This question already has answers here:
How to get the ASCII value of a character
(5 answers)
Closed 3 years ago.
I tried to print the escape sequence characters or the ASCII representation of numbers in Python in a for loop.
Like:
for i in range(100, 150):
b = "\%d" %i
print(b)
I expected the output like,
A
B
C
Or something.
But I got like,
\100
\101
How to print ASCII representation of the numbers?
There's a builtin function for python called ord and chr
ord is used to get the value of ASCII letter, for example:
print(ord('h'))
The output of the above is 104
ord only support a one length string
chr is inverse of ord
print(chr(104))
The output of the above is 'h'
chr only supports integer. float, string, and byte doesn't support
chr and ord are really important if you want to make a translation of a text file (encoded text file)
You can use the ord() function to print the ASCII value of a character.
print(ord('b'))
> 98
Likewise, you can use the chr() function to print the ASCII character represented by a number.
print(chr(98))
> b
Related
This question already has answers here:
Show hex value for all bytes, even when ASCII characters are present
(2 answers)
Closed 3 months ago.
The string is like "e52c886a88b6f421a9324ea175dc281478f03003499de6162ca72ddacf4b09e0", when I run the code, the output is not my expectation, like this.
hexstr = "e52c886a88b6f421a9324ea175dc281478f03003499de6162ca72ddacf4b09e0"
hexstr = bytes.fromhex(hexstr)
print(hexstr)
The output is
b'\xe5,\x88j\x88\xb6\xf4!\xa92N\xa1u\xdc(\x14x\xf00\x03I\x9d\xe6\x16,\xa7-\xda\xcfK\t\xe0'
My expected output should like b'\xe5\x2c\xc8\x86......
Your code is correct.
Python tries to be helpful by displaying bytes that map to an ASCII character as that character. For example, \x2c maps to ,.
>>> b',' == b'\x2c'
True
This question already has answers here:
How are strings compared?
(7 answers)
Closed 1 year ago.
print(4 > 5)
output is False
this is very easy to understand using basic math
print("a" > "A")
output is True
how does python compare a and A ?
Python string comparison is performed using the characters in both strings. The characters in both strings are compared one by one. When different characters are found then their Unicode value is compared. The character with lower Unicode value is considered to be smaller.
The Unicode value of 'A' is 65, whereas the for 'a' it is 97.
The ord() function returns the Unicode value of a character.
ord('A') # returns 65
ord('a') # returns 97
ord('AA') # ERROR: ord() expects a string of length 1.
"a" ascii is 97 --> ord("a")
"A" ascii is 65 --> ord("A")
Hence:
print("a" > "A") --> True
I've got a 4 number string corresponding to the code-point of an unicode character.
I need to dynamically convert it to its unicode character to be stored inside a variable.
For example, my program will spit during its loop a variable a = '0590'. (https://www.compart.com/en/unicode/U+0590)
How do I get the variable b = '\u0590'?
I've tried string concatenation '\u' + a but obviously it's not the way.
chr will take a code point as an integer and convert it to the corresponding character. You need to have an integer though, of course.
a = '0590'
result = chr(int(a))
print(result)
On Python 2, the function is called unichr, not chr. And if you want to interpret the string as a hex number, you can pass an explicit radix to int.
a = '0590'
result = unichr(int(a, 16))
print(result)
I want to create 5 hex bytes length string that is gonna be send through a socket. I want that send 255 packets changing the third byte incremntally. How can I do that?
Something like this code:
i=0
while True:
a="\x3f\x4f"+hex(i)+"\x0D\x0A"
socket.send(a)
i=i+1
The problem is that this code is introducing 0x0 (30 78 30) instead of 00 in the first loop for example.
Thank you
I think you're a bit confused here.
\x3f is a single character (the same character as ?).
If i is, say, 63 (hex 3F), you don't want to add the separate characters \\, x, 3, and f to the string, you want to add the single character \x3f. Likewise, if it's 0 (hex 00), you don't want to add the separate characters \\, x, 0 to the string, you want to add the single character \x0.
That's exactly what the chr function is for:
Return a string of one character whose ASCII code is the integer i. For example, chr(97) returns the string 'a'…
By contrast, the function hex will:
[c]onvert an integer number (of any size) to a lowercase hexadecimal string prefixed with “0x”…
So, hex(97) returns the four character string '0x61'.
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Python returning the wrong length of string when using special characters
I read a multilingual string from file in windows-1251, for example s="qwe абв" (second part in Russian), and then:
for i in s.decode('windows-1251').encode('utf-8').split():
print i, len(i)
and I get:
qwe 3
абв 6
Oh God, why? o_O
In programming languages you can't always think of strings as a sequence of characters, because generally they are actually a sequence of bytes. You can't store every character or symbol in 8 bits, character encodings create some rules to combine multiple bytes into a single character.
In the case of the string 'абв' encoded in utf-8, what you have is 6 bytes that represent 3 characters. If you want to count the number of characters instead of the number of bytes, make sure you are taking the length from a unicode string.
>>> print "абв"
абв
>>> print [char for char in "абв"]
['\xd0', '\xb0', '\xd0', '\xb1', '\xd0', '\xb2']
That's why :)