I am attempting to create a histogram using seaborn and census data that displays 3 subplots for age composition, and I have the data grouped the way that I would like it, but I am struggling to turn that into a histogram.
import pandas as pd
import numpy as np
import seaborn as sns
import matplotlib.pyplot as plt
filename = "/scratch/%s_class_root/%s_class/materials/data/pums_short.csv.gz"
acs = pd.read_csv(filename)
R65_agg = acs.groupby(["R65", "PUMA"])["HINCP"]
R65_meds = R65_agg.agg(np.median).unstack()
R65_f = R65_meds.dropna()
R65_f = R65_meds.reset_index(drop = True)
I was expecting this code to give me data that I could plug into a histogram but instead of being distinct subplots, the "0.0, 1.0, 2,0" in the final variable just get added together when I apply the .describe() function. Any advice for how I can convert this into a form that's readable with the sns.histplot() function?
I want to plot this array. I am using seaborn to do that. I used
import seaborn as sns
sns.set_style('whitegrid')
sns.kdeplot(data= score_for_modelA[:,0])
But the above one only gives for column 1. My scores are in column 1 and 2 and I want both of them plotted in the same graph.
The sample data is like this:
array ([[0.67,0.33],[0.45,0.55],......,[0.81,0.19]]
You can try putting them into a data frame first, with the proper column names, for example:
import seaborn as sns
import numpy as np
import pandas as pd
# create sample dataframe in wide format
score_for_modelA = np.random.normal(0, 1, (50, 2))
df = pd.DataFrame(score_for_modelA, columns=['col1', 'col2'])
# use melt to convert the dataframe to a long form
dfm = df.melt()
Plot the long form dataframe
sns.kdeplot(data=dfm, hue="variable", x="value")
As pointed out by #JohanC, if you want all of the columns:
sns.kdeplot(data=df)
I have categorized data. At specific dates I have data (A to E) that is counted every 15 minutes.
When I want to plot with seaborn I get this:
Bigger bubbles cover smaller ones and the entire thing is not easy readable (e.g. 2020-05-12 at 21:15). Is it possible to display the bubbles for each 15-minute-class next to each other with a little bit of overlap?
My code:
import pandas as pd
import seaborn as sns
import matplotlib
import matplotlib.pyplot as plt
import os
df = pd.read_csv("test_df.csv")
#print(df)
sns.set_theme()
sns.scatterplot(
data = df,
x = "date",
y = "time",
hue = "category",
size = "amount",sizes=(15, 200)
)
plt.gca().invert_yaxis()
plt.show()
My CSV file:
date,time,amount,category
2020-05-12,21:15,13,A
2020-05-12,21:15,2,B
2020-05-12,21:15,5,C
2020-05-12,21:15,1,D
2020-05-12,21:30,4,A
2020-05-12,21:30,2,C
2020-05-12,21:30,1,D
2020-05-12,21:45,3,B
2020-05-12,22:15,4,A
2020-05-12,22:15,2,D
2020-05-12,22:15,9,E
2020-05-12,00:15,21,D
2020-05-12,00:30,11,E
2020-05-12,04:15,7,A
2020-05-12,04:30,1,B
2020-05-12,04:30,2,C
2020-05-12,04:45,1,A
2020-05-14,21:15,1,A
2020-05-14,21:15,5,C
2020-05-14,21:15,3,D
2020-05-14,21:30,4,A
2020-05-14,21:30,1,D
2020-05-14,21:45,5,B
2020-05-14,22:15,4,A
2020-05-14,22:15,11,E
2020-05-14,00:15,2,D
2020-05-14,00:30,11,E
2020-05-14,04:15,9,A
2020-05-14,04:30,11,B
2020-05-14,04:30,5,C
2020-05-14,05:00,7,A
You can use a seaborn swarmplot for this. You first have to separate the "amount" column into separate entries, using .reindex and .repeat. Then you can plot.
Here is the code:
import matplotlib
import matplotlib.pyplot as plt
import pandas as pd
import seaborn as sns
import os
df = pd.read_csv("test.csv")
df = df.reindex(df.index.repeat(df.amount))
sns.swarmplot(data = df, x = "date", y = "time", hue = "category")
plt.gca().invert_yaxis()
plt.show()
Here is the output:
I am trying to create a heatmap with dendrograms on Python using Seaborn and I have a csv file with about 900 rows. I'm importing the file as a pandas dataframe and attempting to plot that but a large number of the rows are not being represented in the heatmap. What am I doing wrong?
This is the code I have right now. But the heatmap only represents about 49 rows.
Here is an image of the clustermap I've obtained but it is not displaying all of my data.
import seaborn as sns
import pandas as pd
from matplotlib import pyplot as plt
# Data set
df = pd.read_csv('diff_exp_gene.csv', index_col = 0)
# Default plot
sns.clustermap(df, cmap = 'RdBu', row_cluster=True, col_cluster=True)
plt.show()
Thank you.
An alternative approach would be to use imshow in matpltlib. I'm not exactly sure what your question is but I demonstrate a way to graph points on a plane from csv file
import numpy as np
import matplotlib.pyplot as plt
import csv
infile = open('diff_exp_gene.csv')
df = csv.DictReader(in_file)
temp = np.zeros((128,128), dtype = int)
for row in data:
if row['TYPE'] == types:
temp[int(row['Y'])][int(row['X'])] = temp[int(row['Y'])][int(row['X'])] + 1
plt.imshow(temp, cmap = 'hot', origin = 'lower')
plt.show()
As far as I know, keywords that apply to seaborn heatmaps also apply to clustermap, as the sns.clustermap passes to the sns.heatmap. In that case, all you need to do in your example is to set yticklabels=True as a keyword argument in sns.clustermap(). That will make all of the 900 rows appear.
By default, it is set as "auto" to avoid overlap. The same applies to the xticklabels. See more here: https://seaborn.pydata.org/generated/seaborn.heatmap.html
i want to convert that dataframe
into this dataframe and plot a matplotlib graph using date along x axis
changed dataframe
Use df.T.plot(kind='bar'):
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame.from_csv('./housing_price_index_2010-11_100.csv')
df.T.plot(kind='bar')
plt.show()
you can also assign the transpose to a new variable and plot that (what you asked in the comment):
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame.from_csv('./housing_price_index_2010-11_100.csv')
df_transposed = df.T
df_transposed.plot(kind='bar')
plt.show()
both result the same: