I am using django_elasticsearch_dsl which is running on 9200 port number
and i have two models.
models.py
class Category(models.Model):
name = models.CharField(max_length=255, blank=True, null=True)
class Book(models.Model):
name = models.CharField(max_length=255, blank=True, null=True)
categories = models.ManyToManyField('Category')
document.py
#posts.doc_type
class PostDocument(DocType):
class Meta:
model = Book
fields = [
'id',
'name'
]
related_models = [Category]
def get_instances_from_related(self, related_instance):
"""If related_models is set, define how to retrieve the book instance(s) from the related model."""
if isinstance(related_instance, Category):
return related_instance.book_set.all()
search.py
from elasticsearch_dsl.query import Q
p = Q("multi_match", query=request.GET.get('q'), fields=['name','categories__name'],
type='phrase_prefix')
s = PostDocument.search().query(p)
result = s.execute()
this search code only works for the books models and i am unable to retrieve using related Category model
my required output should be
like i have two books like jungle and cuop
and jungle book linked to Category model (Category name is sport)
so if search ?q=ju output should show only jungle (working with above code)
and if search ?q=sport output should show only jungle this is not working(it is not giving any results)
Related
I am fairly new to django and I am trying the following:
I am making an ordering web app for a nearby business. I am trying to add all the calories in a combo.
I have a model "Consumable", this represent the different food and drinks there are.
Here is the code for the "Consumable" Model:
class Consumable(models.Model):
name = models.CharField(max_length=80, unique=True)
category = models.ForeignKey(FoodCategory, null=True, on_delete=models.SET_NULL)
price= models.FloatField(default=0.00)
calories = models.IntegerField(blank=False)
image = models.ImageField(upload_to="images/Food/")
description = RichTextField(blank=True, max_length=500)
restaurant = models.ForeignKey(Place, on_delete=models.CASCADE)
added = models.DateTimeField(auto_now_add=True)
updated = models.DateTimeField(auto_now=True)
def __str__(self):
return self.name
Then, I have a model called "Meal" which has the following code:
class Meal(models.Model):
name = models.CharField(max_length=100)
image = models.ImageField(upload_to='images/photos/meals')
consumables = models.ManyToManyField(Consumable, related_name="consumable")
restaurant = models.ForeignKey(Place, on_delete=models.CASCADE)
price = models.FloatField()
def add_cals(meal_consumables):
total_calories = 0
for x in meal_consumables.values():
global total_calories += float(x.calories)
return total_calories
I am trying to call this model's function, add_cals from my HTML file using the DTL (Django Template Language).
For example, if you have a model stored with the variable x in your view, and it is in the view's context dictionary, you could simply call the model by using <p>{{x}}</p>, for example. And if the model has a variable x1, you could call it as <p>{{x.x1}}</p> and it works fine. However, if the x model from my example has a function
add_x(x):
return x
then it wouldn't work when you call it as <p>{{x.add_x(1)}}</p> for some reason. Could some wise individual out there in this world be so humble to share his or her knowledge with me in order to help me?
Thanks to everyone who tries.
Somewhat new to Django and I'm trying to create a car listing site. I've already ran into problems with the models. I can't seem figure out how I can create a model where if you select a particular make (e.g. Dodge) then you can select a model related to that make (e.g. Charger, Challenger, Viper etc.) or if you selected McLaren you could select from the 720s, 765lt, Senna, P1 etc.
models.py
class Make(models.Model):
make = models.CharField('Make', max_length=150)
class Meta:
ordering = ['make']
unique_together = ["make"]
verbose_name_plural = "Manufacturers"
def __str__(self):
return self.make
class CarModel(models.Model):
year = models.IntegerField(default=datetime.datetime.today().year)
make = models.ForeignKey(Make, on_delete=models.CASCADE)
model = models.CharField('Model', max_length=150)
trim = models.CharField('Trim', max_length=150, help_text='Trim level')
class Meta:
ordering = ['make', 'model', 'trim', 'year']
unique_together = ("year", "make", "model", "trim")
verbose_name_plural = "Models"
def __str__(self):
return f' {self.year} {self.make} {self.model} {self.trim}'
class CarListing(models.Model):
content = models.FileField("Media")
make = models.ForeignKey(Make, on_delete=models.CASCADE)
make_model = models.ForeignKey(CarModel, on_delete=models.CASCADE)
class Meta:
ordering = ['make_model']
verbose_name_plural = "Car Listings"
def __str__(self):
return f' {self.make_model.year} {self.make_model.make}
{self.make_model.model}
{self.make_model.trim} '
Use related_name for backwards compatibility.
class CarModel(models.Model):
year = models.IntegerField(default=datetime.datetime.today().year)
make = models.ForeignKey(Make, on_delete=models.CASCADE, related_name="models") # Note the related name here
model = models.CharField('Model', max_length=150)
trim = models.CharField('Trim', max_length=150, help_text='Trim level')
Then when you have a related name, you can easily access it by calling models on an instance
make = Make.objects.get(make="Dodge")
print(make.models) # Viper, Charger, Challenger, etc.
Note: make = Make.objects.get(make="Dodge") this will fire you an error if there are multiple records with the same query.
So you have to do something like this:
make = Make.objects.filter(make="Dodge") # return list of records`
I have a MySQL database with four related tables: project, unit, unit_equipment, and equipment. A project can have many units; a unit can have many related equipment entries. A single unit can only belong to one project, but there is a many-to-many between equipment and unit (hence the unit_equipment bridge table in the DB). I'm using Django and trying to create a view (or a list?) that shows all 3 models on the same page, together. So it would list all projects, all units, and all equipment. Ideally, the display would be like this:
Project --------- Unit ------------- Equipment
Project 1 first_unit some_equipment1, some_equipment2
Project 1 second_unit more_equipment1, more_equipment2
Project 2 another_unit some_equipment1, more_equipment1
Project 2 and_another_unit some_equipment2, more_equipment2
but at this point I'd also be happy with just having a separate line for each piece of equipment, if comma-separating them is a pain.
Although it seems straightforward to create a form where I can add a new project and add related unit and equipment data (using the TabularInline class), I cannot for the life of me figure out how to bring this data together and just display it. I just want a "master list" of everything in the database, basically.
Here's the code I have so far:
models.py
class Project(models.Model):
name = models.CharField(max_length=255, blank=True, null=True)
class Meta:
managed = False
db_table = 'project'
def __str__(self):
return self.name
class Unit(models.Model):
project = models.ForeignKey(Project, models.DO_NOTHING, blank=True, null=True)
name = models.CharField(max_length=255, blank=True, null=True)
class Meta:
managed = False
db_table = 'unit'
def __str__(self):
return self.name
class UnitEquipment(models.Model):
unit = models.ForeignKey(Unit, models.DO_NOTHING, blank=True, null=True)
equipment = models.ForeignKey(Equipment, models.DO_NOTHING, blank=True, null=True)
class Meta:
managed = False
db_table = 'unit_equipment'
class Equipment(models.Model):
name = models.CharField(max_length=100, blank=True, null=True)
description = models.CharField(max_length=255, blank=True, null=True)
class Meta:
managed = False
db_table = 'equipment'
def __str__(self):
return self.name
views.py
def project_detail_view(request):
obj = Project.objects.all()
context = {'object': obj}
return render(request, "project/project_detail.html", context)
urls.py
urlpatterns = [
path('project/', project_detail_view),
path('', admin.site.urls),
]
admin.py
class UnitTabularInLine(admin.TabularInline):
model = Unit
extra = 0
class ProjectAdmin(admin.ModelAdmin):
inlines = [UnitTabularInLine]
class Meta:
model = Project
# a list of displayed columns name.
list_display = ['name']
# define search columns list, then a search box will be added at the top of list page.
search_fields = ['name']
# define filter columns list, then a filter widget will be shown at right side of list page.
list_filter = ['name']
# define model data list ordering.
ordering = ('name')
I think I need to somehow add more entries to the list_display in the admin file, but every time I try to add unit or equipment it throws an error. I've also tried adding more attributes to Project, but I can't seem to get the syntax right, and I'm never sure which model class I'm supposed to make it.
I've also looked at FormSets, but I cannot get my head around how to alter my current code to get it to work.
How do I get these models together into a unified view?
You don't need to edit the admin view to add your own view: which you may find you are able to do in this case to get your data displayed exactly as you want.
If you do want to show the related object values in the admin list, then you can use lookups and custom columns: however in this case your list would be based upon the Unit.
# You don't need an explicit UnitEquipment model here: you can
# use a simple ManyToManyField
class Unit(models.Model):
project = ...
name = ...
equipment = models.ManyToManyField(Equipment, related_name='units')
def equipment_list(admin, instance):
return ', '.join([x.name for x in instance.equimpent.all()])
class UnitAdmin(admin.ModelAdmin):
class Meta:
model = Unit
list_display = ['project__name', 'name', equipment_list]
def get_queryset(self, request):
return super().get_queryset(request)\
.select_related('project')\
.prefetch_related('equipment')
Note that you need to have the queryset override, otherwise there will be a bunch of extra queries as each unit also requires fetching the project and list of equipment for that unit.
There's also a further improvement you can make to your queries: you could aggregate the related equipment names using a Subquery annotation, and prevent the second query (that fetches all related equipment items for the units in the queryset). This would replace the prefetch_related()
Thanks to #Matthew Schinckel, I was able to find my way to the answer. Here's what my files look like now (only edited the Unit class in models.py):
models.py
class Unit(models.Model):
project = models.ForeignKey(Project, models.DO_NOTHING, blank=True, null=True)
name = models.CharField(max_length=255, blank=True, null=True)
equipment = models.ManyToManyField(Equipment, related_name='units')
class Meta:
managed = False
db_table = 'unit'
def __str__(self):
return self.name
def equipment_list(self):
return ', '.join([x.name for x in self.equipment.all()])
admin.py
class UnitAdmin(admin.ModelAdmin):
class Meta:
model = Unit
# a list of displayed columns name.
list_display = ('project', 'name', 'equipment_list')
# define search columns list, then a search box will be added at the top of list page.
search_fields = ['project']
# define filter columns list, then a filter widget will be shown at right side of list page.
list_filter = ['project', 'name']
# define model data list ordering.
ordering = ('project', 'name')
def get_queryset(self, request):
return super().get_queryset(request)\
.select_related('project')\
.prefetch_related('equipment')
So the changes I made were:
1. Make list_display a tuple instead of a list.
2. Throw def equipment_list(self) into the Unit class (so it's callable as an attribute of Unit) and pass (self) instead of (admin, instance) (I kept getting an error that was looking for the instance argument).
Hello Guys I am working on a restaurant project which allow user to select food item and book an order but i am getting this error as i try to book an order
"Django Cannot assign "'Pizza'": "Order.Food_Name" must be a "Foods" instance."
I am using drop down menu to select food items i am using django version 2.1.5 . Please Help
views.py
def place_order(request):
name = request.POST["user"]
food_items = request.POST['food_item']
qty = request.POST['qty']
rating = request.POST['ratings']
price = Foods.Food_Price
order = Order(Date=datetime.date, Name_of_Person=name,Food_Name=food_items, Qty=qty, Total=price, Ratings=rating)
order.save()
return render(request, "index.html")
model.py
from django.db import models
class Foods(models.Model):
Food_Number = models.IntegerField(null=False,)
Food_Name = models.CharField(max_length=30, primary_key=True, null=False)
Food_Qty = models.CharField(max_length=10)
Food_Price = models.IntegerField()
def __str__(self):
return f"{self.Food_Number} - {self.Food_Name} {self.Food_Price}"
class Order(models.Model):
Order_id = models.AutoField(null=False, primary_key=True)
Date = models.DateField()
Name_of_Person = models.CharField(null=False, max_length=40)
Food_Name = models.ForeignKey(Foods, on_delete=models.CASCADE)
Qty = models.CharField(max_length=10)
Total = models.IntegerField()
Ratings = models.IntegerField()
def __str__(self):
return f"{self.Order_id} - {self.Name_of_Person} |{self.Food_Name} |{self.Total}"
What can i do solve this error
Problem is in your Order model Food_Name is foreign-key field. So you need to assign model-instance which is Food in this case to this field. But you are assigning food_items = request.POST['food_item'] which is suppose to be food_name string i guess. That is why this error raise. I don't think your model is properly design. Food_Name is not an unique id field in Food model rather in your Order table you would like to have Food not Food_name.
I've been looking at the docs for search_fields in django admin in the attempt to allow searching of related fields.
So, here are some of my models.
# models.py
class Team(models.Model):
name = models.CharField(max_length=255)
class AgeGroup(models.Model):
group = models.CharField(max_length=255)
class Runner(models.Model):
"""
Model for the runner holding a course record.
"""
name = models.CharField(max_length=100)
agegroup = models.ForeignKey(AgeGroup)
team = models.ForeignKey(Team, blank=True, null=True)
class Result(models.Model):
"""
Model for the results of records.
"""
runner = models.ForeignKey(Runner)
year = models.IntegerField(_("Year"))
time = models.CharField(_("Time"), max_length=8)
class YearRecord(models.Model):
"""
Model for storing the course records of a year.
"""
result = models.ForeignKey(Result)
year = models.IntegerField()
What I'd like is for the YearRecord admin to be able to search for the team which a runner belongs to. However as soon as I attempt to add the Runner FK relationship to the search fields I get an error on searches; TypeError: Related Field got invalid lookup: icontains
So, here is the admin setup where I'd like to be able to search through the relationships. I'm sure this matches the docs, but am I misunderstanding something here? Can this be resolved & the result__runner be extended to the team field of the Runner model?
# admin.py
class YearRecordAdmin(admin.ModelAdmin):
model = YearRecord
list_display = ('result', 'get_agegroup', 'get_team', 'year')
search_fields = ['result__runner', 'year']
def get_team(self, obj):
return obj.result.runner.team
get_team.short_description = _("Team")
def get_agegroup(self, obj):
return obj.result.runner.agegroup
get_agegroup.short_description = _("Age group")
The documentation reads:
These fields should be some kind of text field, such as CharField or TextField.
so you should use 'result__runner__team__name'.