I made a simple program where it asks for the user to type in 2 numbers, and the program will add the numbers. For some reason my program gives me an error and I am not sure why. The code is below.
choice = input("Enter Choice")
choice2 = input("Enter Choice")
num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))
if choice == '1':
print(num1"+",num2,"=", add(num1,num2))
The error states Syntax Error - Invalid Syntax.
Any help would be appreciated.
You miss a ","
choice = input("Enter Choice")
choice2 = input("Enter Choice")
num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))
if choice == '1':
print(num1, "+", num2, "=", add(num1,num2))
'add' is not defined. Try below:
choice = input("Enter Choice") choice2 = input("Enter Choice")
num1 = int(input("Enter first number: ")) num2 = int(input("Enter
second number: "))
if choice == '1': print(num1, "+", num2, "=", num1+num2)
Related
Ok so I am very new to Python and I recently took on the challenge of creating a very simple calculator.
It works completely fine but I want to add a option to restart and go back to the main menu area rather than restarting the program entirely. How could this be done?
here is the code that i have so far
from math import sqrt
import time
print("Welcome to Calculator")
print(" #1 Add \n #2 Subtract \n #3 Multiply \n #4 Divide \n #5 Square Root")
option = input("Select one #: ")
if option == "1":
print("Addition:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) + float(num2)
print("The answer is: ", result)
elif option == "2":
print("Subtraction:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) - float(num2)
print("The answer is: ", result)
elif option == "3":
print("Multiplication:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) * float(num2)
print("The answer is: ", result)
elif option == "4":
print("Division:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) / float(num2)
print("The answer is: ", result)
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)
I tried the adding While True to the program but I was not able to figure out how that works.
Wrapping your whole code in a while True loop would work but you need to write an if statement at the end in order to exit the infinite loop. Here's the working code:
from math import sqrt
import time
while True:
print("Welcome to Calculator")
print(" #1 Add \n #2 Subtract \n #3 Multiply \n #4 Divide \n #5 Square Root")
option = input("Select one #: ")
if option == "1":
print("Addition:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) + float(num2)
print("The answer is: ", result)
elif option == "2":
print("Subtraction:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) - float(num2)
print("The answer is: ", result)
elif option == "3":
print("Multiplication:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) * float(num2)
print("The answer is: ", result)
elif option == "4":
print("Division:")
num1 = input("Enter first Number: ")
num2 = input("Enter Second Number: ")
result = float(num1) / float(num2)
print("The answer is: ", result)
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)
restart = input("Do you want to restart the program? (yes/no) ")
if restart.lower() != "yes":
break
You can add while loop like this:
while True:
option = input("Select one #: ")
if option == "1":
print("Addition:")
...
elif option == "5":
print("Square Root:")
num1 = input("Enter Number: ")
result = sqrt(float(num1))
print("The answer is: ", result)
I am making a python calculator program that asks a user after completing one calculation whether they want to continue or not. If the user says Yes the loop should run or else it should stop. I am Facing a problem where a user says yes or no the loop still executes anyhow. Why is it so ???
print("This is a Calculator In Python. !!!")
print("I Can Do Addition, Subtraction, Multiplication and Division.!!")
def addition():
print("Please Don't Enter Float Values Here.")
num1 = int(input("Enter First Number.!!"))
num2 = int(input("Enter Second Number. !!"))
result = num1 + num2
return result
def subtraction():
print("Please Don't Enter Float Values Here.")
num1 = int(input("Enter First Number.!!"))
num2 = int(input("Enter Second Number.!!"))
result = num1 - num2
return result
def multiplication():
print("You Can Enter Float Values Here.")
num1 = float(input("Enter First Number.!!"))
num2 = float(input("Enter Second Number.!!"))
result = num1 * num2
return result
def division():
print("You Can Enter Float Values Here.")
num1 = float(input("Enter First Number.!!"))
num2 = float(input("Enter Second Number.!!"))
result = num1 / num2
return result
print("""1. a for Addition
2. s for subtraction
3. m for multiplication
4. d for Division""")
select = "Yes"
while select:
choice = str(input("You Choose The Operation."))
if choice == "a":
print(addition())
elif choice == "s":
print(subtraction())
elif choice == "m":
print(multiplication())
elif choice == "d":
print(division())
else:
print("Invalid Input")
select=str(input('Continue Yes or No '))
print("Thank you..!")
You've defined your loop as while select, which means as long as select is considered to not be None, it will continue looping
In your loop, you assign the user input to select, which means as long as the user inputs anything, it will always keep looping.
To fix this, you should have the while loop check if select is "yes":
while select.lower().strip() == "yes":
choice = input("You Choose The Operation. ")
if choice == "a":
print(addition())
elif choice == "s":
print(subtraction())
elif choice == "m":
print(multiplication())
elif choice == "d":
print(division())
else:
print("Invalid Input")
select = input("Continue Yes or No ")
print("Thank you..!")
Also, input() returns a string so you don't need to wrap it in a str() call.
I am just practising basic python and attempting to build a calculator with only addition, subtraction, and multiplication functions. When I run the code and input 1, 2, or 3, I get no output.
Here is my code:
question1 = input("Enter 1 to add, 2 to substract, or 3 to multiply: ")
if question1 == 1:
num1 = input("Enter a number: ")
num2 = input("Enter another number: ")
result = float(num1) + float(num2)
print(result)
elif question1 == 2:
num1 = input("Enter a number: ")
num2 = input("Enter another number: ")
result = float(num1) + float(num2)
print(result)
elif question1 == 3:
num1 = input("Enter a number: ")
num2 = input("Enter another number: ")
result = float(num1) + float(num2)
print(result))
When you get some input with input() in Python3, you get a string.
Test it with following:
foo = input()
print(type(foo))
The result will be <class 'str'>(it means foo's type is string) regardless of your input. If you want to use that input as a integer, you will have to change the type to int(integer).
You should use int(input()) to get a integer like the following:
question1 = int(input("Enter 1 to add, 2 to substract, or 3 to multiply: "))
You have to change the number inputs in each of the if-else blocks too:
if question1 == 1:
num1 = int(input("Enter a number: "))
num2 = int(input("Enter another number: "))
result = num1 + num2
print(result)
Or, you can just change it when you want to calculate:
result = int(num1) + int(num2)
You need to convert your input to the integer. Try this code:
question1 = int(input("Enter 1 to add, 2 to substract, or 3 to multiply: "))
if question1 == 1:
num1 = int(input("Enter a number: "))
num2 = int(input("Enter another number: "))
result = num1 + num2
print(result)
elif question1 == 2:
num1 = int(input("Enter a number: "))
num2 = int(input("Enter another number: "))
result = num1 - num2
print(result)
elif question1 == 3:
num1 = int(input("Enter a number: "))
num2 = int(input("Enter another number: "))
result = num1 * num2
print(result)
You are well on your way! As mentioned in the comments, all your statements are False because input() just by itself returns string type which will never be equal to an integer.
You just have to change the all the input() of your code to convert it as an int to be stored. Below is an example:
question1 = int(input("Enter 1 to add, 2 to substract, or 3 to multiply: "))
total = 0
print ("Enter first number")
num1 = input()
print ("Enter 1)Add 2)Minus 3)Multiply 4)Divide")
choice = input()
while True:
print("Wrong Answer Pick Again")
print("Enter 1)Add 2)Minus 3)Multiply 4)Divide")
choice = input()
if choice => 1 and choice =< 4:
break
if choice == 1:
print ('Enter second number')
num2 = input()
total = num1 + num2
elif choice == 2:
print ('Enter second number')
num2 = input()
total = num1 - num2
elif choice == 3:
print ('Enter second number')
num2 = input()
total = num1 * num2
elif choice == 4:
print ('Enter second number')
num2 = input()
total = num1 / num2
print("Total")
print (total)
I`m getting a syntax error on the "if choice => 1 and choice =<4:" can some one please help. I have tried so many different things and nothing have worked.
This script should work for you :
total = 0
print ("Enter 1)Add 2)Minus 3)Multiply 4)Divide")
choice = int(input())
for _ in range(int(input("total test cases"))):
if choice >= 1 and choice <= 4:
if choice == 1:
print ("Enter first number")
num1 = int(input())
print ('Enter second number')
num2 = int(input())
total = num1 + num2
print("Total is: ",total)
choice=int(input("enter choice again"))
elif choice == 2:
print ("Enter first number")
num1 = int(input())
print ('Enter second number')
num2 = int(input())
total = num1 - num2
print("Total is: ",total)
choice=int(input("enter choice again"))
elif choice == 3:
print ("Enter first number")
num1 = int(input())
print ('Enter second number')
num2 = int(input())
total = num1 * num2
print("Total is: ",total)
choice=int(input("enter choice again"))
elif choice == 4:
print ("Enter first number")
num1 = int(input())
print ('Enter second number')
num2 = int(input())
total = num1 / num2
print("Total is: ",total)
choice=int(input("enter choice again"))
else:
print("wrong number entered")
choice=int(input("enter again"))
Note:If you find this answer helpful you can mark this answer correct
I have managed to create a small calculator in Python, but I am trying to shorten the code unsucsessfully. Can anyone help please?
elif queencommand == "/calc addition" :
num1 = input("Enter first number")
num2 = input("Enter second number")
Answer = (int(num1) + int(num2))
input(Answer)
elif queencommand == "/calc subtraction" :
num1 = input("Enter first number")
num2 = input("Enter second number")
Answer = (int(num1) - int(num2))
input(Answer)
elif queencommand == "/calc multiplication" :
num1 = input("Enter first number")
num2 = input("Enter second number")
Answer = (int(num1) * int(num2))
input(Answer)
elif queencommand == "/calc division" :
num1 = input("Enter first number")
num2 = input("Enter second number")
Answer = (int(num1) / int(num2))
input(Answer)
I am not able to do two operations at once either.
Use functions from the operator module or simple functions you define yourself to the calculation work, then map the operation name from the queencommand string to those functions:
import operator
ops = {
'addition': operator.add,
'subtraction': operator.sub,
'multiplication': operator.mul,
'division': operator.truediv
}
if queencommand.startswith("/calc"):
operation = queencommand.partition(' ')[-1]
if operation in ops:
num1 = input("Enter first number")
num2 = input("Enter second number")
Answer = ops[operation](int(num1), int(num2))
operator.add could be replaced by lambda a, b: a + b, etc. if you don't want to use a module for those operations.
Here is a fully fledged calculator. See if it helps:
def multiplication():
num1 = int(input("First #: "))
num2 = int(input("Second #: "))
ans = num1 * num2
print(ans)
def addition():
num1 = int(input("First #: "))
num2 = int(input("Second #: "))
ans = num1 + num2
print(ans)
def subtraction():
num1 = int(input("First #: "))
num2 = int(input("Second #: "))
ans = num1 - num2
print(ans)
def division():
num1 = int(input("First #: "))
num2 = int(input("Second #: "))
ans = num1 / num2
print(ans)
def Help():
print("""Welcome to Calculator P1!!!
Type "x" for multiplication.
Type "+" for addition.
Type "-" for subtraction.
Type "/" for division.""")
while True:
print("Type 'help' for introduction or instructions")
choice = input("Operator: ")
if choice == "x" or choice == "muliplication":
multiplication()
elif choice == "+" or choice == "addition":
addition()
elif choice == "-" or choice == "subtraction":
subtraction()
elif choice == "/" or choice == "division":
division()
elif choice == "help":
Help()
answer = input('Run again? (y/n): ')
if answer == 'n':
break
elif answer == 'y':
continue
else:
print("""Unrecognized Input.
<<<<RESTARTING PROGRAM>>>>""")
continue