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Parsing HTML with entity ref

I am trying to parse some HTML which has as an example
<solids>
&sub2;
</solids>
The html file is read in as a string. I need to insert the HTML from a file that sub2 defines into the appropriate part of the string before then processing the whole string as XML.
I have tried HTMLParser and using its handlers with
class MyHTMLParser(HTMLParser):
def handle_entityref(self, name):
# This gets called when the entity is referenced
print "Entity reference : "+ name
print "Current Section : "+ self.get_starttag_text()
print self.getpos()
But getpos returns a line number and offset rather than position in the string. ( The insertion can be at any point in the file )
I found this link and this suggest to use lxml. I have looked at lxml but cannot see how it would solve the problem. Its scanner does not seem to have an entity handler and seems to be xml rather than html

Okay found that lxml will handle the ENTITY references for me.
Just had to setup parser with the option resolve_entities=True
parser = etree.XMLParser(resolve_entities=True)
root = etree.parse(filename, parser=parser)

Building a generic XML parser in Python?

I am a newbie and having 1 week experience writing python scripts.
I am trying to write a generic parser (Library for all my future jobs) which parses any input XML without any prior knowledge of tags.
Parse input XML.
Get the values from the XML and Set the values basing on the tags.
Use these values in the rest of the job.
I am using the "xml.etree.ElementTree" library and i am able to parse the XML in the below mentioned way.
#!/usr/bin/python
import os
import xml.etree.ElementTree as etree
import logging
logging.basicConfig(level=logging.DEBUG)
logger = logging.getLogger(__name__)
logger.info('start reading XML property file')
filename = "mood_ib_history_parameters_DEV.xml"
logger.info('getting the current location')
__currentlocation__ = os.getcwd()
__fullpath__ = os.path.join(__currentlocation__,filename)
logger.info('start parsing the XML property file')
tree = etree.parse(__fullpath__)
root = tree.getroot()
hive_db = root.find("hive_db").text
EDGE_HIVE_CONN = root.find("EDGE_HIVE_CONN").text
target_dir = root.find("target_dir").text
to_email_alias = root.find("to_email_alias").text
to_email_cc = root.find("to_email_cc").text
from_email_alias = root.find("from_email_alias").text
dburl = root.find("dburl").text
SQOOP_EDGE_CONN = root.find("SQOOP_EDGE_CONN").text
user_name = root.find("user_name").text
password = root.find("password").text
IB_log_table = root.find("IB_log_table").text
SR_DG_master_table = root.find("SR_DG_master_table").text
SR_DG_table = root.find("SR_DG_table").text
logger.info('Hive DB %s', hive_db)
logger.info('Hive DB %s', hive_db)
logger.info('Edge Hive Connection %s', EDGE_HIVE_CONN)
logger.info('Target Directory %s', target_dir)
logger.info('To Email address %s', to_email_alias)
logger.info('CC Email address %s', to_email_cc)
logger.info('From Email address %s', from_email_alias)
logger.info('DB URL %s',dburl)
logger.info('Sqoop Edge node connection %s',SQOOP_EDGE_CONN)
logger.info('Log table name %s',IB_log_table)
logger.info('Master table name %s',SR_DG_master_table)
logger.info('Data governance table name %s',SR_DG_table)
Now the question is if i want to parse an XML without any knowledge of the tags and elements and use the values how do i do it. I have gone through multiple tutorials but all of them help me with parsing the XML by using the tags like below
SQOOP_EDGE_CONN = root.find("SQOOP_EDGE_CONN").text
Can anybody point me to a right tutorial or library or a code snippet to parse the XML dynamically.

I think official documentation is pretty clear and contains some examples: https://docs.python.org/3/library/xml.etree.elementtree.html
The main part you need to implement is loop over the child nodes (potentially recursively):
for child in root:
# child.tag contains the tag name, child.attrib contains the attributes
print(child.tag, child.attrib)

Well parsing is easy as that - etree.parse(path)
Once you've got the root in hand using tree.getroot() you can just iterate over the tree using Python's "in":
for child_node in tree.getroot():
print child_node.text
Then, to see tags these child_nodes have, you do the same trick.
This lets you go over all tags in the XML without having to know the tag names at all.

Error validating/parsing xml file against xsd with lxml/objectify in Python

in Python/Django, I need to parse and objectify a file .xml according to a given XMLSchema made of three .xsd files referring each other in such a way:
schema3.xsd (referring schema1.xsd)
schema2.xsd (referring schema1.xsd)
schema1.xsd (referring schema2.xsd)
xml schemas import
For this I'm using the following piece of code which I've already tested being succesfull when used with a couple of xml/xsd files (where .xsd is "standalone" without refering others .xsd):
import lxml
import os.path
from lxml import etree, objectify
from lxml.etree import XMLSyntaxError
def xml_validator(request):
# define path of files
path_file_xml = '../myxmlfile.xml'
path_file_xsd = '../schema3.xsd'
# get file XML
xml_file = open(path_file_xml, 'r')
xml_string = xml_file.read()
xml_file.close()
# get XML Schema
doc = etree.parse(path_file_xsd)
schema = etree.XMLSchema(doc)
#define parser
parser = objectify.makeparser(schema=schema)
# trasform XML file
root = objectify.fromstring(xml_string, parser)
test1 = root.tag
return render(request, 'risultati.html', {'risultato': test1})
Unfortunately, I'm stucked with the following error that i got with the multiple .xsd described above:
complex type 'ObjectType': The content model is not determinist.
Request Method: GET Request URL: http://127.0.0.1:8000/xml_validator
Django Version: 1.9.1 Exception Type: XMLSchemaParseError Exception
Value: complex type 'ObjectType': The content model is not
determinist., line 80
Any idea about that ?
Thanks a lot in advance for any suggestion or useful tips to approach this problem...
cheers
Update 23/03/2016
Here (and in the following answers to the post, because it actually exceed the max number of characters for a post), a sample of the files to figure out the problem...
sample files on GitHub

My best guess would be that your XSD model does not obey the Unique Particle Attribution rule. I would rule that out before looking at anything else.

Python 3.4 - XML Parse - IndexError: List Index Out of Range - How do I find range of XML?

Okay guys, I'm new to parsing XML and Python, and am trying to get this to work. If someone could help me with this it would be greatly appreciated. If you can help me (educate me) on how to figure it out for myself, that would be even better!
I am having trouble trying to figure out the range to reference for an XML document as I can't find any documentation on it. Here is my code and I'll include the entire Traceback after.
#import library to do http requests:
import urllib.request
#import easy to use xml parser called minidom:
from xml.dom.minidom import parseString
#all these imports are standard on most modern python implementations
#download the file:
file = urllib.request.urlopen('http://www.wizards.com/dndinsider/compendium/CompendiumSearch.asmx/KeywordSearch?Keywords=healing%20%word&nameOnly=True&tab=')
#convert to string:
data = file.read()
#close file because we dont need it anymore:
file.close()
#parse the xml you downloaded
dom = parseString(data)
#retrieve the first xml tag (<tag>data</tag>) that the parser finds with name tagName:
xmlTag = dom.getElementsByTagName('Data.Results.Power.ID')[0].toxml()
#strip off the tag (<tag>data</tag> ---> data):
xmlData=xmlTag.replace('<id>','').replace('</id>','')
#print out the xml tag and data in this format: <tag>data</tag>
print(xmlTag)
#just print the data
print(xmlData)
Traceback
/usr/bin/python3.4 /home/mint/PycharmProjects/DnD_Project/Power_Name.py
Traceback (most recent call last):
File "/home/mint/PycharmProjects/DnD_Project/Power_Name.py", line 14, in <module>
xmlTag = dom.getElementsByTagName('id')[0].toxml()
IndexError: list index out of range
Process finished with exit code 1

print len( dom.getElementsByTagName('id') )
EDIT:
ids = dom.getElementsByTagName('id')
if len( ids ) > 0 :
xmlTag = ids[0].toxml()
# rest of code
EDIT: I add example because I saw in other comment tha you don't know how to use it
BTW: I add some comment in code about file/connection
import urllib.request
from xml.dom.minidom import parseString
# create connection to data/file on server
connection = urllib.request.urlopen('http://www.wizards.com/dndinsider/compendium/CompendiumSearch.asmx/KeywordSearch?Keywords=healing%20%word&nameOnly=True&tab=')
# read from server as string (not "convert" to string):
data = connection.read()
#close connection because we dont need it anymore:
connection.close()
dom = parseString(data)
# get tags from dom
ids = dom.getElementsByTagName('Data.Results.Power.ID')
# check if there are any data
if len( ids ) > 0 :
xmlTag = ids[0].toxml()
xmlData=xmlTag.replace('<id>','').replace('</id>','')
print(xmlTag)
print(xmlData)
else:
print("Sorry, there was no data")
or you can use for loop if there is more tags
dom = parseString(data)
# get tags from dom
ids = dom.getElementsByTagName('Data.Results.Power.ID')
# get all tags - one by one
for one_tag in ids:
xmlTag = one_tag.toxml()
xmlData = xmlTag.replace('<id>','').replace('</id>','')
print(xmlTag)
print(xmlData)
BTW:
getElementsByTagName() expects tagname ID - not path Data.Results.Power.ID
tagname is ID so you have to replace <ID> not <id>
for this tag you can event use one_tag.firstChild.nodeValue in place of xmlTag.replace
.
dom = parseString(data)
# get tags from dom
ids = dom.getElementsByTagName('ID') # tagname
# get all tags - one by one
for one_tag in ids:
xmlTag = one_tag.toxml()
#xmlData = xmlTag.replace('<ID>','').replace('</ID>','')
xmlData = one_tag.firstChild.nodeValue
print(xmlTag)
print(xmlData)

I haven't used the built in xml library in a while, but it's covered in Mark Pilgrim's great Dive into Python book.
-- I see as I'm typing this that your question has already been answered but since you mention being new to Python I think you will find the text useful for xml parsing and as an excellent introduction to the language.
If you would like to try another approach to parsing xml and html, I highly recommend lxml.

Yajl parse error with githubarchive.org JSON stream in Python

I'm trying to parse a GitHub archive file with yajl-py. I believe the basic format of the file is a stream of JSON objects, so the file itself is not valid JSON, but it contains objects which are.
To test this out, I installed yajl-py and then used their example parser (from https://github.com/pykler/yajl-py/blob/master/examples/yajl_py_example.py) to try to parse a file:
python yajl_py_example.py < 2012-03-12-0.json
where 2012-03-12-0.json is one of the GitHub archive files that's been decompressed.
It appears this sort of thing should work from their reference implementation in Ruby. Do the Python packages not handle JSON streams?
By the way, here's the error I get:
yajl.yajl_common.YajlError: parse error: trailing garbage
9478bbc3","type":"PushEvent"}{"repository":{"url":"https://g
(right here) ------^

You need to use a stream parser to read the data. Yajl supports stream parsing, which allows you to read one object at a time from a file/stream. Having said that, it doesn't look like Python has working bindings for Yajl..
py-yajl has iterload commented out, not sure why: https://github.com/rtyler/py-yajl/commit/a618f66005e9798af848c15d9aa35c60331e6687#L1R264
Not a Python solution, but you can use Ruby bindings to read in the data and emit it in a format you need:
# gem install yajl-ruby
require 'open-uri'
require 'zlib'
require 'yajl'
gz = open('http://data.githubarchive.org/2012-03-11-12.json.gz')
js = Zlib::GzipReader.new(gz).read
Yajl::Parser.parse(js) do |event|
print event
end

The example does not enable any of the Yajl extra features, for what you are looking for you need to enable allow_multiple_values flag on the parser. Here is what you need to modify to the basic example to have it parse your file.
--- a/examples/yajl_py_example.py
+++ b/examples/yajl_py_example.py
## -37,6 +37,7 ## class ContentHandler(YajlContentHandler):
def main(args):
parser = YajlParser(ContentHandler())
+ parser.allow_multiple_values = True
if args:
for fn in args:
f = open(fn)
Yajl-Py is a thin wrapper around yajl, so you can use all the features Yajl provides. Here are all the flags that yajl provides that you can enable:
yajl_allow_comments
yajl_dont_validate_strings
yajl_allow_trailing_garbage
yajl_allow_multiple_values
yajl_allow_partial_values
To turn these on in yajl-py you do the following:
parser = YajlParser(ContentHandler())
# enabling these features, note that to make it more pythonic, the prefix `yajl_` was removed
parser.allow_comments = True
parser.dont_validate_strings = True
parser.allow_trailing_garbage = True
parser.allow_multiple_values = True
parser.allow_partial_values = True
# then go ahead and parse
parser.parse()

I know this has been answered, but I prefer the following approach and it does not use any packages. The github dictionary is on a single line for some reason, so you cannot assume a single dictionary per line. This looks like:
{"json-key":"json-val", "sub-dict":{"sub-key":"sub-val"}}{"json-key2":"json-val2", "sub-dict2":{"sub-key2":"sub-val2"}}
I decided to create a function which fetches one dictionary at a time. It returns json as a string.
def read_next_dictionary(f):
depth = 0
json_str = ""
while True:
c = f.read(1)
if not c:
break #EOF
json_str += str(c)
if c == '{':
depth += 1
elif c == '}':
depth -= 1
if depth == 0:
break
return json_str
I used this function to loop through the Github archive with a while loop:
arr_of_dicts = []
f = open(file_path)
while True:
json_as_str = read_next_dictionary(f)
try:
json_dict = json.loads(json_as_str)
arr_of_dicts.append(json_dict)
except:
break # exception on loading json to end loop
pprint.pprint(arr_of_dicts)
This works on the dataset post here: http://www.githubarchive.org/ (after gunzip)

As a workaround you can split the GitHub Archive files into lines and then parse each line as json:
import json
with open('2013-05-31-10.json') as f:
lines = f.read().splitlines()
for line in lines:
rec = json.loads(line)
...