This question already has answers here:
Formatting floats without trailing zeros
(21 answers)
Closed 3 years ago.
I want to print a float value but if the value has no decimal (1.0, 2.0 etc, etc) I want to either remove the .0 part or convert it into an int so it removes the .0 anyway. Just for visual effect.
output:
You started with: 1.0
Wanted output:
You started with: 1
you can check if the number is a whole number or not
number = 1.5
if number.is_integer():
number = int(number)
print(number)
Related
This question already has answers here:
How to display a float with two decimal places?
(13 answers)
Closed 3 years ago.
I want number from input to print out with 2 decimal places. You can assume that the number will always be a float.
num = 20.0
Desired output - 20.00.
I've tried this code:
num = round(num, 2)
num = float('{0.2f}'.format(num))
print(num)
This should work
print('{0.2f}'.format(num))
When you turn this string back into a float with float() the formatting is lost.
No matter what you do to the float value, as long as it is still a float, it does not have any internal concept of decimal places.
If you want to display two decimal places, then that happens when you convert to text - which everything you print is, whether you asked for the conversion or not. You cannot make num "be" 20.00 as opposed to 20.0, because those aren't actually different things. (And keep in mind that the float simply cannot represent all decimal values exactly.)
Therefore, we use string formatting in the print call:
num = 20.0
print('{.2f}'.format(num))
# Or, using f-strings:
print(f'{num:.2f}')
This question already has answers here:
How to print float to n decimal places including trailing 0s?
(5 answers)
Closed 5 years ago.
Can we get up to 2 precision values when we add 2 float values of containing 0 as 2nd precision without changing its type as Float
I have a snippet like
a = 1.20+1.20
print a
the output should be like
2.40
but I got the output as 2.4 because python rounds off
I've tried like this ,
from decimal import *
getcontext().prec = 3
Decimal(1.20)+Decimal(1.20)
Decimal('2.40')
But every time I need to change the precision value!
can we get as 2.40 without changing its type?
It should contain a float value as 2.40, not a string!
Yes! you can round a float number.
>>> round(2.675, 2)
2.67
You can see more details in python's documentation
This question already has answers here:
How can I format a decimal to always show 2 decimal places?
(13 answers)
Closed 5 years ago.
I have the following:
'{0:n}'.format(0/10.0)
which evaluates to
0
I want it to evaluate to
0.0
That is, there should always be 1 decimal place. What is the correct format for this?
Thanks.
print('{0:3.1f}'.format(0/10.0)) # '0.0'
f for fixed-point notation; 3 for the total number of places to be reserved for the whole string, 1 for the decimal places.
if your number is too big to fit into the 3 reserved spaces, the string will use more space:
print('{0:3.1f}'.format(10.0)) # '10.0'; 4 places
with a more recent python version you can use f-strings (i put the value in a variable for more legibility)
x= 0/10.0
print('f{x:3.1f}')
In [24]: "{0:.1f}".format(0)
Out[24]: '0.0'
If you change the data to float you the decimal .
a= 1.0 # "a" is a float
a= 1 # "a" is now a integer
try that :)
This question already has answers here:
Rounding a number in Python but keeping ending zeros
(6 answers)
Closed 6 years ago.
So let's say I have this code:
num = 1.29283
round(num, 2)
That rounds to 1.29, but if I do this:
num = 1.30293
round(num, 2)
That rounds to 1.3. I want to know if there is a way to have it round to 1.30; I know it is the same number, but I need it to print 1.30.
You can use string formatting for this. A number in python does not have such a thing as trailing zeros. So your question only make sense for strings.
Example:
>>> num = 1.30293
>>> "{:.2f}".format(num)
'1.30'
The .2f says that this is a float (f) and that you want two digits after the point .2. Read more about string formatting here
This question already has answers here:
Formatting floats without trailing zeros
(21 answers)
Closed 8 years ago.
I have written a code that will add up the values in a tuple and calculate the average:
def average(values):
return sum(values[0:]) / len(values[0:])
However, I get an unwanted floating point, like 2.0 instead of 2. How do I eliminate this, but still manage to get the correct average should the average not be an integer?
You may try like this:
if (yournumber).is_integer():
print int(n)
else
print (n)