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How to create a dictionary value for each given key? [closed]

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I have a list l=['a','b','c'] and I want to create a dict that takes these items as keys and then adds a value to it. Such as:
d={ 'a':0, 'b':1, 'c':2 }
How would I be able to this?

There are many ways to create this dictionary. Here is just a few:
>>> dc = dict(zip(ls, range(3)))
>>> dc2 = {v: k for k, v in enumerate(ls)}
>>> dc2
{'a': 0, 'b': 1, 'c': 2}
>>> assert dc == dc2
>>> # silence because they're same

l=['a','b','c']
d = dict(zip(l,range(len(l))))
print(d) # {'a': 0, 'b': 1, 'c': 2}

You could use something like
l = ['a','b','c']
d = {element:index for index,element in enumerate(l)}
which will give you each element mapped to its index.
if you want to set some arbitrary value, use
l = ['a','b','c']
d = {element:value for element in l}

How to get all keys where its values are same and data type of values are always list in python? [closed]

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mydict = {
'name' : ['cat','dog'],
'place' : ['earth','mars'],
'name1' : ['cat','dog'],
'name2' : ['cat','dog'],
'place1' : ['earth','mars'],
'colour' : ['blue','green'],
'colour1' : ['orange']
}
expected_result
[['name','name1','name2'],['place','place1']]
Since 'colour' and 'colour1' are not same we will ignore them.

Probably not the fastest solution, but you can find the duplicate values first, then list the corresponding keys:
>>> values = list(mydict.values())
>>> duplicates = set(tuple(v) for v in values if values.count(v) > 1)
>>> [[k for k, v in mydict.items() if tuple(v) == d] for d in duplicates]
[['name', 'name1', 'name2'], ['place', 'place1']]

from collections import defaultdict
rev = defaultdict(list)
for i in mydict:
rev[tuple(mydict[i])].append(i)
answer = [i for i in rev.values() if len(i)>=2]
#[['name', 'name1', 'name2'], ['place', 'place1']]

Turning Key, Value pairs from a Dictionary into strings [closed]

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I have a dictionary and a string template that I need to fill in with the key, value pairs from the dictionary.
For example, if the dictionary was {'a':'1', 'b':'2'} then I need the string template (key is in value) to read as: "a is in 1" and "b is in 2"
And I need to iterate through the dictionary and apply each key, value pair into the string template.

Here you go. Simply iterate the key, value pairs and format your template.
mydict = {'a':'1', 'b':'2'}
for key, value in mydict.items():
print('{} is in {}'.format(key, value))
Output:
a is in 1
b is in 2
If you would like to get a list of formated strings just do:
mylist = ['{} is in {}'.format(key, value) for key, value in mydict.items()]
mylist will be ['a is in 1', 'b is in 2'].

You can use the following function:
def fill(d, template):
s = ""
for k, v in d.items():
s += f"{k} {template} {v}\n"
return s[:-1]
>>> d = {'a':'1', 'b':'2'}
>>> print(fill(d, 'is in'))
a is in 1
b is in 2
Note that this will only preserve order in python 3.6+.

dictionary = {'a':'1', 'b':'2'}
template = '{} is in {}'
for key, value in dictionary.items():
print(template.format(key, value))
will do the trick

You could be fancy and use itertools.starmap:
from itertools import starmap
d = {'a': '1', 'b': '2'}
list(starmap('{} is in {}'.format, d.items()))
# ['a is in 1', 'b is in 2']

You can also use an f-string for python 3.5+:
d = {'a': '1', 'b': '2'}
print('\n'.join(f'{k} is in {v}' for k, v in d.items()))
a is in 1
b is in 2

Python : Map over multidimensional dictionary using a list [closed]

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I need a function to change values within a nested dictionary,
by crawling a list instead of the usual dic[key1][key2] = value
e.g :
IN[0]: dic = {'1': 23, '3': {'a': 'foo', 'b': 67}}
IN[1]: l = ['3', 'a']
IN[2]: func(dic, l , newvalue)
IN[3]: print dic
Expected output :
OUT[4]: dic = {'1': 23, '3': {'a': newvalue, 'b': 67}}

Try this:
def func(dic, keys, value):
for key in keys[:-1]:
dic = dic.setdefault(key, {})
dic[keys[-1]] = value
func(dic, l , newvalue)
print(dic)
This is not good to use unnecessary things like exec and globals().

Working with python dictionary [closed]

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How can I store multiple keys and values in school dictionary?
I was trying to store a list of keys and values in a dictionary with a for loop but I did t know how to go about it.
Can any one help me out?

keys = ['a', 'b']
values = [1, 2]
print(dict(zip(keys,values)))
Output:
{'a':1,'b':2}

You can do following:
keys = ['bob', 'alice']
values = [40, 20]
d = {}
for i in range(len(keys)):
d[keys[i]] = values[i]
Learn the basics of python dictionary and looping. You will find tons of resources in the internet.

For example:
lst1 = ['a', 'b', 'c']
lst2 = [1, 2, 3]
# First way
d1 = {k: v for k, v in zip(lst1, lst2)}
print d1
# {'a': 1, 'c': 3, 'b': 2}
# Second way
d2 = dict(zip(lst1, lst2))
print d2
# {'a': 1, 'c': 3, 'b': 2}