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How can I write a function that adds the number of possitive number in a list [closed]

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I am trying to write a simple function that takes a list of number passed as an argument and prints how many positive number is in the list.
I can't seem to figure out what is wrong with the code here. Can someone please explain this.

You should return add instead of num. And you should initialize add outside the for loop.

lst = [1,2,3,4,-4,-3,-2,-1]
def count_positives(lst):
return sum(i > 0 for i in lst)
print(count_positives(lst))
the program above will print 4

Why is reading from a file not working after using a function? [closed]

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My code is supposed to find the occurrence of words in a text. For some reason, after using this function, the reading method from this specific textwon't work(empty lists for .readlines() method and nothing for .read()). The code is:
def counter(new):
words = dict()
lines=new.readlines()
for line in lines:
text=line.split()
for word in text:
if word not in words:
words[word]=1
else: words[word]+=1
return [tuple(x) for x in words.items()]
I haven't found any mistake that can cause this.

I am assuming new is the result of calling open(..), which should be a file handle that you are passing into the function. Calling readlines() is exhausting it, so trying to read from the file using the same handle won't work. Either open a new handle, or you can call new.seek(0) (better option than opening a completely new handle - although there are some cases where the same handle will be returned again, but lets not dive too deep into that here) to move the index to the beginning of the file.

inaccurately reading from file logic error Python [closed]

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Hi I have the following text file on which I am using a csv reader:
number,obstacle,location,message
1,gobacktostart,8,Sorry but you've landed on a dangerous number, back to the start for you!
2,movetosquare42,matrix[1][0],The meaning of life is 42 or so they say, and that's where you're headed
I wish to (at the end) retrieve the number 8 from the row that starts 1,gobacktostart,8....etc.
My code is:
def gobacktostart():
with open("obstacles.txt","r") as f:
idnumber="1"
fReader=csv.reader(f)
for row in fReader:
for field in row:
if field==idnumber:
print(row[3])
player1position==row[2]
print(player1position)
and the undesired output however, is:
>>>
Sorry but you've landed on a dangerous number
1
>>>
I do need to read the value into the variable player1position in order to pass it on to another function at a different part of the program.
Any thoughts on solving this logic error? Why is it printing "1", when row[2] refers to the 8. Also, Row[3] seems to execute properly in the previous line....

You are checking for equality not assignment in player position == row[2]

Using "if not" with multiple string arguments Python [closed]

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Here is what I currently have, which is not working:
if "Forwarder" not in shp_name or "T_" not in shp_name or "Grad" not in shp_name:
I've also tried:
if ("Forwarder", "T_", "Grad") not in shp_name:
Samples of the input would be "DS_Forwarder_1" or "DS_Harvester_1". The script proceeds directly to else as it's unable to identify any of the above substrings in the primary string.

Try using the any built in.
if any(s in shp_name for s in ("Forwarder", "T_", "Grad")):
...
This will be true if any of the given strings are present in shp_name. You can use if not any(... if you want False when one of the strings is present.

url.strip()+' - CatchAllError' [closed]

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I am try to run this program as it start run but while running it's create error regrading CatchAllError . I want output as ' Pass ' But its not please help. Thanks
if line:
msg = url.strip()+' - CatchAllError'
print msg
with open("log_Error.txt", "a") as log:
log.write(msg+"\n")
else:
pass
You can see my whole program at https://ghostbin.com/paste/ypdmd.
You can see that if condition should be pass but it's not. To include target list go to https://ghostbin.com/paste/pjuox and download target list and other information.

You are mixing tabs and spaces. This confuses Python* and may cause unexpected behavior.
Use only tabs or only spaces, not both. Spaces is preferable.
(*well, not really. Python knows exactly how to handle tabs; it just does so in a way that is very surprising to most users. In particular, one tab is not equivalent to 4 spaces, or 8, or whatever it looks like in your text editor. See 2.1.8 - Indentation for more information.)