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How to create a single json file from two DataFrames?

I have two DataFrames, and I want to post these DataFrames as json (to the web service) but first I have to concatenate them as json.
#first df
input_df = pd.DataFrame()
input_df['first'] = ['a', 'b']
input_df['second'] = [1, 2]
#second df
customer_df = pd.DataFrame()
customer_df['first'] = ['c']
customer_df['second'] = [3]
For converting to json, I used following code for each DataFrame;
df.to_json(
path_or_buf='out.json',
orient='records', # other options are (split’, ‘records’, ‘index’, ‘columns’, ‘values’, ‘table’)
date_format='iso',
force_ascii=False,
default_handler=None,
lines=False,
indent=2
)
This code gives me the table like this: For ex, input_df export json
[
{
"first":"a",
"second":1
},
{
"first":"b",
"second":2
}
]
my desired output is like that:
{
"input": [
{
"first": "a",
"second": 1
},
{
"first": "b",
"second": 2
}
],
"customer": [
{
"first": "d",
"second": 3
}
]
}
How can I get this output like this? I couldn't find the way :(

You can concatenate the DataFrames with appropriate key names, then groupby the keys and build dictionaries at each group; finally build a json string from the entire thing:
out = (
pd.concat([input_df, customer_df], keys=['input', 'customer'])
.droplevel(1)
.groupby(level=0).apply(lambda x: x.to_dict('records'))
.to_json()
)
Output:
'{"customer":[{"first":"c","second":3}],"input":[{"first":"a","second":1},{"first":"b","second":2}]}'
or a dict by replacing the last to_json() to to_dict().

how do you convert json output to a data frame in python

I need to convert this json file to a data frame in python:
print(resp2)
{
"totalCount": 1,
"nextPageKey": null,
"result": [
{
"metricId": "builtin:tech.generic.cpu.usage",
"data": [
{
"dimensions": [
"process_345678"
],
"dimensionMap": {
"dt.entity.process_group_instance": "process_345678"
},
"timestamps": [
1642021200000,
1642024800000,
1642028400000
],
"values": [
10,
15,
12
]
}
]
}
]
}
Output needs to be like this:
metricId dimensions timestamps values
builtin:tech.generic.cpu.usage process_345678 1642021200000 10
builtin:tech.generic.cpu.usage process_345678 1642024800000 15
builtin:tech.generic.cpu.usage process_345678 1642028400000 12
I have tried this:
print(pd.json_normalize(resp2, "data"))
I get invalid syntax, any ideas?

Take a look at the examples of json_normalize, and you'll see a list of dictionaries that have the key names of the columns you want, unique to each row. When you have nested lists/objects, then the columns will be flatten to have dot-notation, but nested arrays will not end up duplicated across rows.
Therefore, parse the data into a flat list, then you can use from_records.
data = []
for r in resp2['result']:
metricId = r['metricId']
for d in r['data']:
dimension = d['dimensions'][0] # unclear why this is an array
timestamps = d['timestamps']
values = d['values']
for t, v in zip(timestamps, values):
data.append({'metricId': metricId, 'dimensions': dimension, 'timestamps': t, 'values': v})
df = pd.DataFrame.from_records(data)

Complex json to pandas dataframe

There are lots of question about json to pandas dataframe but none of them solved my issues. I am practicing on this complex json file which looks like this
{
"type" : "FeatureCollection",
"features" : [ {
"Id" : 265068000,
"type" : "Feature",
"geometry" : {
"type" : "Point",
"coordinates" : [ 22.170376666666666, 65.57273333333333 ]
},
"properties" : {
"timestampExternal" : 1529151039629
}
}, {
"Id" : 265745760,
"type" : "Feature",
"geometry" : {
"type" : "Point",
"coordinates" : [ 20.329506666666667, 63.675425000000004 ]
},
"properties" : {
"timestampExternal" : 1529151278287
}
} ]
}
I want to convert this json directly to pandas dataframe using pd.read_json() My Primary Goal is to extract Id, Coordinates and timestampExternal. As this is very complex json, normal way of pd.read_json(), simply doesnt give correct output. Can you suggest me, how can i approach to solve in this kind of situations. Expected output is something like this
Id,Coordinates,timestampExternal
265068000,[22.170376666666666, 65.57273333333333],1529151039629
265745760,[20.329506666666667, 63.675425000000004],1529151278287

You can read the json to load it into a dictionary. Then, using dictionary comprehension, extract the attributes you want as columns -
import json
import pandas as pd
_json = json.load(open('/path/to/json'))
df_dict = [{'id':item['Id'], 'coordinates':item['geometry']['coordinates'],
'timestampExternal':item['properties']['timestampExternal']} for item in _json['features']]
extracted_df = pd.DataFrame(df_dict)
>>>
coordinates id timestampExternal
0 [22.170376666666666, 65.57273333333333] 265068000 1529151039629
1 [20.329506666666667, 63.675425000000004] 265745760 1529151278287

You can read the json directly, and then given the features array to pandas as a dict like:
Code:
import json
with open('test.json', 'rU') as f:
data = json.load(f)
df = pd.DataFrame([dict(id=datum['Id'],
coords=datum['geometry']['coordinates'],
ts=datum['properties']['timestampExternal'],
)
for datum in data['features']])
print(df)
Results:
coords id ts
0 [22.170376666666666, 65.57273333333333] 265068000 1529151039629
1 [20.329506666666667, 63.675425000000004] 265745760 1529151278287

Flattening nested JSON included embedded array in Python using Pandas

I have a JSON-array from a mongoexport containing data from the Beddit sleeptracker. Below is an example of one of the truncated documents (removed some unneeded detail).
{
"user" : "xxx",
"provider" : "beddit",
"date" : ISODate("2016-11-30T23:00:00.000Z"),
"data" : [
{
"end_timestamp" : 1480570804.26226,
"properties" : {
"sleep_efficiency" : 0.8772404,
"resting_heart_rate" : 67.67578,
"short_term_resting_heart_rate" : 61.36963,
"activity_index" : 50.51958,
"average_respiration_rate" : 16.25667,
"total_sleep_score" : 64,
},
"date" : "2016-12-01",
"session_range_start" : 1480545636.55059,
"start_timestamp" : 1480545636.55059,
"session_range_end" : 1480570804.26226,
"tags" : [
"not_enough_sleep",
"long_sleep_latency"
],
"updated" : 1480570805.25201
}
],
"__v" : 0
}
Several related questions like this and this do not seem to work for the data structure above. As recommended in other related questions I am trying to stay away from looping over each row for performance reasons (the full dataset is ~150MB). How would I flatten out the "data"-key with json_normalize so that each key is at the top-level? I would prefer one DataFrame where e.g. total_sleep_score is a column.
Any help is much appreciated! Even though I know how to 'prepare' the data using JavaScript, I would like to be able to understand and do it using Python.
edit (request from comment to show preferred structure):
{
"user" : "xxx",
"provider" : "beddit",
"date" : ISODate("2016-11-30T23:00:00.000Z"),
"end_timestamp" : 1480570804.26226,
"properties.sleep_efficiency" : 0.8772404,
"properties.resting_heart_rate" : 67.67578,
"properties.short_term_resting_heart_rate" : 61.36963,
"properties.activity_index" : 50.51958,
"properties.average_respiration_rate" : 16.25667,
"properties.total_sleep_score" : 64,
"date" : "2016-12-01",
"session_range_start" : 1480545636.55059,
"start_timestamp" : 1480545636.55059,
"session_range_end" : 1480570804.26226,
"updated" : 1480570805.25201,
"__v" : 0
}
The 'properties' append is not necessary but would be nice.

Try This algo for flatten:-
def flattenPattern(pattern):
newPattern = {}
if type(pattern) is list:
pattern = pattern[0]
if type(pattern) is not str:
for key, value in pattern.items():
if type(value) in (list, dict):
returnedData = flattenPattern(value)
for i,j in returnedData.items():
if key == "data":
newPattern[i] = j
else:
newPattern[key + "." + i] = j
else:
newPattern[key] = value
return newPattern
print(flattenPattern(dictFromJson))
OutPut:-
{
'session_range_start':1480545636.55059,
'start_timestamp':1480545636.55059,
'properties.average_respiration_rate':16.25667,
'session_range_end':1480570804.26226,
'properties.resting_heart_rate':67.67578,
'properties.short_term_resting_heart_rate':61.36963,
'updated':1480570805.25201,
'properties.total_sleep_score':64,
'properties.activity_index':50.51958,
'__v':0,
'user':'xxx',
'provider':'beddit',
'date':'2016-12-01',
'properties.sleep_efficiency':0.8772404,
'end_timestamp':1480570804.26226
}

Although not explicitly what I asked for, the following worked for me so far:
Step 1
Normalize the data record using json_normalize on the original dataset (not inside a Pandas DataFrame) and prefix the data.
beddit_data = pd.io.json.json_normalize(beddit, record_path='data', record_prefix='data.', meta='_id')
Step 2
The properties record was a Series with dicts so these can be 'formatted' with .apply(pd.Series)
beddit_data_properties = beddit_data['data.properties'].apply(pd.Series)
Step 3
Final step is to merge both DataFrames. In step 1, I kept the 'meta=_id' so that DataFrame can be merged with the original DataFrame from Bedit. I didn't include it in the final step yet because I can spend some time on the results from the results so far.
beddit_final = pd.concat([beddit_data_properties[:], beddit_data[:]], axis=1)
If anyone is interested, I can share the final Jupyter Notebook when it is ready :)

Apply $geoNear to find nearest latlong using aggregation in pymongo?

My documents in a collection looks like this -
{'_id' : 'Delhi1', 'loc' : [28.34242,77.656565] }
{'_id' : 'Delhi2', 'loc' : [27.34242,78.626523] }
{'_id' : 'Delhi3', 'loc' : [25.34242,77.612345] }
{'_id' : 'Delhi4', 'loc' : [28.34242,77.676565] }
I want to apply aggregation using pymongo, to find out relevant document based on input latlong. I have created the index on 'loc'. Here is what I have done so far -
pipeline = [{'$geoNear':{'near': [27.8787, 78.2342],
'distanceField': "distance",
'maxDistance' : 2000 }}]
db['mycollection'].aggregate(pipeline)
But this is not working for me ? How to correctly use this ?

Actually, I created the '2dsphere' index in collection, and to use geoNear with 2dsphere we need to specify, spherical = True in the pipeline
pipeline = [{'$geoNear':{'near': [27.8787, 78.2342],
'distanceField': "distance",
'maxDistance' : 2000,
'spherical' : True }}]

It looks like you have a few formatting mistakes: 1) neither the collection nor operators need parentheses or brackets, 2) logical operators are lowercase.
db.mycollection.aggregate([
{
$geoNear: {
near: { coordinates: [ 27.8787 , 78.2342 ] },
distanceField: "distance",
maxDistance: 2000,
spherical: true
}
}
])