We Keep Coding

Search <Li> List via children text

so I'm currently using python to import data from an excel sheet and then take that information and use it to fill out a form on a webpage.
The problem I'm having is selecting a profile of the drop-down menu.
I've been using the Selenium library and I can actually select the element using find_element_by_xpath assuming, but that's assuming I know the data value, the data value is auto-generated for each new profile that's added so I can't use that as a reliable means.
Profile = Browser.find_element_by_xpath("/html/something/something/.....")
Profile.click()
time.sleep(0.75) #allowing time for link to be clickable
The_Guy = Browser.find_element_by-xpath("/html/something/something/...")
The_Guy.click()
This works only on known paths I would like to do something like this
Profile = Browser.find_element_by_xpath("/html/something/something/.....")
Profile.click()
time.sleep(0.75) #allowing time for link to be clickable
The_Guy = Browser.find_element_by_id("Caption.A")
The_Guy.click()
EXAMPLE OF HTML
<ul class ="list">
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
Thor
</li>
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
IronMan
</li>
<li class = "option" data-value= XXXXX-XXXXX-XXXXX-XX-XXX>
::marker
Caption.A
</li>
....
</ul>
What I'll like to be able to do is search via name (like Caption.A) and then step back to select the parent Li. Thanks in advance

Try using following xpath to find the li containing desired text and then click on it. Sample code:
driver.find_element(By.xpath("//li[contains(text(), 'Caption.A')]")).click()
Hope it helps :)

How to click a button from Python

I am using Anaconda2, Jupiter, and Chrome browser.
I am writing below code which is running successfully but now I want to click on button.
<a href="#" action="exportSelected" class="btn btn-default">
<i class="glyphicon glyphicon-download"></i> Export
</a>
What should I write in Python to access this?
find_element_by_partial_link_text('btn btn-default').click()
It's giving an error.

"btn btn-default" is not a link text, but class names.
You can use one of below solutions:
Locate by exact link text:
find_element_by_link_text('Export').click()
Locate by compound class name:
find_element_by_css_selector('a.btn.btn-default').click()
Locate by action attribute
find_element_by_css_selector('a[action="exportSelected"]').click()

Thank you all replying me and suggesting pyhthon doc. appreciate it.
So i have used very simple lines to get my job done.
driver.find_element_by_xpath('copy your xpath').
which is very simple
driver.find_element_by_xpath('//[#id="app_content"]/div[2]/div/div/section/div/div[2]/div[1]/div[1]/div/div[2]/a[1]').click()
driver.implicitly_wait(5)
driver.find_element_by_xpath('//[#id="export_button"]').click()

Python 3.5 + Selenium Scrape. Is there anyway to select <a><a/> tags?

So I'm very new to python and selenium. I'm writting an scraper to take some balances and download a txt file. So far I've managed to grab the account balances but downloading the txt files have proven to be a difficult task.
This is a sample of the html
<td>
<div id="expoDato_msdd" class="dd noImprimible" style="width: 135px">
<div id="expoDato_title123" class="ddTitle">
<span id="expoDato_arrow" class="arrow" style="background-position: 0pt 0pt"></span>
<span id="expoDato_titletext" class="textTitle">Exportar Datos</span>
</div>
<div id="expoDato_child" class="ddChild" style="width: 133px; z-index: 50">
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=txt">txt</a>
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=pdf">PDF</a>
<a class="enabled" href="/CCOLEmpresasCartolaHistoricaWEB/exportarDatos.do;jsessionid=9817239879882871987129837882222R?tipoExportacion=excel">Excel</a>
<a class="modal" href="#info_formatos">Información Formatos</a>
</div>
</div>
I need to click on the fisrt "a" class=enabled. But i just can't manage to get there by xpath, class or whatever really. Here is the last thing i tried.
#Descarga de Archivos
ddmenu2 = driver.find_element_by_id("expoDato_child")
ddmenu2.find_element_by_css_selector("txt").click()
This is more of the stuff i've already tryed
#TXT = driver.select
#TXT.send_keys(Keys.RETURN)
#ddmenu2 = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]")
#Descarga = ddmenu2.find_element_by_visible_text("txt")
#Descarga.send_keys(Keys.RETURN)
Please i would apreciate your help.
Ps:English is not my native language, so i'm sorry for any confusion.
EDIT:
This was the approach that worked, I'll try your other suggetions to make a more neat code. Also it will only work if the mouse pointer is over the browser windows, it doesn't matter where.
ddmenu2a = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[1]").click()
ddmenu2b = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]")
ddmenu2c = driver.find_element_by_xpath("/html/body/div[1]/div[1]/div/div/form/table/tbody/tr[2]/td/div[2]/table/tbody/tr/td[4]/div/div[2]/a[1]").click()
Pretty much brute force, but im getting to like python scripting.

Or simply use CSS to match on the href:
driver.find_element_by_css_selector("div#expoDato_child a.enabled[href*='txt']")

You can get all anchor elements like this:
a_list = driver.find_elements_by_tag_name('a')
this will return a list of elements. you can click on each element:
for a in a_list:
a.click()
driver.back()
or try xpath for each anchor element:
a1 = driver.find_element_by_xpath('//a[#class="enabled"][1]')
a2 = driver.find_element_by_xpath('//a[#class="enabled"][2]')
a3 = driver.find_element_by_xpath('//a[#class="enabled"][3]')
Please let me know if this was helpful

you can directly reach the elements by xpath via text:
driver.find_element_by_xpath("//*[#id='expoDato_child' and contains(., 'txt')]").click()
driver.find_element_by_xpath("//*[#id='expoDato_child' and contains(., 'PDF')]").click()
...

If there is a public link for the page in question that would be helpful.
However, generally, I can think of two methods for this:
If you can discover the direct link you can extract the link text and use pythons' urllib and download the file directly.
or
Use use Seleniums' click function and have it click on the link in the page.
A quick search resulted thusly:
downloading-file-using-selenium

Locating an element in Selenium with a custom value

I am working with a web page that needs some automation and having trouble interacting with certain elements due to their structure. Brief example:
<ul>
<li data-title="Search" data-action="search">
<li class="disabled" data-title="Ticket Grid" data-action="ticket-grid">
<li data-title="Create Ticket" data-action="create">
<li data-title="Settings" data-action="settings">
</ul>
I am aware of all the locator strategies like id and name listed here:
http://selenium-python.readthedocs.org/en/latest/locating-elements.html
However, is there a way to specify finding something by a custom value like in this example "data-title"?

You can use CSS to select any attribute, this is what the formula looks like:
element[attribute(*|^|$|~)='value']
Per your example, it would be:
li[data-title='Ticket Grid']
(source http://ddavison.io/css/2014/02/18/effective-css-selectors.html)

If there are multiple possibilities it is also worth knowing the following option
from selenium.webdriver import Firefox
driver = Firefox()
driver.get(<your_html>)
li_list = driver.find_elements_by_tag_name('li')
for li in li_list:
if li.get_attribute('data-title') == '<wanted_value>':
<do_your_thing>

You can use:
"//li[#data-title='Ticket Grid']"

Using SST framework, how do you click a link by css class or xpath?

I am testing a website that has buttons that are not discernible by element or id. However, I am able to identify it by xpath or css class. How do you click on a button using one of those two attributes. I'm able to assert the button is there using get_element_by_xpath; however, I seem unable to use the click_element, click_link, or click_button using id_or_elem. What statement would you use to click on a button like this?
Edit:
The test code looks like this: (webpage name removed on purpose)
class TestMyTest(cases.SSTTestCase):
def test_mytestcase_home_page(self):
go_to('http://www.mywebpage.com')
assert_title_contains('Page Name')
assert_element(tag='a', text='Log in')
click_element(id_or_elem='page_nav')
assert_title_contains('Login')
assert_element(id='tbLUser')
write_textfield('tbLUser','username')
assert_element(id='tbLPass')
write_textfield('tbLPass','badpassword')
assert_element(css_class='btn-login1')
get_element_by_xpath('//*[#id="login_box"]/div/a/img')
The code I'm trying to test from:
<div class="btn-login1">
<a href="javascript:void(0)" onclick=javascript:return Validate(document.theLoginForm,'/mypage/mywebpage.asp');" onmouseout="MM_swapImgRestore();" onmouseover="MM_swapImage('lg5_login','','/assets/page4/lg5_login_f2.png',1);">
<img name="lg5_login" src="http://www.mywebpage.com/login/lg5_login.png" border="0" alt="Log in Now">
</a>
</div>

If this answer is helpful to someone else. We we able to solve the issue with the following solutions.
click_element(get_element_by_xpath('your xpath'), wait=True)
click_link(get_element_by_xpath('your xpath'), wait=True)
click_button(get_element_by_xpath('your xpath'), wait=True)
Parameters: id_or_elem The identifier of the element, or its element object.
All of the click actions should support id or element