I want to get the amount of hours, mins and seconds that have passed between two dates using datetime in python3.
This allows for the duration to be calculated, and makes the amount of hours, mins and seconds that have passed.
Note this has not been fully tested.
Code can also be found on Github here
from datetime import datetime
def calculate_time_duration(start_datetime, end_datetime):
"""
Requires two datetime objects,
returns (hours, minutes, seconds)
"""
seconds = (end_datetime - start_datetime).total_seconds()
minutes = seconds // 60
seconds -= minutes * 60
hours = minutes // 60
minutes -= hours * 60
return hours, minutes, seconds
Related
I have written this code where I want that code to run exactly at the minute. However, each iteration take few milliseconds and this causes a small delay in my program. Is there a way to where I can subtract these milliseconds just like the way I have subtracted seconds.
import pandas as pd
import datetime as dt
import time
while True:
now = dt.datetime.now()
current_time = now.strftime('%Y-%m-%d %H:%M:%S')
seconds = int(current_time[-2:])
sleep_sec = 60 - seconds
time.sleep(sleep_sec)
print(dt.datetime.now())
This is the output:
As you can see from the output that with each iteration few milliseconds are added to the time. What I want is to print the exact minute where milliseconds is also zero.
using time.time() instead of time.sleep()
import time
import datetime as dt
start_time = time.time()
while True:
if time.time() - start_time > 60:
# if 60 seconds pass do something
print(dt.datetime.now())
start_time = time.time()
print("60 seconds passed")
output:
2021-12-24 12:48:30.542806
60 seconds passed
2021-12-24 12:49:30.543792
60 seconds passed
2021-12-24 12:50:30.544508
60 seconds passed
2021-12-24 12:51:30.544826
60 seconds passed
2021-12-24 12:52:30.545028
60 seconds passed
2021-12-24 12:53:30.545661
60 seconds passed
2021-12-24 12:54:30.546452
60 seconds passed
there's still offset, but it's less significant than in your output
time.sleep accepts float if you want to sleep for fractions of seconds. That being said I would not expect python to be able to do exact milisecond precision (there is just way too much happening in your system usually for this level of precision).
With threading the code is fast and executes exactly at the start of the minute.
def create_candle():
candle_timeframe = 60 # seconds
current_sec = dt.datetime.now().second
sleep_sec = candle_timeframe - current_sec
print(dt.datetime.now())
threading.Timer(sleep_sec, create_candle).start()
candle_timeframe = 60 # seconds
current_sec = dt.datetime.now().second
sleep_sec = candle_timeframe - current_sec
threading.Timer(sleep_sec, create_candle).start()
How would I go about converting a float like 3.65 into 4 mins 5 seconds.
I have tried using:
print(datetime.datetime.strptime('3.35','%M%-S'))
However, I get this back:
ValueError: '-' is a bad directive in format '%-M:%-S'
Take a look at the following script, you can figure out how to make it work for days years, etc, this only works if we assume the format is "hours.minutes"
import datetime
# Assuming the 3 represents the hours and the 0.65 the minutes
number = 3.65
# First, we need to split the numbero into its whole decimal part
# and its decimal part
whole_decimal_part = hours = int(number) # 3
decimal_part = number % whole_decimal_part # 0.6499999
# Now, we need to know how many extra hours are in the decimal part
extra_hours = round((decimal_part * 100) / 60) # 1
minutes = round((decimal_part * 100) % 60) # 5
hours += extra_hours # 4
time_str = "%(hours)s:%(minutes)s" % {
"hours": hours,
"minutes": minutes
} # 4:5
final_time = datetime.datetime.strptime(time_str, "%H:%M").time()
print(final_time) # 04:05:00
First, you should complain to whoever is giving you time data expressed like that.
If you need to process minutes and seconds as a standalone value, then the datetime object may not your best choice either.
If you still need to convert "3.65" into a datetime object corresponding to "4-05" you could adjust it to be a valid time representation before passing it to strptime()
m,s = map(int,"3.65".split("."))
m,s = (m+s)//60,s%60
dt = datetime.datetime.strptime(f"{m}-{s}","%M%-S")
Split your time into minute and seconds
If seconds is 60 or more, then add extra minutes (//) ; second is the modulo (%)
t="3.65"
m, s = [int(i) for i in t.split('.')]
if s >= 60:
m += s//60
s = s % 60
print(f'{m} mins {s} seconds') # -> 4 mins 5 seconds
while 65 seconds cannot be parsed correctly so you have to manipulate by yourself to clean the data first before parsing.
NOTE: assuming seconds is not a very very big number which can make minutes>60
import datetime
time= '3.65'
split_time = time.split(".")
minute =int(split_time[0])
seconds = int(split_time[1])
minute_offset, seconds = divmod(seconds, 60);
minute = int(split_time[0]) + minute_offset
print(datetime.datetime.strptime('{}.{}'.format(minute,seconds),'%M.%S')) #1900-01-01 00:04:05
You can alternatively use .time() on datetime object to extract the time
print(datetime.datetime.strptime('{}.{}'.format(minute,seconds),'%M.%S').time()) #00:04:05
A much cleaner and safer solution is (to consider hour as well). Convert everything into seconds and then convert back to hours, minutes, seconds
def convert(seconds):
min, sec = divmod(seconds, 60)
hour, min = divmod(min, 60)
return "%d:%02d:%02d" % (hour, min, sec)
time='59.65'
split_time = time.split(".")
minute =int(split_time[0])
seconds = int(split_time[1])
new_seconds = minute*60 +65
datetime.datetime.strptime(convert(new_seconds),'%H:%M:%S').time()
I need express my time in Hours and minutes. This is what I have:
0.0425 hours
~153 seconds, How can I show this as 0 Hours 2 minutos 33 seconds?
Here is one way.
time = '0.0425 hours'
# Extract time from string
time = time.split()[0]
# Convert time to a number of hours, then a number of seconds
time = float(time)
time = int(time * 3600)
# Compute the constituent elements of the time
hours = time // 3600
minutes = (time // 60) % 60
seconds = time % 60
# Print the result
print '{hours} Hours {minutes} minutos {seconds} seconds'.format(
hours=hours, minutes=minutes, seconds=seconds)
import time
import re
secs = int(re.sub('\D', '','~153'))
print '%d hours %d minutos %s seconds'%(time.gmtime(secs)[3:6])
I have timestamps that are calculated by a given interval. Ex: timestamp being 193894 and interval being 20000. The time is calculated by doing 193894/20000 = 9.6947. 9.6947 being 9 minutes and 0.6947 of a minute in seconds (0.6947 * 60) = 42 s (rounded up) thus the human readable timestamp being 9 min 42 sec.
Is there a Pythonic (assuming there is some library) way of doing this rather than doing a silly math calculation like this for every timestamp?
The reason being is because if timestamp is 1392338 (1 hour 9 min 37 sec) something that yields in the hours range, I want to be able to keep it dynamic.
I am just wondering if there was a better way to do this than the mathematical calculation way.
The linked question can help you actually format timedelta object once you have it, but there are a few tweaks you need to make to get the exact behavior you want
from __future__ import division
from datetime import timedelta
from math import ceil
def get_interval(timestamp, interval):
# Create our timedelta object
td = timedelta(minutes=timestamp/interval)
s = td.total_seconds()
# This point forward is based on http://stackoverflow.com/a/539360/2073595
hours, remainder = divmod(s, 3600)
minutes = remainder // 60
# Use round instead of divmod so that we'll round up when appropriate.
# To always round up, use math.ceil instead of round.
seconds = round(remainder - (minutes * 60))
return "%d hours %d min %d sec" % (hours, minutes, seconds)
if __name__ == "__main__:
print print_interval(1392338, 20000)
print get_interval(193894, 20000)
Output:
1 hours 9 min 37 sec
0 hours 9 min 42 sec
I need to get time in format: hour:minutes:seconds. But if I use:
time.strftime('%H:%M:%S', time.gmtime(my_time))) #my_time is float
hour have a 24-hour clock (00 to 23). And when I have for example 25 hour and 2 minutes, it writes 1:02:00, but I need 25:02:00. How can I solve it? Thank you.
Don't use time.strftime() to format elapsed time. You can only format a time of day value with that; the two types of values are related but not the same thing.
You'll need to use custom formatting instead.
If my_time is elapsed time in seconds, you can use the following function to format it to a hours:minutes:seconds format:
def format_elapsed_time(seconds):
seconds = int(seconds + 0.5) # round to nearest second
minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)
return '{:02d}:{:02d}:{:02d}'.format(hours, minutes, seconds)
Demo:
>>> def format_elapsed_time(seconds):
... seconds = int(seconds + 0.5) # round to nearest second
... minutes, seconds = divmod(seconds, 60)
... hours, minutes = divmod(minutes, 60)
... return '{:02d}:{:02d}:{:02d}'.format(hours, minutes, seconds)
...
>>> format_elapsed_time(90381.33)
'25:06:21'