convert python objects to string - python

I have different python classes and I want to convert instances of these classes to ascii strings.Suppose that I have the following objects:
class A:
name = "A"
field = 2
x = "a"
class B:
name = "b"
item = "c"
a = A()
b = B()
I want a function like serialize() which converts the objects as follows:
serialize(a) # results "A2a"
serialize(b) # results "bc"
I don't want to write a serialization function for every classe, I want to have a function capable of serializing all classes. One way is to use the dir() function to get a list of object attributes and then create a string out of them, but the dir() function does not return the attributes in the same order that they are defined. For example calling dir(a) would return ['__doc__', '__module__', 'filed', 'name', 'x'], and I cannot find out which attribute is defined first in the class.
Thanks.

You can override __repr__ function for print Object the desired way:
class A:
name = "A"
field = 2
x = "a"
def __repr__(self):
return A.name + str(A.field) + A.x

You have to create methods in your classes:
ON behalf to put the value in the class the best can be to pass argument of class A during the call%
class A:
def __init__(self, name, field, x) :
self.name = name
self.field = field
self.x = x
def serialize(self) :
return f"{self.name}{self.field}{self.x}"
#main:
a=A(name="a", field="field", x="x")
result=a.serialize()
print(result)

Related

How do I iterate over a list and print all attributes in a list [duplicate]

When I try to print an instance of a class, I get an output like this:
>>> class Test():
... def __init__(self):
... self.a = 'foo'
...
>>> print(Test())
<__main__.Test object at 0x7fc9a9e36d60>
How can I make it so that the print will show something custom (e.g. something that includes the a attribute value)? That is, how can I can define how the instances of the class will appear when printed (their string representation)?
See How can I choose a custom string representation for a class itself (not instances of the class)? if you want to define the behaviour for the class itself (in this case, so that print(Test) shows something custom, rather than <class __main__.Test> or similar). (In fact, the technique is essentially the same, but trickier to apply.)
>>> class Test:
... def __repr__(self):
... return "Test()"
... def __str__(self):
... return "member of Test"
...
>>> t = Test()
>>> t
Test()
>>> print(t)
member of Test
The __str__ method is what gets called happens when you print it, and the __repr__ method is what happens when you use the repr() function (or when you look at it with the interactive prompt).
If no __str__ method is given, Python will print the result of __repr__ instead. If you define __str__ but not __repr__, Python will use what you see above as the __repr__, but still use __str__ for printing.
As Chris Lutz explains, this is defined by the __repr__ method in your class.
From the documentation of repr():
For many types, this function makes an attempt to return a string that would yield an object with the same value when passed to eval(), otherwise the representation is a string enclosed in angle brackets that contains the name of the type of the object together with additional information often including the name and address of the object. A class can control what this function returns for its instances by defining a __repr__() method.
Given the following class Test:
class Test:
def __init__(self, a, b):
self.a = a
self.b = b
def __repr__(self):
return f"<Test a:{self.a} b:{self.b}>"
def __str__(self):
return f"From str method of Test: a is {self.a}, b is {self.b}"
..it will act the following way in the Python shell:
>>> t = Test(123, 456)
>>> t
<Test a:123 b:456>
>>> print(repr(t))
<Test a:123 b:456>
>>> print(t)
From str method of Test: a is 123, b is 456
>>> print(str(t))
From str method of Test: a is 123, b is 456
If no __str__ method is defined, print(t) (or print(str(t))) will use the result of __repr__ instead
If no __repr__ method is defined then the default is used, which is roughly equivalent to:
def __repr__(self):
cls = self.__class__
return f"<{cls.__module_}.{cls.__qualname__} object at {id(self)}>"
If you're in a situation like #Keith you could try:
print(a.__dict__)
It goes against what I would consider good style but if you're just trying to debug then it should do what you want.
A generic way that can be applied to any class without specific formatting could be done as follows:
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return str(self.__class__) + ": " + str(self.__dict__)
And then,
elem = Element('my_name', 'some_symbol', 3)
print(elem)
produces
__main__.Element: {'symbol': 'some_symbol', 'name': 'my_name', 'number': 3}
A prettier version of response by #user394430
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return str(self.__class__) + '\n'+ '\n'.join(('{} = {}'.format(item, self.__dict__[item]) for item in self.__dict__))
elem = Element('my_name', 'some_symbol', 3)
print(elem)
Produces visually nice list of the names and values.
<class '__main__.Element'>
name = my_name
symbol = some_symbol
number = 3
An even fancier version (thanks Ruud) sorts the items:
def __str__(self):
return str(self.__class__) + '\n' + '\n'.join((str(item) + ' = ' + str(self.__dict__[item]) for item in sorted(self.__dict__)))
Simple. In the print, do:
print(foobar.__dict__)
as long as the constructor is
__init__
For Python 3:
If the specific format isn't important (e.g. for debugging) just inherit from the Printable class below. No need to write code for every object.
Inspired by this answer
class Printable:
def __repr__(self):
from pprint import pformat
return "<" + type(self).__name__ + "> " + pformat(vars(self), indent=4, width=1)
# Example Usage
class MyClass(Printable):
pass
my_obj = MyClass()
my_obj.msg = "Hello"
my_obj.number = "46"
print(my_obj)
Just to add my two cents to #dbr's answer, following is an example of how to implement this sentence from the official documentation he's cited:
"[...] to return a string that would yield an object with the same value when passed to eval(), [...]"
Given this class definition:
class Test(object):
def __init__(self, a, b):
self._a = a
self._b = b
def __str__(self):
return "An instance of class Test with state: a=%s b=%s" % (self._a, self._b)
def __repr__(self):
return 'Test("%s","%s")' % (self._a, self._b)
Now, is easy to serialize instance of Test class:
x = Test('hello', 'world')
print 'Human readable: ', str(x)
print 'Object representation: ', repr(x)
print
y = eval(repr(x))
print 'Human readable: ', str(y)
print 'Object representation: ', repr(y)
print
So, running last piece of code, we'll get:
Human readable: An instance of class Test with state: a=hello b=world
Object representation: Test("hello","world")
Human readable: An instance of class Test with state: a=hello b=world
Object representation: Test("hello","world")
But, as I said in my last comment: more info is just here!
You need to use __repr__. This is a standard function like __init__.
For example:
class Foobar():
"""This will create Foobar type object."""
def __init__(self):
print "Foobar object is created."
def __repr__(self):
return "Type what do you want to see here."
a = Foobar()
print a
__repr__ and __str__ are already mentioned in many answers. I just want to add that if you are too lazy to add these magic functions to your class, you can use objprint. A simple decorator #add_objprint will help you add the __str__ method to your class and you can use print for the instance. Of course if you like, you can also use objprint function from the library to print any arbitrary objects in human readable format.
from objprint import add_objprint
class Position:
def __init__(self, x, y):
self.x = x
self.y = y
#add_objprint
class Player:
def __init__(self):
self.name = "Alice"
self.age = 18
self.items = ["axe", "armor"]
self.coins = {"gold": 1, "silver": 33, "bronze": 57}
self.position = Position(3, 5)
print(Player())
The output is like
<Player
.name = 'Alice',
.age = 18,
.items = ['axe', 'armor'],
.coins = {'gold': 1, 'silver': 33, 'bronze': 57},
.position = <Position
.x = 3,
.y = 5
>
>
There are already a lot of answers in this thread but none of them particularly helped me, I had to work it out myself, so I hope this one is a little more informative.
You just have to make sure you have parentheses at the end of your class, e.g:
print(class())
Here's an example of code from a project I was working on:
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return "{}: {}\nAtomic Number: {}\n".format(self.name, self.symbol, self.number
class Hydrogen(Element):
def __init__(self):
super().__init__(name = "Hydrogen", symbol = "H", number = "1")
To print my Hydrogen class, I used the following:
print(Hydrogen())
Please note, this will not work without the parentheses at the end of Hydrogen. They are necessary.
Hope this helps, let me know if you have anymore questions.
Even though this is an older post, there is also a very convenient method introduced in dataclasses (as of Python 3.7). Besides other special functions such as __eq__ and __hash__, it provides a __repr__ function for class attributes. You example would then be:
from dataclasses import dataclass, field
#dataclass
class Test:
a: str = field(default="foo")
b: str = field(default="bar")
t = Test()
print(t)
# prints Test(a='foo', b='bar')
If you want to hide a certain attribute from being outputted, you can set the field decorator parameter repr to False:
#dataclass
class Test:
a: str = field(default="foo")
b: str = field(default="bar", repr=False)
t = Test()
print(t)
# prints Test(a='foo')

Python bind method to another instance

I need to merge two methods from different instances of different classes to a single instance of a class.
For example I define two classes:
class A:
def __init__(self):
self.name = "a"
def print_name(self):
print(self.name)
class B:
def __init__(self):
self.name = "b"
def print_name(self):
print(self.name)
and then I will try to make another object c and its print_name method must return the results of a.print_name() and b.print_name() so I tried the following :
a = A()
b = B()
c = A()
c.name = "c"
c.print_name_1 = a.print_name
c.print_name_2 = b.print_name
def final_print(self):
self.print_name_1()
self.print_name_2()
c.print_name = MethodType(final_print, c)
c.print_name()
Expected output:
c
c
but I get :
a
b
I tried to use types.MethodType as described here but it creates some kind of a method which takes two arguments : the first one will be the 'a' instance and the second one will be the 'c' instance.
Any help to do that properly?
I managed to succeed with this, thanks to this answer. I am using the __func__ attribute of a method. So here is the code :
c.name = "c"
c.print_name_1 = MethodType(lambda instance: copy.deepcopy(a.print_name).__func__(instance), c)
c.print_name_2 = MethodType(lambda instance: copy.deepcopy(b.print_name).__func__(instance), c)
def final_print(self):
self.print_name_1()
self.print_name_2()
c.print_name = MethodType(final_print, c)
c.print_name()

How do I find which row column is failing to be mapped? [duplicate]

When I try to print an instance of a class, I get an output like this:
>>> class Test():
... def __init__(self):
... self.a = 'foo'
...
>>> print(Test())
<__main__.Test object at 0x7fc9a9e36d60>
How can I make it so that the print will show something custom (e.g. something that includes the a attribute value)? That is, how can I can define how the instances of the class will appear when printed (their string representation)?
See How can I choose a custom string representation for a class itself (not instances of the class)? if you want to define the behaviour for the class itself (in this case, so that print(Test) shows something custom, rather than <class __main__.Test> or similar). (In fact, the technique is essentially the same, but trickier to apply.)
>>> class Test:
... def __repr__(self):
... return "Test()"
... def __str__(self):
... return "member of Test"
...
>>> t = Test()
>>> t
Test()
>>> print(t)
member of Test
The __str__ method is what gets called happens when you print it, and the __repr__ method is what happens when you use the repr() function (or when you look at it with the interactive prompt).
If no __str__ method is given, Python will print the result of __repr__ instead. If you define __str__ but not __repr__, Python will use what you see above as the __repr__, but still use __str__ for printing.
As Chris Lutz explains, this is defined by the __repr__ method in your class.
From the documentation of repr():
For many types, this function makes an attempt to return a string that would yield an object with the same value when passed to eval(), otherwise the representation is a string enclosed in angle brackets that contains the name of the type of the object together with additional information often including the name and address of the object. A class can control what this function returns for its instances by defining a __repr__() method.
Given the following class Test:
class Test:
def __init__(self, a, b):
self.a = a
self.b = b
def __repr__(self):
return f"<Test a:{self.a} b:{self.b}>"
def __str__(self):
return f"From str method of Test: a is {self.a}, b is {self.b}"
..it will act the following way in the Python shell:
>>> t = Test(123, 456)
>>> t
<Test a:123 b:456>
>>> print(repr(t))
<Test a:123 b:456>
>>> print(t)
From str method of Test: a is 123, b is 456
>>> print(str(t))
From str method of Test: a is 123, b is 456
If no __str__ method is defined, print(t) (or print(str(t))) will use the result of __repr__ instead
If no __repr__ method is defined then the default is used, which is roughly equivalent to:
def __repr__(self):
cls = self.__class__
return f"<{cls.__module_}.{cls.__qualname__} object at {id(self)}>"
If you're in a situation like #Keith you could try:
print(a.__dict__)
It goes against what I would consider good style but if you're just trying to debug then it should do what you want.
A generic way that can be applied to any class without specific formatting could be done as follows:
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return str(self.__class__) + ": " + str(self.__dict__)
And then,
elem = Element('my_name', 'some_symbol', 3)
print(elem)
produces
__main__.Element: {'symbol': 'some_symbol', 'name': 'my_name', 'number': 3}
A prettier version of response by #user394430
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return str(self.__class__) + '\n'+ '\n'.join(('{} = {}'.format(item, self.__dict__[item]) for item in self.__dict__))
elem = Element('my_name', 'some_symbol', 3)
print(elem)
Produces visually nice list of the names and values.
<class '__main__.Element'>
name = my_name
symbol = some_symbol
number = 3
An even fancier version (thanks Ruud) sorts the items:
def __str__(self):
return str(self.__class__) + '\n' + '\n'.join((str(item) + ' = ' + str(self.__dict__[item]) for item in sorted(self.__dict__)))
Simple. In the print, do:
print(foobar.__dict__)
as long as the constructor is
__init__
For Python 3:
If the specific format isn't important (e.g. for debugging) just inherit from the Printable class below. No need to write code for every object.
Inspired by this answer
class Printable:
def __repr__(self):
from pprint import pformat
return "<" + type(self).__name__ + "> " + pformat(vars(self), indent=4, width=1)
# Example Usage
class MyClass(Printable):
pass
my_obj = MyClass()
my_obj.msg = "Hello"
my_obj.number = "46"
print(my_obj)
Just to add my two cents to #dbr's answer, following is an example of how to implement this sentence from the official documentation he's cited:
"[...] to return a string that would yield an object with the same value when passed to eval(), [...]"
Given this class definition:
class Test(object):
def __init__(self, a, b):
self._a = a
self._b = b
def __str__(self):
return "An instance of class Test with state: a=%s b=%s" % (self._a, self._b)
def __repr__(self):
return 'Test("%s","%s")' % (self._a, self._b)
Now, is easy to serialize instance of Test class:
x = Test('hello', 'world')
print 'Human readable: ', str(x)
print 'Object representation: ', repr(x)
print
y = eval(repr(x))
print 'Human readable: ', str(y)
print 'Object representation: ', repr(y)
print
So, running last piece of code, we'll get:
Human readable: An instance of class Test with state: a=hello b=world
Object representation: Test("hello","world")
Human readable: An instance of class Test with state: a=hello b=world
Object representation: Test("hello","world")
But, as I said in my last comment: more info is just here!
You need to use __repr__. This is a standard function like __init__.
For example:
class Foobar():
"""This will create Foobar type object."""
def __init__(self):
print "Foobar object is created."
def __repr__(self):
return "Type what do you want to see here."
a = Foobar()
print a
__repr__ and __str__ are already mentioned in many answers. I just want to add that if you are too lazy to add these magic functions to your class, you can use objprint. A simple decorator #add_objprint will help you add the __str__ method to your class and you can use print for the instance. Of course if you like, you can also use objprint function from the library to print any arbitrary objects in human readable format.
from objprint import add_objprint
class Position:
def __init__(self, x, y):
self.x = x
self.y = y
#add_objprint
class Player:
def __init__(self):
self.name = "Alice"
self.age = 18
self.items = ["axe", "armor"]
self.coins = {"gold": 1, "silver": 33, "bronze": 57}
self.position = Position(3, 5)
print(Player())
The output is like
<Player
.name = 'Alice',
.age = 18,
.items = ['axe', 'armor'],
.coins = {'gold': 1, 'silver': 33, 'bronze': 57},
.position = <Position
.x = 3,
.y = 5
>
>
There are already a lot of answers in this thread but none of them particularly helped me, I had to work it out myself, so I hope this one is a little more informative.
You just have to make sure you have parentheses at the end of your class, e.g:
print(class())
Here's an example of code from a project I was working on:
class Element:
def __init__(self, name, symbol, number):
self.name = name
self.symbol = symbol
self.number = number
def __str__(self):
return "{}: {}\nAtomic Number: {}\n".format(self.name, self.symbol, self.number
class Hydrogen(Element):
def __init__(self):
super().__init__(name = "Hydrogen", symbol = "H", number = "1")
To print my Hydrogen class, I used the following:
print(Hydrogen())
Please note, this will not work without the parentheses at the end of Hydrogen. They are necessary.
Hope this helps, let me know if you have anymore questions.
Even though this is an older post, there is also a very convenient method introduced in dataclasses (as of Python 3.7). Besides other special functions such as __eq__ and __hash__, it provides a __repr__ function for class attributes. You example would then be:
from dataclasses import dataclass, field
#dataclass
class Test:
a: str = field(default="foo")
b: str = field(default="bar")
t = Test()
print(t)
# prints Test(a='foo', b='bar')
If you want to hide a certain attribute from being outputted, you can set the field decorator parameter repr to False:
#dataclass
class Test:
a: str = field(default="foo")
b: str = field(default="bar", repr=False)
t = Test()
print(t)
# prints Test(a='foo')

How to define a class with dynamic attributes?

In my project, I need to create a class with attributes passed by a dict, something like this:
class_attributes = {"sensor": Nested(Sensor),
"serial_interface": Nested(SerialInterface)}
class MSchema(marshmallow.ModelSchema):
class Meta:
model = cls
attr = class_attributes
I need that "sensor" and "serial_interface" to be in the class, and can be access using MSchema.sensor or MSchema.serial_interface.
You can call the metaclass of ModelSchema directly, rather than defining the class declaratively using a class statement.
m = marshmallow.ModelSchema
class_attributes = {
"sensor": Nested(Sensor),
"serial_interface": Nested(SerialInterface)
}
m = marshmallow.ModelSchema
mc = type(m)
MSchema = mc('MSchema', (m,), {
'Meta': type('Meta', (), {'model': cls}),
**class_attributes
})
In case you aren't aware, a class statement is just a declarative syntax for calling type (or some other metaclass) with 3 arguments: the name of the class, a tuple of parent classes, and a dict of class attributes. The class statement evaluates its body to produce the dict, then calls type (or another given metaclass), and binds the return value to the name. Some simpler examples:
# Foo = type('Foo', (), {})
class Foo:
pass
# Foo = Bar('Foo', (), {})
class Foo(metaclass=Bar):
pass
# Foo = Bar('Foo', (Parent,), {'x': 3})
class Foo(Parent, metaclass=Bar):
x = 3
# def foo_init(self, x):
# self.x = x
# Foo = Bar('Foo', (), {'__init__': foo_init})
class Foo(metaclass=Bar):
def __init__(self, x):
self.x = x
Not entirely sure I understand the question to 100%, but have you tried using setattr()?
Example code would look like the following:
m_schema = MSchema()
for key, value in class_attributes.items():
setattr(m_schema, key, value)
setattr(object, string, value) takes an object to set attributes on, a string for the attribute name, and an arbitrary value as the attribute value.

Is it possible to define an __iter__ method for a class? [duplicate]

I have inherited a project with many large classes constituent of nothing but class objects (integers, strings, etc). I'd like to be able to check if an attribute is present without needed to define a list of attributes manually.
Is it possible to make a python class iterable itself using the standard syntax? That is, I'd like to be able to iterate over all of a class's attributes using for attr in Foo: (or even if attr in Foo) without needing to create an instance of the class first. I think I can do this by defining __iter__, but so far I haven't quite managed what I'm looking for.
I've achieved some of what I want by adding an __iter__ method like so:
class Foo:
bar = "bar"
baz = 1
#staticmethod
def __iter__():
return iter([attr for attr in dir(Foo) if attr[:2] != "__"])
However, this does not quite accomplish what I'm looking for:
>>> for x in Foo:
... print(x)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'classobj' object is not iterable
Even so, this works:
>>> for x in Foo.__iter__():
... print(x)
bar
baz
Add the __iter__ to the metaclass instead of the class itself (assuming Python 2.x):
class Foo(object):
bar = "bar"
baz = 1
class __metaclass__(type):
def __iter__(self):
for attr in dir(self):
if not attr.startswith("__"):
yield attr
For Python 3.x, use
class MetaFoo(type):
def __iter__(self):
for attr in dir(self):
if not attr.startswith("__"):
yield attr
class Foo(metaclass=MetaFoo):
bar = "bar"
baz = 1
this is how we make a class object iterable. provide the class with a iter and a next() method, then you can iterate over class attributes or their values.you can leave the next() method if you want to, or you can define next() and raise StopIteration on some condition.
e.g:
class Book(object):
def __init__(self,title,author):
self.title = title
self.author = author
def __iter__(self):
for each in self.__dict__.values():
yield each
>>> book = Book('The Mill on the Floss','George Eliot')
>>> for each in book: each
...
'George Eliot'
'The Mill on the Floss'
this class iterates over attribute value of class Book.
A class object can be made iterable by providing it with a getitem method too.
e.g:
class BenTen(object):
def __init__(self, bentenlist):
self.bentenlist = bentenlist
def __getitem__(self,index):
if index <5:
return self.bentenlist[index]
else:
raise IndexError('this is high enough')
>>> bt_obj = BenTen([x for x in range(15)])
>>>for each in bt_obj:each
...
0
1
2
3
4
now when the object of BenTen class is used in a for-in loop, getitem is called with succesively higher index value, till it raises IndexError.
You can iterate over the class's unhidden attributes with for attr in (elem for elem in dir(Foo) if elem[:2] != '__').
A less horrible way to spell that is:
def class_iter(Class):
return (elem for elem in dir(Class) if elem[:2] != '__')
then
for attr in class_iter(Foo):
pass
class MetaItetaror(type):
def __iter__(cls):
return iter(
filter(
lambda k: not k[0].startswith('__'),
cls.__dict__.iteritems()
)
)
class Klass:
__metaclass__ = MetaItetaror
iterable_attr_names = {'x', 'y', 'z'}
x = 5
y = 6
z = 7
for v in Klass:
print v
An instance of enum.Enum happens to be iterable, and while it is not a general solution, it is a reasonable option for some use cases:
from enum import Enum
class Foo(Enum):
bar = "qux"
baz = 123
>>> print(*Foo)
Foo.bar Foo.baz
names = [m.name for m in Foo]
>>> print(*names)
bar baz
values = [m.value for m in Foo]
print(*values)
>>> qux 123
As with .__dict__, the order of iteration using this Enum based approach is the same as the order of definition.
You can make class members iterable within just a single line.
Despite the easy and compact code there are two mayor features included, additionally:
Type checking allows using additional class members not to be iterated.
The technique is also working if (public) class methods are defined. The proposals above using the "__" string checking filtering method propably fail in such cases.
# How to make class members iterable in a single line within Python (O. Simon, 14.4.2022)
# Includes type checking to allow additional class members not to be iterated
class SampleVector():
def __init__(self, x, y, name):
self.x = x
self.y = y
self.name = name
def __iter__(self):
return [value for value in self.__dict__.values() if isinstance(value, int) or isinstance(value, float)].__iter__()
if __name__ == '__main__':
v = SampleVector(4, 5, "myVector")
print (f"The content of sample vector '{v.name}' is:\n")
for m in v:
print(m)
This solution is fairly close and inspired by answer 12 from Hans Ginzel and Vijay Shanker.

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