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Convert String of List to List in Python

I need to convert a string of list to List in Python. I have seen many of the similar questions but none of them works in this case.
I am passing some values through PostMan.
The key passing as a form data
Key = controls
value = [CR1,CR2]
I am fetching the data like this
c_list = self._kwargs['data'].get('controls', [])
print(c-list)
print(type(c-list))
I am getting the following o/p
[CC-2,CC-3]
<class 'str'>
But I need to get it as a list so I have tried the following method
import ast
c_list = self._kwargs['data'].get('controls', [])
res = ast.literal_eval(c_list)
But I am getting the following Error
malformed node or string: <_ast.Name object at 0x7f82966942b0>

You could simply do the following: strip the brackets and split on the commas
>>> s = "[CC-2,CC-3]"
>>> s.strip('[]').split(',')
['CC-2', 'CC-3']

Python 2.7 parsing data

I have data that look like this:
data = 'somekey:value4thekey&second-key:valu3-can.be?anything&third_k3y:it%can have spaces;too'
In a nice human-readable way it would look like this:
somekey : value4thekey
second-key : valu3-can.be?anything
third_k3y : it%can have spaces;too
How should I parse the data so when I do data['somekey'] I would get >>> value4thekey?
Note: The & is connecting all of the different items
How am I currently tackling with it
Currently, I use this ugly solution:
all = data.split('&')
for i in all:
if i.startswith('somekey'):
print i
This solution is very bad due to multiple obvious limitations. It would be much better if I can somehow parse it into a python tree object.

I'd split the string by & to get a list of key-value strings, and then split each such string by : to get key-value pairs. Using dict and list comprehensions actually makes this quite elegant:
result = {k:v for k, v in (part.split(':') for part in data.split('&'))}

You can parse your data directly to a dictionary - split on the item separator & then split again on the key,value separator ::
table = {
key: value for key, value in
(item.split(':') for item in data.split('&'))
}
This allows you direct access to elements, e.g. as table['somekey'].

If you don't have objects within a value, you can parse it to a dictionary
structure = {}
for ele in data.split('&'):
ele_split = ele.split(':')
structure[ele_split[0]] = ele_split[1]
You can now use structure to get the values:
print structure["somekey"]
#returns "value4thekey"

Since the keys have a common format of being in the form of "key":"value".
You can use it as a parameter to split on.
for i in x.split("&"):
print(i.split(":"))
This would generate an array of even items where every even index is the key and odd index being the value. Iterate through the array and load it into a dictionary. You should be good!

I'd format data to YAML and parse the YAML
import re
import yaml
data = 'somekey:value4thekey&second-key:valu3-can.be?anything&third_k3y:it%can have spaces;too'
yaml_data = re.sub('[:]', ': ', re.sub('[&]', '\n', data ))
y = yaml.load(yaml_data)
for k in y:
print "%s : %s" % (k,y[k])
Here's the output:
third_k3y : it%can have spaces;too
somekey : value4thekey
second-key : valu3-can.be?anything

Process malformed JSON string in Python

I'm trying to process a log from Symphony using Pandas, but have some trouble with a malformed JSON which I can't parse.
An example of the log :
'{id:46025,
work_assignment:43313=>43313,
declaration:<p><strong>Bijkomende interventie.</strong></p>\r\n\r\n<p>H </p>\r\n\r\n<p><strong><em>Vaststellingen.</em></strong></p>\r\n\r\n<p><strong><em>CV. </em></strong>De.</p>=><p><strong>Bijkomende interventie.</strong></p>\r\n\r\n<p>He </p>\r\n\r\n<p><strong><em>Vaststellingen.</em></strong></p>\r\n\r\n<p><strong><em>CV. </em></strong>De.</p>,conclusions:<p>H </p>=><p>H </p>}'
What is the best way to process this?
For each part (id/work_assignment/declaration/etc) I would like to retrieve the old and new value (which are separated by "=>").

Use the following code:
def clean(my_log):
my_log.replace("{", "").replace("}", "") # Removes the unneeded { }
my_items = list(my_log.split(",")) # Split at the comma to get the pairs
my_dict = {}
for i in my_items:
key, value = i.split(":") # Split at the colon to separate the key and value
my_dict[key] = value # Add to the dictionary
return my_dict
Function returns a Python dictionary, which can then be converted to JSON using a serializer if needed, or directly used.
Hope I helped :D

how to create a dictionary from a set of properly formatted tuples in python

Is there a simple way to create a dictionary from a list of formatted tuples. e.g. if I do something like:
d={"responseStatus":"SUCCESS","sessionId":"01234","userId":2000004904}
This creates a dictionary called d. However, if I want to create a dictionary from a string which contains the same string, I can't do that
res=<some command that returns {"responseStatus":"SUCCESS","sessionId":"01234","userId":2000004904}>
print res
# returns {"responseStatus":"SUCCESS","sessionId":"01234","userId":2000004904}
d=dict(res)
This throws an error that says:
ValueError: dictionary update sequence element #0 has length 1; 2 is required

I strongly strongly suspect that you have json on your hands.
import json
d = json.loads('{"responseStatus":"SUCCESS","sessionId":"01234","userId":2000004904}')
would give you what you want.

Use dict(zip(tuples))
>>> u = ("foo", "bar")
>>> v = ("blah", "zoop")
>>> d = dict(zip(u, v))
>>> d
{'foo': 'blah', 'bar': 'zoop'}
Note, if you have an odd number of tuples this will not work.

Based on what you gave is, res is
# returns {"responseStatus":"SUCCESS","sessionId":"01234","userId":2000004904}
So the plan is to grab the string starting at the curly brace to the end and use json to decode it:
import json
# Discard the text before the curly brace
res = res[res.index('{'):]
# Turn that text into a dictionary
d = json.loads(res)

All you need to do in your particular case is
d = eval(res)
And please keep security in mind when using eval, especially if you're mixing it with ajax/json.
UPDATE
Since others pointed out you might be getting this data over the web and it isn't just a "how to make this work" question, use this:
import json
json.loads(res)

How can I parse a dictionary string?

I am trying to convert a string to a dictionary with dict function, like this
import json
p = "{'id':'12589456'}"
d = dict(p)
print d['id']
But I get the following error
ValueError: dictionary update sequence element #0 has length 1; 2 is required
Why does it fail? How can I fix this?

What you have is a string, but dict function can only iterate over tuples (key-value pairs) to construct a dictionary. See the examples given in the dict's documentation.
In this particular case, you can use ast.literal_eval to convert the string to the corresponding dict object, like this
>>> p = "{'id':'12589456'}"
>>> from ast import literal_eval
>>> d = literal_eval(p)
>>> d['id']
'12589456'

Since p is a string containing JSON (ish), you have to load it first to get back a Python dictionary. Then you can access items within it:
p = '{"id":"12589456"}'
d = json.loads(p)
print d["id"]
However, note that the value in p is not actually JSON; JSON demands (and the Python json module enforces) that strings are quoted with double-quotes, not single quotes. I've updated it in my example here, but depending on where you got your example from, you might have more to do.