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print a triangle figure [duplicate]

I want to make a function to print triangle like the following picture. User can insert the row number of the triangle. The total lenght of first row is must an odd.
I try to use below code :
def triangle(n):
k = 2*n - 2
for i in range(0, n):
for j in range(0, k):
print(end=" ")
k = k - 1
for j in range(0, i+1):
print("* ", end="")
print("\r")
n = 5
triangle(n)
Here is the expected output image :
and here is my actual output image :
but I can't remove the star middle star. And it's not Upside - Down Triangle

You could try a different way.
def triangle(n) :
for i in range(1,n+1) :
for j in range(1,i) :
print (" ",end="")
for j in range(1,(n * 2 - (2 * i - 1))
+1) :
if (i == 1 or j == 1 or
j == (n * 2 - (2 * i - 1))) :
print ("*", end="")
else :
print(" ", end="")
print ("")
n = 5
triangle(n)

Not sure how cool implementation is this but it gives results:
def triangle(n):
print(' '.join(['*']*(n+2)))
s = int((n/2)+1)
for i in range(s):
star_list = [' ']*(n+2)
star_list[-i-2] = ' *'
star_list[i+1] = '*'
print(''.join(star_list))
n = 5
triangle(n)
Output:
* * * * * * *
* *
* *
*
for n = 7:
* * * * * * * * *
* *
* *
* *
*

I would try a recursive solution where you call the printTriangle() function. This way, it will print the point first and move it's way down the call stack.

how to reverse the for loop in python and print the elements from left to right

This is my code which i wrote in python
n = 5
row = 2 * n - 2
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
for k in range(i+1):
print('*',end=" ")
print()
The output what is get is this
* * * * *
* * * *
* * *
* *
*
i want to print this start from left to right order for example
The expected output is :-
* * * * *
* * * *
* * *
* *
*
if it's any possible way to print the elements from left to right because in most of my program i need that logic i'm searching for it please help me and even i used reversed function for loop it will reverse the loop but i'm not getting what i expect

n = 5
print(*[' '.join(' '*i + '*'*(n-i)) for i in range(n)], sep='\n')
Output:
* * * * *
* * * *
* * *
* *
*
Explanation:
for i in range(n):
chars = ' '*i + '*'*(n-i) # creating list of (i) spaces followed
# by (n-i) stars to finish a line of n elements
print(' '.join(chars)) # join prepared values with spaces

Here is a simple solution not using list comprehension:
n = 5
for i in range(n+1):
for j in range(i):
print(" ", end="")
for j in range(i+1, n+1):
print("* ", end="")
print()
Output:
* * * * *
* * * *
* * *
* *
*

My solution - I'm new to python as well:
n = 5
c = 0
for i in range(n, 0, -1):
print(" " * c + "*" * i)
c += 1
or
n = 5
c = 0
while n >= 0:
print(" " * c + "*" * n)
n -= 1
c += 1

The problem is that print itself cannot print right-justified text. But you can print a right-justified string instead of using multiple calls to print.
Here's your original code, using join instead of an inner loop:
n = 5
row = 2 * n - 2
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
row_str = " ".join(["*"] * i)
print(row_str)
And here's the modified code to make the output right-justified:
n = 5
row = 2 * n - 2
whole = row + 1
for i in range(n,-1,-1):
for j in range(row):
print(end="")
row -=2
row_str = " ".join(["*"] * i).rjust(whole)
print(row_str)

Printing christmas tree in python

How can I make a perfect Christmas tree in python? i have here my code but its not working well, it needs to print '~~' in the first for loop.
height = 7
for a in range(1, (height + height) - 3):
if a % 2 != 0:
if a == 1:
print(a * 'o')
else:
print(a * '* ')
for a in range(height + 1):
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
Output of my code is:
o
* * *
* * * * *
* * * * * * *
* * * * * * * * *
~~~~~~~~|~~~~~~~~
~~~~~~~~|~~~~~~~~
my desired output is:
~~~~~~~~o~~~~~~~~
~~~~~~* * *~~~~~~
~~~~* * * * *~~~~
~~* * * * * * *~~
* * * * * * * * *
~~~~~~~~|~~~~~~~~
~~~~~~~~|~~~~~~~~

def values():
yield 'o'
for i in range(3, 10, 2):
yield ' '.join('*' * i)
yield from '||'
for v in values():
print('{:~^17}'.format(v))
Prints:
~~~~~~~~o~~~~~~~~
~~~~~~* * *~~~~~~
~~~~* * * * *~~~~
~~* * * * * * *~~
* * * * * * * * *
~~~~~~~~|~~~~~~~~
~~~~~~~~|~~~~~~~~
Or:
for v in ['o'] + [' '.join('*' * i) for i in range(3, 10, 2)] + ['|', '|']:
print('{:~^17}'.format(v))

Here is an example using the string method center.
for x in range(1, 30, 2):
s = '*' * x
print(s.center(30))
*
***
*****
*******
*********
***********
*************
***************
*****************
*******************
*********************
***********************
*************************
***************************
*****************************
>>>
EDIT: Including the tildes.
limit = 30
for x in range(1, limit, 2):
tildes = '~' * ((limit-x)//2)
out = tildes + '*' * x + tildes
print(out)
~~~~~~~~~~~~~~*~~~~~~~~~~~~~~
~~~~~~~~~~~~~***~~~~~~~~~~~~~
~~~~~~~~~~~~*****~~~~~~~~~~~~
~~~~~~~~~~~*******~~~~~~~~~~~
~~~~~~~~~~*********~~~~~~~~~~
~~~~~~~~~***********~~~~~~~~~
~~~~~~~~*************~~~~~~~~
~~~~~~~***************~~~~~~~
~~~~~~*****************~~~~~~
~~~~~*******************~~~~~
~~~~*********************~~~~
~~~***********************~~~
~~*************************~~
~***************************~
*****************************

I have modified your code a little bit, well here's the code:
height = 7
z = height - 3
x = 1
for i in range(1, (height + height) - 3):
if i % 2 != 0:
if(i==1):
print('~~' * z + 'o' +'~~' * z)
else:
print('~~' * z + '* ' * (x-1)+ '*' *1 +'~~' * z)
x+=2
z-=1
for a in range(height + 1):
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
Output:
~~~~~~~~o~~~~~~~~
~~~~~~* * *~~~~~~
~~~~* * * * *~~~~
~~* * * * * * *~~
* * * * * * * * *
~~~~~~~~|~~~~~~~~
~~~~~~~~|~~~~~~~~

I edited your code just a little:
height = 7
width = 17
for a in range(1, (height + height) - 3):
if a % 2 != 0:
if a == 1:
sym = 'o'
curly = ''.join(['~' for i in range((width-len(sym))//2)])
print(curly + a * sym + curly)
else:
sym = a * '* '
curly = ''.join(['~' for i in range((width - len(sym)) // 2)])
print(curly + sym + curly)
for a in range(height + 1):
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
if a % (height + 1) == 1:
test = height - 3
print(test * '~~' + a * '|' + test * '~~')
~~~~~~~~o~~~~~~~~
~~~~~* * * ~~~~~
~~~* * * * * ~~~
~* * * * * * * ~
* * * * * * * * *
~~~~~~~~|~~~~~~~~
~~~~~~~~|~~~~~~~~
It's not perfect but no Christmas tree is 100% straight.

It is a simple programming problem. So let's create a simple program for solving it.
First, we need to draw our tree. in each line, our tree has an odd number of starts for showing tree and some ~ characters for representing the background. If we want to have a tree which its height is equal to the height variable. at the heightth line, we don't want to have any ~ character. But in the first line, we want to have only one * character.
So it seems to be a good idea to having a for loop that counts from height to the zero and relates the number of ~ characters somehow to it.
Let's see the code first:
for i in range(height, 0, -1):
print("~" * (i - 1)) // repeating `~` character (i - 1) times
If you run this code, you will get the following output:
~~~~~~
~~~~~
~~~~
~~~
~~
~
Now let's add the * characters for drawing the tree. We should have the exact opposite relation for * characters from ~.
for i in range(height, 0, -1):
print("~" * (i - 1), end="")
print("*" * (((height - i) *2) + 1))
We add end="" at the end of the previous print function. Because print will add a newline character at the end in each call and we want to prevent it (because we want to add * characters after ~ characters).
Then we want to add * characters at each line. But we want to count their number
for 1 to height * 2. But we only need the odd numbers. That's what we did in the second line. Now, we have the following number of * characters at each line: 1, 3, 5, 7,...
Below is the output of that code (We considered that height = 7):
~~~~~~*
~~~~~***
~~~~*****
~~~*******
~~*********
~***********
*************
As you can see, now we have our Christmas tree. But our background is incomplete.
The only thing we should do is to repeat our first print statement. But this time we should not add end="" because we want that newline at the end of each line.
for i in range(height, 0, -1):
print("~" * (i - 1), end="")
print("*" * (((height - i) *2) + 1), end="")
print("~" * (i - 1))
Now our tree is complete:
~~~~~~*~~~~~~
~~~~~***~~~~~
~~~~*****~~~~
~~~*******~~~
~~*********~~
~***********~
*************
You can add other things to your tree by following this simple approach. I hope this helps you.

Try using more conditionals to handle the number of stars (*). Drop a comment below if that doesn't work.
Like, you could do:
if '1star' do this..:
elif '2stars' do this..:

I would code it like this:
sky=8
tree=1
for i in range(0,5):
if i==0:
print(sky*'~'+tree*'o'+sky*'~')
else:
print(sky*'~'+tree*'*'+sky*'~')
sky-=1
tree+=2
sky=8
tree=1
for i in range(0,2):
print(sky*'~'+tree*'|'+sky*'~')
I modified the Christmas tree so that it looked thinner.

This is my code:
var = 14
for i in range(1, var + 1):
print(" " * (var - i) + "*" * i + "*" * (i - 1))
Sample output:
*
***
*****
*******
*********
***********
*************
***************
*****************
*******************

How to create a triangle made of asterisk characters? [duplicate]

This question already has answers here:
How to recreate pyramid triangle?
(3 answers)
Closed 5 years ago.
I am trying to print a triangle made of asterisk (*) separated by spaces.
If n = 4, it should look like:
*
* *
* * *
* * * *
This is the code I have:
n = 4
for i in range(1, n + 1):
for j in range(i):
print("*")
This is the result I get:
*
*
*
*
*
*
*
*
*
*
I would very appreciate what is wrong with my code...

print() adds a newline to your string each time.
It is easier to multiply the * with the number of times you would like to see it:
n = 4
for i in range(1, n + 1):
print("* " * i)
Output:
*
* *
* * *
* * * *

You could use the built-in "end" parameter:
n = 4
for i in range(1, n + 1):
for j in range(i):
print("*", end=" ")
print()

n = 4
for i in range(1, n + 1):
lvl = ""
for j in range(i):
lvl += "* "
print(lvl)
You need to aggregate the level of the triangle to print.
edit :
if you don't want spaces at the end of the line :-/
n = 4
for i in range(1, n+1):
print( " ".join([c for c in '*' * i]))

Hollow Diamond in python

My goal is to create a hollow diamond using python.
Sample input:
Input an odd Integer:
9
Sample output:
*
* *
* *
* *
* *
* *
* *
* *
*
But so far, I have the following code that is not working right. Please help me to modify the code to achieve the goal above:
a=int(input("Input an odd integer: "))
k=1
c=1
r=a
while k<=r:
while c<=r:
print "*"
c+=1
r-=1
c=1
while c<=2*k-1:
print "*"
c+=1
print "\n"
k+=1
r=1
k=1
c=1
while k<=a-1:
while c<=r:
print " "
c+=1
r+=1
c=1
while c<= 2*(a-k)-1:
print ("*")
c+=1
print "\n"
k+=1
The code above return a result that is very far from my goal.
Input an odd integer: 7
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
*
I am actually converting the code from this post: http://www.programmingsimplified.com/c/source-code/c-program-print-diamond-pattern written in C language and will modify later for the hollow one but I can't get it... There is something wrong with my conversion..

A Hollow diamond is the solution to the equation
|x|+|y| = N
on an integer grid. So Hollow diamond as a 1-liner:
In [22]: N = 9//2; print('\n'.join([''.join([('*' if abs(x)+abs(y) == N else ' ') for x in range(-N, N+1)]) for y in range(-N, N+1)]))
*
* *
* *
* *
* *
* *
* *
* *
*

Your problem is that you keep using print. The print statement (and the function in Python 3) will add a line-break after what you printed, unless you explicitely tell it not to. You can do that in Python 2 like this:
print '*', # note the trailing comma
Or in Python 3 (with the print function) like this:
print('*', end='')
My solution
I took my own take at the problem and came up with this solution:
# The diamond size
l = 9
# Initialize first row; this will create a list with a
# single element, the first row containing a single star
rows = ['*']
# Add half of the rows; we loop over the odd numbers from
# 1 to l, and then append a star followed by `i` spaces and
# again a star. Note that range will not include `l` itself.
for i in range(1, l, 2):
rows.append('*' + ' ' * i + '*')
# Mirror the rows and append; we get all but the last row
# (the middle row) from the list, and inverse it (using
# `[::-1]`) and add that to the original list. Now we have
# all the rows we need. Print it to see what's inside.
rows += rows[:-1][::-1]
# center-align each row, and join them
# We first define a function that does nothing else than
# centering whatever it gets to `l` characters. This will
# add the spaces we need around the stars
align = lambda x: ('{:^%s}' % l).format(x)
# And then we apply that function to all rows using `map`
# and then join the rows by a line break.
diamond = '\n'.join(map(align, rows))
# and print
print(diamond)

def diamond(n, c='*'):
for i in range(n):
spc = i * 2 - 1
if spc >= n - 1:
spc = n - spc % n - 4
if spc < 1:
print(c.center(n))
else:
print((c + spc * ' ' + c).center(n))
if __name__ == '__main__':
diamond(int(input("Input an odd integer: ")))

this is not pretty, but its a function that does what you want:
def make_diamond(size):
if not size%2:
raise ValueError('odd number required')
r = [' ' * space + '*' + ' ' * (size-2-(space*2)) + '*' + ' ' * space for space in xrange((size-1)/2)]
r.append(' ' * ((size-1)/2) + '*' + ' ' * ((size-1)/2))
return '\n'.join(r[-1:0:-1] + r)
first i check to make sure its an odd number,
then i create a list of the lines from the center downwards.
then i create the last point.
then i return them as as a string, with a mirror of the bottom on top without the center line.
output:
>>> print make_diamond(5)
*
* *
* *
* *
*
>>> print make_diamond(9)
*
* *
* *
* *
* *
* *
* *
* *
*

Made it in one single loop ;)
x = input("enter no of odd lines : ") #e.g. x=5
i = int(math.fabs(x/2)) # i=2 (loop for spaces before first star)
j = int(x-2) #j=3 # y & j carry loops for spaces in between
y = int(x-3) #y=2
print ( " " * i + "*" )
i = i-1 #i=1
while math.fabs(i) <= math.fabs((x/2)-1): # i <= 1
b = int(j- math.fabs(y)) # b = (1, 3, 1) no of spaces in between stars
a = int(math.fabs(i)) # a = (1, 0, 1) no of spaces before first star
print (" "* a + "*" + " "*b + "*")
y = y-2 # 2,0,-2
i = i-1 # 1,0,-1, -2 (loop wont run for -2)
i = int(math.fabs(i)) # i = -2
print ( " " * i + "*")

The previous answer has got two corrections, which've been done here :
import math
x = int(input("enter no of odd lines : ")) #e.g. x=5
i = int(math.fabs(x/2)) # i=2 (loop for spaces before first star)
j = int(x-2) #j=3 # y & j carry loops for spaces in between
y = int(x-3) #y=2
print ( " " * i + "*" )
i = i-1 #i=1
while math.fabs(i) <= math.fabs((x/2)-1): # i <= 1
b = int(j- math.fabs(y)) # b = (1, 3, 1) no of spaces in between stars
a = int(math.fabs(i)) # a = (1, 0, 1) no of spaces before first star
print (" "* a + "*" + " "*b + "*")
y = y-2 # 2,0,-2
i = i-1 # 1,0,-1, -2 (loop wont run for -2)
i = int(math.fabs(i)) # i = -2
print ( " " * i + "*")
Note : Now this works for both python 2.5x and python 3.x
If you wish to know the difference in the two answers, then google it!

sizeChoice = 13
N = sizeChoice//2
for column in range (-N, N + 1):
for row in range (-N, N + 1):
if abs(column) + abs(row) == N:
print ("*", end = " ")
else:
print(" ", end = " ")
print ( )

this code works perfectly to print a hollow diamond where you can set diagonal length upto user requirement
n=int(input('Enter Odd Diagonal length :'))-1
j=n-1
print(' '*(n)+'*')
for i in range(1, 2*n):
if i>n:
print(' '*(i-n)+'*'+' '*(2*j-1)+'*')
j-=1
else:
print(' '*(n-i)+'*'+' '*(2*i-1)+'*')
if n>1:
print(' '*n+'*')

Hallow Diamond in Python using only print function
for i in range(1,6):
print(' '*(5-i) + '*'*1 + ' '*(i-1) + ' '*max((i-2),0) + '*'*(1%i) )
for j in range(4,0,-1):
print(' '*(5-j) + '*'*1 + ' '*(j-1) + ' '*max((j-2),0) + '*'*(1%j) )