I am quite new in python and made a Tkinter application that will execute all python files existing in the directory when pressed the start button. My GUI also has progressbar to see the current progress.
so here is my code
import os
from tkinter import *
from tkinter.ttk import *
from tkinter import messagebox
directory = dir_path = os.path.dirname(os.path.realpath(__file__))
files = os.listdir(directory)
root = Tk()
root.geometry('200x200')
root.maxsize(200,200)
root.minsize(200,200)
root.title('PYTOEXE')
v = 0
def begin():
global v
for x in files:
os.system('pyinstaller '+x)
v=v+1
p['value']=v
p = Progressbar(root,length=200,max=len(files))
b = Button(root,text="Start",command=lambda: begin())
p.place(x=0,y=0)
b.place(x=62,y=30)
root.mainloop()
but my problem is, Whenever i press start button, The GUI freezes and codes start getting compiled and when completed, the GUI unfreezes and the Progressbar fills itself full at once...
So i want the GUI not to freeze while processing and show correct progress on the Progressbar.
Example code and Explanation will be better for me.
Thanks for your valuable time...
This worked.No need to use .after() to check the thread is finished.
import os
from tkinter import *
from tkinter.ttk import *
import threading
def use_pyinstaller(): # this function is to execute pyinstaller command and add value to progressbar.
v = 0
for x in files:
os.system('pyinstaller '+x)
v+=1
p['value'] = v
def begin():
threading.Thread(target=use_pyinstaller).start() # create a non-block thread to start the function.
directory = dir_path = os.path.dirname(os.path.realpath(__file__))
files = os.listdir(directory)
root = Tk()
root.geometry('200x200')
root.maxsize(200,200)
root.minsize(200,200)
root.title('PYTOEXE')
p = Progressbar(root,length=200,max=len(files))
b = Button(root,text="Start",command=begin)
p.place(x=0,y=0)
b.place(x=62,y=30)
root.mainloop()
First off, the command argument for the button can just be: command=begin.
GUI toolkits like tkinter are event-driven. They depend on a smooth flow of keyboard and mouse events to work properly.
Callbacks (like the command from a button) are called from witin the event loop (root.mainloop).
So a callback should only take a short time (say 50 ms) as to not freeze the GUI. You should therefore never run a long-running loop in a callback. You have to program in a different style.
The above link takes you to an article on my website where I compare a simple command-line program with an equivalent GUI program. While that program doesn't use external processes, it illustrates the principle.
The proper way to do this in a GUI, is to start a multiprocessing.Process from the button callback.
Then use the root.after method to periodically run a callback that checks if the Process is finished, and then start a new process.
Related
I'm making a simple GUI using Python 3.7.3 and tkinter to open and close windows applications. I'm not able to find a way to close a running program using an onscreen button. I need the 'close' button to do something else as well, hence the simply using 'x' button (which is next to the minimize and maximize) won't work for my case.
from tkinter import *
import os, subprocess
root = Tk()
root.geometry("300x300")
def OpenCalc():
app1 = os.startfile("C:\Windows\System32\calc.exe")
def CloseCalc():
os.close(app1)
# or
# os.closefile("C:\Windows\System32\calc.exe")
b1=Button(root, text="Open Calc", command=OpenCalc).pack()
b2=Button(root, text="Close Calc", command=CloseCalc).pack()
root.mainloop()
I am wondering on how I can create a restart button that once clicked, can restart the entire script. What I thought was that you destroy the window then un-destroy it but apparently there is no un-destroy function.
I found a way of doing it for a generic python program on this website: https://www.daniweb.com/programming/software-development/code/260268/restart-your-python-program. I wrote an example with a basic tkinter GUI to test it:
import sys
import os
from tkinter import Tk, Label, Button
def restart_program():
"""Restarts the current program.
Note: this function does not return. Any cleanup action (like
saving data) must be done before calling this function."""
python = sys.executable
os.execl(python, python, * sys.argv)
root = Tk()
Label(root, text="Hello World!").pack()
Button(root, text="Restart", command=restart_program).pack()
root.mainloop()
The following solution works as well but is quite harsh, i.e. the entire environment is lost.
# kills the whole application and starts a fresh one
def restart():
root.destroy()
root = Tk()
root.mainloop()
I would Like to Use this Function:-
First of All Import os Module
import os
Then Use this Code:-
# Restarts the Whole Window
def restart():
root.destroy()
os.startfile("main.py")
Or if You want no console behind then Simply Change the extension of the file to .pyw
And Run this Code:-
# Restarts the Whole Window
def restart():
root.destroy()
os.startfile("main.pyw")
When running a tkinter program in the standard python idle program the window displays and you are able to interact with it, yet running the same program in pycharm causes the program window to flash up briefly then close.
I'm assuming its to do with the mainloop, what do you need to modify in your code to prevent the program from automatically closing when running in pycharm
An excert from my code follows
from tkinter import *
import tkinter
from tkinter import Text, Tk, ttk
import csv
from csv import DictReader
import sys
import os
class GUI:
def __init__(self, root):
....
def main():
global label
root = Tk()
root.title(" My program")
root.geometry("550x330+600+300")
mycolor = '#%02x%02x%02x' % (39, 39, 39) # background color
root.configure(bg=mycolor)
gui = GUI(root)
main()
Update : After a bit of mucking around, partly due to my code not being the best (rookie), I've managed to get it to work. For anyone interested heres the modification:
from tkinter import *
import csv
from csv import DictReader
import sys
import os
class GUI:
def __init__(self, master):
self.master = master
master.title(" My Programs")
master.geometry("550x330+600+300")
master.iconbitmap('logo.ico')
mycolor = '#%02x%02x%02x' % (39, 39, 39) # background color
master.configure(bg=mycolor)
....... Most of the above is program set up stuff but shown
MAIN CODE HERE
root = Tk()
gui = GUI(root)
root.mainloop()
Works now as expected
Python has a -i startup option which cause Python to enter interactive move when the program finishes, instead of exiting. IDLE executes code as if one entered python -i file.py at the terminal. This allows one to interactively explore the live gui by entering code in the Shell.
From this question and the one referenced by flyingmeatball, it appears that PyCharm does not use or simulate -i. So one must finish a tkinter program with root.mainloop to see anything. Unless one adds a button to quit the mainloop without destroying the application, one will not be able to interact with interactive statements. (Again, this is completely based on what has been posted on SO, as I have no experience with PyCharm.)
I'm really lost...I open a window with two buttons, and when you click on the button called "REGISTER SOME KEY PRESSES" it runs the script called registerSomeKeyPresses.py, BUUUUT once finished I want to close that execution but keep the first window displaying...it's being impossible for me....
Please, i would reaaaally appreciate any help...
Thanks!
#!/usr/bin/env python
from Tkinter import *
import threading
v0 = Tk()
def finishApplication(): v0.destroy()
def registerSomeKeyPresses():
t = threading.Thread(target=execfile("registerSomeKeyPresses.py"))
t.start()
def waitAndRun(f): v0.after(200, f)
b1=Button(v0,text="TERMINAR APLICACION",command=lambda: finishApplication()).pack()
button_keyPresses=Button(v0,text="REGISTER SOME KEY PRESSES",command=lambda: waitAndRun(registerSomeKeyPresses())).pack()
v0.mainloop()
================ registerSomeKeyPresses.py ===========================
Do several things and last command:
io.quit()
When you destroy the instance of Tk, your programm will (and should) exit. If you want to create and destroy windows, create and destroy an instance of Toplevel while keeping the main window active. If you don't want to see the main window you can hide it.
Also, tkinter and threads don't mix very well. You cannot call any methods on any widgets from another thread. I've heard other people say you can call event_generate from another thread, but I think that's the only tkinter function you can call from another thread.
Edit 1
A second try as a response to your comment:
from Tkinter import *
from subprocess import call
import sys
t = Tk()
def click():
t.iconify()
try:
call([sys.executable, 'script.py'])
finally:
t.deiconify() # if it should close do t.quit() and t.destroy()
b = Button(t, command= click)
b.pack()
t.mainloop()
Old Version
What does that do?
================ registerSomeKeyPresses.py ===========================
v0.quit()
v0.destroy()
io.mainloop()
An other error is:
threading.Thread(target=execfile, args = ("registerSomeKeyPresses.py",))
if you really neeed a thread.
Do never mix tkinter mainloop things with threads. Threads can use event_generate - thats safe.
I have written a short module that can be passed an image and simply creates a Tkinter window and displays it. The problem that I am having is that even when I instantiate and call the method that displays the image in a separate thread, the main program will not continue until the Tkinter window is closed.
Here is my module:
import Image, ImageTk
import Tkinter
class Viewer(Tkinter.Tk):
def __init__(self,parent):
Tkinter.Tk.__init__(self,parent)
self.parent = parent
self.initialize()
def initialize(self):
self.grid()
def show(self,img):
self.to_display = ImageTk.PhotoImage(img)
self.label_image = Tkinter.Label(self,image=self.to_display)
self.label_image.grid(column = 0, row = 0, sticky = "NSEW")
self.mainloop()
It seems to work fine, except when I call it from my test program like the one below, it will not seem to allow my test program to continue, even when started in a different thread.
import Image
from viewer import Viewer
import threading
def showimage(im):
view = Viewer(None)
view.show(im)
if __name__ == "__main__":
im = Image.open("gaben.jpg")
t = threading.Thread(showimage(im))
t.start()
print "Program keeps going..."
I think that perhaps my problem is that I should be creating a new thread within the module itself, but I was wanting to just try and keep it simple, as I am new to Python.
Anyway, thanks in advance for any assistance.
edit: To clarity, I am just trying to make a module that will display an image in a Tkinter window, so that I can use this module any time I want to display an image. The problem that I am having is that any time a program uses this module, it cannot resume until the Tkinter window is closed.
Tkinter isn't thread safe, and the general consensus is that Tkinter doesn't work in a non-main thread. If you rewrite your code so that Tkinter runs in the main thread, you can have your workers run in other threads.
The main caveat is that the workers cannot interact with the Tkinter widgets. They will have to write data to a queue, and your main GUI thread will have to poll that queue.
If all you're doing is showing images, you probably don't need threading at all. Threading is only useful when you have a long running process that would otherwise block the GUI. Tkinter can easily handle hundreds of images and windows without breaking a sweat.
From your comments it sound's like you do not need a GUI at all. Just write the image to disk and call an external viewer.
On most systems it should be possible to launch the default viewer using something like this:
import subprocess
subprocess.Popen("yourimage.png")
From what I can tell, Tkinter doesn't like playing in other threads. See this post...I Need a little help with Python, Tkinter and threading
The work around is to create a (possibly hidden) toplevel in your main thread, spawn a separate thread to open images, etc - and use a shared queue to send messages back to the Tk thread.
Are you required to use Tkinter for your project? I like Tkinter. It's "quick and dirty." - but there are (many) cases where other GUI kits are the way to go.
I have tried to run tkinter from a separate thread, not a good idea, it freezes.
There is one solution that worked. Run the gui in the main thread, and send events to the main gui. This is similar example, it just shows a label.
import Tkinter as t
global root;
root = t.Tk()
root.title("Control center")
root.mainloop()
def new_window(*args):
global root
print "new window"
window = t.Toplevel(root)
label = t.Label(window, text="my new window")
label.pack(side="top", fill="both", padx=10, pady=10)
window.mainloop()
root.bind("<<newwin>>",new_window)
#this can be run in another thread
root.event_generate("<<newwin>>",when="tail")