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How to test if var is not either of two strings?

I've stumbled upon a problem I can't explain.
chosen = input()
if chosen == "1" or chosen == "2":
print("Okay")
else:
print("Please choose between 1 or 2.")
If written like that it executes as intended, but the flow felt weird, so I want to continue with else, so I changed the statement to !=
chosen = input()
if chosen != "1" or chosen != "2":
print("Please choose between 1 or 2.")
else:
print("Okay")
That way (to me) it feels natural to continue the code, but now no input returns "Okay".

Ideally, you'd use in for this, which reads much cleaner
while True:
chosen = input()
if chosen in ["1", "2"]:
print("Okay")
break
else:
print("Please choose between 1 or 2.")

You need to use the and keyword instead of or,
by using or this makes it so that if you answer 1 then it will not print "Okay" due to the fact that it is not 2 which makes the function true, and vice versa for the input equaling 2.
This should work:
chosen = input()
if chosen != "1" and chosen != "2":
print("Please choose between 1 or 2.")
else:
print("Okay")
Note you may benefit from changing the numbers into integers by doing this:
chosen = int(input())
if chosen != 1 and chosen != 2:
print("Please choose between 1 or 2.")
else:
print("Okay")
The int function makes your input into a number, however it will give an error if the user doesn't put in a number.

Number guessing game will not print the right phrase

I am extremely new to python and this is one of the first things I have tried. There are 3 criteria that I want this game to meet. First is to use the number 0-10 and guess the number 3 which it does correctly. Next is 0-25 when 11 is chosen. This also works correctly.
However this last part has been giving me trouble. When picking from 0-50, it should guess 1 which it does. It should also print the "I'm out of guesses" line when another input is placed as it cannot go higher than one now. What am I doing wrong here?
import random
import math
smaller = int(input("Enter the smaller number: "))
larger = int(input("Enter the larger number: "))
maxTry = math.log(larger - smaller)
count = 0
guess = int((smaller+larger)/2)
while count != maxTry:
count += 1
guess = int((smaller+larger)/2)
print("Your number is ", guess)
help = input("Enter =, <, or >: ")
if help == ">":
smaller = guess +1
elif help == "<":
larger = guess -1
elif help == "=":
print("Hooray, I've got it in", count, "tries")
break
elif count == maxTry:
print("I'm out of guesses, and you cheated")
break

Your maxTry is a log so it is not an integer, therefore it can never be equal to count.
You can either use an int for maxTry (cast it to int maxTry = int(math.log(larger - smaller))) or compute it with something different than log that will return an int.
Alternatively, your condition could be count > maxTry instead of equal. It would actually be a bit better conceptually.
Note: you should not use capital letters in variable names in python but all lowercase with _ max_try. It is only a convention though so won't affect your program directly. You can find more info on conventions in the PEP8 documentation

how can I reduce my code? A lot of it is repetitive

The code creates a random addition problem and spits out "Congratulations" if correct and "sorry...." if the inputted value is wrong. The while loop repeats this process until the user inserts "N" for the question "continue (Y/N):, at the same time it keeps track of how many questions have been answered, and which ones are correct. The code works fine, my problem is it has repetitive code. I was wondering if there is a way to shrink it.
**I appreciate everyone one's help and advice. I"m a noob that's just learning python **
import random
correct=0
count=1
num1=random.randint(0,100)
num2=random.randint(0,100)
print(format(num1,'4d'))
print('+',num2)
answer=int(input('='))
sum=num1+num2
if answer==sum:
print('Congraulations!')
correct+=1
else:
print('Sorry the correct answer is',sum)
c=input('Continue (Y/N):')
while c == "Y":
count+=1
num1=random.randint(0,100)
num2=random.randint(0,100)
print(format(num1,'4d'))
print('+',num2)
answer=int(input('='))
sum=num1+num2
if answer==sum:
print('Congraulations!')
correct+=1
else:
print('Sorry the correct answer is',sum)
c=input('Continue (Y/N):')
else:
print('Your final score is',correct,'/',count)

A first start, would be eliminating the code before the while, by initializing the count variable (which keeps track of the turns), in zero, and allowing the while loop to run the first turn, we just need to have a variable like want_to_play and by default it's True, so the first time we'll be playing, and at the end of the game If I don't input Y or y it will asume I don't want to play any more and set the variable to false, that way I can have all the turns ran by the while loop.
and you'll be getting something like this.:
from random import sample
correct = 0
count = 0 # STartint in turn zero
want_to_play = True # Control Variable
while want_to_play:
count += 1
# First turn this is zero, and adds one.
[num1, num2] = sample(range(0, 101), 2)
# Just another way of getting two random numbers from 1 up to (including) 100.
# Printing could be done in one line.
print(format(num1, '5d') + '\n+' + format(num2, '4d'))
answer = int(input('= '))
# The comparison really doesn't really hurt if you do it this way.
if answer == num1 + num2:
print('Congraulations!')
correct += 1
else:
print('Sorry the correct answer is', sum)
# HERE you ask if you want to play again or not, using a one line if
# you decide.
want_to_play = (True if 'y' == input('Continue (Y/N).lower():')
else False)
else:
print('Your final score is',correct,'/',count)

By initializing the variable c as "Y", the condition is met and the loop can be executed:
import random
correct=0
count=1
c = "Y"
while c == "Y":
count+=1
num1=random.randint(0,100)
num2=random.randint(0,100)
print(format(num1,'4d'))
print('+',num2)
answer=int(input('='))
sum=num1+num2
if answer==sum:
print('Congraulations!')
correct+=1
else:
print('Sorry the correct answer is',sum)
c=input('Continue (Y/N):')
c = c.upper()
else:
print('Your final score is',correct,'/',count)
I also added the method upper() to the Y/N input so the user can also type it in lowercase

Try to move as much of the processing as possible into the loop. The first "paragraph" of your code was basically a duplicate of the main-loop. By creating the continuation variable c so that it drops straight into the loop, most of that first block could be removed.
import random
correct=0
count=0
c = 'Y'
while c == "Y":
count+=1
num1=random.randint(0,100)
num2=random.randint(0,100)
print(format(num1,'4d'))
print('+',num2)
answer=int(input('='))
sum=num1+num2
if answer==sum:
print('Congratulations!')
correct+=1
else:
print('Sorry the correct answer is',sum)
c=input('Continue (Y/N):')
else:
print('Your final score is',correct,'/',count)
The two formula printing statements can also be reduced to a single one:
print(format(num1,'4d'))
print('+',num2)
could be
print( format(num1,'4d') + '+', num2 )
The variable sum could be removed, but it does make the code self-documenting, which is a good thing.

Creating a game where the computer guesses a value through inputs of <,> or =

I am trying to create a game where i think of a number in my head. And then the computer guesses the number through me telling it if its guess is too low or high.
This is what I've come up with but i am pretty lost tbh.
maxguess = 100
minguess = 1
count = 0
print("Think of a number between {} and {}".format(minguess,maxguess))
def midpoint(maxguess, minguess) :
z = ((maxguess + minguess)/2)
def guessing(x) :
print("Is you number greater (>) , equal (=) ,or less (<) than" ,z,)
print("please answer <,=, or >! >")
x = input()
if x == (">") :
minpoint = z
count += 1
continue
elif x == ("<") :
maxpoint = z
count += 1
continue
elif x == ("=") :
print ("I have guessed it!")
count += 1
break
print("I needed {} steps!".format(count))

Purposely not a complete solution, but some hints for you:
I'd recommend avoiding the global variables like count, maxguess, and minguess. Instead, make a function that holds all these variables.
Change your midpoint function to return z instead, then call it inside your guessing function.
Your continue and break functions would need to be inside a for or while loop. Since you aren't sure how many iterations you need to guess the number, I think a while loop would make sense here

Your functions are never run. On a style point, bring all your 'main' statements down to the bottom so they're together. After the prompt to think of a number, you need to call the guessing() function. When you call it, you should pass the minguess and maxguess values to it.
I can see what you're trying to do with the if...elif statements, but they need to be in a while True: block. So should the three statements preceding them so the script repeatedly asks for new advice from you.
Either bring the content of the midpoint() function into guessing() or make it return the value of z.
You also offer the user a choice of '>1' but don't handle it - and you don't need it as far as I can tell.
You never use minpoint or maxpoint - and you dont need them. Call the midpoint function instead and pass it the appropriate values, e.g., if '>', z = midpoint(z, maxguess).
Also, you're going to spend forever trying to get it to guess as you are using floats. Make sure everything is an integer.
Finally, you should add some code to manage input that isn't expected, i.e., not '<', '>' or '='.
Good luck!

minguess=1
maxguess=100
z=50
count=0
print("Think of a number between 1 and 100")
condition = True
while condition:
z=((maxguess + minguess)//2)
print("Is your number greater (>) , equal (=) ,or less (<) than" ,z,)
print("Please answer <,=, or >! >")
x = input()
if x == (">"):
minguess=z
count += 1
elif x == ("<") :
maxguess=z
count += 1
elif x == ("=") :
print ("I have guessed it!")
count += 1
condition=False

I need to figure out how to make my program repeat. (Python coding class)

I am a beginner student in a python coding class. I have the majority of the done and the program itself works, however I need to figure out a way to make the program ask if wants a subtraction or an adding problem, and if the user would like another question. I asked my teacher for assistance and he hasn't gotten back to me, so I'm simply trying to figure out and understand what exactly I need to do.
import random
x = int(input("Please enter an integer: "))
if x < 0:
x = 0
print('Negative changed to zero')
elif x == 0:
print('Zero')
elif x == 1:
print('Single')
else:
print('More')
maximum = 10 ** x;
maximum += 1
firstnum = random.randrange(1,maximum) # return an int from 1 to 100
secondnum = random.randrange(1, maximum)
compsum = firstnum + secondnum # adds the 2 random numbers together
# print (compsum) # print for troubleshooting
print("What is the sum of", firstnum, " +", secondnum, "?") # presents problem to user
added = int(input("Your answer is: ")) # gets user input
if added == compsum: # compares user input to real answer
print("You are correct!!!")
else:
print ("Sorry, you are incorrect")

You'll want to do something like this:
def foo():
print("Doing good work...")
while True:
foo()
if input("Want to do more good work? [y/n] ").strip().lower() == 'n':
break
I've seen this construct (i.e., using a break) used more often than using a sentinel in Python, but either will work. The sentinel version looks like this:
do_good_work = True
while do_good_work:
foo()
do_good_work = input("Want to do more good work? [y/n] ").strip().lower() != 'n'
You'll want to do more error checking than me in your code, too.

Asking users for input is straightforward, you just need to use the python built-in input() function. You then compare the stored answer to some possible outcomes. In your case this would work fine:
print('Would you like to test your adding or subtracting skills?')
user_choice = input('Answer A for adding or S for subtracting: ')
if user_choice.upper() == 'A':
# ask adding question
elif user_choice.upper() == 'S':
# ask substracting question
else:
print('Sorry I did not understand your choice')
For repeating the code While loops are your choice, they will repeatedly execute a statement in them while the starting condition is true.
while True: # Condition is always satisfied code will run forever
# put your program logic here
if input('Would you like another test? [Y/N]').upper() == 'N':
break # Break statement exits the loop
The result of using input() function is always a string. We use a .upper() method on it which converts it to UPPERCASE. If you write it like this, it doesn't matter whether someone will answer N or n the loop will still terminate.

If you want the possibility to have another question asked use a while loop and ask the user for an input. If you want the user to input whether (s)he want an addition or substraction you already used the tools to ask for such an input. Just ask the user for a string.