I have an app called 'vocab', which so far contains a CreateView and a ListView. In my project urls.py file, I have the following:
urlpatterns = [
path('admin/', admin.site.urls),
path('',views.HomePage.as_view(),name='home'),
re_path(r"^accounts/", include("accounts.urls", namespace="accounts")),
re_path(r"^accounts/", include("django.contrib.auth.urls")),
re_path(r"^logout/$", views.LogOutPage.as_view(), name="logout"),
re_path(r"^vocab/", include("vocab.urls", namespace="vocab")),
]
And then, in my app urls.py file, I have the following:
urlpatterns = [
path('list/', views.WordList.as_view(), name="list"),
path("home/",views.VocabHome.as_view(),name='home'),
path("create/", views.CreateWord.as_view(), name="create"),
]
And in my html templates I have links to these views. The home and list views work, but when I click on the 'create' link, it takes me to 'list' instead. In the command line I can see that it is accessing /vocab/list/? instead of /vocab/create/. I know the create view works, because if I type it in manually it goes there. And if I delete all the other views it works as well. So it is as if django cannot find the 'create' view when there are others. I've tried my best to solve this problem by making sure all the paths are unique, and I've tried using regular expressions, but it still doesn't work. Any help would greatly be appreciated!
I found the mistake...
I had a missing form closing tag in my html. This resulted in my second form (and therefore link) being invalid.
Related
I'm following a django tutorial that is a little outdated and in the urls.py file of the first app's directory we need to configure where to direct django to for any url starting with 'notes/'.
There are two separate 'apps' inside the project. I'm in the first one, not notes.
This is the code currently. I added include to import statement:
from django.contrib import admin
from django.urls import path, include
urlpatterns = [
path('admin/', admin.site.urls),
path(url(r’^notes/‘, include('notes.urls'))),
]
Inside the urlpatterns object, on the first line, path('admin/', admin.site.urls), comes predefined, but I need to add a redirect such that django goes to a different app, called 'notes' and searches there for its entry point, since all of the urls will begin with ‘notes/’.
The tutorial says to use a regular expression and uses this code:
url(r’^notes/‘, include(notes.urls))
so that any url that starts with 'notes/' should be redirected to this other file notes.urls.
However the predefined ones that currently come out of the box with a django project start with path.
I enclosed my notes/n redirect line in path, but not sure if this is correct. Should I instead directly write:
url(r’^notes/‘, include(notes.urls))
Also, do I need to delete the first line provided?
path('admin/', admin.site.urls),
The tutorial has:
urlpatterns = patterns('',
url(r’^notes/‘, include(notes.urls)),
)
and no admin urls line. It's from 2014 I believe.
Simply do:
path('notes/', include('notes.urls'))
I'm trying o add to my Django project a registration view from the django-allauth package.
I added the view to my urls.py file but i keep getting the following error:
Reverse for 'account_login' not found. 'account_login' is not a valid view function or pattern name.
Here is how i added the view to my urls:
from allauth.account.views import SignupView
urlpatterns = [
path("signup/", SignupView.as_view(), name="account_signup"),
]
I don't really understand what am i missing when importing the view, can anyone help me?
It looks like you need to include the following pattern in urls.py
url(r'^accounts/', include('allauth.urls')),
So I create an url in root/project/urls.py with this lines
from django.conf.urls import include
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
path('users/', include('app.urls'))
]
while in my root/app/urls.py
from django.urls import path
from .views import UserView, AuthenticationView
urlpatterns = [
path('register/', UserView.as_view()),
path('auth/', AuthenticationView.as_view()),
]
So it is expected to give me http://localhost:8000/users/register and http://localhost:8000/users/auth urls.
Meanwhile my request doesn't behave as expected.
apparently it returns me a space between the root path and include path. I check my root/project/settings.py file I don't find any weird settings. Does anybody know what is going on?
The space is just for displaying how the URL is built up, on the debug screen only.
I have experienced the same and at first I too thought Django somehow added the space. In the end it really is that there is no match between the URL's specified and the URL in your browser. Safari doesn't display the full url, so error can happen quickly...
Some additional info on urls in Django can be found here.
The error message in your screenshot states that the request URL is http://localhost:8000/users does not exist.
Here you redirects /users/ to app.urls:
path('users/', include('app.urls'))
But in app.urls, you never included a pattern for when the URL ends with only "/users/". Instead, "/users/register/" and "/users/auth/" are both specified.
urlpatterns = [
path('register/', UserView.as_view()),
path('auth/', AuthenticationView.as_view()),
]
So http://localhost:8000/users/register and http://localhost:8000/users/auth should be valid URLs, but http://localhost:8000/users is not.
You can add another URL pattern for when the URL ends at "/users/":
urlpatterns = [
path('', AuthenticationView.as_view()), # maybe the same as /auth/ ?
path('register/', UserView.as_view()),
path('auth/', AuthenticationView.as_view()),
]
In conclusion, Django's actually not wrong about that page does not exist (404), it's because you hadn't match http://localhost:8000/users in any of the urlpatterns.
Have you tried to use regular expressions?
path(r'^admin/', admin.site.urls)
Otherwise in the Django 2 version the urls schema has been changed, I use url function instead the path function, that can be a possible fix for your problem
I'm using models.FileField like this below.
It's a fantastic django function. Because, it makes user can upload within Django administration page without any code.
So, I clicked Part image url Link. But, I got a error message below.
my urls pattern is below.
urls.py
urlpatterns = [
url(r'^parts/', include('parts.urls', namespace='parts')),
url(r'^admin/', include(admin.site.urls)),
url(r'^$', views.MW_Hello.as_view(), name='Hello'),
]
Do I have to add url mapping in url patterns?
You need to configure your urls and settings for managing the static files
https://docs.djangoproject.com/en/1.8/howto/static-files/
https://docs.djangoproject.com/en/1.8/topics/files/
I'm trying to get any sort of nested inline to work with python 3 and django 1.8.
I tried django super-inlines and that didn't really make them nested, they just kinda showed up next to eachother.
I'm currently trying django-nested-admin and I get a page not found error with this pattern search:
^ ^$ [name='browse']
^admin/ ^server-data.js$ [name='nesting_server_data']
browse links to a separate set of urls and this just will not load any admin links.
urls.py:
from django.conf.urls import include, url
import nested_admin
urlpatterns = [
url(r'^', include('flightdb.urls')),
url(r'^admin/', include('nested_admin.urls')),
]
Connecting to /admin/ gets a 404 not found error.
Any help with why the page isn't loading or any better way to get nested-inlines to work would be greatly appreciated.
The pattern r'^' will match anything that also matches r'^admin/'. Django performs the URL matching by starting from the beginning of urlpatterns and progresses until it finds the first match. So in this case things that were supposed to be in admin are matching '^' which is flightdb.urls where they won't be found. You could potentially fix this issue by reordering the url's as follows:
urlpatterns = [
url(r'^admin/', include('nested_admin.urls')),
url(r'^', include('flightdb.urls')),
]
Now admin is checked for a match before the rest of the top level urls.
EDIT: I suspect your issues are coming from using "admin" in your url pattern to go to somewhere other than the default Django admin package. I did some searching around in the source of django-nested-admin and in particular came across something here:
https://github.com/theatlantic/django-nested-admin/blob/master/nested_admin/options.py in particular have a look at line 275:
context = {
'title': _('Add %s') % force_unicode(opts.verbose_name),
'adminform': adminForm,
'is_popup': (IS_POPUP_VAR in request.POST or
IS_POPUP_VAR in request.GET),
'show_delete': False,
'media': mark_safe(media),
'inline_admin_formsets': inline_admin_formsets,
'errors': helpers.AdminErrorList(form, formsets),
'root_path': reverse('admin:index'),
'app_label': opts.app_label,
}
Here there is a call to reverse('admin:index'). This needs to resolve to the usual admin path in order to work. When you have your url's defined like you do you run into the problem of admin now being something other than the default that django-nested-admin is expecting to see.
Perhaps try a different url pattern that is not "admin" such as the one suggested by their documentation:
url(r'^nested_admin/', include('nested_admin.urls')),
This way the reverse used in the internals of the django-nested-admin package will work.
I had the same problem. This is what my settings.py and urls.py look like
settings.py
INSTALLED_APPS = [
'nested_admin',
'django.contrib.admin',
# ...
]
urls.py
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^nested_admin/', include('nested_admin.urls')),
#...
]
Now, don't go to yourproject.com/nested_admin but yourproject.com/admin .
You still need the include for nested_admin or it won't work.