Completely new and learning python, so please be patient with my noob problems lol.
i tried entering this code:
file = open('Test.txt','w')
file.write('Hello world')
After that it doesn't give me an error but also wont open nor write. The Text.txt file is on my desktop and i tried direct path but also same problem. could i be missing something? Thank you in advance.
your file is not where you think it is try changing to this
print(os.getcwd())
file = open('Test.txt','w')
file.write('Hello world')
print("Wrote : {0}".format(os.path.abspath("Test.txt")))
print("Contents: ",open("Test.txt","r").read())
as an aside when opening for writing you should really use a filecontext
with open("Test.txt","w") as f:
f.write('Hello world')
this ensures the file is properly closed afterwards
my observations are as under.
1. After the second line of code , Python returns the no. of characters written into the file, in your case 11. Have you observed it?.
2. Although you may see your file using file explorer on your desktop, you won't see any thing written in it if you open it using notepad. For you to see the contents you wrote, you need to close the file by file.close() in python.
3. The file name is test.txt as you mentioned, but you have stated 'Text.txt' is on desktop. Pl. reconcile.
best regards
NR
Related
I wrote this simple code and no text file was created. I also tried to create it manually in the same folder and append something on and that also didn't work.
employee_file = open("employees.txt" , "w")
employee_file.write("toby human resources")
employee_file.close()
You should really put the code in the question. After some time the image will probably be deleted and many people won't be able to benefit from your question.
Try the following code:
import os
print (os.getcwd())
employee_file = open("employees.txt" , "w")
employee_file.write("toby human resources")
employee_file.close()
It should print the current working directory, where the file should be saved.
Firstly - your code is correct.
Secondly - why not use "built-in" statements (which closes the file so we don't have take care of it)
with open('employees.txt','w') as file:
file.write("some data")
# do sth else ...
and we don't have to close the file here.
If I run
file = open("BAL.txt","w")
I = '200'
file.write(I)
file.close
from a script, it outputs nothing in the file. (It literally overwrites the file with nothing)
Furthermore, running cat BAL.txt just goes to the next line like nothing is in the file.
But if I run it line by line in a python console it works perfectly fine.
Why does this happen. ( I am a begginner learning python the mistake may be super obvious. I have thrown about 2 hours into trying to figure this out)
Thanks in advance
You aren't closing your file properly. To close it you are missing the () at the end of file.close so it should look like this:
file = open("BAL.txt", "w")
file.write("This has been written to a file")
file.close()
This site has the same example and may be of some use to you.
Another way, especially useful when you are appending multiple values into a single file is to use something like with open("BAL.txt","w") as file:. Here is your script rewritten to include this example:
I = '200'
with open("BAL.txt","w") as file:
file.write(I)
This opens our file with the value file and allows us to write values to it. Also note that file.close() is not needed here and when appending text w+ needs to be used.
to write to a file you do this:
file = open("file.txt","w")
file.write("something")
file.close()
when you use file.write() it deletes all of the contents of the file, if you want to write to the end of the file do this:
file = open("file.text","w+")
file.write(file.read()+"something")
file.close()
There are other ways to do this but this one is the most intuitive (not the most efficient), also the other way tends to be buggy so there is no reason to post it because this is reliable.
Firstly, you're missing the parentheses when you're closing the file. Secondly, writing to a file should be done like this:
file = open("BAL.txt", "w")
file.write("This has been written to a file")
file.close()
Let me know if you have any questions.
As part of a bigger project, I would simply like to make sure that a file can be opened and Python can read and use it. So after I opened up the txt file, I said:
data = txtfile.read()
first_line = data.split('\n',1)[2]
print(first_line)
I also tried
print(f1.readline())
where f1 is the txt file. This, again, did nothing.
I am using the spyder IDE, and it just says running file, and doesn't print anything. Is it because my file is too large? It is 4.6 gigs.
Does anyone have any idea what's going on?
and it just says running file, and doesn't print anything. Is it
because my file is too large? It is 4.6 gigs.
Yes.
data = txtfile.read()
This function is going to read the entire file. Since you stated that the file is 4.6GB, it is going to take time to load the entire file and then split the by newline character.
See this: Read large text files in Python
I don't know your context of use, so, if you can process line by line, it would be simpler. Or even chunks would make it simpler than reading the entire file.
first_line = open('myfile.txt', 'r').readline()
for some reason the readline() function in my following code seems to print nothing.
fileName = input()
fileName += ".txt"
fileA = open(fileName, 'a+')
print("Opened", fileA.name)
line = fileA.readline()
print(line)
fileA.close()
I'm using PyCharm, and I've been attempting to access 'file.txt' which is located inside my only PyCharm project folder. It contains the following:
Opened file!!
I have no idea what is wrong, and I can't find any relevant information for my problem whatsoever. Any help is appreciated.
Because you opened the file in a+ mode, the file pointer starts at the end of the file. After all, that is where you would normally append text.
If you want to read from the top, you need to place fileA.seek(0) just before you call readline:
fileA.seek(0)
line = fileA.readline()
Doing so sets the pointer to the top of the file.
Note: After reading the comments, it appears that you only need to do this if you are running a Windows machine. Those using a *nix system should not have this problem.
I'm attempting to do a "find and replace" in a file on a Mac OS X computer. Although it appears to work correctly. It seems that the file is somehow altered. The text editor that I use (Text Wrangler) is unable to even open the file once this is completed.
Here is the code as I have it:
import fileinput
for line in fileinput.FileInput("testfile.txt",inplace=1):
line = line.replace("newhost",host)
print line,
When I view the file from the terminal, it does say "testfile" may be a binary file. See it anyway? Is there a chance that this replace is corrupting the file? Do I have another option for this to work? I really appreciate the help.
Thank you,
Aaron
UPDATE: the actual file is NOT a .txt file it is a .plist file which is preference file in Mac OS X if that makes any difference
LINK to plist file:
http://www.queencitytech.com/plist.zip
Your code worked for me fine. However, I would suggest a different approach: don't try overwriting the file directly. I never like changing the file directly because if you have a bug or something like that the file is lost. Generate a new file then copy it over manually (or within python, if you really want to).
PATH = 'testfile.txt'
FILE = open(PATH)
OUT_FILE = open('out_' + PATH, 'w')
for line in FILE.readlines():
print >> OUT_FILE, line.replace('newhost', host),
Try using sys.stdout.write instead of print. readlines() retains the new line characters at the end of the read line. The print statement adds an additional new line character, so it's likely double spacing the file.