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Get user input for a Python script ran from a bash script

Tldr at the end
I have a simple Python script with a few functions, let's give this main.py as a minimal example :
import sys
def userAdd():
var = input("Please type any input: ")
print("My input is", var)
if __name__ == '__main__':
globals()[sys.argv[1]]()
When I call :
python main.py userAdd
Everything works fine. The script runs, the Python console asks me for my input, and then edits the JSON file. Now I want this script to be executed everytime I edit a text file, let's say myfile.txt which for now only has this line :
foo
For this, I use this bash script and changed the "RUN COMMAND" line with python main.py userAdd (let's call it update.sh):
#!/bin/bash
### Set initial time of file
LTIME=`stat -c %Z ./myfile.txt`
while true
do
ATIME=`stat -c %Z ./myfile.txt`
if [[ "$ATIME" != "$LTIME" ]]
then
python main.py userAdd
LTIME=$ATIME
fi
sleep 1
done
My problem happens here. Everytime the Python script is called from the Bash script, the input prompt shows up. I enter a value, and I get a bash : <input> command not found, which means the current tty I'm using isn't Python, but Bash
$ chmod +x update.sh
$ ./update.sh &
$ echo "bar" >> myfile.txt
$ Please type any input: test
bash: test : command not found
I tried a few things (using /usr/bin/env and /dev/tty or <&1, or using python -i).
tldr; My Python script asks for a user input to update a file. When I run it directly from my bash terminal (python main.py myfunction), it works fine. When I run this Python script from a Bash script (which contains this same python [...] line) and type my input, I get a bash <input> command not found. This means that the terminal isn't Python's but Bash's. How can I get a Python terminal which will accept my input in this case ?

For anyone who might be facing the same issue, here's how I solved it : I edited the line from update.sh invoking the Python script like so :
#!/bin/bash
### Set initial time of file
LTIME=`stat -c %s ./myfile.txt`
while true
do
ATIME=`stat -c %s ./myfile.txt`
if [[ "$ATIME" >= "$LTIME" ]]
then
/usr/bin/konsole -e /usr/bin/bash -c './main.py userAdd'
LTIME=$ATIME
fi
sleep 1
done
So this line ties me up to a specific terminal, but I think this could easily be bypassed by more advanced Linux users.
Then, when I run the script using ./update.sh & and add this line to a cron, everytime I edit and close the file, a new terminal runs, asks for the input prints the results then closes (although for the sake of the example a wait() command should be added after the print()).

Error in check_call() subprocess, executing 'mv' unix command: "Syntax error: '(' unexpected"

I'm making a python script for Travis CI.
.travis.yml
...
script:
- support/travis-build.py
...
The python file travis-build.py is something like this:
#!/usr/bin/env python
from subprocess import check_call
...
check_call(r"mv !(my_project|cmake-3.0.2-Darwin64-universal) ./my_project/final_folder", shell=True)
...
When Travis building achieves that line, I'm getting an error:
/bin/sh: 1: Syntax error: "(" unexpected
I just tried a lot of different forms to write it, but I get the same result. Any idea?
Thanks in advance!
Edit
My current directory layout:
- my_project/final_folder/
- cmake-3.0.2-Darwin64-universal/
- fileA
- fileB
- fileC
I'm trying with this command to move all the current files fileA, fileB and fileC, excluding my_project and cmake-3.0.2-Darwin64-universal folders into ./my_project/final_folder. If I execute this command on Linux shell, I get my aim but not through check_call() command.
Note: I can't move the files one by one, because there are many others
I don't know which shell Travis are using by default because I don't specify it, I only know that if I write the command in my .travis.yml:
.travis.yml
...
script:
# Here is the previous Travis code
- mv !(my_project|cmake-3.0.2-Darwin64-universal) ./my_project/final_folder
...
It works. But If I use the script, it fails.
I found this command from the following issue:
How to use 'mv' command to move files except those in a specific directory?

You're using the bash feature extglob, to try to exclude the files that you're specifying. You'll need to enable it in order to have it exclude the two entries you're specifying.
The python subprocess module explicitly uses /bin/sh when you use shell=True, which doesn't enable the use of bash features like this by default (it's a compliance thing to make it more like original sh).
If you want to get bash to interpret the command; you have to pass it to bash explicitly, for example using:
subprocess.check_call(["bash", "-O", "extglob", "-c", "mv !(my_project|cmake-3.0.2-Darwin64-universal) ./my_project/final_folder"])
I would not choose to do the job in this manner, though.

Let me try again: in which shell do you expect your syntax !(...) to work? Is it bash? Is it ksh? I have never used it, and a quick search for a corresponding bash feature led nowhere. I suspect your syntax is just wrong, which is what the error message is telling you. In that case, your problem is entirely independent form python and the subprocess module.
If a special shell you have on your system supports this syntax, you need to make sure that Python is using the same shell when invoking your command. It tells you which shell it has been using: /bin/sh. This is usually just a link to the real shell executable. Does it point to the same shell you have tested your command in?
Edit: the SO solution you referenced contains the solution in the comments:
Tip: Note however that using this pattern relies on extglob. You can
enable it using shopt -s extglob (If you want extended globs to be
turned on by default you can add shopt -s extglob to .bashrc)
Just to demonstrate that different shells might deal with your syntax in different ways, first using bash:
$ !(uname)
-bash: !: event not found
And then, using /bin/dash:
$ !(uname)
Linux

The argument to a subprocess.something method must be a list of command line arguments. Use e.g. shlex.split() to make the string be split into correct command line arguments:
import shlex, subprocess
subprocess.check_call( shlex.split("mv !(...)") )
EDIT:
So, the goal is to move files/directories, with the exemption of some file(s)/directory(ies). By playing around with bash, I could get it to work like this:
mv `ls | grep -v -e '\(exclusion1\|exclusion2\)'` my_project
So in your situation that would be:
mv `ls | grep -v -e '\(myproject\|cmake-3.0.2-Darwin64-universal\)'` my_project
This could go into the subprocess.check_call(..., shell=True) and it should do what you expect it to do.

Sha-bang line gives different result than calling the script manually

I have a Python script script.py that has been defined as executable and which begins with the following sha-bang:
#!/usr/bin/env python -W all
But when I call it from the shell, this is what I get:
$ ./script.py
/usr/bin/env: python -W all: No such file or directory
Calling it directly works though:
$ env python -W all script.py
... some good stuff happens here
What am I doing wrong here?

On a shebang line, you only get one argument. So python -W all is being passed to env as one argument. On the command line, the shell correctly parses the arguments before invoking env.

Shell Script: Execute a python program from within a shell script

I've tried googling the answer but with no luck.
I need to use my works supercomputer server, but for my python script to run, it must be executed via a shell script.
For example I want job.sh to execute python_script.py
How can this be accomplished?

Just make sure the python executable is in your PATH environment variable then add in your script
python path/to/the/python_script.py
Details:
In the file job.sh, put this
#!/bin/sh
python python_script.py
Execute this command to make the script runnable for you : chmod u+x job.sh
Run it : ./job.sh

Method 1 - Create a shell script:
Suppose you have a python file hello.py
Create a file called job.sh that contains
#!/bin/bash
python hello.py
mark it executable using
$ chmod +x job.sh
then run it
$ ./job.sh
Method 2 (BETTER) - Make the python itself run from shell:
Modify your script hello.py and add this as the first line
#!/usr/bin/env python
mark it executable using
$ chmod +x hello.py
then run it
$ ./hello.py

Save the following program as print.py:
#!/usr/bin/python3
print('Hello World')
Then in the terminal type:
chmod +x print.py
./print.py

You should be able to invoke it as python scriptname.py e.g.
# !/bin/bash
python /home/user/scriptname.py
Also make sure the script has permissions to run.
You can make it executable by using chmod u+x scriptname.py.

Imho, writing
python /path/to/script.py
Is quite wrong, especially in these days. Which python? python2.6? 2.7? 3.0? 3.1? Most of times you need to specify the python version in shebang tag of python file. I encourage to use #!/usr/bin/env python2 #or python2.6 or python3 or even python3.1 for compatibility.
In such case, is much better to have the script executable and invoke it directly:
#!/bin/bash
/path/to/script.py
This way the version of python you need is only written in one file. Most of system these days are having python2 and python3 in the meantime, and it happens that the symlink python points to python3, while most people expect it pointing to python2.

This works for me:
Create a new shell file job. So let's say:
touch job.sh and add command to run python script (you can even add command line arguments to that python, I usually predefine my command line arguments).
chmod +x job.sh
Inside job.sh add the following py files, let's say:
python_file.py argument1 argument2 argument3 >> testpy-output.txt && echo "Done with python_file.py"
python_file1.py argument1 argument2 argument3 >> testpy-output.txt && echo "Done with python_file1.py"
Output of job.sh should look like this:
Done with python_file.py
Done with python_file1.py
I use this usually when I have to run multiple python files with different arguments, pre defined.
Note: Just a quick heads up on what's going on here:
python_file.py argument1 argument2 argument3 >> testpy-output.txt && echo "completed with python_file.py" .
Here shell script will run the file python_file.py and add multiple command-line arguments at run time to the python file.
This does not necessarily means, you have to pass command line arguments as well.
You can just use it like: python python_file.py, plain and simple.
Next up, the >> will print and store the output of this .py file in the testpy-output.txt file.
&& is a logical operator that will run only after the above is executed successfully and as an optional echo "completed with python_file.py" will be echoed on to your cli/terminal at run time.

This works best for me:
Add this at the top of the script:
#!c:/Python27/python.exe
(C:\Python27\python.exe is the path to the python.exe on my machine)
Then run the script via:
chmod +x script-name.py && script-name.py

I use this and it works fine
#/bin/bash
/usr/bin/python python python_script.py

Since the other posts say everything (and I stumbled upon this post while looking for the following).
Here is a way how to execute a python script from another python script:
Python 2:
execfile("somefile.py", global_vars, local_vars)
Python 3:
with open("somefile.py") as f:
code = compile(f.read(), "somefile.py", 'exec')
exec(code, global_vars, local_vars)
and you can supply args by providing some other sys.argv

Here I have demonstrated an example to run python script within a shell script. For different purposes you may need to read the output from a shell command, execute both python script and shell command within the same file.
To execute a shell command from python use os.system() method. To read output from a shell command use os.popen().
Following is an example which will grep all processes having the text sample_program.py inside of it. Then after collecting the process IDs (using python) it will kill them all.
#!/usr/bin/python3
import os
# listing all matched processes and taking the output into a variable s
s = os.popen("ps aux | grep 'sample_program.py'").read()
s = '\n'.join([l for l in s.split('\n') if "grep" not in l]) # avoiding killing the grep itself
print("To be killed:")
print(s)
# now manipulating this string s and finding the process IDs and killing them
os.system("kill -9 " + ' '.join([x.split()[1] for x in s.split('\n') if x]))
References:
Execute a python program from within a shell script
Assign output of os.system to a variable and prevent it from being displayed on the screen

If you have a bash script and you need to run inside of it a python3 script (with external modules), I recommend that you point in your bash script to your python path like this.
#!/usr/bin/env bash
-- bash code --
/usr/bin/python3 your_python.py
-- bash code --

How to use export with Python on Linux

I need to make an export like this in Python :
# export MY_DATA="my_export"
I've tried to do :
# -*- python-mode -*-
# -*- coding: utf-8 -*-
import os
os.system('export MY_DATA="my_export"')
But when I list export, "MY_DATA" not appear :
# export
How I can do an export with Python without saving "my_export" into a file ?

export is a command that you give directly to the shell (e.g. bash), to tell it to add or modify one of its environment variables. You can't change your shell's environment from a child process (such as Python), it's just not possible.
Here's what's happening when you try os.system('export MY_DATA="my_export"')...
/bin/bash process, command `python yourscript.py` forks python subprocess
|_
/usr/bin/python process, command `os.system()` forks /bin/sh subprocess
|_
/bin/sh process, command `export ...` changes its local environment
When the bottom-most /bin/sh subprocess finishes running your export ... command, then it's discarded, along with the environment that you have just changed.

You actually want to do
import os
os.environ["MY_DATA"] = "my_export"

Another way to do this, if you're in a hurry and don't mind the hacky-aftertaste, is to execute the output of the python script in your bash environment and print out the commands to execute setting the environment in python. Not ideal but it can get the job done in a pinch. It's not very portable across shells, so YMMV.
$(python -c 'print "export MY_DATA=my_export"')
(you can also enclose the statement in backticks in some shells ``)

Not that simple:
python -c "import os; os.putenv('MY_DATA','1233')"
$ echo $MY_DATA # <- empty
But:
python -c "import os; os.putenv('MY_DATA','123'); os.system('bash')"
$ echo $MY_DATA #<- 123

I have an excellent answer.
#! /bin/bash
output=$(git diff origin/master..origin/develop | \
python -c '
# DO YOUR HACKING
variable1_to_be_exported="Yo Yo"
variable2_to_be_exported="Honey Singh"
… so on
magic=""
magic+="export onShell-var1=\""+str(variable1_to_be_exported)+"\"\n"
magic+="export onShell-var2=\""+str(variable2_to_be_exported)+"\""
print magic
'
)
eval "$output"
echo "$onShell-var1" // Output will be Yo Yo
echo "$onShell-var2" // Output will be Honey Singh
Mr Alex Tingle is correct about those processes and sub-process stuffs
How it can be achieved is like the above I have mentioned.
Key Concept is :
Whatever printed from python will be stored in the variable in the catching variable in bash [output]
We can execute any command in the form of string using eval
So, prepare your print output from python in a meaningful bash commands
use eval to execute it in bash
And you can see your results
NOTE
Always execute the eval using double quotes or else bash will mess up your \ns and outputs will be strange
PS: I don't like bash but your have to use it

I've had to do something similar on a CI system recently. My options were to do it entirely in bash (yikes) or use a language like python which would have made programming the logic much simpler.
My workaround was to do the programming in python and write the results to a file.
Then use bash to export the results.
For example:
# do calculations in python
with open("./my_export", "w") as f:
f.write(your_results)
# then in bash
export MY_DATA="$(cat ./my_export)"
rm ./my_export # if no longer needed

You could try os.environ["MY_DATA"] instead.

Kind of a hack because it's not really python doing anything special here, but if you run the export command in the same sub-shell, you will probably get the result you want.
import os
cmd = "export MY_DATA='1234'; echo $MY_DATA" # or whatever command
os.system(cmd)

In the hope of providing clarity over common cinfusion...
I have written many python <--> bash <--> elfbin toolchains and the proper way to see it is such as this:
Each process (originator) has a state of the environment inherited from whatever invoked it. Any change remains lokal to that process. Transfering an environment state is a function by itself and runs in two directions, each with it's own caveats. The most common thing is to modify environment before running a sub-process. To go down to the metal, look at the exec() - call in C. There is a variant that takes a pointer to environment data. This is the only actually supported transfer of environment in typical OS'es.
Shell scripts will create a state to pass when running children when you do an export. Otherwise it just uses that which it got in the first place.
In all other cases it will be some generic mechanism used to pass a set of data to allow the calling process itself to update it's environment based on the result of the child-processes output.
Ex:
ENVUPDATE = $(CMD_THAT_OUTPUTS_KEYVAL_LISTS)
echo $ENVUPDATE > $TMPFILE
source $TMPFILE
The same can of course be done using json, xml or other things as long as you have the tools to interpret and apply.
The need for this may be (50% chance) a sign of misconstruing the basic primitives and that you need a better config or parameter interchange in your solution.....
Oh, in python I would do something like...
(need improvement depending on your situation)
import re
RE_KV=re.compile('([a-z][\w]*)\s*=\s*(.*)')
OUTPUT=RunSomething(...) (Assuming 'k1=v1 k2=v2')
for kv in OUTPUT.split(' ')
try:
k,v=RE_KV.match(kv).groups()
os.environ[k]=str(v)
except:
#The not a property case...
pass

One line solution:
eval `python -c 'import sysconfig;print("python_include_path={0}".format(sysconfig.get_path("include")))'`
echo $python_include_path # prints /home/<usr>/anaconda3/include/python3.6m" in my case
Breakdown:
Python call
python -c 'import sysconfig;print("python_include_path={0}".format(sysconfig.get_path("include")))'
It's launching a python script that
imports sysconfig
gets the python include path corresponding to this python binary (use "which python" to see which one is being used)
prints the script "python_include_path={0}" with {0} being the path from 2
Eval call
eval `python -c 'import sysconfig;print("python_include_path={0}".format(sysconfig.get_path("include")))'`
It's executing in the current bash instance the output from the python script. In my case, its executing:
python_include_path=/home/<usr>/anaconda3/include/python3.6m
In other words, it's setting the environment variable "python_include_path" with that path for this shell instance.
Inspired by:
http://blog.tintoy.io/2017/06/exporting-environment-variables-from-python-to-bash/

import os
import shlex
from subprocess import Popen, PIPE
os.environ.update(key=value)
res = Popen(shlex.split("cmd xxx -xxx"), stdin=PIPE, stdout=PIPE, stderr=PIPE,
env=os.environ, shell=True).communicate('y\ny\ny\n'.encode('utf8'))
stdout = res[0]
stderr = res[1]

os.system ('/home/user1/exportPath.ksh')
exportPath.ksh:
export PATH=MY_DATA="my_export"