Error. You'll need to either define something for / or use http://0.0.0.0:8000/hello instead. E.g.,
#app.route('/')
def index_view():
return "hello from index"

Related

Flask 404 Not Found ( 33mGET / HTTP/1.1 [0m" 404 - )

I am trying to create my first script with flask.
Here is my code:
from flask import Flask
from flask import Blueprint, request
prediction_app = Blueprint('prediction_app', __name__)
#prediction_app.route('/health', methods=['GET'])
def health():
if request.method == 'GET':
return 'ok'
def create_app() -> Flask:
"""Create a flask app instance."""
flask_app = Flask('ml_api')
# import blueprints
flask_app.register_blueprint(prediction_app)
return flask_app
application = create_app()
if __name__ == '__main__':
application.run()
I run this code as python run.py and I am getting "Running on http://127.0.0.1:5000/".
I go to this link and I am getting instead of "ok" a page with the next error:
Not Found
The requested URL was not found on the server. If you entered the URL manually please check your spelling and try again.
Command promt gives the following output:
127.0.0.1 - - [17/Jun/2020 16:59:25] "[33mGET / HTTP/1.1[0m" 404 -
Where is the problem?
I don't see a default route (/) defined; did you try pointing your browser at http://localhost:5000/health? That's the route you did define.
(localhost and 127.0.0.1 are typically equivalent, by the way...)

My code shows this error whatever I try, and when I click on the link it shows there's a 404

Whatever I seem to try (using different secret keys, trying to fix small errors) this error shows when I run my code.
I have tried making small changes to the code such as changing the secret key, fixing indentation, etc. However, I do not understand why my code does not work, so I wanted to ask here.
from flask import Flask, render_template, session, request
from flask_socketio import SocketIO, emit, join_room
app = Flask(__name__)
app.debug = True
app.config['SECRET_KEY'] = 'secretcodehere29403949493'
socketio = SocketIO(app)
#app.route("/template/chat.html/")
def chat():
return render_template("template/login.html")
#app.route(r'/template/login.html/')
def login():
return render_template('login.html')
#socketio.on('message', namespace='/chat')
def chat_message(message):
print("message = ", message)
emit('message', {'data': message['data']}, broadcast=True)
#socketio.on('connect', namespace='/chat')
def test_connect():
emit('my response', {'data': 'Connected', 'count': 0})
if __name__ == '__main__':
socketio.run(app)
Restarting with stat
Debugger is active!
Debugger PIN: 183-355-780
(18512) wsgi starting up on http://127.0.0.1:5000
nothing displays in the link it provides in the error here, and localhost:8080 shows nothing.
Your routes may not be correct. When you call app.route, you're mapping a url to the function.
In your case the urls in your routes are defining: 127.0.0.1:5000/template/chat.html/ and 127.0.0.1:5000/template/login.html/.
Try changing a route to #app.route('/') and then navigating to 127.0.0.1:5000 or localhost:5000
Concerning your last comment (I can't comment on dylanj.nz's post), the render_template function uses the default templates folder, so there is no need to specify it on your code :)
Thus you should remove template/ in this line:
return render_template("template/login.html").
If you want to change the default folder location, add a template_folder instruction in your app = Flask(...).
Example:
app = Flask(__name__, template_folder='application/templates', static_folder='heyanotherdirectory/static')

I can't go to the other paths i am using flask

I am studying this course on flask. This is the basic flask code. When I am on the first route I am fine but when I try to put slash and got for another page it doesn't work.
I get this message:
"The requested URL was not found on the server. If you entered the URL manually please check your spelling and try again."
I did run FLASK_APP=app.py flask run
after saving.
from Flask import flask
app= Flask(__name__)
#app.route('/')
def index():
return "index"
#app.route('/me')
def me():
return "me"
if __name__== "__main__":
app.run(debug=True)
In class it works well. When i do it it does not
127.0.0.1 - - [08/Jul/2019 02:43:55] "GET /me/ HTTP/1.1" 404 -
I'm guessing 404 at the end is problem
After the reply
from Flask import flask
app= Flask(__name__)
strict_slashes=False
#app.route('/')
def index():
return "index"
#app.route('/me/')
def me():
return "me"
if __name__== "__main__":
app.run(debug=True)
You have declared your "/me" route explicitly without trailing slash. However, when calling the URL, you are calling it with slash in the end "/me/". Werkzeug (Flask development application server) by default has the rule of "strict_slashes=True", which requires you to follow exact route declaration when calling your URLs. In other words, if in your code, you declared "#app.route('/me'), your should call "127.0.0.1/me", not "127.0.0.1/me/".
Removing the slash in the end (e.g. http://localhost/me) will fix your issue. You can also change the Werkzeug setting and set strict_slashes=False if you want to remove the default rule.
I would say make a app.errorhandler(404) and then define what to do after you get an error to check if it is a 404 error, and other errors. I would also say use html and make links which you can use to go into different pages, it is easier than typing manually. here is my code:
python:
from flask import Flask, render_template
app = Flask(__name__)
app.route('/')
def home():
return render_template('home.html')
app.route('/me')
def me():
return 'me'
app.errorhandler(404)
def error(arg):
return 'wrong url'
if __name__ == "__main__":
app.run(host="0.0.0.0", port=8080)
html:
<!-- you can use css to make the link look better or <style> </style>-->

The browser only shows the first application results with Flask

When I run the code:
from flask import Flask
app = Flask(__name__)
#app.route('/')
def index():
return "Hello, world!"
if __name__ == '__main__':
app.run(debug=True)
I get the string "Hello, world!" in the chrome browser, but when I change the code:
return "Hello, world!"
to:
return "Hello"
The browser also shows the "Hello, world!" not the "Hello".
How does that happen?
Maybe the page is cached by your browser? Use Ctrl + F5 to force reload , or append ?foo=1 to the url to make your browser make a new request to your web app.

Flask custom "not found" code

I want to change the default 404 code, when flask doesn't finds the route, to other code. How can I do that?
As already said, it is generally not a good idea to redefine the meaning of standard status codes.
Although you can change a status code returned, here's an example:
from flask import Flask
app = Flask(__name__)
#app.route('/')
def hello_world():
return 'Hello World!'
#app.errorhandler(404)
def page_not_found(error):
return 'This page does not exist', 777
if __name__ == '__main__':
app.run()
This will return status code 777 on any page other than /.
Here's a result:
More on the topic you can find here.

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