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Unable to locate element whose xpath contains lots 'div'

I am trying to locate an element that is a simple message (not a hyperlink) inside a chatbot. I tried to get xpath using 'inspect' and tried this -
driver.find_element_by_xpath("//[#id='app']/div[1]/div/div/div/div/div[2]/div[2]/div/div[2]/div[3]/div[3]/div[1]/div/div/speak").text
This works but this is not a reliable solution. I tried to shorten xpath using starts-with or contains but dint worked.
Is there any other locator other than xpath that I can use when there are lots of 'div' in xpath? What does this means in xpath above
[#id='app']

You should try to write custom xpath instead of generate it by browser.
It will looks like "//[#id='app']//speak".

Python Selenium Find Element

I'm searching for a tag in class.I tried many methods but I couldn't get the value.
see source code
The data I need is inside the "data-description".
How can i get the "data-description" ?
I Tried some method but didn't work
driver.find_element_by_name("data-description")
driver.find_element_by_css_selector("data-description")
I Solved this method:
icerisi = browser.find_elements_by_class_name('integratedService ')
for mycode in icerisi:
hizmetler.append(mycode.get_attribute("data-description"))
Thanks for your help.

I think css selector would work best here. "data-description" isn't an element, it's an attribute of an element. The css selector for an element with a given attribute would be:
[attribute]
Or, to be more specific, you could use:
[attribute="attribute value"]

Here's a good tip:
Most web browsers have a way of copying an elements Selector or XPATH. For example, in Safari if you view the source code then right-click on an element it will give you the option to copy it. Then select XPATH or Selector and in your code use driver.find_element_by_xpath() or driver.find_element_by_css_selector(). I am certain Google Chrome and Firefox have similar options.
This method is not always failsafe, as the XPATH can be very specific, meaning that slight changes to the website will cause your script to crash, but it is a quick and easy solution, and is especially useful if you don't plan on reusing your code months or years later.

Find elements with specific class name

for chrome, I install ChroPath to find elements on the page.
I want to find XPath for like elements on Instagram Page, but seems that not work :
//span[contains(#class,'glyphsSpriteHeart__outline__24__grey_9 u-__7')]
also, I try it :
/html[1]/body[1]/div[3]/div[1]/div[2]/div[1]/article[1]/div[2]/section[1]/span[1]/button[1]/span[1]
when selenium click :
elenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"div._2dDPU.vCf6V div.zZYga div.PdwC2._6oveC article.M9sTE.L_LMM.JyscU div.eo2As section.ltpMr.Slqrh span.fr66n button.coreSpriteHeartOpen.oF4XW.dCJp8 > span.glyphsSpriteHeart__outline__24__grey_9.u-__7"}
how can I find XPath? any good extension or something?

how can I find XPath? any good extension or something?
You cannot "find" the Xpath of an element. There are many, many XPath's that will find any element. Some will be stable, others will be unstable. The decision on which Xpath to use is based upon your understanding and experience of Selenium, and you understanding of how the Application Under Test is written and behaves.
If you are looking for a tool to experiment with different XPaths, then Chrome's built-in Developer Tools Console allows you to test both Xpath & CSS Selectors;
In your specific scenario about finding elements by class name, then CSS Selector is a much better choice than XPath as CSS selectors will treat multiple classes as an array where as XPath sees "class" as a literal string, hence why you needed to use "contains".

This might help:
https://selectorgadget.com/
This as well, to understand what you are manipulating:
https://www.w3schools.com/xml/xpath_syntax.asp
As for your example where you go down the tree using index numbers (ie: /html[1]/body[1]), A slight change in the site will make your script to fail. Find a way to build something more robust! Also have a look at CSS selectors if you object's appearance is known in advance.

To get all like buttons on instagram use css selector below:
span[aria-label="Like"]
You can get some helpful details here: https://www.w3schools.com/cssref/css_selectors.asp

Trouble clicking button using Selenium with Python

I am trying to make a basic form filler using Selenium on nike.com. I have completed most of it but I am having trouble clicking on the button to select the gender. I have attempted to use many examples of find_element_by_xxxxx code bit none of it has worked. Finding elements by id and xpath haven't come to much either. A typical error i get is Message: no such element: Unable to locate element. I am very new to coding so I could very easily have made an error, but any idea on how you guys would solve it would be much appreciated

That XPATH is very long and you can simplify.
By the looks of it , I would guess those Ids are changing every time there is a new session.
A more straightforward XPATH selector could be...
"//span[text() = 'Male']"
// specifies to search the entire document
span specifies the type of element to search for
text() specifies text that needs to be inside the element
(this will give you the span element but it should still work)
or
"//span[text() = 'Male']/parent::li//input"
(this will give you the actual input button)
Also , like Ollin Boer Bohan suggested, look into using waits before performing actions on your elements.

#cavan answer is correct, Also you can use xpaht like this too
//input[#type='button']//following::span[text()='Male']
Here we can use following to locate the male, same you can do for female button

Can't find element with Selenium even though I know the element exists

Okay, so I'm trying to find
<span class="totalcount">171</span>
on https://boston.craigslist.org/search/sss?query=food+stamps&sort=rel&search_distance=200&postal=01841
with
pagelement = driver.find_element_by_class_name('totalcount')
but for some reason I keep getting the following error
selenium.common.exceptions.NoSuchElementException: Message: Unable to find element with css selector == .totalcount
For reference, I'm using internet explorer 11 with Selenium because my boss requested I switch over to that from Firefox. Could that be what is causing the problem? (Before someone asks, I know it isn't because the page hasn't loaded yet, I added a wait specifically to deal with that.)

I did work for me, but im using find_elements as there are more than one element with the same locator strategy and also using chrome
not sure if it will help you, but you can use the below code for a better approach
Update: Tired with IE and its working
from selenium.webdriver import Ie
driver = Ie('path to IE driver')
driver.get('https://boston.craigslist.org/search/sss?
query=food+stamps&sort=rel&search_distance=200&postal=01841')
total_count = [x.text for x in driver.find_elements_by_class_name('totalcount')]
print(total_count)
['170', '170']