I'm using VS Code with anaconda and it's python vers. is 3.6.x. I installed python 3.9 on last day. After this my anaconda stability is disturbed. When I started the VS Code it was running "conda activate" command automatically. But now it's not. Also git can't recognize now from terminal. I solved it ctrl+p and then select shell -> git bash.
But now I have another problem. I was debugging with F5 but now it says
cmd /C "C:\Users\Fordev\anaconda3\python.exe c:\Users\Fordev\.vscode\extensions\ms-python.python-2021.3.680753044\pythonFiles\lib\python\debugpy\launcher 58000 -- c:\Users\Fordev\Desktop\tkczmkmsi\.vscode\settings.json "
'cmd' is not recognized as an internal or external command,
operable program or batch file.
after this it waits and then says "timed out waiting for launcher to connect"
Now I removed my python path's from env. variables and system variables. I think now my configuration's are really complicated cause I tried all solves that i saw.
At the current, my environment variables:
User variables Path = C:\Users\Fordev\anaconda3\;C:\Users\Fordev\anaconda3\Scripts
System variables Path = C:\Users\Mp\AppData\Local\Programs\Python\Python39\;C:\Users\Fordev\anaconda3\;C:\Users\Fordev\anaconda3\Scripts
My launcher Json:
{
// Use IntelliSense to learn about possible attributes.
// Hover to view descriptions of existing attributes.
// For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
"version": "0.2.0",
"configurations": [
{
"name": "Python: Geçerli Dosya",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "integratedTerminal"
}
]
}
My settings Json:
{
"python.pythonPath": "C:\\Users\\Fordev\\anaconda3\\python.exe"
}
How can I stabil configuration VS Code in Anaconda? I can run my python code but I can't debug it. And also for use github I have to change my shell to git bash everytime and I don't want that.
Can anybody tell me what's the problem?
According to the information you provided,
"c:\Users\Fordev\Desktop\tkczmkmsi\.vscode\settings.json"
it means that the file VS Code is currently debugging is "settings.json".
Please try to reload VS Code, then open the python file and click 'F5' to debug the python file.
When I run files in VS Code, I get quote a bit of gobbledegook and not the output I'm expecting.
Like so:
I've changed launch.json like so:
"name": "Python: Current File",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "internalConsole",
"cwd": "${fileDirname}"
What's going on here?
The good news is that the DEBUG CONSOLE returns the output I'm expecting. But shouldn't that output be in the terminal as well?
(On a related note, what's a good way to learn basic terminal commands?)
According to your description, here are the following suggestions:
"Terminal information". The information displayed by the terminal is useful. It shows us the path information of the script that needs to be run, as well as the current VSCode running environment information and so on.
"Showing paths but not output". When you debug the script, you don’t see the running result in the terminal because you set the debug output mode: "console": "internalConsole",. It makes the debugging results displayed in the internal debugging console instead of the terminal.
The default is:"console": "integratedTerminal",The result is displayed in the terminal in VSCode. If you set it to: "console": "externalTerminal",The result will open a new cmd window, and only display the running result:
For setting the display to the terminal, please refer to: Set configuration options.
For more terminal information, you could refer to: Integrated Terminal.
I have a script that effectively does the following:
top_script.py:
os.system("bash_script.sh")
bash_script.sh
python3 child_script.py
child_script.py
# Actual work goes here
In VSCode, I love the integrated debugger, but when I follow their advice[1] when launching from the IDE, I get "ECONNREFUSED 127.0.0.1:5678".
When I execute the following from the integrated terminal in VSCode, it runs without the errors, but it doesn't stop on breakpoints in child_script.py.
python3 -m debugpy --listen 5678 top_script.py
How can I execute the top script first (either from the IDE or command line) and have breakpoints I attach in child_script.py be rendered in VSCode?
[1] https://code.visualstudio.com/docs/python/debugging
It's fairly simple. You can add a configuration to your launch.json file like the following:
{
"name": "MySubProcess",
"type": "python",
"request": "attach",
"processId": "${command:pickProcess}
}
Now start your python process separately (via a prompt, or however). This will generate a python subprocess. You can see this in Windows Task Manager (or also in MacOS Activity monitor, or in Linux a similar way).
In VSCode, then click Debug, (select your subprocess configuration: "MySubProcess" in our example above), and then choose the process which was just started. The debugger will then stop at the breakpoints in your subprocess code.
The problem is that by using os.system() the debugger doesn't know you started another Python interpreter that you care about. What you will need to do is attach to the second process. Details will vary depending on how you want to set this up, but you can look at https://code.visualstudio.com/docs/python/debugging#_local-script-debugging as a starting point.
I followed RexBarker's suggestion, but VSC always gave me an error of "Timed out waiting for debug server to connect". In order to find out the cause, the "log to file" was enabled in the Configuration like below,
{
"name": "MySubProcess",
"type": "python",
"request": "attach",
"processId": "${command:pickProcess}",
"logToFile": true
}
Then I could find the detailed error in the log file on the VSC host, which is located at ~/.local/share/code-server/extensions/ms-python.python-2021.5.926500501/debugpy.adapter-{pid}.log
It told me 'gdb' not found. After I installed gdb, it works as expected.
I have just installed VS Code and the Python extension, and I have not been able to get the debugger to work. Every time I try to use the debugger, it just skips over any breakpoints that I have set and runs the program like normal.
I am using VS Code on a Windows 10 PC with Python 3.7.3 and the Python extension installed. I followed the instructions here (https://code.visualstudio.com/docs/python/python-tutorial) to make a test folder called 'hello' in C:\python_work\hello and create a program called 'hello.py' inside that folder. hello.py is shown below. I tried using the debugger both by pressing the green arrow and by pressing F5, but neither seemed to make the debugger work properly. My 'launch.json' file is also shown below.
hello.py:
msg = "Hello World!"
print(msg) # Breakpoint
launch.json:
{
// Use IntelliSense to learn about possible attributes.
// Hover to view descriptions of existing attributes.
// For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
"version": "0.2.0",
"configurations": [
{
"name": "Python: Current File",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "integratedTerminal",
"stopOnEntry": true
},
]
}
I expected the bottom bar to turn orange and the program to stop on the second line, allowing me to examine the local and global variables in the preview pane. Instead, the bottom bar stayed orange for 1/2 a second while the program ran as if I had pressed "Run Python File in Terminal," without stopping at the breakpoint. Please help!
Setting "justMyCode": false makes it stop at breakpoint:
{
"version": "0.2.0",
"configurations": [
{
"name": "Python: Debug Current File",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "integratedTerminal",
"stopOnEntry": true,
"justMyCode": false
},
]
}
If you're using a pytest-cov module you might also wanna have a look at pytest configuration settings note:
Note If you have the pytest-cov coverage module installed, VS Code doesn't stop at breakpoints while debugging because pytest-cov is using the same technique to access the source code being run. To prevent this behavior, include --no-cov in pytestArgs when debugging tests, for example by adding "env": {"PYTEST_ADDOPTS": "--no-cov"} to your debug configuration.
See an example configuration file (launch.json) below:
{
"version": "0.2.0",
"configurations": [
{
"name": "Debug Tests",
"type": "python",
"request": "test",
"console": "integratedTerminal",
"justMyCode": false,
"env": {"PYTEST_ADDOPTS": "--no-cov"}
}
]
}
I experienced the same behaviour and was able to solve it by installing the virtual environment of Python in the following way:
[MyProjectFolder] \ venv
by entering the command
python -m venv [MyProjectFolder]\venv
in the console.
VS Code seems to expect exactly that folder structure.
Before I had installed the venv-folder-structure directly in my projects-folder, i.e.
[MyProjectFolder] \ Scripts
[MyProjectFolder] \ Lib
[MyProjectFolder] \ Include
[MyProjectFolder] \ pyvenv.cfg
which did not work and caused exactly the described debug problems.
just as a reference: VS Code version 1.52.1 and Python 3.8.5
Downgrading from Python 3.9 to 3.8 worked for me.
VC Code 1.56.2 ignored breakpoints running Python 3.9 64-bit on Windows 10 version 20H2. Installing Python 3.8.10 64-bit fixed the problem. I just needed to select the Python 3.8.10 interpreter within VS code and it now recognizes breakpoints. No changes to the configuration file were needed, for example, I did not need "justMyCode": false
I realize this is an old question, but my google search lead me to it. Many of the previous answers no longer apply. So I'm posting this fix for others who land here in 2021 trying to use 3.9.
I had the same problem having upgraded from Python version 3.7 to version 3.9. I later found out that the old version was 32 bit, and the new version I upgraded to was 64 bit, which apparently caused the issues. Uninstalling the 64 bit version and installing the 32 bit version of Python 3.9 solved my problem, and I was then able to use the Visual Studio Code breakpoint functionality again.
For everyone coming here looking for a solution related to breakpoints in python unittests:
If not already done add a configuration file, i.e. launch.json, as described in the vscode python debugging tutorial.
For me the following configuration settings worked, whereby setting cwd (because of src and test folders) and purpose (see also here) were essential.
"version": "0.2.0",
"configurations": [
{
"name": "Python: Test Cases",
"type": "python",
"request": "launch",
"cwd": "${workspaceFolder}/afinad/src",
"purpose": [
"debug-test"
],
"console": "integratedTerminal",
}
]
Happy debugging!
I recently found out ( 5th May 2020) that using Python 3.9 as interpreter the breakpoints were not hitting. Install 3.8 and it will start working again.
My issue was that I was putting the breakpoint on the line of the function declaration itself, so the def foo(x): line, instead of putting the breakpoint on the first non-comment line inside of the function.
If the first line of your function is a comment, the debugger will assume you meant to place the breakpoint on the line of the function declaration and move your breakpoint back, so really make sure you aren't placing your breakpoint on a comment!
Another source of no-breakpoints-working is elevate:
try: # https://pypi.org/project/elevate/
from elevate import elevate
except ModuleNotFoundError: # install it if not found
subprocess.call([sys.executable, "-m", "pip", "install", 'elevate'])
finally:
from elevate import elevate
# require elevated permissions right away...
elevate()
The elevate() command restarts the program as a new (child) process, so the entire file becomes un-breakpoint-able. From the author:
On Windows, the new process’s standard streams are not attached to the parent, which is an inherent limitation of UAC.
In windows, to debug python applications in VS Code which need to be run as administrator, a work-around is this:
Close VS Code.
Right-click VS Code icon, choose "Run as Administrator."
Linux users could likely do the same with sudo code. Now the process will be spawned initially as administrator, so the call to elevate() does nothing and the whole file is debuggable.
Another source of debugger not stopping at breakpoint: an homonym file, from another directory, is open in VS Code.
In fact, VS Code can set breakpoints on any Python file, even outside of your Python project's directory; if the path of the file does not match the one in launch.json, "program": [your-file-name-here] entry, then breakpoints are not hit.
For example: copies of Python source files are located under dist/lib, the output of setuptools (run: python setup.py bdist_wheel to generate them).
If dist/lib is not excluded through .gitignore, then its contents shows up in the search results sidebar and can be click open by mistake.
Caveat: the above does not hold if the launch.json configuration has "program": "${file}".
I (re)downloaded VS Code again: https://code.visualstudio.com/
The breakpoint got to show up on hover and function with the Run and Debug for the python file I was working on.
Additionally, I had to solve a syntax error in my code before the debugger buttons (step over/in, etc) had to go through the code lines
I have been battling with this for the last hour, and it finally worked by renaming my python file from camelCase.py to snake_case.py
I've had a big problem with debugging in VSCODE lately. I have tried to fix it my self by searching the site and reinstalling some of my extensions.
Instead of showing my results in the debug console it writes the following output to my terminal:
cd /Users/AVFL/Documents/Programming ; env "PYTHONIOENCODING=UTF-8"
PYTHONUNBUFFERED=1" /usr/local/bin/python3
/Users/AVFL/.vscode/extensions/ms-python.python-2018.3.1/pythonFiles/PythonTools/visualstudio_py_launcher.py
/Users/AVFL/Documents/Programming 54323 34806ad9-833a-4524-8cd6-18ca4aa74f14 RedirectOutput,RedirectOutput
/Users/AVFL/Documents/Programming/Python/Projects/Entrepeneuring/employeeDatabase.py
and the results from my script show up below that. The results also show up in the debug console but I would like them to only show up there.
I am debugging with the Python: Current file. I have tried changing the console to none in the external and integrated terminal function, but I need those to be default.
What can I do to make it debug in the debug console when I use Python: Current File?
I've seen one post with this question but they changed the console to none and debug in the Python: Integrated Terminal instead of Current File
The problem occurred when I made a virtualenv in my folder.
Just go to your launch.json script and find thre attach part. Change the setting from integrated terminal to none. Should work :)
I've found the answer myself. Instead of changing the other configurations to print the info in the debug console I create a new Configuration with the name "Python: Current File" which I added as the fist configuration. I made the console "none" in this configuration and I deleted the other one. This solved my problem with out removing other vulnerable settings.
Setting "console": "None" in the launch.json is not valid in the latest versions of VS Code. Note, however, that you will still get the desired behavior, but VS Code will consider it an invalid setting. To make VS Code happy, set "console" to "internalConsole" to get the output to go to the Debug Console instead of to a Terminal, like this:
{
"version": "0.2.0",
"configurations": [
{
"name": "Python: Current File",
"type": "python",
"request": "launch",
"program": "${file}",
"console": "internalConsole"
}
]
}