{
'userid' : '5e6f2f38e8cfcfaf34ee76a6',
'c':[
{'cid':123 ,'flist':['5e6de87050fba047c4c666e1','5e65e475aa1d2a77e1e7d9b3','5e75e5a02dfcda6e321be941']} ,
{'cid':321 ,'flist':['5e92533b0f93cb0f6d813631','5e946afbfd003483a47d412b','5e6de87050fba047c4c666e1']} ,
{'cid':431 ,'flist':['5e65e475aa1d2a77e1e7d9b3','5e946afbfd003483a47d412b','5e75e5a02dfcda6e321be941']}
]
}
userid ='5e6f2f38e8cfcfaf34ee76a6'
fid = '5e6de87050fba047c4c666e1'
db.find({'userid':userid ,'c.flist':{'$eq':fid}} , {'c.$.cid':1} )
i am trying to get all cid that the flist contain fid
i tryed this method but i got only first match without {'c.$.cid':1} i got the whole list
if your intention is to get only cid alone, then below query would work,
db.collection.aggregate([{
'$match': {
'userid': '5e6f2f38e8cfcfaf34ee76a6'
}
},
{
'$unwind': {
'path': '$c'
}
}, {
'$match': {
'c.flist': '5e6de87050fba047c4c666e1'
}
},
{
'$project': {
"c.cid": 1,
"_id": 0
}
}])
would give you below output
{ "c" : { "cid" : "123" } }
{ "c" : { "cid" : "321" } }
I think as per your need, you need to change the structure of collection. And as mention in document of MongoDb projection param,
The $ operator projects the first matching array element from each document in a collection based on some condition from the query statement
you can check that in https://docs.mongodb.com/manual/reference/operator/projection/positional/#project-array-documents.
You need to make cid outside the array I think.
You can use below query
db.collection.aggregate([ { $match: { userid: "5e6f2f38e8cfcfaf34ee76a6", "c.flist": "5e6de87050fba047c4c666e1" } }, { $addFields: { c: { $filter: { input: { $reduce: { input: "$c", initialValue: [], in: { $concatArrays: [ "$$value", [ { cid: "$$this.cid", flist: { $filter: { input: "$$this.flist", as: "item", cond: { $eq: [ "$$item", "5e6de87050fba047c4c666e1" ] } } } } ] ] } } }, as: "item2", cond: { $gt: [ "$$item2.flist", [] ] } } } } } ]).pretty()
to get the following output
{
"_id" : ObjectId("5e95ca8801423e0f9af19b4b"),
"userid" : "5e6f2f38e8cfcfaf34ee76a6",
"c" : [
{
"cid" : 123,
"flist" : [
"5e6de87050fba047c4c666e1"
]
},
{
"cid" : 321,
"flist" : [
"5e6de87050fba047c4c666e1"
]
}
]
}
Related
I have the following document structure.
{
_id: ...,
unique_id: 1234,
config_no: 1,
configs: [
{
data: "qwertyuiop" // random string
},
{
data: "asdfghjkl" // random string
}
]
}
I want to update value of data from one of the configs. The index of the config that needs to be updated is available in the config_no key.
Is there any way to update the value without querying the document.
This is what I am currently doing
doc = db.collection.findOne({"unique_id": 1234})
config_no = doc.config_no
db.collection.updateOne(
{"unique_id": 1234},
{"$set": {"configs."+config_no+".data": "zxcvbnm"}} //"configs.1.data"
)
Following is something what i would like to achive.
db.collection.updateOne(
{"unique_id": 1234},
{"$set": {"configs.${config_no}.data": "zxcvbnm"}}
)
You can $unwind with includeArrayIndex option. Use the index to perform conditional update and $merge back into the collection.
db.collection.aggregate([
{
$match: {
unique_id: 1234
}
},
{
"$unwind": {
path: "$configs",
includeArrayIndex: "idx"
}
},
{
$set: {
"configs.data": {
"$cond": {
"if": {
$eq: [
"$config_no",
"$idx"
]
},
"then": "zxcvbnm",
"else": "$configs.data"
}
}
}
},
{
$group: {
_id: "$_id",
config_no: {
$first: "$config_no"
},
configs: {
$push: "$configs"
},
unique_id: {
$first: "$unique_id"
}
}
},
{
"$merge": {
"into": "collection",
"on": "_id",
"whenMatched": "merge"
}
}
])
Mongo Playground
With a schema like this
{
"doc1": {
"items": [
{
"item_id": 1
},
{
"item_id": 2
},
{
"item_id": 3
},
]
},
"doc2": {
"items": [
{
"item_id": 1
},
{
"item_id": 2
},
{
"item_id": 1
},
]
}
}
I want to query for documents that contain a duplicate item in their items array field. A duplicate means items with the same item_id field.
So the result for the example above should return doc2 only, because it has two items with the same item_id
Something like this?
qry = {
"items": {
"$size": {
"$ne": {
"items.unique_count" # obviously this doesn't exist, not sure how to do it
}
}
}
}
result = MyDocument.find(qry)
One option similar to #rickhg12hs and your suggestions is:
db.collection.aggregate([
{$match: {
$expr: {
$ne: [
{$size: "$items"},
{$size: {
$reduce: {
input: "$items",
initialValue: [],
in: {$setUnion: ["$$value", ["$$this.item_id"]]}
}
}
}
]
}
}
}
])
See how it works on the playground example
I was wondering if it was possible to somehow use the $match operator within the $sum function for aggregation.
{ "$unwind": "$info.avatarInfoList" },
{ "$unwind": "$info.avatarInfoList.equipList" },
{ "$unwind": "$info.avatarInfoList.equipList.flat.reliquarySubstats" },
{
"$project": {
"name" : "$name",
"character" : "$info.avatarInfoList.avatarId",
"artifact" : "$info.avatarInfoList.equipList.itemId",
"statValue" : {
"$sum": [
{"$match" : { "$info.avatarInfoList.equipList.flat.reliquarySubstats.appendPropId" : "FIGHT_PROP_CRITICAL_HURT" } },
{"$multiply": [2, {"$match" : { "$info.avatarInfoList.equipList.flat.reliquarySubstats.appendPropId" : "FIGHT_PROP_CRITICAL" } }]}
]
},
}
},
{ "$sort": { "statValue": -1 }},
{ '$limit' : 30 }
]).to_list(length=None)
print(data)
I want to be able to use the value of the $sum operator within the project fields somehow, I just don't really understand what the right approach would be for this.
Sample Input (may be too long):
https://www.toptal.com/developers/hastebin/ixamekaxoq.json
Sample Output:
( 2 * FIGHT_PROP_CRITICAL ) + FIGHT_PROP_CRITICAL_HURT sorted from highest to lowest for each item.
{name: hat, character: Slayer, artifact: 13, statValue : 25.6}
There are still a few ambiguities about how you want to aggregate your data, but using the full document from your link, here's one way to produce the output you want.
N.B.: Weapons in the "equipList" don't have "reliquarySubstats" so they show a "statValue" of null in the output.
db.collection.aggregate([
{"$unwind": "$info.avatarInfoList"},
{"$unwind": "$info.avatarInfoList.equipList"},
{
"$project": {
"_id": 0,
"name": 1,
"character": "$info.avatarInfoList.avatarId",
"artifact": "$info.avatarInfoList.equipList.itemId",
"statValue": {
"$reduce": {
"input": "$info.avatarInfoList.equipList.flat.reliquarySubstats",
"initialValue": 0,
"in": {
"$switch": {
"branches": [
{
"case": {"$eq": ["$$this.appendPropId", "FIGHT_PROP_CRITICAL"]},
"then": {
"$add": [
"$$value",
{"$multiply": [2, "$$this.statValue"]}
]
}
},
{
"case": {"$eq": ["$$this.appendPropId", "FIGHT_PROP_CRITICAL_HURT"]},
"then": {"$add": ["$$value", "$$this.statValue"]}
}
],
"default": "$$value"
}
}
}
}
}
},
{"$sort": {"statValue": -1}}
])
Try it on mongoplayground.net.
It's not quite clear what you want to achieve, but as mentioned you want to be using $cond here.
like so:
{
"$project": {
"statValue": {
"$sum": [
{
$cond: [
{ // if this condition is true (prop id = prop critical hurt )
$eq: [
"$info.avatarInfoList.equipList.flat.reliquarySubstats.appendPropId",
"FIGHT_PROP_CRITICAL_HURT"
]
},
{ // then use this value for the "$sum"
"$multiply": [
2,
"$info.avatarInfoList.equipList.flat.reliquarySubstats.statValue"
]
},
0 // otherwise use this value for the sum.
]
}
]
}
}
Mongo Playground
generate unique id in nested document - Pymongo
my database looks like this...
{
"_id":"5ea661d6213894a6082af6d1",
"blog_id":"blog_one",
"comments": [
{
"user_id":"1",
"comment":"comment for blog one this is good"
},
{
"user_id":"2",
"comment":"other for blog one"
},
]
}
I want to add unique id in each and every comment,
I want it to output like this,
{
"_id":"5ea661d6213894a6082af6d1",
"blog_id":"blog_one",
"comments": [
{
"id" : "something" (auto generate unique),
"user_id":"1",
"comment":"comment for blog one this is good"
},
{
"id" : "something" (auto generate unique),
"user_id":"2",
"comment":"other for blog one"
},
]
}
I'm using PyMongo, is there a way to update this kind of document?
it's possible or not?
This update will add an unique id value to each of the comments array with nested documents. The id value is calculated based upon the present time as milliseconds. This value is incremented for each array element to get the new id value for the nested documents of the array.
The code runs with MongoDB version 4.2 and PyMongo 3.10.
pipeline = [
{
"$set": {
"comments": {
"$map": {
"input": { "$range": [ 0, { "$size": "$comments" } ] },
"in": {
"$mergeObjects": [
{ "id": { "$add": [ { "$toLong" : datetime.datetime.now() }, "$$this" ] } },
{ "$arrayElemAt": [ "$comments", "$$this" ] }
]
}
}
}
}
}
]
collection.update_one( { }, pipeline )
The updated document:
{
"_id" : "5ea661d6213894a6082af6d1",
"blog_id" : "blog_one",
"comments" : [
{
"id" : NumberLong("1588179349566"),
"user_id" : "1",
"comment" : "comment for blog one this is good"
},
{
"id" : NumberLong("1588179349567"),
"user_id" : "2",
"comment" : "other for blog one"
}
]
}
[ EDIT ADD ]
The following works from mongo shell. It adds unique id for the comments array's nested documents - unique across the documents.
db.collection.aggregate( [
{
"$unwind": "$comments" },
{
"$group": {
"_id": null,
"count": { "$sum": 1 },
"docs": { "$push": "$$ROOT" },
"now": { $first: "$$NOW" }
}
},
{
"$addFields": {
"docs": {
"$map": {
"input": { "$range": [ 0, "$count" ] },
"in": {
"$mergeObjects": [
{ "comments_id": { "$add": [ { "$toLong" : "$now" }, "$$this" ] } },
{ "$arrayElemAt": [ "$docs", "$$this" ] }
]
}
}
}
}
},
{
"$unwind": "$docs"
},
{
"$addFields": {
"docs.comments.comments_id": "$docs.comments_id"
}
},
{
"$replaceRoot": { "newRoot": "$docs" }
},
{
"$group": {
"_id": { "_id": "$_id", "blog_id": "$blog_id" },
"comments": { "$push": "$comments" }
}
},
{
$project: {
"_id": 0,
"_id": "$_id._id",
"blog_id": "$_id.blog_id",
"comments": 1
}
}
] ).forEach(doc => db.blogs.updateOne( { _id: doc._id }, { $set: { comments: doc.comments } } ) )
You can use ObjectId constructor to create the ids and place them in your nested documents.
I have a document that references another document, and I'd like to join these documents and filter based on the contents of an array in the child document:
deployment_machine document:
{
"_id": 1,
"name": "Test Machine",
"machine_status": 10,
"active": true
}
machine_status document:
{
"_id": 10,
"breakdown": [
{
"status_name": "Rollout",
"state": "complete"
},
{
"status_name": "Deploying",
"state": "complete"
}
]
}
I'm using Mongo 3.6 and am having mixed success with the lookup and pipeline, heres the object I'm using in the python MongoEngine being passed to the aggregate function:
pipeline = [
{'$match': {'breakdown': {'$elemMatch': {'status_name': 'Rollout'}}}},
{'$lookup':
{
'from': 'deployment_machine',
'let': {'status_id': '$_id'},
'pipeline': [
{'$match':
{'$expr':
{'$and': [
{'$eq': ['$machine_status', '$$status_id']},
]},
}
}
],
'as': 'result',
},
},
{'$project': {
'breakdown': {'$filter': {
'input': '$breakdown',
'as': 'breakdown',
'cond': {'$eq': ['$$breakdown.status_name', 'Rollout']}
}}
}},
]
result = list(MachineStatus.objects.aggregate(*pipeline))
This works well, but how can I exclude results where the Deployment Machine isn't active? I feel it must go in the project but can't find a condition that works. Any help appreciated.
You can add more condition in $lookup pipeline
pipeline = [
{ $match: { breakdown: { $elemMatch: { status_name: "Rollout" } } } },
{
$lookup: {
from: "deployment_machine",
let: { status_id: "$_id" },
pipeline: [
{
$match: {
$expr: { $eq: ["$machine_status", "$$status_id"] },
active: false
}
}
],
as: "result",
}
},
{
$project: {
breakdown: {
$filter: {
input: "$breakdown",
as: "breakdown",
cond: { $eq: ["$$breakdown.status_name", "Rollout"] },
}
}
}
}
];