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How to check if only one statement equals 0?

I got some trouble with finding the matching if-statement to check if only one entry equals 0 of 3.
Here's the code:
def thanx(self):
if len(self.e.get()) == 0:
messagebox.showerror("Error", "Please enter affordable infos")
self.boo = False
else:
messagebox.showinfo("Submition done", "Thank you")
self.boo = True
It is only checking if my variable e equals 0, but i actually got 2 more entries. I know i could check every single one individually, however there has to be an easier way of doing this.
Im using "tkinter" btw, but this shouldnt be too much important.
I tried it with or but this isn't working or I'm doing it wrong.
(Also tried to solve this with lambda, but again just errors...)
Maybe someone can help me there...
Edit:
I might have explained this a bit confusing, I'll add the rest of the code here that you can understand this better:
from tkinter import Tk, Label, Entry, Button, W
from tkinter import messagebox
class MyForm:
def thanx(self):
if len(self.e.get()) == 0:
messagebox.showerror("Error", "Please enter affordable infos")
self.boo = False
else:
messagebox.showinfo("Submition done", "Thank you")
self.boo = True
def callback(self):
#print("Name: %s\nPassword: %s\nEmail: %s" % (self.e.get(), self.e2.get(),self.e3.get()))
if self.boo:
f = open("PrivatData.txt", "w+")
f.write("Name: %s\nPassword: %s\nEmail: %s" % (self.e.get(), self.e2.get(),self.e3.get()))
def __init__(self):
self.root = Tk()
self.root.title("Your privat details")
Label(self.root, text="Your Name").grid(row = 0, padx = 12, pady=5)
Label(self.root, text="Password").grid(row=1, padx=12, pady=5)
Label(self.root, text="Email").grid(row=2, padx=12, pady=5)
self.e = Entry(self.root)
self.e2 = Entry(self.root)
self.e3= Entry(self.root)
self.e.grid(row=0,column=1,columnspan=2)
self.e2.grid(row=1, column=1, columnspan=2)
self.e3.grid(row=2, column=1, columnspan=2)
self.e.focus_set()
self.show= Button(self.root, text="Submit", command=lambda:[self.thanx(),self.callback()])
self.quit = Button(self.root,text="Quit", command = self.root.quit)
self.show.grid(row=3, column=1, pady=4)
self.quit.grid(row=3, column=2, sticky = W, pady=4)
self.root.geometry("230x140")
self.root.configure(background= "#65499c")
self.root.mainloop()
if __name__ == "__main__":
app= MyForm()

Use any:
if any((len(self.e.get().strip())==0,len(self.e2.get().strip())==0,len(self.e2.get().strip())==0)):
do stuff to say that user did not input all fields
else:
do stuff to say that user inputted all fields
So full code:
from tkinter import Tk, Label, Entry, Button, W
from tkinter import messagebox
class MyForm:
def thanx(self):
if any((len(self.e.get().strip())==0,len(self.e2.get().strip())==0,len(self.e2.get().strip())==0)):
messagebox.showerror("Error", "Please enter affordable infos")
self.boo = False
else:
messagebox.showinfo("Submition done", "Thank you")
self.boo = True
def callback(self):
#print("Name: %s\nPassword: %s\nEmail: %s" % (self.e.get(), self.e2.get(),self.e3.get()))
if self.boo:
f = open("PrivatData.txt", "w+")
f.write("Name: %s\nPassword: %s\nEmail: %s" % (self.e.get(), self.e2.get(),self.e3.get()))
def __init__(self):
self.root = Tk()
self.root.title("Your privat details")
Label(self.root, text="Your Name").grid(row = 0, padx = 12, pady=5)
Label(self.root, text="Password").grid(row=1, padx=12, pady=5)
Label(self.root, text="Email").grid(row=2, padx=12, pady=5)
self.e = Entry(self.root)
self.e2 = Entry(self.root)
self.e3= Entry(self.root)
self.e.grid(row=0,column=1,columnspan=2)
self.e2.grid(row=1, column=1, columnspan=2)
self.e3.grid(row=2, column=1, columnspan=2)
self.e.focus_set()
self.show= Button(self.root, text="Submit", command=lambda:[self.thanx(),self.callback()])
self.quit = Button(self.root,text="Quit", command = self.root.quit)
self.show.grid(row=3, column=1, pady=4)
self.quit.grid(row=3, column=2, sticky = W, pady=4)
self.root.geometry("230x140")
self.root.configure(background= "#65499c")
self.root.mainloop()
if __name__ == "__main__":
app= MyForm()

I am assuming that at the moment you are checking if some string element equals 0.
For example
e = 'abc'
len(e) == 3 # True
l = []
len(l) == 0 # True
If you want to check if your string variable is 0 then simply:
if not self.e.get():
messagebox.showerror("Error")
self.boo = False

You may try this:
if len(self.e.get()) == 0 or len(self.e2.get()) == 0 or len(self.e3.get()) == 0:
messagebox.showerror("Error", "Please enter affordable infos")
self.boo = False
else:
messagebox.showinfo("Submition done", "Thank you")
self.boo = True
Since you have 3 variables, there's no way to check them all 'in batch' unless you build a data structure containing them and then check some conditions on that data structure. However, it does not give any advantage. If you add a new variable, say e4, you still have to add it manually to the the data structure.

To ensure that all three textboxes are not empty in one if statement, you can use the following:
if "" in [self.e.get().strip(), self.e2.get().strip(), self.e3.get().strip()]:
messagebox.showerror("Error", "Please enter affordable infos")
self.boo = False
else:
messagebox.showinfo("Submition done", "Thank you")
self.boo = True
This is a short and neat way to write what you are trying to do. This works because entry widgets will return "" if they are empty, and self.e.get().strip() makes the text returned empty (.strip() removes all whitespace at both the start and the end of the string) if it is just whitespace (" ", \t, n, etc...).
It is better to check the contents of the string rather than the length of it, because a box with just whitespace in it will not return 0, as shown below.
>>> len(" ")
1
>>> len("")
0
>>> len("\t")
1

I cant generate a random number and print it

I can't generate the number because I get the error NameError: name 'z' is not defined.
import tkinter as tk
from random import randint
def randomize():
z.set ( randint(x.get(),y.get()))
root = tk.Tk()
x = tk.IntVar()
y = tk.IntVar()
text= tk.Label(root, text = "press the button for random number")
enterX = tk.Entry(root)
enterY = tk.Entry(root)
button = tk.Button(root, text = "Press here", command=randomize)
result = tk.Label(root,text="Number is:")
number = tk.Label(root, textvariable=z)
text.pack()
enterX.pack()
enterY.pack()
button.pack()
result.pack()
number.pack()
root.mainloop()
I need help to resolve the error

You have 2 problems here.
One. You are missing z = tk.Intvar() in the global namespace.
Two. You need to assign each entry field one of the IntVar()'s.
Keep in mind that you are not validating the entry fields so if someone types anything other than a whole number you will run into an error.
Take a look at this code.
import tkinter as tk
from random import randint
def randomize():
z.set(randint(x.get(),y.get()))
print(z.get()) # added print statement to verify results.
root = tk.Tk()
x = tk.IntVar()
y = tk.IntVar()
z = tk.IntVar() # added IntVar()
text= tk.Label(root, text = "press the button for random number")
enterX = tk.Entry(root, textvariable=x) # added textvariable
enterY = tk.Entry(root, textvariable=y) # added textvariable
button = tk.Button(root, text = "Press here", command=randomize)
result = tk.Label(root,text="Number is:")
number = tk.Label(root, textvariable=z)
text.pack()
enterX.pack()
enterY.pack()
button.pack()
result.pack()
number.pack()
root.mainloop()

Tkinter questionnaire based on get() method

I am trying to make my first GUI script based on the answers of 2 questions. I'll show an example of the non GUI script
while True:
ammount = input("What is your debt")
if ammount.isdigit() == True:
break
else:
print("Please try typing in a number")
while True:
month = input("In which month did the debt originate?")
if month not in ["January", "February"]:
print("Try again")
else:
break
The point of this script is that it is scalable with all the questions one may add, I want to understand it in the same way in Tkinter. I'll show what I've tried:
from tkinter import *
def click():
while True:
entered_text = text_entry.get()
if entered_text .isdigit() == False:
error = Label(window, text="Try again", bg = "black", fg="red", font="none 11").grid(row = 3, column = 2, sticky= W).pack()
else:
break
return True
window = Tk()
window.title("Tax calculator")
window.configure(background="black")
monto = Label(window, text="¿What is your debt?", bg="black", fg="white", font="none 12 bold")
monto.grid(row = 1, column = 0, sticky= W)
text_entry = Entry(window, width = 20, bg="white")
text_entry.grid(row = 2, column=2, sticky=W)
output = Button(window, text = "Enter", width = 6, command = click)
output.grid(row = 3, column = 0, sticky = W)
The thing is, I can't add a Label() method in the if/else of the click() method, because I would like to ask a new question once the condition is met. I can't also can't get True from click once the condition is met, because the input comes from Button() method. Thanks in advance

You don't actually need any loops here, a simple if statement would be enough to do the trick. Also, there is no need to recreate the label every time, you can just configure() its text. And, note that indexing starts from 0 - so, in your grid, actual first row (and column) needs to be numbered 0, not 1. Besides that, I suggest you get rid of import *, since you don't know what names that imports. It can replace names you imported earlier, and it makes it very difficult to see where names in your program are supposed to come from. You might want to read what PEP8 says about spaces around keyword arguments, as well:
import tkinter as tk
def click():
entered_text = text_entry.get()
if not entered_text.isdigit():
status_label.configure(text='Please try again')
text_entry.delete(0, tk.END)
else:
status_label.configure(text='Your tax is ' + entered_text)
text_entry.delete(0, tk.END)
root = tk.Tk()
root.title('Tax calculator')
root.configure(background='black')
monto = tk.Label(root, text='¿What is your debt?', bg='black', fg='white', font='none 12 bold')
monto.grid(row=0, column=0, padx=10, pady=(10,0))
text_entry = tk.Entry(root, width=20, bg='white')
text_entry.grid(row=1, column=0, pady=(10,0))
status_label = tk.Label(root, text='', bg='black', fg='red', font='none 11')
status_label.grid(row=2, column=0)
button = tk.Button(root, text='Enter', width=17, command=click)
button.grid(row=3, column=0, pady=(0,7))
root.mainloop()
I forgot to mention, if your application gets bigger, you might be better off using a class.

Python Tkinter StringVar only displaying Py_Var(number)

I am using Tkinter in python 3.4 to make a text based game, and I cannot figure out how to get a string from an Entry widget, it just returns Py_Var#, # being a number. I have looked at answers to similar questions, but none of them quite line up with what I need and have. Here's the relevant pieces of code:
from tkinter import *
win = Tk()
win.geometry("787x600")
playername = StringVar()
def SubmitName():
playername.get
#messagebox.showinfo("Success", playername)
print(playername)
frame3 = Frame(win)
frame3.pack()
label1 = Label(frame3, text="You awaken in a room, with no memories of yourself or your past. ")
label2 = Label(frame3, text="First, how about you give yourself a name:")
label1.config(font=("Courier", 11))
label2.config(font=("Courier", 11))
entry1 = Entry(frame3, textvariable=playername)
entry1.config(font=("Courier", 11))
label1.grid(row=0, column=0, columnspan=3)
label2.grid(row=1, column=0)
entry1.grid(row=1, column=1)
bnamesub= Button(frame3, text="Submit", command=lambda: SubmitName())
bnamesub.grid()
win.mainloop()
Also, first time using stackoverflow and its reading weird but w/e.

You have two mistakes in SubmitName().
First, you need to get the text like this:
txt = playername.get()
Then you need to print that txt:
print(txt)
By mistake you printed the StringVar variable itself.

from tkinter import *
import pickle
win = Tk()
win.geometry("787x600")
def SubmitName():
playername = entry1.get()
messagebox.showinfo("Success", playername)
print(playername)
frame3 = Frame(win)
frame3.grid()
label1 = Label(frame3, text="You awaken in a room, with no memories of yourself or your past. ")
label2 = Label(frame3, text="First, how about you give yourself a name:")
label1.config(font=("Courier", 11))
label2.config(font=("Courier", 11))
#name entered is a StringVar, returns as Py_Var7, but I need it to return the name typed into entry1.
entry1 = Entry(frame3)
entry1.config(font=("Courier", 11))
label1.grid(row=0, column=0, columnspan=3)
label2.grid(row=1, column=0)
entry1.grid(row=1, column=1)
bnamesub= Button(frame3, text="Submit", command=lambda: SubmitName())
bnamesub.grid()
What I changed:
-deleted playername = StringVar(). We don't really need it;
-changed inside the function: changed playername.get to playername = entry1.get();
-added frame3.grid() (without geometry managment, widgets cannot be shown on the screen.);
-also, a little edit: in Python, comments are created with # sign. So I changed * to #.

I was happy to find a solution here, but all these answers "as it is" are not working with my setting, python3.8, pycharm 2018.2
So if anyone could answer this, it seems that entry1.get() cannot be used as a string. I first wanted to append it in a list, and I did a more simple version to point out the trouble :
from tkinter import *
import pickle
win = Tk()
win.geometry("300x300")
#playername = StringVar()
def SubmitName():
labell = Label(win, text="Little tryup").grid()
playername = entry1.get()
# result about line 11: 'NoneType' object has no attribute 'get'
labelle = Label(win, text=playername).grid()
# print(txt)
label1 = Label(win, text="Enter a name:").grid()
entry1 = Entry(win).grid()
boutonne = Button(win, text="label-it!", command=lambda: SubmitName())
boutonne.grid()
win.mainloop()

Python Tkinter error: "Label has no __call__method"

Im trying to create a Python tkinter login registeration but running into a small issue.
The error message is:
self.Label_Name = Label(top, text="What is your username: ")
AttributeError: Label instance has no __call__ method
Please can you proof read my code:
from Tkinter import *
class Register:
def __init__(self, parent):
top = self.top = Toplevel(parent)
# Variables to store the entries
self.VarEntUser = StringVar()
self.VarEntPass = StringVar()
self.VarEntRetype = StringVar()
self.Label_Name = Label(top, text="What is your username: ")
self.Label_Password = Label(top, text="Enter a password: ")
self.Label_Retype = Label(top, text="Retype Password: ")
# Entry fields for the user to enter there details
self.Ent_Name = Entry(top, textvariable=self.VarEntUser)
self.Ent_Password = Entry(top, textvariable=self.VarEntPass)
self.Ent_Retype = Entry(top, textvariable=self.VarEntRetype)
# Puts all the fields ^, into the window
self.Label_Name.grid(row=0, sticky=W)
self.Label_Password.grid(row=1, sticky=W)
self.Label_Retype.grid(row=2, sticky=W)
self.Ent_Password.grid(row=1, column=1)
self.Ent_Retype.grid(row=2, column=1)
self.Ent_Name.grid(row=0, column=2)
# Run the RegisterCheck function
# submit button which Checks the Entered details then writes the user and pass to a .txt file
self.MySubmitButton = Button(top, text='Submit', command=RegisterCheck)
self.MySubmitButton.pack()
self.U = raw_input(self.VarEntUser.get())
self.P = raw_input(self.VarEntPass.get())
self.R = raw_input(self.VarEntRetype.get())
class LogIn:
def __init__(self, parent):
top = self.top = Toplevel(parent)
self.a = StringVar()
self.b = StringVar()
self.Label_Log_User1 = Label(top, text='Username:')
self.Label_Log_Pass = Label(top, text='Password: ')
self.Ent_User_Log = Entry(top, textvariable=self.a)
self.Ent_Pass_Log = Entry(top, textvariable=self.b)
self.Label_Log_User1.grid(row=1)
self.Pass_Log.grid(row=2)
self.EntUserLog.grid(row=1, column=1)
self.EntPassLog.grid(row=2, column=1)
self.User = raw_input(self.EntUserLog.get())
self.Pass = raw_input(self.EntUserLog.get())
# runs the 'LoginCheck' function
self.LogInButton = Button(top, text="Log In", command=LogInCheck)
self.LogInButton.pack()
def LogInCheck(self):
# Checks if the fields are blanking displaying an error
if len(self.User) <= 0 and len(self.Pass) <= 0:
print "Please fill in all fields."
else:
pass
# Checks to see if the user and pass have been created
if self.User in 'username.txt' and self.Pass in 'password':
print 'You are now logged in!'
else:
print "Log in Failed"
def RegisterCheck(self):
# Checks if the fields are blank
if len(self.P) <= 0 and len(self.U) <= 0:
print "Please fill out all fields."
else:
pass
# Check is the password and the retype match
if self.P == self.R:
pass
else:
print "Passwords do not match"
# After registering write the user and pass to a .txt file
with open('username.txt', 'a') as fout:
fout.write(self.U + '\n')
with open('password.txt', 'a') as fout:
fout.write(self.P + '\n')
# Depending on what the user chooses, either log in or register than opens the specific window
def launch_Register():
inputDialog = Register(root)
root.wait_window(inputDialog.top)
def launch_LogIn():
inputdialog2 = LogIn(root)
root.wait_window(inputdialog2.top)
root = Tk()
label = Label(root, text='Choose an option')
label.pack()
loginB = Button(root, text='Log In', command=launch_LogIn)
loginB.pack()
registerB = Button(root, text='Register', command=launch_Register)
registerB.pack()
root.mainloop()

The problem is that in this line
Label = Label(root, text='Choose an option')
you define a Label called Label, thus shadowing the Label constructor. Then, then you create the several labels in your Register and Login classes (triggered by those two buttons), the name Label is no longer bound to the constructor, but to that specific label.
Change the name of the label, then it should work. Also, I would advise you to use lower-case names for variables and methods. This alone might help prevent many such errors.
root = Tk()
label = Label(root, text='Choose an option')
label.pack()
loginB = Button(root, text='Log In', command=launch_LogIn)
loginB.pack()
registerB = Button(root, text='Register', command=launch_Register)
registerB.pack()
root.mainloop()
Note that there are a few many more problems with your code:
StringVar a and b should probably be self.a and self.b
You are trying to use raw_input to get the user input in the Entry widgets; this is wrong! Instead, just read the value of the variables to get the values, e.g. instead of self.User, use self.a.get()
do not mix grid and pack layout
if self.User in 'username.txt' will not check whether that name is in that file
loginCheck and registerCheck should be methods of the respective class
Once I'm at it, here's (part of) my version of your code, to help you getting started:
class Register:
def __init__(self, parent):
top = self.top = Toplevel(parent)
self.var_user = StringVar()
self.var_pass = StringVar()
self.var_retype = StringVar()
Label(top, text="What is your username: ").grid(row=0, sticky=W)
Label(top, text="Enter a password: ").grid(row=1, sticky=W)
Label(top, text="Retype Password: ").grid(row=2, sticky=W)
Entry(top, textvariable=self.var_user).grid(row=0, column=1)
Entry(top, textvariable=self.var_pass).grid(row=1, column=1)
Entry(top, textvariable=self.var_retype).grid(row=2, column=1)
Button(top, text='Submit', command=self.registerCheck).grid(row=3)
def registerCheck(self):
u, p, r = self.var_user.get(), self.var_pass.get(), self.var_retype.get()
if p and u:
if p == r:
logins[u] = p
else:
print "Passwords do not match"
else:
print "Please fill out all fields."
class LogIn:
# analogeous to Register; try to figure this out xourself
def launch_Register():
inputDialog = Register(root)
root.wait_window(inputDialog.top)
def launch_LogIn():
inputDialog = LogIn(root)
root.wait_window(inputDialog.top)
logins = {}
root = Tk()
Label(root, text='Choose an option').pack()
Button(root, text='Log In', command=launch_LogIn).pack()
Button(root, text='Register', command=launch_Register).pack()
root.mainloop()
Note that I changed the login "database" from files to a dictionary to keep things simple and to focus on the Tkinter problems. Of course, neither a simple dictionary nor a plain-text file is an appropriate way to store login information.
Also, I put the creation and the layout of the GUI widgets on one line. In this case this is possible since we do not need a reference to those widgets, but beware never to do e.g. self.label = Label(...).grid(...), as this will bind self.label to the result of grid, and not to the actual Label.
Finally, this will still print all the messages to the standard output. Instead, you should add another Label for that, or open a message dialogue, but this is left as an excercise to the reader...