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How to make an URL 'clickable' in Excel with Python? [duplicate]

I am using win32com to modify an Excel spreadsheet (Both read and edit at the same time) I know there are other modules out there that can do one or the other but for the application I am doing I need it read and processed at the same time.
The final step is to create some hyperlinks off of a path name. Here is an Example of what I have so far:
import win32com.client
excel = r'I:\Custom_Scripts\Personal\Hyperlinks\HyperlinkTest.xlsx'
xlApp = win32com.client.Dispatch("Excel.Application")
workbook = xlApp.Workbooks.Open(excel)
worksheet = workbook.Worksheets("Sheet1")
for xlRow in xrange(1, 10, 1):
a = worksheet.Range("A%s"%(xlRow)).Value
if a == None:
break
print a
workbook.Close()
I found some code for reading Hyperlinks using win32com:
sheet.Range("A8").Hyperlinks.Item(1).Address
but not how to set hyperlinks
Can someone assist me?

Borrowing heavily from this question, as I couldn't find anything on SO to link to as a duplicate...
This code will create a Hyperlink in cells A1:A9
import win32com.client
excel = r'I:\Custom_Scripts\Personal\Hyperlinks\HyperlinkTest.xlsx'
xlApp = win32com.client.Dispatch("Excel.Application")
workbook = xlApp.Workbooks.Open(excel)
worksheet = workbook.Worksheets("Sheet1")
for xlRow in xrange(1, 10, 1):
worksheet.Hyperlinks.Add(Anchor = worksheet.Range('A{}'.format(xlRow)),
Address="http://www.microsoft.com",
ScreenTip="Microsoft Web Site",
TextToDisplay="Microsoft")
workbook.Save()
workbook.Close()
And here is a link to the Microsoft Documentation for the Hyperlinks.Add() method.

Retrieve Excel Workbook Connection Properties

I am attempting to grab the "Command Text" from the Connection Property window in an Excel file using python. However, I cannot find the object that contains this information. In the below picture I would like to retrieve the highlighted EXEC sp_FooBar as a string:
I am able to retrieve the Connection names with:
import odbc
import win32com.client
file = r'PATH_TO_FILE'
xl = win32com.client.DispatchEx('Excel.Application')
wb = xl.workbooks.open(file)
for x in wb.connections:
print(x)
But I'm not sure how to use the <COMObject <unknown>> object further to grab the command text. I'm thinking win32com may have something, but can't seem to crack the code.

You can get the CommandText property from a OLEDBConnectioninstance like this:
import odbc
import win32com.client
file = r'PATH_TO_FILE'
xl = win32com.client.DispatchEx('Excel.Application')
wb = xl.workbooks.open(file)
for x in wb.Connections:
print(x.OLEDBConnection.CommandText)
xl.Application.Quit()

Accessing UpdateLinks() in COM Object using Python

I am working on automating an Excel file which is linked to certain .csv files.
Those .csv files are created from a SAS Code which is run every Quarter.
The files created are timestamped accordingly for example XYZ_201603.csv and XYZ_201606.csv and so on.
I need to update the links on my Excel File so that it automatically changes the link to the file from next quarter. I am trying to do this using Python win32com.client and my code looks like
from win32com import Dispatch
xl_app = Dispatch("Excel.Application")
xl_app.Visible = True
xl_app.DisplayAlerts = False
wb = xl_app.workbooks.open(r"C:\Users\XYZ\Desktop\Test\Summary.xlsx")
xl_app.AskToUpdateLinks = False
try:
wb.UpdateLink(Name=r"C:\Users\XYZ\Desktop\Test\XYZ_201606.csv")
except Exception as e:
print(e)
finally:
wb.Close(True)
wb = None
return True
xl_app.Quit()
xl = None
Whenever I run this, I get the following error
(-2147352567,'Exception occured.',(0,'Microsoft Excel','UpdateLink method of
Workbook class failed','xlmain11.chm',0,-2146827284),None)
Can Somebody tell me what is going wrong here. Also, incase I have multiple links, how do I tell which link needs to be changed to what? Can I pass a dictionary of directories of updated datasets
The code and the approach has been taken from this answer on Stack Overflow
Update Links in for Excel Spreadsheet Using Python

If you review the Microsoft Documentation, it seems that the UpdateLink method can be called without any parameters. Therefore this program should work:
import win32com.client as win32
xl_app = win32.gencache.EnsureDispatch("Excel.Application")
xl_app.Visible = True
xl_app.DisplayAlerts = False
wb = xl_app.workbooks.open(r"C:\Users\XYZ\Desktop\Test\Summary.xlsx")
wb.UpdateLink()
wb.Save()
wb.Close()
xl_app.Quit()

I'm not sure if my solution solves your issue, but I had the same problem and I used LinkSources() and ChangeLink() instead
newSource = r"C:\Users\XYZ\Desktop\Test\XYZ_201606.csv"
oldSource = wb.LinkSources()
wb.ChangeLink(Name = oldSource[0], NewName = newSource, Type = 1)
Hope it helps!

Release excel workbook after write operations through a script

I am using a python script to write data into the excel workbook. Now, I want to release the pointer. I dont want to close the workbook because of some other reasons. I just want to release the pointer. I searched on google but no answer. Can anyone please help?
from win32com.client import Dispatch
xl = Dispatch('Excel.Application')
xl.ScreenUpdating = True # performance
xl.Visible = 1
xl.DisplayAlerts = True
wbs = xl.Workbooks
return xl, wbs
Then i am using wb to refer to workbook's different sheets.
wb = xl.Workbooks.open(filename)

Variables will be released as they go out of scope. In the example below, the variable xl is released when the get_workbook function is exited. If you need to explicitly remove a variable, use the del statement.
from win32com.client import Dispatch
def get_workbook(path):
xl = Dispatch('Excel.Application')
xl.Visible = 1
return xl.Workbooks.open(path)
wb = get_workbook(r'c:\temp\test.xlsx')
sheet = wb.Worksheets.Item(1)
sheet.Range('A1').Value2 = 'test'
del wb, sheet

how to output xlsx generated by Openpyxl to browser?

I was using stackoverflow for a while now and it helped me very often. Now I have a problem I couldn't solve myself or through searching.
I'm trying to output my excel file generated by openpyxl in browser as I was doing it with phpexcel. The method appears to be the same, but I only get broken file. My code looks like this:
from openpyxl.workbook import Workbook
from openpyxl.writer.excel import ExcelWriter
from openpyxl.writer.excel import save_virtual_workbook
from openpyxl.cell import get_column_letter
from StringIO import StringIO
print 'Content-Type: application/vnd.openxmlformats-officedocument.spreadsheetml.sheet'
print 'Content-Disposition: attachment;filename="results.xlsx"'
print 'Cache-Control: max-age=0\n'
output = StringIO()
wb = Workbook()
ws = wb.worksheets[0]
ws.cell('A1').value = 3.14
wb.save(output)
print output.getvalue()
#print save_virtual_workbook(wb)
I use the version 1.5.8 and python 2.7.
None of the approaches works. When I just use it from desktop and not browser it works flawlessly.
I would be very thankful for help.
P.S. please don't tell me that using other language or program would be easier. I need to solve this with python.

this is work for me. I use python 2.7 and latest openpyxl and send_file from flask
... code ...
import StringIO
from openpyxl import Workbook
wb = Workbook()
ws = wb.active # worksheet
ws.title = "Excel Using Openpyxl"
c = ws.cell(row=5, column=5)
c.value = "Hi on 5,5"
out = StringIO.StringIO()
wb.save(out)
out.seek(0)
return send_file(out, mimetype='application/vnd.openxmlformats-officedocument.spreadsheetml.sheet',
attachment_filename='xxl.xlsx', as_attachment=True)

output = HttpResponse(mimetype='application/application/vnd.openxmlformats-officedocument.spreadsheetml.sheet')
file_name = "Test.xlsx"
output['Content-Disposition'] = 'attachment; filename='+ file_name
wb = Workbook()
ws = wb.worksheets[0]
ws.cell('A1').value = 3.14
wb.save(output)
return output
I used this tips to download my files with openpyxl. Hope that will help

Writing the xlsx output to disk and then serving it up via Apache worked perfectly, but putting it out directly caused errors in Excel and other issues.
I added a couple of extra steps and made one minor change to your code:
buffer=output.getvalue()
In the HTTP headers:
print "Content-Length: " + str(len(buffer))
And used write() instead of print() to push the buffer into the standard output stream:
stdout.write(buffer)

Your scripts works for me as you expect without alterations.
I can only assume you have a problem with your cgi script setup.
Make sure you have the directory where the script lives actually gets served by the web server. On apache you can achieve this with:
ScriptAlias /cgi-bin/ /home/WWW/localhost/cgi-bin/
Make sure the script is excutable by setting the script permissions. For commandline operation (python scriptname) that was not necessary, for your webbrowser that is. And make sure the owner of the webserver can excute the scripts, as the webserver probably does not run as you.

Because Excel uses a binary format you should be using BytesIO to buffer.
from io import BytesIO
But what error are you getting if you use save_virtual_workbook() which does this for you?

I have same problem.
Solution is to switch stdout to bin mode:
import msvcrt
print 'Content-Type:application/octet-stream; name="{}"'.format(os.path.basename(xls_file))
print 'Content-Disposition:attachment; filename="{}"'.format(os.path.basename(xls_file))
print "Content-Length: " + str(os.path.getsize(xls_file))
print 'Cache-Control: max-age=0\r\n'
msvcrt.setmode (1, os.O_BINARY) # stdout = 1
sys.stdout.flush()
with open(xls_file, 'rb') as fobj:
copyfileobj(fobj, sys.stdout)

If you want to build an HTML table that looks like your spreadsheet, you probably want to work with CSV. Either do this, instead of Excel, OR convert your Excel to CSV after you build it.
In any case, once you have the data in CSV format, then it's simply a matter of using python to build the HTML page and looping through the CSV data, while inserting your <table>, <tr>, and <td> tags, as appropriate.