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Pandas DF.output write to columns (current data is written all to one row or one column)

I am using Selenium to extract data from the HTML body of a webpage and am writing the data to a .csv file using pandas.
The data is extracted and written to the file, however I would like to manipulate the formatting of the data to write to specified columns, after reading many threads and docs I am not able to understand how to do this.
The current CSV file output is as follows, all data in one row or one column
0,
B09KBFH6HM,
dropdownAvailable,
90,
1,
B09KBNJ4F1,
dropdownAvailable,
100,
2,
B09KBPFPCL,
dropdownAvailable,
110
or if I use the [count] count +=1 method it will be one row
0,B09KBFH6HM,dropdownAvailable,90,1,B09KBNJ4F1,dropdownAvailable,100,2,B09KBPFPCL,dropdownAvailable,110
I would like the output to be formatted as follows,
/col1 /col2 /col3 /col4
0, B09KBFH6HM, dropdownAvailable, 90,
1, B09KBNJ4F1, dropdownAvailable, 100,
2, B09KBPFPCL, dropdownAvailable, 110
I have tried using columns= options but get errors in the terminal and don't understand what feature I should be using to achieve this in the docs under the append details
https://pandas.pydata.org/docs/reference/api/pandas.DataFrame.append.html?highlight=append#pandas.DataFrame.append
A simplified version is as follows
from selenium import webdriver
import pandas as pd
price = []
driver = webdriver.Chrome("./chromedriver")
driver.get("https://www.example.co.jp/dp/zzzzzzzzzz/")
select_box = driver.find_element_by_name("dropdown_selected_size_name")
options = [x for x in select_box.find_elements_by_tag_name("option")]
for element in options:
price.append(element.get_attribute("value"))
price.append(element.get_attribute("class"))
price.append(element.get_attribute("data-a-html-content"))
output = pd.DataFrame(price)
output.to_csv("Data.csv", encoding='utf-8-sig')
driver.close()
Do I need to parse each item separately and append?
I would like each of the .get_attribute values to be written to a new column.
Is there any advice you can offer for a solution to this as I am not very proficient at pandas, thank you for your helps

 Approach similar to #user17242583, but a little shorter:
data = [[e.get_attribute("value"), e.get_attribute("class"), e.get_attribute("data-a-html-content")] for e in options]
df = pd.DataFrame(data, columns=['ASIN', 'dropdownAvailable', 'size']) # third column maybe is the product size
df.to_csv("Data.csv", encoding='utf-8-sig')

Adding all your items to the price list is going to cause them all to be in one column. Instead, store separate lists for each column, in a dict, like this (name them whatever you want):
data = {
'values': [],
'classes': [],
'data_a_html_contents': [],
}
...
for element in options:
values.append(element.get_attribute("value"))
classes.append(element.get_attribute("class"))
data_a_html_contents.append(element.get_attribute("data-a-html-content"))
...
output = pd.DataFrame(data)
output.to_csv("Data.csv", encoding='utf-8-sig')

You were collecting the value, class and data-a-html-content and appending them to the same list price. Hence, the list becomes:
price = [value1, class1, data-a-html-content1, value2, class2, data-a-html-content2, ...]
Hence, within the dataframe it looks like:
Solution
To get value, class and data-a-html-content in seperate columns you can adopt any of the below two approaches:
Pass a dictionary to the dataframe.
Pass a list of lists to the dataframe.
While the #user17242583 and #h.devillefletcher suggests a dictionary, you can still achieve the same using list of lists as follows:
values = []
classes = []
data-a-html-contents = []
driver = webdriver.Chrome("./chromedriver")
driver.get("https://www.example.co.jp/dp/zzzzzzzzzz/")
select_box = driver.find_element_by_name("dropdown_selected_size_name")
options = [x for x in select_box.find_elements_by_tag_name("option")]
for element in options:
values.append(element.get_attribute("value"))
classes.append(element.get_attribute("class"))
data-a-html-contents.append(element.get_attribute("data-a-html-content"))
df = pd.DataFrame(data=list(zip(values, classes, data-a-html-contents)), columns=['Value', 'Class', 'Data-a-Html-Content'])
output = pd.DataFrame(my_list)
output.to_csv("Data.csv", encoding='utf-8-sig')
References
You can find a couple of relevant detailed discussions in:
Selenium: Web-Scraping Historical Data from Coincodex and transform into a Pandas Dataframe
Python Selenium: How do I print the values from a website in a text file?

Parsing a zipcode boundary geojson file based on a condition, then appending to a a new json file if condition is met

I have a geojson file of zipcode boundaries.
with open('zip_geo.json') as f:
gj = geojson.load(f)
gj['features'][0]['properties']
Prints out;
{'STATEFP10': '36',
'ZCTA5CE10': '12205',
'GEOID10': '3612205',
'CLASSFP10': 'B5',
'MTFCC10': 'G6350',
'FUNCSTAT10': 'S',
'ALAND10': 40906445,
'AWATER10': 243508,
'INTPTLAT10': '+42.7187855',
'INTPTLON10': '-073.8292399',
'PARTFLG10': 'N'}
I also have a pandas dataframe with one of the fields being the zipcode.
I want to create a new geojson file only if the 'ZCTA5CEO' value of the specific element is present in the zipcode column of my dataframe.
How would I go about doing this?
I was thinking of something like; (This is pseudo code)
new_dict = {}
for index,item in enumerate(gj):
if item['features'][index]['properties']['ZCTACE10'] in df['zipcode']:
new_dict += item
The syntax of the code above is obviously wrong, but I am not sure how to parse though multiple nested dictionaries and append the results to a new dictionary.
Link to the geojson file : https://github.com/OpenDataDE/State-zip-code-GeoJSON/blob/master/ny_new_york_zip_codes_geo.min.json
In short I want to remove all the elements relating to the zipcodes that are not there in the zipcode column in my dataframe.

try this. just update your ziplist. then you can save the new json to a local file
ziplist = ['12205', '14719', '12193', '12721'] #list of zips in your dataframe
url='https://github.com/OpenDataDE/State-zip-code-GeoJSON/raw/master/ny_new_york_zip_codes_geo.min.json'
gj = requests.get(url).json()
inziplist = []
for ft in gj['features']:
if ft['properties']['ZCTA5CE10'] in ziplist:
print(ft['properties']['ZCTA5CE10'])
inziplist.append(ft)
print(len(inziplist))
new_zip_json = {}
new_zip_json['type'] = 'FeatureCollection'
new_zip_json['features'] = inziplist
new_zip_json = json.dumps(new_zip_json)

Looking for a better way do accomplish dataframe to dictionary by series

Here's a portion of what the Excel file looks like. Meant to include this the first time. Thanks for the help so far.
Name Phone Number Carrier
FirstName LastName1 3410142531 Alltel
FirstName LastName2 2437201754 AT&T
FirstName LastName3 9247224091 Boost Mobile
FirstName LastName4 6548310018 Cricket Wireless
FirstName LastName5 8811620411 Project Fi
I am converting a list of names, phone numbers, and carriers to a dictionary for easy reference by other code. The idea is separate code will be able to call a name and access that person's phone number and carrier.
I got the output I need, but I'm wondering if there were an easier way I could have accomplished this task and get the same output. Though it's fairly concise, I'm interested in any module or built in of which I'm not aware. My python skills are beginner at best. I wrote this in Thorny with Python 3.6.4. Thanks!
#Imports
import pandas as pd
import math
# Assign spreadsheet filename to `file`
file = 'Phone_Numbers.xlsx'
# Load spreadsheets
xl = pd.ExcelFile(file)
# Load a sheet into a DataFrame by name: df1
df1 = xl.parse('Sheet1', header=0)
# Put the dataframe into a dictionary to start
phone_numbers = df1.to_dict(orient='records')
# Converts PhoneNumbers.xlsx to a dictionary
x=0
temp_dict = {}
for item in phone_numbers:
temp_list = []
for key in phone_numbers[x]:
tempholder = phone_numbers[x][key]
if (isinstance(tempholder, float) or isinstance(tempholder, int)) and math.isnan(tempholder) == False: # Checks to see if there is a blank and if the phone number comes up as a float
# Converts any floats to string for use in later code
tempholder = str(int(tempholder))
else:
pass
temp_list.append(tempholder)
temp_dict[temp_list[0]] = temp_list[1:] # Makes the first item in the list the key and add the rest as values
x += 1
print(temp_dict)
Here's the desired output:
{'FirstName LastName1': ['3410142531', 'Alltel'], 'FirstName LastName2': [2437201754, 'AT&T'], 'FirstName LastName3': [9247224091, 'Boost Mobile'], 'FirstName LastName4': [6548310018, 'Cricket Wireless'], 'FirstName LastName5': [8811620411, 'Project Fi']

One way to do it would be to iterate through the dataframe and use a dictionary comprehension:
temp_dict = {row['Name']:[row['Phone Number'], row['Carrier']] for _, row in df.iterrows()}
where df is your original dataframe (the result of xl.parse('Sheet1', header=0)). This basically iterates through all rows in your dataframe, creating a dictionary key for each Name, with Phone number and carrier as it's values (in a list), as you indicated in your output.
To make sure that your phone number is not null (as you did in your loop), you could add an if clause to your dict comprehension, such as this:
temp_dict = {row['Name']:[row['Phone Number'], row['Carrier']]
for _, row in df.iterrows()
if not math.isnan(row['Phone Number'])}

df.set_index('Name').T.to_dict('list')
should do the job ,Here df is your dataframe

Python reading Excel spreadsheet, creating multiple lists according to variables and conditions

Hi there’s an Excel spreadsheet showing Product ID and Location, like below.
I want to list all the locations of each product ID in sequence with no duplication.
For example:
53424 has Phoenix, Matsuyama, Phoenix, Matsuyama, Phoenix, Matsuyama, Phoenix.
56224 has Samarinda, Boise. Seoul.
etc.
What's the best way to achieve it with Python?
I can only read the cells in the spreadsheet but have no idea what’s good to proceed.
Thank you.
the_file = xlrd.open_workbook("C:\\excel file.xlsx")
the_sheet = the_file.sheet_by_name("Sheet1")
for row_index in range(0, the_sheet.nrows):
product_id = the_sheet.cell(row_index, 0).value
location = the_sheet.cell(row_index, 1).value

You need to make use of Python's groupby() function to take away the duplicates as follows:
from collections import defaultdict
from itertools import groupby
import xlrd
the_file = xlrd.open_workbook(r"excel file.xlsx")
the_sheet = the_file.sheet_by_name("Sheet1")
products = defaultdict(list)
for row_index in range(1, the_sheet.nrows):
products[int(the_sheet.cell(row_index, 0).value)].append(the_sheet.cell(row_index, 1).value)
for product, v in sorted(products.items()):
print "{} has {}.".format(product, ', '.join(k for k, g in groupby(v)))
This uses a defaultlist() with a dictionary to build your products. So each key in the dictionary holds your product ID and the contents is automatically a list of the matching entries. Finally the groupby() is used to read out each raw value and only give you one entry for the cases where there are consecutive identically values. Finally the list this produces is joined together with commas between them.

You should use a dictionary to store the data from excel and then traverse it according to product ID.
So, following code should help you out -
the_file = xlrd.open_workbook("C:\\excel file.xlsx")
the_sheet = the_file.sheet_by_name("Sheet1")
dataset = dict()
for row_index in range(0, the_sheet.nrows):
product_id = the_sheet.cell(row_index, 0).value
location = the_sheet.cell(row_index, 1).value
if product_id in dataset:
dataset[product_id].append(location)
else:
dataset[product_id] = [location]
for product_id in sorted(dataset.keys()):
print "{0} has {1}.".format(product_id, ", ".join(dataset[product_id]))
Above will preserve the order of locations as per product_id (in sequence).

Pandas + HDF5 Panel data storage for large data

As part of my research, I am searching a good storing design for my panel data. I am using pandas for all in-memory operations. I've had a look at the following two questions/contributions, Large Data Work flows using Pandas and Query HDF5 Pandas as they come closest to my set-up. However, I have a couple of questions left. First, let me define my data and some requirements:
Size: I have around 800 dates, 9000 IDs and up to 200 variables. Hence, flattening the panel (along dates and IDs) corresponds to 7.2mio rows and 200 columns. This might all fit in memory or not, let's assume it does not. Disk-space is not an issue.
Variables are typically calculated once, but updates/changes probably happen from time to time. Once updates occur, old versions don't matter anymore.
New variables are added from time to time, mostly one at a time only.
New rows are not added.
Querying takes place. For example, often I need to select only a certain date range like date>start_date & date<end_date. But some queries need to consider rank conditions on dates. For example, get all data (i.e. columns) where rank(var1)>500 & rank(var1)<1000, where rank is as of date.
The objective is to achieve fast reading/querying of data. Data writing is not so critical.
I thought of the following HDF5 design:
Follow the groups_map approach (of 1) to store variables in different tables. Limit the number of columns for each group to 10 (to avoid large memory loads when updating single variables, see point 3).
Each group represents one table, where I use the multi-index based on dates & ids for each table stored.
Create an update function, to update variables. The functions loads the table with all (10) columns to memory as a df, deletes the table on the disk, replaces the updated variable in df and saves the table from memory back to disk.
Create an add function, add var1 to a group with less than 10 columns, or create new group if required. Saving similar as in 3. load current group to memory, delete table on disk, add new column and save it back on disk.
Calculate ranks as of date for relevant variables and add them to disk-storage as rank_var1, which should reduce the query as of to simply rank_var1 > 500 & rank_var1<1000.
I have the following questions:
Updating HDFTable, I suppose I have to delete the entire table in order to update a single column?
When to use 'data_columns', or should I simply assign True in HDFStore.append()?
If I want to query based on condition of rank_var1 > 500 & rank_var1<1000, but I need columns from other groups. Can I enter the index received from the rank_var1 condition into the query to get other columns based on this index (the index is a multi-index with date and ID)? Or would I need to loop this index by date and then chunk the IDs similar as proposed in 2 and repeat the procedure for each group where I need. Alternatively, (a) I could add to each groups table rank columns, but it seems extremely inefficient in terms of disk-storage. Note, the number of variables where rank filtering is relevant is limited (say 5). Or (b) I could simply use the df_rank received from the rank_var1 query and use in-memory operations via df_rank.merge(df_tmp, left_index=True, right_index=True, how='left') and loop through groups (df_tmp) where I select the desired columns.
Say I have some data in different frequencies. Having different group_maps (or different storages) for different freq is the way to go I suppose?
Copies of the storage might be used on win/ux systems. I assume it is perfectly compatible, anything to consider here?
I plan to use pd.HDFStore(str(self.path), mode='a', complevel=9, complib='blosc'). Any concerns regarding complevel or complib?
I've started to write up some code, once I have something to show I'll edit and add it if desired. Please, let me know if you need any more information.
EDIT I here a first version of my storage class, please adjust path at bottom accordingly. Sorry for the length of the code, comments welcome
import pandas as pd
import numpy as np
import string
class LargeDFStorage():
# TODO add index features to ensure correct indexes
# index_names = ('date', 'id')
def __init__(self, h5_path, groups_map):
"""
Parameters
----------
h5_path: str
hdf5 storage path
groups_map: dict
where keys are group_names and values are dict, with at least key
'columns' where the value is list of column names.
A special group_name is reserved for group_name/key "query", which
can be used as queering and conditioning table when getting data,
see :meth:`.get`.
"""
self.path = str(h5_path)
self.groups_map = groups_map
self.column_map = self._get_column_map()
# if desired make part of arguments
self.complib = 'blosc'
self.complevel = 9
def _get_column_map(self):
""" Calc the inverse of the groups_map/ensures uniqueness of cols
Returns
-------
dict: with cols as keys and group_names as values
"""
column_map = dict()
for g, value in self.groups_map.items():
if len(set(column_map.keys()) & set(value['columns'])) > 0:
raise ValueError('Columns have to be unique')
for col in value['columns']:
column_map[col] = g
return column_map
#staticmethod
def group_col_names(store, group_name):
""" Returns all column names of specific group
Parameters
----------
store: pd.HDFStore
group_name: str
Returns
-------
list:
of all column names in the group
"""
if group_name not in store:
return []
# hack to get column names, straightforward way!?
return store.select(group_name, start=0, stop=0).columns.tolist()
#staticmethod
def stored_cols(store):
""" Collects all columns stored in HDF5 store
Parameters
----------
store: pd.HDFStore
Returns
-------
list:
a list of all columns currently in the store
"""
stored_cols = list()
for x in store.items():
group_name = x[0][1:]
stored_cols += LargeDFStorage.group_col_names(store, group_name)
return stored_cols
def _find_groups(self, columns):
""" Searches all groups required for covering columns
Parameters
----------
columns: list
list of valid columns
Returns
-------
list:
of unique groups
"""
groups = list()
for column in columns:
groups.append(self.column_map[column])
return list(set(groups))
def add_columns(self, df):
""" Adds columns to storage for the first time. If columns should
be updated use(use :meth:`.update` instead)
Parameters
----------
df: pandas.DataFrame
with new columns (not yet stored in any of the tables)
Returns
-------
"""
store = pd.HDFStore(self.path, mode='a' , complevel=self.complevel,
complib=self.complib)
# check if any column has been stored already
if df.columns.isin(self.stored_cols(store)).any():
store.close()
raise ValueError('Some cols are already in the store')
# find all groups needed to store the data
groups = self._find_groups(df.columns)
for group in groups:
v = self.groups_map[group]
# select columns of current group in df
select_cols = df.columns[df.columns.isin(v['columns'])].tolist()
tmp = df.reindex(columns=select_cols, copy=False)
# set data column to False only in case of query data
dc = None
if group=='query':
dc = True
stored_cols = self.group_col_names(store,group)
# no columns in group (group does not exists yet)
if len(stored_cols)==0:
store.append(group, tmp, data_columns=dc)
else:
# load current disk data to memory
df_grp = store.get(group)
# remove data from disk
store.remove(group)
# add new column(s) to df_disk
df_grp = df_grp.merge(tmp, left_index=True, right_index=True,
how='left')
# save old data with new, additional columns
store.append(group, df_grp, data_columns=dc)
store.close()
def _query_table(self, store, columns, where):
""" Selects data from table 'query' and uses where expression
Parameters
----------
store: pd.HDFStore
columns: list
desired data columns
where: str
a valid select expression
Returns
-------
"""
query_cols = self.group_col_names(store, 'query')
if len(query_cols) == 0:
store.close()
raise ValueError('No data to query table')
get_cols = list(set(query_cols) & set(columns))
if len(get_cols) == 0:
# load only one column to minimize memory usage
df_query = store.select('query', columns=query_cols[0],
where=where)
add_query = False
else:
# load columns which are anyways needed already
df_query = store.select('query', columns=get_cols, where=where)
add_query = True
return df_query, add_query
def get(self, columns, where=None):
""" Retrieve data from storage
Parameters
----------
columns: list/str
list of columns to use, or use 'all' if all columns should be
retrieved
where: str
a valid select statement
Returns
-------
pandas.DataFrame
with all requested columns and considering where
"""
store = pd.HDFStore(str(self.path), mode='r')
# get all columns in stored in HDFStorage
stored_cols = self.stored_cols(store)
if columns == 'all':
columns = stored_cols
# check if all desired columns can be found in storage
if len(set(columns) - set(stored_cols)) > 0:
store.close()
raise ValueError('Column(s): {}. not in storage'.format(
set(columns)- set(stored_cols)))
# get all relevant groups (where columns are taken from)
groups = self._find_groups(columns)
# if where query is defined retrieve data from storage, eventually
# only index of df_query might be used
if where is not None:
df_query, add_df_query = self._query_table(store, columns, where)
else:
df_query, add_df_query = None, False
# dd collector
df = list()
for group in groups:
# skip in case where was used and columns used from
if where is not None and group=='query':
continue
# all columns which are in group but also requested
get_cols = list(
set(self.group_col_names(store, group)) & set(columns))
tmp_df = store.select(group, columns=get_cols)
if df_query is None:
df.append(tmp_df)
else:
# align query index with df index from storage
df_query, tmp_df = df_query.align(tmp_df, join='left', axis=0)
df.append(tmp_df)
store.close()
# if any data of query should be added
if add_df_query:
df.append(df_query)
# combine all columns
df = pd.concat(df, axis=1)
return df
def update(self, df):
""" Updates data in storage, all columns have to be stored already in
order to be accepted for updating (use :meth:`.add_columns` instead)
Parameters
----------
df: pd.DataFrame
with index as in storage, and column as desired
Returns
-------
"""
store = pd.HDFStore(self.path, mode='a' , complevel=self.complevel,
complib=self.complib)
# check if all column have been stored already
if df.columns.isin(self.stored_cols(store)).all() is False:
store.close()
raise ValueError('Some cols have not been stored yet')
# find all groups needed to store the data
groups = self._find_groups(df.columns)
for group in groups:
dc = None
if group=='query':
dc = True
# load current disk data to memory
group_df = store.get(group)
# remove data from disk
store.remove(group)
# update with new data
group_df.update(df)
# save updated df back to disk
store.append(group, group_df, data_columns=dc)
store.close()
class DataGenerator():
np.random.seed(1282)
#staticmethod
def get_df(rows=100, cols=10, freq='M'):
""" Simulate data frame
"""
if cols < 26:
col_name = list(string.ascii_lowercase[:cols])
else:
col_name = range(cols)
if rows > 2000:
freq = 'Min'
index = pd.date_range('19870825', periods=rows, freq=freq)
df = pd.DataFrame(np.random.standard_normal((rows, cols)),
columns=col_name, index=index)
df.index.name = 'date'
df.columns.name = 'ID'
return df
#staticmethod
def get_panel(rows=1000, cols=500, items=10):
""" simulate panel data
"""
if items < 26:
item_names = list(string.ascii_lowercase[:cols])
else:
item_names = range(cols)
panel_ = dict()
for item in item_names:
panel_[item] = DataGenerator.get_df(rows=rows, cols=cols)
return pd.Panel(panel_)
def main():
# Example of with DataFrame
path = 'D:\\fc_storage.h5'
groups_map = dict(
a=dict(columns=['a', 'b', 'c', 'd', 'k']),
query=dict(columns=['e', 'f', 'g', 'rank_a']),
)
storage = LargeDFStorage(path, groups_map=groups_map)
df = DataGenerator.get_df(rows=200000, cols=15)
storage.add_columns(df[['a', 'b', 'c', 'e', 'f']])
storage.update(df[['a']]*3)
storage.add_columns(df[['d', 'g']])
print(storage.get(columns=['a','b', 'f'], where='f<0 & e<0'))
# Example with panel and rank condition
path2 = 'D:\\panel_storage.h5'
storage_pnl = LargeDFStorage(path2, groups_map=groups_map)
panel = DataGenerator.get_panel(rows=800, cols=2000, items=24)
df = panel.to_frame()
df['rank_a'] = df[['a']].groupby(level='date').rank()
storage_pnl.add_columns(df[['a', 'b', 'c', 'e', 'f']])
storage_pnl.update(df[['a']]*3)
storage_pnl.add_columns(df[['d', 'g', 'rank_a']])
print(storage_pnl.get(columns=['a','b','e', 'f', 'rank_a'],
where='f>0 & e>0 & rank_a <100'))
if __name__ == '__main__':
main()

It's bit difficult to answer those questions without particular examples...
Updating HDFTable, I suppose I have to delete the entire table in
order to update a single column?
AFAIK yes unless you are storing single columns separately, but it will be done automatically, you just have to write your DF/Panel back to HDF Store.
When to use 'data_columns', or should I simply assign True in
HDFStore.append()?
data_columns=True - will index all your columns - IMO it's waste of resources unless you are going to use all columns in the where parameter (i.e. if all columns should be indexed).
I would specify there only those columns that will be used often for searching in where= clause. Consider those columns as indexed columns in a database table.
If I want to query based on condition of rank_var1 > 500 &
rank_var1<1000, but I need columns from other groups. Can I enter the
index received from the rank_var1 condition into the query to get
other columns based on this index (the index is a multi-index with
date and ID)?
I think we would need some reproducible sample data and examples of your queries in order to give a reasonable answer...
Copies of the storage might be used on win/ux systems. I assume it is
perferctly compatible, anything to consider here?
Yes, it should be fully compatible
I plan to use pd.HDFStore(str(self.path), mode='a', complevel=9,
complib='blosc'). Any concerns regarding complevel or complib?
Test it with your data - results might depend on dtypes, number of unique values, etc. You may also want to consider lzo complib - it might be faster in some use-cases. Check this. Sometimes a high complevel doesn't give you better copression ratio, but will be slower (see results of my old comparison)