import tkinter as tk
from tkinter import filedialog, Text
from subprocess import call
import os
root = tk.Tk()
def buttonClick():
print('Button is clicked')
def openAgenda():
call("cd '/media/emilia/Linux/Programming/PycharmProjects/SmartschoolSelenium' && python3 SeleniumMain.py",
shell=True)
return
canvas = tk.Canvas(root, height=700, width=700, bg='#263D42')
canvas.pack()
frame = tk.Frame(root, bg='white')
frame.place(relwidth=0.8, relheight=0.8, relx=0.1, rely=0.1)
openFile = tk.Button(root, text='Open file', padx=10,
pady=5, fg="white", bg='#263D42', command=openAgenda)
openFile.pack()
root.mainloop()
the script it calls opens a new browser window, after finishing entering text in that window, it opens a new browser windows and loops.
meanwhile the tkinter button stays clicked, visually.
the reason your Tk GUI freezes is because you have everything running on 1 thread. The mainloop is haulted by the submit function call which must be taking a "long time", so you probably see "Not Responding" appear in your Tk window when you click the button. To fix this, you need spawn a separate thread for submit to run in, so that the mainloop can keep doing it's thing and keep your Tk window from freezing.
this is done using threading. Instead of your button directly calling submit, have the button call a function that starts a new thread which then starts submit. Then create another functions which checks on the status of the submit thread. You can add a status bar too
import tkinter as tk
from tkinter import filedialog, Text
from subprocess import call
import os
import threading
root = tk.Tk()
def buttonClick():
print('Button is clicked')
def openAgenda():
call("cd ' /media/emilia/Linux/Programming/PycharmProjects/SmartschoolSelenium' && python3 SeleniumMain.py",
shell=True)
canvas.update()
return
def start_Agenda_thread(event):
global Agenda_thread
Agenda_thread = threading.Thread(target=openAgenda)
Agenda_thread.daemon = True
Agenda_thread.start()
canvas = tk.Canvas(root, height=700, width=700, bg='#263D42')
canvas.pack()
frame = tk.Frame(root, bg='white')
frame.place(relwidth=0.8, relheight=0.8, relx=0.1, rely=0.1)
openFile = tk.Button(root, text='Open file', padx=10,
pady=5, fg="white", bg='#263D42', command=lambda:start_Agenda_thread(None))
openFile.pack()
root.mainloop()
Tkinter is single-threaded: it can only do one thing at a time. While the script is running, the GUI will be frozen. You'll need to do threading, multiprocessing, or find some other way to incorporate that other script in your GUI.
Related
I want run python file which opens camera preview by Tkinter button that placed on the main window.But it runs automatically camera window without opening the main window when executing the code.
from tkinter import *
import tkinter as tk
import os
window = tk.Tk()
window.title("Camera")
window.geometry("640x480")
lbl=Label(window,text="Start", font=("Arial Bold",10))
lbl.grid(column=0,row=0)
btn = Button(window, text="Start",command=os.system('capture.py'))
btn.grid(column=1, row=0)
window.mainloop()
It should be command=lambda: os.system('capture.py'):
btn = Button(window, text="Start",command=lambda: os.system('capture.py'))
btn.grid(column=1, row=0)
If you use () near a function name, it will call the function immediately. Which is not what you want, you want it to be called upon press, so just pass the function name(with lambda if it has arguments) and tkinter will handle the rest.
I have a simple program with start and exit buttons. The start button makes a notification using win10toast, but the button remains visibly pressed down and the window becomes unresponsive. The exit button works fine before the start button is pressed. Here's my code:
from tkinter import *
from win10toast import ToastNotifier
root = Tk()
def exit_p():
exit()
def new():
hr.show_toast("New", "Alert")
return
#creates a label widget
myLabel1 = Label(root, text="Full Moon Notification!")
myLabel2 = Label(root, text="Here you can start and exit the program")
button1 = Button(root, text="Start",padx=50,command=new).grid(row=3,column=0)
button2 = Button(root, text="Exit", padx=50,command=exit_p).grid(row=4,column=0)
#puts the widget on the screen
myLabel1.grid(row=0,column=0)
myLabel2.grid(row=1,column=0)
#loop to keep program running
root.mainloop()
The issue is likely because hr.show_toast("New", "Alert") blocks.
The win10toast library conveniently provides an option threaded=True, so just change that code to
hr.show_toast("New", "Alert", threaded=True)
should make it work.
When I make a button that closes the current window and opens another, the current window doesn't close.
from tkinter import *
root = Tk()
def new_window():
root.quit()
new_window = Tk()
new_window.mainloop()
Button(root, text="Create new window", command=new_window).pack()
root.mainloop()
(This isn't my program, it's just an example)
You should be able to do it like this:
import tkinter as tk
root = tk.Tk()
def new_window():
root = tk.Tk()
test = tk.Button(root, text="Create new window", command= lambda:[root.destroy(), new_window()]).pack()
root.mainloop()
test = tk.Button(root, text="Create new window", command= lambda:[root.destroy(), new_window()]).pack()
root.mainloop()
This will literally keep opening the exact same window with a button. The lambda allows you to call multiple functions. By calling .destroy() on your root window, it destroys your window, but doesn’t stop the program. Then you create a new root window with your function.
You can use this technique on your actual script.
I've made 3 buttons on my window. I choosed that the main window should have a specific background image and a full screen.
Now there is a problem. I would like to move to a new window (page) (with an other background and other things) by clicking on button 3.
Things i tryd:
from Main.Info.travelhistry import *
I've added this to the main window to open a new python file with the code of the second screen that has to open when clicking on button 3. But I found out that if I do this both windows will open when running main window.
I added root1 = Tk() at the beginning, root1.mainloop() at the end and between them the code for the other window. But this won't work also, its opening 2 windows like above.
Those were all my attempts and i cant figure out a better way. I can but the background would stay the same. But I have to change the background for the new window to a background image i made...
Any idea what im doing wrong?
from tkinter import *
from tkinter.messagebox import showinfo
from Main.Info.travelhistry import *
def clicked1():
bericht = 'Deze functie is uitgeschakeld.'
showinfo(title='popup', message=bericht)
root = Tk()
a = root.wm_attributes('-fullscreen', 1)
#Hoofdmenu achtergrond
C = Canvas(root, bg="blue", height=250, width=300)
filename = PhotoImage(file = "test1.png")
background_label = Label(root, image=filename)
background_label.place(x=0, y=0, relwidth=1, relheight=1)
C.pack()
# Geen OV-chipkaart button
b=Button(master=root, command=clicked1)
photo=PhotoImage(file="button1.png")
b.config(image=photo,width="136",height="53", background='black')
b.place(x=310, y=340)
#Buitenland button
b2=Button(master=root, command=clicked1)
photo1=PhotoImage(file="button2.png")
b2.config(image=photo1,width="136",height="53", background='black')
b2.place(x=490, y=340)
#Reis informatie
b3=Button(master=root)
photo2=PhotoImage(file="button3.png")
b3.config(image=photo2,width="136",height="53", background='black')
b3.place(x=680, y=340)
root.mainloop()
root2.mainloop()
You shouldn't call more than one Tk() window.
Instead, tkinter has another widget called Toplevel which can be used to generate a new window.
See below for an example:
from tkinter import *
root = Tk()
def command():
Toplevel(root)
button = Button(root, text="New Window", command=command)
button.pack()
root.mainloop()
This one opens new window that you can edit.
from tkinter import *
Window = Tk()
def Open():
New_Window = Tk()
#You can edit here.
New_Window.mainloop()
Btn1 = Button(text="Open", command=Open)
Bt1n.pack()
Window.mainloop()
If have this piece of code:
import Tkinter as tk
import tkFileDialog
menu = tk.Tk()
res = tkFileDialog.askopenfilename() # un-/comment this line
label = tk.Label(None, text="abc")
label.grid(row=0, column=0, sticky=tk.W)
entry = tk.Entry(None)
entry.grid(row=0, column=1, sticky=tk.EW)
res = menu.mainloop()
Note: the askopenfilename is just a dummy input. So Just close it to get to the (now blocked) main window of TK.
When I comment the askopenfilename everything works fine. But with the it, I can not enter data in the entry.
This only happens with Windoze environments. The askopenfilename seems to steal the focus for the main TK window. After clicking a totally different window and back again in the TK window, input is possible.
I've seen reports of this before, I think it's a known bug on windows. You need to let mainloop start before you open a dialog.
If you want the dialog to appear when the app first starts up you can use after or after_idle to have it run after mainloop starts up.
For example:
menu = tk.Tk()
...
def on_startup():
res = tkFileDialog.askopenfilename()
menu.after_idle(on_startup)
menu.mainloop()
If you don't want any other GUI code to execute until after the dialog, move all your code except for the creation of the root window and call to mainloop into on_startup or some other function.
For example:
def main(filename):
label = tk.Label(None, text="abc")
label.grid(row=0, column=0, sticky=tk.W)
entry = tk.Entry(None)
entry.grid(row=0, column=1, sticky=tk.EW)
def on_startup():
res = tkFileDialog.askopenfilename()
main(filename)
root = Tk()
root.after_idle(on_startup)
askopenfilenamehas it's own event loop. The programm stops, until you selected a filename, and continues afterwards.