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Accessing data from class selenium

Currently trying to get the data which is stored in this class using selenium and print it into console.
<h3 class="tiktok-dvof16-AuthorTitle e10yw27c0">allawi_9</h3>
I tried print(driver.find_elements_by_class_name("tiktok-dvof16-AuthorTitle e10yw27c0"))
I also tried adding .text at the end, however you cant do that on a list obj. (And the returned list is empty may I add.
However, it just returns an empty list. I'm unsure what I'm doing wrong. Any help would be great!

if the element value is unique on the page you can use
myelemnt = driver.find_element_by_name('Some text')
myelement.print()
if not you can use X-path for this like
myelement = driver.find_element_by_xpath('/html/body/div[1]/section/main/div/div[3]/article/div[1]/div/div[1]/div[1]/a/div/div[2]')
myelement.print()
if that doesnt worked use Full x-path
myelement = driver.find_element_by_xpath('//*[#id="react-root"]/section/main/div/div[2]/article/div[1]/div/div[1]/div[1]/a/div/div[2]')
myelement.print()
for getting the x-path/full x-path simple just right-click on the element on the google chrome developer tools and click on Copy then x-path / full x-path

Click on li element searching specific displayed text

Using python 3 and chrome driver. I'm trying to click on my desired element searching for the text displayed on this page . For example, in case of "BEBES" I'm using:
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.XPATH,'//*[contains(text(), "BEBES")]'))).click()
but nothing happens. Just throws the time out exception. What's my error?

Your xPath is not correct. Use this:
WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.XPATH,'//span[contains(text(), "Bebes")]'))).click()
Note: upper/lowercase makes difference
and

This post suggests using the following as text() returns a node set:
//*[text()[contains(.,'BEBES')]]
XPath contains(text(),'some string') doesn't work when used with node with more than one Text subnode

Selenium click on XPath button

I have the following code when I inspect on Chrome.
<span id="button-1111-btnInnerEl" class="x-btn-inner x-btn-inner-center" unselectable="on" style="">New Email</span>
I need to click on the label "New Email", but how should invoke it in Selenium (I'm using Python).
def CreateMail():
EmailButton="//*[contains(text(),'New Email')]"
driver.find_elements_by_xpath(EmailButton) // there is no method to enable click.

You can use execute_script
driver.execute_script("document.getElementById('button-1111-btnInnerEl').click()")

driver.find_element_by_id("button-1111-btnInnerEl").click()

Thanks all for your help. Finally i found the answer to my question.I had to add a wait statement, before finding the key. key wasn't present when the page loads, so had to wait a little bit to find the correct key.
def CreateMail():
try:
element = WebDriverWait(driver,10).until(EC.presence_of_element_located((By.ID, "button-1143-btnInnerEl")))
driver.find_element_by_id("button-1143-btnInnerEl").click()
except TimeoutException:
print ("Loading took too much time!")

Hope This XPath will work for you.If you want to validate xpath using your chrome browser just paste this text on your chrome console $x("//*[text()='New Email']") and check how many elements found using this XPath
driver.find_elements_by_xpath("//span[text()='New Email']")

Your statement : "driver.find_elements_by_xpath(EmailButton)" . Click does not work on group of elements. It is actionable only on single element. So you use a singular finder.
driver.find_**element**_by_id(EmailButton).click()

As per the HTML you have shared, the id attribute looks dynamic to me. So we must construct a dynamic xpath or css. Additionally instead of find_elements we have to use find_element so a single WebElement is returned and we can invoke the click() method. Finally, if you look at the node properly, the unselectable attribute is on so we will take help of JavascriptExecutor as follows :
myElement = driver.find_element_by_xpath("//span[starts-with(#id, 'button-')][#class='x-btn-inner x-btn-inner-center']")
driver.execute_script("arguments[0].click();", myElement);

Actually there is different way for locating elements
but in your case there is a ID,
so you can prefer id if its exists
find solution below :
driver.find_element_by_id("button-1111-btnInnerEl").click()

Locating web element using selenium in python

I am trying to find an element in the web page using selenium. when I "right click" on the web element and inspect, I can find the html code in the console. However when I copy the xpath of the same element from the console and try to execute it in firepath, it says "No matching nodes". Why is it so and how can I fix this ?
Here is the HTML of the element.
<input id="mobile" type="text" onchange="javascript:dispLocMob(this);
"onkeydown="javascript:dispLocMob(this);
"onkeyup="javascript:dispLocMob(this);" value="" maxlength=
"10" placeholder="Mobile Number" name="mobile">
And this is what I am doing:
receiverMobileElement = browser.find_element_by_xpath('//*[#id="mobile"]')
Please help.

Why using xpath when you can find the element by unique id?
from selenium import webdriver
browser = webdriver.Firefox()
browser.get('http://example.com')
target_element = browser.find_element_by_id('mobile')

I always say screw firebug, use the Chrome console..
From the looks of it, the best way to get this particular element would be one of the following two options (given that 'id=mobile' is unique)..
By.cssSelector("#mobile");
By.xpath("//input[#id = 'mobile']");
To use the chrome console -->
Start Chrome
Right click and inspect your element.
You should see the html code and the console appear below it. (If you can not see the console, click the three vertical dots and select 'Show Console'
Now, from here you can do some awesome stuff! You can search for the elements that you are trying to identify and see if they can be found. for example, to see if the By.cssSelector("#mobile"); will work type this
document.querySelectorAll("#mobile")
for the xpath, type this
$xBy.xpath("//input[#id = 'mobile']");
Just a suggestion... dont be concerned about firebug if your code works, and seriously try out this way in chrome!!

Using python selenium to click an element not visible

I am using python selenium on browser to fill in some form. I was trying to select an element in the drop-down list,
0
but if I try to find it by text using this script:
browser.find_element_by_link_text("0").click()
it result an error:
"unknown error: Element is not clickable at point (498, 612). Other element would receive the click: ..."
and if try to find it by class name:
browser.find_element_by_class_name("dropdown-toggle").click()
it result in another error: "element not visible"
is there any way I can click onto that drop-down list? Thanks very much.

I had a similar problem. You can execute a script to change the visibility of that element once you find it and then click it.
driver.execute_script("arguments[0].style.visibility = 'visible';",myElement)
myElement.click()

Try to find it by Xpath searching for partial class and text at the same time:
browser.find_element_by_xpath(//a[contains(#class, 'dropdown-toggle select') and contains(text(), '0')]).click();

you should get the element by xpath and then press it.
browser.find_element_by_xpath(xpath).
read here how to get the xpath: http://www.wikihow.com/Find-XPath-Using-Firebug

Thanks for the feedback, I've found the problem which was due to the new script being loaded by javascript as triggered by some clicks. I've created the following code to capture the exception and retrying until the element is ready:
while True:
try:
time.sleep(1)
browser.find_element_by_xpath("//div[#class='tckt']/a").click()
print("found")
break
except ElementNotVisibleException:
print("notvisible")
except WebDriverException:
print("clickduplicate")
I read it on articles says this happened a lot on radio button for Chrome webdriver, hope this helps.

Firstly click the parent element by finding it, using it's xpath->find the element you want to click within the parent element like the way you did. i.e
browser.find_element_by_link_text("0").click()
Hope this 2 steps will work for you. Otherwise please post the url with the code you've tried-It'll be easy to find out the issue.