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I have the following code :
Integration_Minute = 00
Integration_Schedule = '''{"cluster":{"scheduling":{"shutdownHours":{"isEnabled":true,"timeWindows":["Sat:00:00-Mon:04:xx","Tue:00:00-Tue:04:xx","Wed:00:00-Wed:04:xx","Thu:00:00-Thu:04:xx","Fri:00:00-Fri:04:xx"]}}}}'''
print(Integration_Schedule.replace("xx", Integration_Minute))
I want to replace xx with 00 but this doesnt work. Whats the best way of doing this in python ?
The error I get is :
File "s.py", line 4, in <module>
print(Integration_Schedule.replace("xx", Integration_Minute))
TypeError: expected a character buffer object
Integration_Minute = '00'
>>> print(Integration_Schedule.replace("xx", Integration_Minute))
{"cluster":{"scheduling":{"shutdownHours":{"isEnabled":true,"timeWindows":["Sat:
00:00-Mon:04:00","Tue:00:00-Tue:04:00","Wed:00:00-Wed:04:00","Thu:00:00-Thu:04:0
0","Fri:00:00-Fri:04:00"]}}}}
Related
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def calculate_money_made(**trips):
total_money_made = 0
for trip_id, trip from trips.items():
trip_revenue = trip.cost - trip.driver.cost
total_money_made += trip_revenue
return total_money_made
gives an error! cannot figure out
File "script.py", line 41
for trip_id, trip from trips.items():
^
SyntaxError: invalid syntax
Change "from" to "in"
for trip_id, trip in trip.items():
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I am trying to use machine learning to predict students' future grade, but am stuck at the beginning.
Seems like pandas.read_csv cannot read psv file, I got:
df = pd.read_csv(‘training.psv’)
^
SyntaxError: invalid character in identifier
How can I read psv file through python?
The problem is in the quotes symbol. You should either use ' or ".
Try:
df = pd.read_csv('training.psv')
pd.read_csv("training.psv", sep = "|", header = FALSE, stringsAsFactors = FALSE)
That should work
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Just doing some basic code and then this error popped up. I have no idea what I should fix everything seems fine. (Using Python)
Code:
dict = {'name':'Bob','ref':'Python','sys':'Win'}
print('\nReference:',dict['ref'])
print('n\Keys:',dict.keys()
del dict[ 'name' ]
dict['user']='Tom'
print('\nDictionary:',dict)
print('\nIs There A name Key?:','name' in dict)
C:\Python>dictionary.py
File "C:\Python\dictionary.py", line 4
del dict[ 'name' ]
^
SyntaxError: invalid syntaxer code here
You are missing a parenthesis on line 3. It should be:
print('n\Keys:',dict.keys())
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When I run this code
from numpy import linspace,arange
from pylab import plot, show
T=1.05
pp=[]
nn=[]
for V in arange (1,50):
P=(8*T)/(3*V-1)-3/(V**2)
a=((V-1/3)*(8/3)*(V**2))/((8/3)*T*(V**3)-6(V-1/3)**2)
pp.append(P)
nn.append(a)
plot(P,a)
show()
I get:
File "C:\Users\asus\Desktop\", line 8, in <module>
a=((V-1/3)*(8/3)*(V**2))/((8/3)*T*(V**3)-6(V-1/3)**2)
TypeError: 'int' object is not callable
And I don't know why.
Issue is in line -
a=((V-1/3)*(8/3)*(V**2))/((8/3)*T*(V**3)-6(V-1/3)**2)
You are using 6(V-1/3) , you need to use - 6*(V-1/3) , as -
a=((V-1/3)*(8/3)*(V**2))/((8/3)*T*(V**3)-6*(V-1/3)**2)
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I need help with a cryptic error message with python:
def format1(arg1,arg2,arg3,bf):
yu = 0
if(bf):
yu = concat(concat("Back: [",numtostr(arg1)),concat("]: ",concat(arg2,concat(" -- ",arg3))))
else:
yu = concat(concat("Forward: [",numtostr(arg1),concat("]: ",concat(arg2,concat(" -- ",arg3))))
return yu
result:
File "testdirectoryscroll2.py", line 27
return yu
^
??? :D
There is a missing closing parenthesis in the previous line:
yu = concat(concat("Forward: [",numtostr(arg1)),concat("]: ",concat(arg2,concat(" -- ",arg3))))
^