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Check AngularJS checkbox with Selenium

HTML Source here
It seems trivial, but after hours of attempts I cannot manage to check this checkbox using Selenium. I am able to select the element no problem, and have even been able to 'highlight' (see code snippet below) it by sending Keys.RETURN to the element, but on attempting to click it, nothing happens. Perhaps someone has an idea?
What I have tried already:
Using with WebDriverWait
Using multiple and different combinations of .click()/.send_keys(Keys.RETURN)
Just about every combination of XPATH/css selector/id/name/classname/text that Selenium would accept for the element, and all of its children and most of its parents (including spans/labels, and the text inside the label itself).
Directly clicking the element/label coordinates using actions (nothing happens, even when I can 100% confirm it is clicking the right spot by using context_click()).
Using execute_script to change the "checked" attribute to True (the checkbox appears checked, but it is clear it is only client side as a box that is supposed to render when it is actually clicked doesn't).
Using execute_script to change the class to 'ng-valid ng-not-empty ng-dirty ng-valid-parse ng-touched'
Here is the code that I feel got me the closest (it is 'highlighting' the box as seen here)
browser.find_element(By.ID, "sp_formfield_none_of_the_above").send_keys(Keys.RETURN)

Managed to solve it after another while of testing. Hopefully this helps someone in the future. I had to use JS to execute .click() on the checkbox element. In retrospect, I should have tried this solution sooner. See code snippet:
cb_none = browser.find_element(By.ID, 'sp_formfield_none_of_the_above')
browser.execute_script("arguments[0].click();", cb_none)

Finding XPath without using inspecting element?

I am making an automation for download data from a weather institution.
The issue is that in my effort to make it more independent I am trying to make Selenium to Tab keys to a certain spot, so the Browser focus can "Walk" to the download button. When I call the click() function it doesn't do anything. So I tried to Extract the XPath with the function get_attribute("xpath") but it returns None. How I can extract the XPath?
I am going to paste the issue down here:
Bandera=driver.find_element_by_xpath('/html/body/div[2]/div[2]/div/div[3]/div/div/div/div[1]/div/div/div[2]/div/table/tbody/tr[1]/td[1]/div/input')
Bandera.click()
Bandera.click()
## So Here i just select and dis-select a checkbox just to be near the Download button.
actions = ActionChains(driver)
actions.send_keys(Keys.TAB * 1 )
actions.perform()
#Here i just tabed to the button
Accion=driver.switch_to.active_element
#Maybe, here is when i lost the focus of the button?
Descarga_Actual=Accion.get_attribute("xpath")
Thank you and sorry to borrow your time.

To make a click on hover I would use the following sequence:
your_dropdown_locator.click()
dropdown_option = driver.find_element_by_xpath("dropdown option locator")
actions = ActionChains(driver)
actions.move_to_element(dropdown_option)
actions.click().perform()
But, this is the approach that is usually used for dropdowns.
You use: driver.find_element_by_xpath('/html/body/div[2]/div[2]/div/div[3]/div/div/div/div[1]/div/div/div[2]/div/table/tbody/tr[1]/td[1]/div/input') This is the main problem of your code.
If you pasted html code of this dropdown (or button you need to click), people would help you to find a better locator. XPath/CSS must be unique. In your case the locator is very bad.
Also, I see no sense making Bandera.click() two times.
In your case, as I understand, you just need to click the button. So the locator is your main problem.
You need to find the correct locator, to wait till the button is clickable and then to click it.
Another problem in what you are trying to do:
get_attribute("xpath") looks like incorrect expectation of how get_attribute function works. Check at least here what this function means Python Selenium: Find object attributes using xpath

Selenium Python: Census ACS Data- unable to select Download button in window

I am attempting to scrape the Census website for ACS data. I have scripted the whole processes using Selenium except the very last click. I am using Python. I need to click a download button that is in a window that pops when the data is zipped and ready, but I can't seem to identify this button. It also seems that the button might change names based on when it was last run, for example, yui-gen2, yui-gen3, etc so I am thinking I might need to account for this someone. Although I normally only see yui-gen2.
Also, the tag seems to be in a "span" which might be adding to my difficulty honing in on the button I need to click.
Please help if you can shed any light on this for me.
code snippet:
#Refine search results to get tables
driver.find_element_by_id("prodautocomplete").send_keys("S0101")
time.sleep(2)
driver.find_element_by_id("prodsubmit").click()
driver.implicitly_wait(100)
time.sleep(2)
driver.find_element_by_id("check_all_btn_above").click()
driver.implicitly_wait(100)
time.sleep(2)
driver.find_element_by_id("dnld_btn_above").click()
driver.implicitly_wait(100)
driver.find_element_by_id("yui-gen0-button").click()
time.sleep(10)
driver.implicitly_wait(100)
driver.find_element_by_id("yui-gen2-button").click()
enter image description here
enter image description here

Instead of using the element id, which as you pointed out varies, you can use XPath as Nogoseke mentioned or CSS Selector. Be careful to not make the XPath/selector too specific or reliant on changing values, in this case the element id. Rather than using the id in XPath, try expressing the XPath in terms of the DOM structure (tags):
//*/div/div/div/span/span/span/button[contains(text(),'Download')]
TIL you can validate your XPath by using the search function, rather than by running it in Selenium. I right-clicked the webpage, "inspect element", ctrl+f, and typed in the above XPath to validate that it is the Download button.
For posterity, if the above XPath is too specific, i.e. it is reliant on too many levels of the DOM structure, you can do something shorter, like
//*button[contains(text(),'Download')]
although, this may not be specific enough and may require an additional field, since there may be multiple buttons on the page with the 'Download' text.

Given the HTML you provided, you should be able to use
driver.find_element_by_id("yui-gen2-button")
I know you said you tried it but you didn't say if it works at all or what error message you are getting. If that never works, you likely have an IFRAME that you need to switch to.
If it works sometimes but not consistently due to changing ID, you can use something like
driver.find_element_by_xpath("//button[.='Download']")

On the code inspection view on Chrome you can right click on the item you want to find and copy the xpath. You can they find your element by xpath on Selenium.

How to click on an element based on its coordinates with selenium webdriver

So, the web app we're developing has a TV/PC mode, and i'm testing the ability to transit between these two modes. `
def pc_to_tv(self):
pc_to_tv = self.driver.find_element_by_xpath(
'html/body/div[1]/div/topbar/header/div[2]/div[2]/div[1]/button[1]')
pc_to_tv.click()
def tv_to_pc(self):
tv_to_pc = self.driver.find_element_by_xpath(
'html/body/div[1]/div/topbar/header/div[2]/div[2]/div[1]/button[2]')
tv_to_pc.click()`
The problem is, when i switch from pc to tv, the screen "zooms in", making the button appear in the same place it would be without the zoom. so, i can't click on the button with my 'tv_to_pc' method, 'cause instead on clicking on the actual button, it clicks where the button should be.
So, the solution i found was clicking on the button with coordinates, that way i'll actually click on the place i want, instead of clicking on an unclickable place like i was doing.
The thing is, i don't know how to do this, and need help on this matter.

I would suggest that you just click the button using JavaScriptExecutor. It will click it no matter where it is on the page. See How to execute a javascript in a Python webdriver and other questions for more info. The general format is
element = driver.find_element_by_id("someId")
driver.execute_script("arguments[0].click();", element)
Also... you don't want to use XPaths like that. Any XPath that starts at the HTML tag or is more than just a few levels deep is going to be very brittle. Do some googling on selenium xpaths and read some guides for more info.

try moveToElement and then perform click
((JavascriptExecutor) driver).executeScript("arguments[0].scrollIntoView(true);", element);
new Actions(driver).moveToElement(element, x, y).click().perform();
x is xoffset
y is yoffset
Please see that if you use Javascript for click its not going to be native click.

Python with Seleneium Webdriver, reading a button and saving its text

so Ive been using selenium webdriver in Python3 right now, so far its working great and I can do most the things Id like, one thing though, on instagram, the xpath for the follow or following button is the same, Id assume it is for all web pages with buttons in the same place, but if the text and color are different when its follow vs following, is there a way to let python discern that?
Id like to write sort of like an if follow: do this, elif following: do this
the xpath for the button is this:
/html/body/span/section/main/article/header/div[2]/div[1]/span[2]/button
in html the text is different and all but I dont know how to make this work, if any of you have any advice thatd be great!

To "find" Following button you should use next xpath:
//button[#class="_jvpff _k2yal _988x3 _i46jh _nv5lf"]'
while for the Follow:
//button[#class="_jvpff _k2yal _csba8 _i46jh _nv5lf"]
Text of a button could be defined like this:
follow = driver._find_element_by_xpath('//button[#class="_jvpff _k2yal _csba8 _i46jh _nv5lf"]').text