I am trying to read an excel file from a NAS using Jupyter Notebook (macOS, Python 3, SynologyDS218+).
Script worked absolutely fine when the file was stored locally, but I cannot determine the correct code or file path adjustment to access the file once moved to the NAS.
I am logged into the NAS and from Mac Finder the file path is:
Server: smb://NAS/home/folder/file.xlsx
I have reviewed...
How to read an excel file directly from a Server with Python
Python - how to read path file/folder from server
https://apple.stackexchange.com/questions/337472/how-to-access-files-on-a-networked-smb-server-with-python-on-macos
... and tried numerous code variations as a result, but with no success.
I am using:
pd.read_excel(“//NAS/home/folder/file.xlsx”, sheet_name=‘total’, header=84, index_col=0, usecols=‘B,AL,DC’, skiprows=0, parse_dates=True).dropna()
But regardless of the code/file path variation, the same error is returned:
FileNotFoundError [Errno 2] No such file or directory: //NAS/home/folder/file.xlsx
I finally located the correct code / file path adjustment necessary to read the file. See https://apple.stackexchange.com/questions/349102/accessing-a-nas-device-from-python-code-on-mac-os
Although the drive was mapped and Mac Finder indicated a file path of "smb://NAS/home/folder/file.xlsx", using Control+Command+C instead, to copy the file path from Finder to the clipboard returned "/Volumes/home/folder/file.xlsx". Using this file path located the file and allowed it to be read.
Related
first, i'd like to mention that im using python via visual studio. not sure if this information will
be relevant but this is my first time using file input so i'm not sure
basically, i have a .txt file located in the same location as my .py file. however, when i go to access it, i get an error 'FileNotFoundError: [Errno 2] No such file or directory'
is there a way to make it work or a different IDE i should use?
I tried reading a .txt file from the same location as my .py file. however, i keep getting the error 'FileNotFoundError: [Errno 2] No such file or directory'
Take into account that the script might not be running from the same path where your python script is and most probably your are not specifying the exact path of the file.
If your file is located in the same directory where your python sript is you can use the pathlib library this way to get your script to work:
import pathlib
# Some custom code
# find your current script path
current_script_path = pathlib.Path(__file__).parent
my_file_name = "my_file_name.txt"
# Specify the file path relative to your script's path
my_file_path = current_script_path / my_file_name
with open(my_file_path, "r+") as f:
print(f.read())
data = pd.read_excel("ETH-USD")
I continually receive an error message informing me that the file cannot be found
this is despite the fact that
1: my directory has been changed within to Python to the same address as the folder where the excel file is stored
2: the file name is input exactly as displayed
Any ideas on why it is unable to find my file?
Is it possible that the excel file has an extension of .xlsx, but your file explorer is set to "hide file extensions"? Try:
data = pd.read_excel("ETH-USD.xlsx")
Or, see what's in the current directory by running:
import os
print(os.listdir())
A tip from the comments:
Windows tip too: hold Shift, right click the excel file and copy as path, then you can see its path (if you don't enable viewing file extensions in the file browser). –
creanion
Often when running python scripts from compilers the "working directory", or where you are running the script from doesn't match the location of your script, hence why I find it much more reliable to use this instead:
import os
BASE_DIR = os.path.dirname(os.path.abspath(__file__))
data = pd.read_excel(os.path.join(BASE_DIR,"ETH-USD")
To add, while I do not use Jupyter, in VSCode which I use, the working directory (which is where python looks for if you put a path in read_excel() but its not a full path) is often the current directory opened in there, so I expect a similar issue to be the reason for your issue.
I have a file that I can see in my current working directory:
%sh
pwd
ls
The output of above is:
/databricks/driver
conf
sample.csv
logs
I want to move the sample.csv file from here to Workspace/Shared directory for which I am using dbutils.fs.mv:
dbutils.fs.mv("dbfs:/databricks/driver/sample.csv","dbfs:/Workspace/Shared/")
but this gives error as java.is.FileNotFoundException:dbfs:/databricks/driver/sample.csv
How do I resolve this error?
when you're executing command on via %sh, it's executed on the driver node, so file is local to it. But you're trying to copy file as it's on the DBFS already, and then it isn't found. You need to change scheme from dbfs to file to point to the file on the driver node, like this:
dbutils.fs.mv("file:///databricks/driver/sample.csv","dbfs:/Workspace/Shared/")
I'm running OSX Mavericks but this problem has been going on since I had Snow Leopard.
When writing a script in any language, eg: Python. When I try to open a file the short
form doesn't work.
file = open('donkey.jpg')
And I get this error:
IOError: [Errno 2] No such file or directory: 'donkey.jpg'
Instead, I always have to specify the full path.
file = open('/Users/myName/Desktop/donkey.jpg')
Any ideas on why this could be happening and how to correct it?
If you specify donkey.png, it means donkey.jpg file in the current working directory. (relative path)
Make sure you're running the script in the same directory where donkey.jpg exists.
If you want specify the image file path relative to the script file instead of current working directory use following:
import os
filepath = os.path.join(os.path.dirname(os.path.abspath(__file__)), 'donkey.jpg')
NOTE You can use __file__ only in script file. (not in interactive mode)
Your open call does not have a mode parameter. In which case, it defaults to opening the file in read mode.
Unless the file you are opening (to read) resides in the current working directory, it is completely expected that the python script throws a IOError.
Background
I am working on a basic text editor, and need to use Windows Explorer to get the path of a file. This is my code currently, but it simply opens the file - I need it to return the path as a string:
import subprocess
subprocess.Popen(r'explorer /select, "C:\"')
Question(s)
How would I have it return the path as a string?
How would I use the path to access a specific file? For instance, if I wanted to open file myFile, but it wasn't in the same folder as my program, how would I have it access that file, in a different folder? Sorry for the ambiguity!
Tech Specs
OS: Windows 7
Language: Python 2.7.3
I would not recommend using Windows Explorer for this purpose, you might want to look at Tkinter. This is very close to this other question.
The main reason for using a third party library is that python runs on multiple platforms. Choosing a file on OSX and Windows 7 and Ubuntu is of course pretty different. This is the main reason why it is not part of the python runtime.
About question 2, to open a file located in the process working directory, you could use:
file = open('filename.txt', 'r')
To open a file which is in a different directory, you can use:
directory = 'C:\Users\MyName\Documents\example.txt'
file = open(directory, 'r')
That would also work, opening the file at the directory specified. If there is no such file in the directory, you would get the following error:
File "filename.py", line #, in <module>
file = open('filename.txt', 'r')
IOError: [Errno 2] No such file or directory: 'filename.txt'