Right now the code is working but if I don't capitalize the first letter of both first and last name the code will return "error: person not found."
How can I set it up so that no matter how the user inputs the search it will return the requested data?
#Iterate through the lines and save them in a dictionary, with the
#full name as the key
for line in file:
stripped = line.strip()
name = stripped[:stripped.index(',')]
d[name] = stripped[stripped.index(',')+1:].strip()
def main():
#call the input function to read the file
addresses = input_address()
#Get the user option
option = int(input("Lookup (1) phone numbers or (2) addresses: "))
if option == 1:
phone = True
else:
phone = False
#Ask for names and print their information in case they exist, end on blank entry
while True:
name = input("Enter space-separated first and last name: ")
if name == "":
return main()
if name not in addresses:
print("Error: person not found")
else:
display(addresses[name], phone)
main()
Try using:
.capitalize()
For example:
'hello world'.capitalize()
yields,
'Hello World'
So in your case, you would do:
name.capitalize()
then look for it inside addresses.
You can use lower(), upper(), or capitalize(), as long as you attach the chosen method to end of both variables.
Using lower():
for i in range(len(addresses)):
addresses[i] = addresses[i].lower() # Converting array values to lowercase
if name.lower() not in addresses: # Seeing if lowercase variable is in lowercase array
print("Error: person not found")
else:
print("Person found")
Related
in case it isn't already obvious im new to python so if the answers could explain like im 5 years old that would be hugely appreirecated.
I'm basically trying to prove to myself that I can apply some of the basic that I have learnt into making a mini-contact book app. I don't want the data to save after the application has closed or anything like that. Just input your name, phone number and the city you live in. Once multiple names are inputted you can input a specific name to have their information printed back to you.
This is what I have so far:
Name = input("enter name here: ")
Number = input("enter phone number here: ")
City = input("enter city here: ")
User = list((Name, Number, City))
This, worked fine for the job of giving python the data. I made another input that made python print the information back to me just to make sure python was doing what I wanted it to:
print("Thank you! \nWould you like me to read your details back to you?")
bck = input("Y / N")
if bck == "Y":
print(User)
print("Thank you! Goodbye")
else:
print("Goodbye!")
The output of this, is the list that the user creates through the three inputs. Which is great! I'm happy that I have managed to make it function so far;
But I want the 'Name' input to be what names the 'User' list. This way, if I ask the user to input a name, that name will be used to find the list and print it.
How do I assign the input from Name to ALSO be what the currently named "User" list
You will need to create a variable which can store multiple contacts inside of it. Each contact will be a list (or a tuple. Here I have used a tuple, but it doesn't matter much either way).
For this you could use a list of lists, but a dictionary will be more suitable in this case.
What is a dictionary?
A dictionary is just like a list, except that you can give each of the elements a name. This name is called a "key", and it will most commonly be a string. This is perfect for this use case, as we want to be able to store the name of each contact.
Each value within the dictionary can be whatever you want - in this case, it will be storing a list/tuple containing information about a user.
To create a dictionary, you use curly brackets:
empty_dictionary = {}
dictionary_with_stuff_in_it = {
"key1": "value1",
"key2": "value2"
}
To get an item from a dictionary, you index it with square brackets, putting a key inside the square brackets:
print(dictionary_with_stuff_in_it["key1"]) # Prints "value1"
You can also set an item / add a new item to a dictionary like so:
empty_dictionary["a"] = 1
print(empty_dictionary["a"]) # Prints 1
How to use a dictionary here
At the start of the code, you should create an empty dictionary, then as input is received, you should add to the dictionary.
Here is the code I made, in which I have used a while loop to continue receiving input until the user wants to exit:
contacts = {}
msg = "Would you like to: \n - n: Enter a new contact \n - g: Get details for an existing contact \n - e: Exit \nPlease type n, g, or e: \n"
action = input(msg)
while action != "e":
if action == "n": # Enter a new contact
name = input("Enter name here: ")
number = input("Enter phone number here: ")
city = input("Enter city here: ")
contacts[name] = (number, city)
print("Contact saved! \n")
action = input(msg)
elif action == "g": # Get details for an existing contact
name = input("Enter name here: ")
try:
number, city = contacts[name] # Get that contact's information from the dictionary, and store it into the number and city variables
print("Number:", number)
print("City:", city)
print()
except KeyError: # If the contact does not exist, a KeyError will be raised
print("Could not find a contact with that name. \n")
action = input(msg)
else:
action = input("Oops, you did not enter a valid action. Please type n, g, or e: ")
#can be easier to use with a dictionary
#but its just basic
#main list storing all the contacts
Contact=[]
#takes length of contact list,'int' just change input from string to integer
contact_lenght=int(input('enter lenght for contact'))
print("enter contacts:-")
#using for loop to add contacts
for i in range(0,len(contact_lenght)):
#contact no.
print("contact",i+1)
Name=input('enter name:')
Number=input('enter number:')
City=input("enter city:")
#adding contact to contact list using .append(obj)
Contact.append((Name,Number,City))
#we can directly take input from user using input()
bck=input("Thank you! \nWould you like me to read your details back to you?[y/n]:")
#checking if user wants to read back
if bck=='y':
u=input("enter your name:")
#using for loop to read contacts
for i in range(0,len(Contact)):
#if user name is same as contact name then print contact details
if u==Contact[i][0]:
print("your number is",Contact[i][1])
print("your city is",Contact[i][2])
else:
#if user doesnt want to read back then print thank you
print("Good bye")
For this purpose you should use a dictionary.
The key of every entry should be the string 'User[0]' that corresponds to the person's name.
The contents of every entry should be the list with the information of that user.
I'll give you an example:
# first we need to create an empty dictionary
data = {}
# in your code when you want to store information into
# the dictionary you should do like this
user_name = User[0] # this is a string
data[user_name] = User # the list with the information
If you want to access the information of one person you should do like this:
# user_you_want string with user name you want the information
data[user_you_want]
Also you can remove information with this command:
del data[user_you_want_to_delete]
You can get more information on dictionaries here: https://docs.python.org/3/tutorial/datastructures.html#dictionaries
You should start by defining a class to support name, phone and city. Once you've done that, everything else is easy.
class Data:
def __init__(self, name, city, phone):
self.name = name
self.city = city
self.phone = phone
def __eq__(self, other):
if isinstance(other, str):
return self.name == other
if isinstance(name, type(self)):
return self.name == other.name and self.city == other.city and self.phone == other.phone
return False
def __str__(self):
return f'Name={self.name}, City={self.city}, Phone={self.phone}'
DataList = []
while (name := input('Name (return to finish): ')):
city = input('City: ')
phone = input('Phone: ')
DataList.append(Data(name, city, phone))
while (name := input('Enter name to search (return to finish): ')):
try:
print(DataList[DataList.index(name)])
except ValueError:
print('Not found')
I am trying to make a script that asks for user input in Python, it is supposed to error with the response "Please enter first name", and then return the user back to the initial input question prompt.
This isn't working, instead after asking for both the first and last name if no name is given for both I am thrown into an infinite loop of the first error.
# User input for first name
first_name = input('Enter FIRST name here: ')
# User input for last name
last_name = input('Enter LAST name here: ')
def print_name():
# store user input in separate variable
fname = first_name
lname= last_name
while True:
# throw error if user enters no first name
if len(fname) == 0:
# error msg
print('No FIRST name entered...')
# loop back to prompt asking for first name
continue
else:
# if first name given move on to prompting for last name
# break loop
break
# loop into prompting user for last name
while True:
# throw error if user enters no last name
if len(lname) == 0:
print('No LAST name entered...')
# loop back to prompt asking for last name
continue
else:
# if last name given move on to running print command
# break loop
break
return fname, lname
print(f'your name is {fname} {lname}')
print_name()
Please can someone help me understand whats going wrong here? It should only loop back to asking for a first name (or last name) when nothing is given, other wise it should print the users name to console. both names should be given too, if first name is not given then id expect an error in the first while loop, like wise if last name is not given.
Also is there a better way to do this? using 2 while loops seems wrong?
Don't repeat yourself. If you copy and paste a section of code, stop and think. It should either be a function, or a loop.
def wait_for_input(prompt):
data = ""
while data == "":
data = input(prompt).strip()
return data
def print_name(fname, lname):
print(f'your name is {fname} {lname}')
first_name = wait_for_input('Enter FIRST name: ')
last_name = wait_for_input('Enter LAST name: ')
print_name(first_name, last_name)
Also, don't use comments to repeat what the code says.
The issue is with your infinite loops, you can simplify your function like:
def print_name():
first_name = ""
last_name = ""
# User input for first name
while first_name == "":
first_name = input('Enter FIRST name here: ')
# User input for last name
while last_name == "":
last_name = input('Enter LAST name here: ')
print(f'your name is {first_name} {last_name}')
I have the impression you are new at this:
While-loops generally look as follows:
while <condition>
...
<check_condition>
...
This means that in most cases, at every time the loop is executed, the condition is re-calculated and checked again by the while.
In your case, this would become something like:
while (len(fname) == 0)
<show_error_message>
<get fname again>
The case you have written here (while true) also exists and is used regularly, but in very different cases, like in multi-threaded event-based programs:
while true
<get_event>
This means that a part of the program (a so-called thread) is waiting for an event (like a buttonclick) to be catched and then something happens. This, however, is mostly done in multi-threaded applications, which means that the "main" program is doing something, while a subprogram is handling the events, which are coming in.
I am not fully understanding why you need so many loops. Something like this should do:
def print_name():
fname = input('Enter FIRST name here: ')
if len(fname) == 0:
raise Exception('No FIRST name entered...')
lname= input('Enter LAST name here: ')
if len(lname) == 0:
raise Exception('No LAST name entered...')
print(f"your name is {fname} {lname}")
And if all you wanted is to repeat this loop all you need to do is nest your print_name() function in a loop.
EDIT: Now that I seen other answers, I believe #Tomalak answer is better, was not getting what you really wanted.
Try this code:
def print_name():
# store user input in separate variable
first_name = input('Enter FIRST name here: ')
fname = first_name
while True:
fname = first_name
# throw error if user enters no first name
if len(fname) == 0:
# error msg
print('No FIRST name entered...')
first_name = input('Enter FIRST name here: ')
# loop back to prompt asking for first name
continue
else:
# if first name given move on to prompting for last name
# break loop
break
# loop into prompting user for last name
while True:
last_name = input('Enter LAST name here: ')
lname= last_name
# throw error if user enters no last name
if len(lname) == 0:
print('No LAST name entered...')
# loop back to prompt asking for last name
continue
else:
# if last name given move on to running print command
# break loop
break
return fname, lname
print(f'your name is {fname} {lname}')
print_name()
I am trying to search a string (which is input by the user) in a text file and if the string exist in the text file then it will return it's position (position in the file)
I am using seek and tell methods of text file in python
def search(self,identity):
with open("dbase.txt", 'r') as dbase:
find = dbase.readline()
while str.casefold(find) == str.casefold(identity):
pos = dbase.tell()
find = dbase.readline()
return pos
complete code :
class app:
''' class that takes the data and save it
into a text file name dbase.txt'''
def get_data(self):
self.name = input("Name : ")
self.add = input("Address : ")
self.mob = input("Mobile : ")
def write_data(self):
dbase = open("dbase.txt",'a')
dbase.write(self.name+"\n")
dbase.write(self.add+"\n")
dbase.write(self.mob+"\n")
dbase.close()
def read_data(self,pos):
dbase = open("dbase.txt",'r')
dbase.seek(pos)
self.name = dbase.readline()
self.add = dbase.readline()
self.mob = dbase.readline()
print(self.name)
print(self.add)
print(self.mob)
def search(self,identity):
data = open("dbase.txt", 'r').read()
desired_string = identity
if desired_string in data:
pos = data.find(desired_string)
return pos
else:
print("The desired string does not exist in the file")
call = app()
f = input("Enter :")
pos = call.search(f)
call.read_data(pos)
identity stands for the user input which I passed in this function as a parameter and I want to match this identity in the file and i am extracting file data in a variable find so if find is equals to identity then I want to return it's current position in file but it's not working, I had tried to print something in the while loop such as print("x") or something else to check weather the While Loop condition goes true or not because if it goes true then it will print that "x" but it does not print anything from which I concluded that the while loop condition goes false therefore I am thinking that the fault is in the line.
while str.casefold(find) == str.casefold(identity):
but I am not getting why is it so because the string which I input is actually existing in the file.
data = open("filename.ext", 'r').read().replace("\n", "\n\n")
desired_string = "apples"
if desired_string in data:
index = data.find(desired_string)
else:
print("The desired string does not exist in the file")
The above code will search for the desired string in the file, and if it exists the index of its first occurrence will be stored in the variable index. Otherwise The desired string does not exist in the file will be printed.
I am attempting to create a program that asks for the user to enter his/her name and records the input into a list (Was working towards dictionary but seems like I made a boo boo!) but it is returning with "TypeError: can only concatenate list (not "str") to list". The following is the code.Thanks in advance.
namedic = []
while True:
print ("Please, enter your name:")
name = input()
if len(name) > 3:
print ("Welcome")
else:
print ("Ew, your name have less than 4 letters! Gross! Try a new one")
continue
namedic = namedic + name
print ("Ah, your name have at least 4 words, good name.")
for name in namedic:
print (name)
Your erroring line is namedic = namedic + name. What you're trying to do is add a list (namedic) to a string (name). You should do namedic.append(name) instead.
The + operator isn't used to append elements to a list, as the error shows. You can use the append method for that:
namedic.append(name)
#your code should rather be like this;
namedic = []
while True:
print ("Please, enter your name:")
name = input()
if len(name) > 3:
print ("Welcome")
else:
print ("Ew, your name have less than 4 letters! Gross! Try a new one")
continue
namedic.append(name)
print ("Ah, your name have at least 4 words, good name.")
for name in namedic:
print (name)
Hello everyone thanks for looking into my problem. What I am trying to do is write a "Structured" program in python that takes txt from a file and parses it into lists. Then after closing the file, I need to reference the user input (zipcode) in those lists and then print out the city and state according to the zipcode that they entered. My instructor is having us use structure by making several functions. I know there are probably lots of more efficient ways of doing this, but I must keep the structure thats in place.
EDIT
Here is my code(Current):
#-----------------------------------------------------------------------
# VARIABLE DEFINITIONS
eof = False
zipRecord = ""
zipFile = ""
zipCode = []
city = []
state = []
parsedList = []
#-----------------------------------------------------------------------
# CONSTANT DEFINITIONS
USERPROMPT = "\nEnter a zip code to find (Press Enter key alone to stop): "
#-----------------------------------------------------------------------
# FUNCTION DEFINITIONS
def startUp():
global zipFile
print "zipcode lookup program".upper()
zipFile = open("zipcodes.txt","r")
loadList()
def loadList():
while readRecord():
pass
processRecords()
def readRecord():
global eof, zipList, zipCode, city, state, parsedList
zipRecord = zipFile.readline()
if zipRecord == "":
eof = True
else:
parsedList = zipRecord.split(",")
zipCode.append(parsedList[0])
city.append(parsedList[1])
state.append(parsedList[2])
eof = False
return not eof
def processRecords():
userInput = raw_input(USERPROMPT)
if userInput:
print userInput
print zipCode
if userInput in zipCode:
index_ = zipcode.index(userInput)
print "The city is %s and the state is %s " % \
(city[index_], state[index_])
else:
print "\nThe zip code does not exist."
else:
print "Please enter a data"
def closeUp():
zipFile.close()
#-----------------------------------------------------------------------
# PROGRAM'S MAIN LOGIC
startUp()
closeUp()
raw_input("\nRun complete. Press the Enter key to exit.")
Here is a sample from the zipcode txt file:
00501,HOLTSVILLE,NY
I am definitely stuck at this point and would appreciate your help in this matter.
EDIT
Thanks for all the help everyone. I really do appreciate it. :)
why you fill the lists zipcode, city , state like that, i mean in each user entry we get the next line from the file
i think that you should do :
def loadList():
# Fill all the list first , make the readRecord() return eof (True or False).
while readRecord():
pass
# than process data (check for zip code) this will run it only one time
# but you can put it in a loop to repeat the action.
processRecords()
about your problem :
def processRecords():
userInput = raw_input(USERPROMPT)
# Check if a user has entered a text or not
if userInput:
# check the index from zipcode
if userInput in zipcode:
# the index of the zipcode in the zipcode list is the same
# to get related cities and states.
index_ = zipcode.index(userInput)
print "The city is %s and the state is %s " % \
(city[index_], state[index_])
else:
print "\nThe zip code does not exist."
else:
print "Please enter a data"
one of the beauties of Python is that it's interactive. if you take processRecords() out of loadList(), and then at the bottom of your program put:
if __name__ == '__main__':
processRecords()
Then, from the command prompt, type "python". You'll get the Python shell prompt, ">>>". There you type:
from zipcodes import * # this assumes your program is zipcodes.py
dir() # shows you what's defined
print zipCode # shows you what's in zipCode
that ought to help debugging.
Strings don't have an append method like lists do. What I think you're trying to do is append the strings zipCode, city, and state to parsedList. This is the code you'd use to do that:
parsedList.append(zipCode)
parsedList.append(city)
parsedList.append(state)
Or, even more compactly:
parsedList = [zipCode, city, state]
Let me know if you get another error message and I can offer more suggestions.