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Element not Clickable ( Chrome + Selenium + Python)

I am using Chromewebdriver /Selenium in Python
I tried several solutions ( actions, maximize window etc) to get rid of this exception without success.
The error is :
selenium.common.exceptions.ElementClickInterceptedException: Message: element click intercepted: Element ... is not clickable at point (410, 513). Other element would receive the click: ...
The code :
from selenium import webdriver
import time
url = 'https://www.tmdn.org/tmview/welcome#/tmview/detail/EM500000018203824'
driver = webdriver.Chrome(executable_path = "D:\Python\chromedriver.exe")
driver.get(url)
time.sleep(30)
driver.find_element_by_link_text('Show more').click()

I tested this code on my linux pc with latest libraries, python3 and chromedriver. It works perfectly(to my mind). So try to update everything and try again(Try to not to leave chrome). Here is the code:
from selenium import webdriver
import time
url = 'https://www.tmdn.org/tmview/welcome#/tmview/detail/EM500000018203824'
driver = webdriver.Chrome(executable_path = "chromedriver")
driver.get(url)
time.sleep(30)
driver.find_element_by_link_text('Show more').click()
P.S. chromedriver is in the same folder as script.

Thank you for your assistance.
Actually, the issue was the panel on the footer of the web page 'We use cookies....' which is overlapping with the 'Show more' link, when the driver tries to click, the click was intercepted by that panel.
The solution is to close that panel, and the code worked fine.

code is working fine but if you manually click on some other element after page loaded before sleep time is over then you can recreate same error
for example after site is loaded and i clicked on element search for trade mark with similar image then selenium is not able to find search element.so maybe some other part of your code is clicking on other element and loading different url due to which
selenium is generating this error .your code is fine just check for conflict cases.

Is there a way around cookie and privacy popus in selenium browser?

So I'm trying to make a python script using selenium and bs4 to automatically buy shoes for from adidas.com. It's just that whenever selenium browser starts the adidas site it shows a popup concerning cookies and privacy. I can't click on the accept button using selenium(can't find the element to click on) and I've tried starting the selenium browser with my firefox profile containing cookies and what not. But it still shows that damn popup and it's stopping the script.
Is there anyway to fix this?
Tried starting selenium with firefox cookies like this:
ffprofile = webdriver.FirefoxProfile(r'C:\Users\chico\AppData\Local\Mozilla\Firefox\Profiles\e5108gza.default')
driver = webdriver.Firefox(firefox_profile=ffprofile)
driver.get('https://www.adidas.nl/on/demandware.store/Sites-adidas-NL-Site/nl_NL/MyAccount-CreateOrLogin')
driver.find_element_by_xpath("//input[#id='dwfrm_login_username']").send_keys('email')
driver.find_element_by_xpath("//input[#id='dwfrm_login_password']").send_keys('password')
driver.find_element_by_xpath("//button[#value='Inloggen']").click()
The popup from the adidas site just keeps poping up and stopping my script from continuing. Sometimes it will fill in email and password before being stopped, sometimes it will be stopped before that.

I ran into this same issue recently, and it was SO frustrating, because it can't be handled with a "switch to alert" and "accept" it approach sometimes.
Here's how I got around my issue. First, and this was most important, you need to "inspect" the page you are writing selenium code for in a way that the cookie acceptance popup will show up.
For me, I was using the Chrome driver, and so for inspecting the page, I had to run incognito, so that the page would not know I had already accepted cookies. Use the method for Firefox that will achieve the same effect.
Then you can find the element ID (or class name) for the acceptance button and add a click to the end of your command. My code to do this looks as follows:
from selenium import webdriver
import time
URL = "http:some_site.com"
driver = webdriver.Chrome()
driver.get(URL)
time.sleep(5)
driver.find_element_by_id(the_id_name_for_cookie_acceptance_as_a_string).click()
# Do more stuff ...
Now, if you run into a cookie dialog that won't act as an alert, you can handle it.

I tried the code you posted and didn't receive any alert pop up.But if there is a Alert windows it needs to be handled by switching to it and accepting it
from selenium import webdriver
driver = webdriver.Firefox()
driver.set_page_load_timeout(30)
driver.get('https://www.adidas.nl/on/demandware.store/Sites-adidas-NL-Site/nl_NL/MyAccount-CreateOrLogin')
try:
WebDriverWait(browser, 3).until(EC.alert_is_present(),'Timed out waiting for alert popup')
alert = driver.switch_to.alert
alert.accept()
except:
print "no alert"
driver.find_element_by_xpath("//input[#id='dwfrm_login_username']").send_keys('email')
driver.find_element_by_xpath("//input[#id='dwfrm_login_password']").send_keys('password')
driver.find_element_by_xpath("//button[#value='Inloggen']").click()

How to send CTRL-P to a web browser in Python

The aim of this is to open a browser window and save the site as PDF.
I'm writing Python code that:
1) Opens a web page
2) Does a control-p to bring up the print dialog box
NOTE: I will have pre-configured the browser to save as PDF instead of defaulting as printing to a printer)
3) Does "return"
4) Enters the file name
5) Does "return" again
NOTE: In my full code, I'll be doing these steps hundreds of times
I'm having a problem early on with control-p. As a test, I'm able to send dummy text to Google's search, but I can't seem to be able to send a control-p (no error messages). I'm using Google as an easy example, but my final code will use various other sites.
Obviously I'm missing something but just can't figure out what.
I tried an alternate method of using javascript instead of ActionChains:
driver.execute_script('window.print();')
This worked in getting the print dialog but I wasn't able to feed anything else in that dialog box (like , file name and location for the pdf).
I tried PDFkit, to convert the web page into pdf. It worked on some sites, but it crashed often (depending on what the site returned), the page was sometimes poorly formatted and some sites (pinterest) just didn't render at all. For this reason, I changed method and decided to use selenium and Chrome in order for the pdf to render just like it shows in the browser.
I thought about using "element.send_keys("some text")" instead of ActionChains, but since I'm going across multiple different web sites, I don't necessarily know what element to look for.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.action_chains import ActionChains
import time
DRIVER = 'chromedriver'
driver = webdriver.Chrome(DRIVER)
URL = "http://www.google.com"
driver.get(URL)
actions = ActionChains(driver)
time.sleep(5) #Give the page time to load
actions.key_down(Keys.CONTROL)
actions.send_keys('p')
actions.key_up(Keys.CONTROL)
actions.perform()
time.sleep(5) #Sleep to see if the print dialog came up
driver.quit()

You can use autoit to achieve your requirement.
First do pip install -U pyautoit
from selenium import webdriver
import autoit
import time
DRIVER = 'chromedriver'
driver = webdriver.Chrome(DRIVER)
driver.get('http://google.com')
driver.maximize_window()
time.sleep(10)
autoit.send("^p")
time.sleep(10) # Pause to allow you to inspect the browser.
driver.quit()
Please let me know if it's working.

try this:
webdriver.ActionChains(driver).key_down(Keys.CONTROL).send_keys('P').key_up
(Keys.CONTROL).perform()

check this out :
robot.keyPress(KeyEvent.VK_CONTROL)
robot.keyPress(KeyEvent.VK_P)
// CTRL+P is now pressed
robot.keyRelease(KeyEvent.VK_P)
robot.keyRelease(KeyEvent.VK_CONTROL)

logging into a website and downloading a file

I would like to log into a website and download a file. I'm using selenium and the chromedriver. Would like to know if there is a better way. It currently opens up a chrome browser window and sends the info. I don't want to see the browser window opened up and the data being sent. Just want to send it and return the data into a variable.
from selenium import webdriver
driver = webdriver.Chrome()
def site_login(URL,ID_username,ID_password,ID_submit,name,pas):
driver.get(URL)
driver.find_element_by_id(ID_username).send_keys(name)
driver.find_element_by_id(ID_password).send_keys(pas)
driver.find_element_by_id(ID_submit).click()
URL = "www.mywebsite.com/login"
ID_username = "name"
ID_password = "password"
ID_submit = "submit"
name = "myemail#mail.com"
pas = "mypassword"
resp=site_login(URL,ID_username,ID_password,ID_submit,name,pas)

You can run chrome in headless mode. In which case, the chrome UI won't show up and still performing the task you were doing. Some article I found on this https://intoli.com/blog/running-selenium-with-headless-chrome/. Hope this helps.

First option: If you are able to change the driver, you can use phantom-js as driver. That was a headless browser and you can use it with selenium.
Second option: If the site are not dynamic (easily called it SPA) or you are able to trace packet (which can be done in chrome dev tools), you can directly use request with the help of beautifulsoup if you need to get some data on the page.

Just add this two lines
chrome_options = Options()
chrome_options.add_argument("--headless")
This should make chrome run in the background.

Selenium PhantomJS save screenshot not getting the correct page

I have the following Python code to take screenshots of webpages. It is working good for most cases, but when i tried to print
http://www.totalwine.com/wine/red-wine/pinot-noir/c/000018
i am getting a different screenshot - different from the actual page (I am getting the correct screenshot sometimes). Can someone help. I've attached the output screenshot that i got as well. Please load the above link on a browser and you will see a different page.
I'm thinking the possible reasons could be
1) Timing of page load
2) Popup
Can someone help
def screenshot_util(url):
browser = webdriver.PhantomJS(service_log_path='ghostdriver.log')
browser.set_window_size(1024, 768)
browser.get(url)
browser.save_screenshot('temp.png')
print(browser.current_url)
browser.quit()
return
url_to_print = 'http://www.totalwine.com/wine/red-wine/pinot-noir/c/000018'
screenshot_util(url_to_print)

Programmatically click the yes button on the pop-up and wait a few seconds like this:
from selenium import webdriver
from time import sleep
def screenshot_util(url):
browser = webdriver.PhantomJS(service_log_path='ghostdriver.log')
browser.set_window_size(1024, 768)
browser.get(url)
browser.find_element_by_id("btnYes").click()
sleep(4)
browser.save_screenshot('temp.png')
print(browser.current_url)
browser.quit()
return
url_to_print = 'http://www.totalwine.com/wine/red-wine/pinot-noir/c/000018'
screenshot_util(url_to_print)
For clarity the lines I added to your code were:
from time import sleep
...
browser.find_element_by_id("btnYes").click()
sleep(4)

Your code was nearly perfect but had a small bug. You are trying to take a screenshot and save it simply as temp.png. Here webdriver gets the name of the screenshot but is not sure about the location where you want to save the screenshot.
browser.save_screenshot('temp.png')
Solution:
As a solution I have used your own code and have provided a logical path to the Screenshots sub-directory (./Screenshots/) already created under my project space. driver seems to be happily saving the screenshot there named as temp.png. Here is the modified code block:
from selenium import webdriver
def screenshot_util(url):
browser = webdriver.PhantomJS(service_log_path='./Logs/logs.log', executable_path="C:\\Utility\\phantomjs-2.1.1-windows\\bin\\phantomjs.exe")
browser.set_window_size(1024, 768)
browser.get(url)
browser.save_screenshot('./Screenshots/temp.png')
print(browser.current_url)
browser.quit()
return
url_to_print = 'http://www.totalwine.com/wine/red-wine/pinot-noir/c/000018'
screenshot_util(url_to_print)