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Delete specific duplicated punctuation from string

I have this string s = "(0|\\+33)[1-9]( *[0-9]{2}){4}". And I want to delete just the duplicated just one ' \ ', like I want the rsult to look like (0|\+33)[1-9]( *[0-9]{2}){4}.
When I used this code, all the duplicated characters are removed:
result = "".join(dict.fromkeys(s)).
But in my case I want just to remove the duplicated ' \ '. Any help is highly appreciated

A solution using the re module:
import re
s = r"(0|\\+33)[1-9]( *[0-9]{2}){4}"
s = re.sub(r"\\(?=\\)", "", s)
print(s)
I look for all backslashes, that are followed by another backslash and replace it with an empty sign.
Output: (0|\+33)[1-9]( *[0-9]{2}){4}​

The function you need is replace
s = "(0|\\+33)[1-9]( *[0-9]{2}){4}"
result = s.replace("\\","")
EDIT
I see now that you want to remove just one \ and not both.
In order to do this you have to modify the call to replace this way
result = s.replace("\","",1) # last argument is the number of occurrances to replace
or
result = s.replace("\\","\")
EDIT of the EDIT
Backslashes are special in Python.
I'm using Python 3.10.5. If I do
x = "ab\c"
y = "ab\\c"
print(len(x)==len(y))
I get a True.
That's because backslashes are used to escape special characters, and that makes the backslash a special character :)
I suggest you to try a little bit with replace until you get what you need.

How to remove backslashes in strings in python

As an output of Pytesseract, I get a string variable which contains backslashes. I would like to remove all of the back slashes.
'13, 0\\'70'
Unforturnately the replace function does not work as the string doesn't seem to be an actual string when the variable value is copied. Anybody knows how I can remove all the backslashes?

I replaced your outermost quotation marks with double-quotes, and then properly applied `replace:
>>> brut_mass = "13, 0\\'70"
>>> brut_mass.replace('\\', '')
"13, 0'70"
Does that solve your problem?

Fixed it with the code below.
brut_mass = repr(brut_mass).replace(" ' ", '')
or alternatively to avoid the double quotations
brut_mass = brut_mass.replace(" ' ", '')

I want to replace single quotes with double quotes in a list

So I am making a program that takes a text file, breaks it into words, then writes the list to a new text file.
The issue I am having is I need the strings in the list to be with double quotes not single quotes.
For example
I get this ['dog','cat','fish'] when I want this ["dog","cat","fish"]
Here is my code
with open('input.txt') as f:
file = f.readlines()
nonewline = []
for x in file:
nonewline.append(x[:-1])
words = []
for x in nonewline:
words = words + x.split()
textfile = open('output.txt','w')
textfile.write(str(words))
I am new to python and haven't found anything about this.
Anyone know how to solve this?
[Edit: I forgot to mention that i was using the output in an arduino project that required the list to have double quotes.]

You cannot change how str works for list.
How about using JSON format which use " for strings.
>>> animals = ['dog','cat','fish']
>>> print(str(animals))
['dog', 'cat', 'fish']
>>> import json
>>> print(json.dumps(animals))
["dog", "cat", "fish"]
import json
...
textfile.write(json.dumps(words))

Most likely you'll want to just replace the single quotes with double quotes in your output by replacing them:
str(words).replace("'", '"')
You could also extend Python's str type and wrap your strings with the new type changing the __repr__() method to use double quotes instead of single. It's better to be simpler and more explicit with the code above, though.
class str2(str):
def __repr__(self):
# Allow str.__repr__() to do the hard work, then
# remove the outer two characters, single quotes,
# and replace them with double quotes.
return ''.join(('"', super().__repr__()[1:-1], '"'))
>>> "apple"
'apple'
>>> class str2(str):
... def __repr__(self):
... return ''.join(('"', super().__repr__()[1:-1], '"'))
...
>>> str2("apple")
"apple"
>>> str2('apple')
"apple"

In Python, double quote and single quote are the same. There's no different between them. And there's no point to replace a single quote with a double quote and vice versa:
2.4.1. String and Bytes literals
...In plain English: Both types of literals can be enclosed in matching single quotes (') or double quotes ("). They can also be enclosed in matching groups of three single or double quotes (these are generally referred to as triple-quoted strings). The backslash () character is used to escape characters that otherwise have a special meaning, such as newline, backslash itself, or the quote character...
"The issue I am having is I need the strings in the list to be with double quotes not single quotes." - Then you need to make your program accept single quotes, not trying to replace single quotes with double quotes.

Removing the single quotes after using re.sub() in python

After replacing all word characters in a string with the character '^', using re.sub("\w", "^" , stringorphrase) I'm left with :
>>> '^^^ ^^ ^^^^'
Is there any way to remove the single quotes so it looks cleaner?
>>> ^^^ ^^ ^^^^

Are you sure it's just not how it's displayed in the interactive prompt or something (and there aren't actually apost's in your string)?
If the ' is actually part of the string, and is first/last then either:
string = string.strip("'")
or:
string = string[1:-1] # lop ending characters off

Use the print statement. The quotes aren't actually part of the string.

To remove all occurrences of single quotes:
mystr = some_string_with_single_quotes
answer = mystr.replace("'", '')
To remove single quotes ONLY at the ends of the string:
mystr = some_string_with_single_quotes
answer = mystr.strip("'")
Hope this helps

Escape string and split it right after

i've the following code:
import re
key = re.escape('#one #two #some #tests #are #done')
print(key)
key = key.split()
print(key)
and the following output:
\#one\ \#two\ \#some\ \#tests\ \#are\ \#done
['\\#one\\', '\\#two\\', '\\#some\\', '\\#tests\\', '\\#are\\', '\\#done']
How come the backslashes are duplicated? I just want them once in my list, because i would like to use this list in a regular expression.
Thanks in advance! John

There is only one backslash each, but when printing the repr of the strings, they are duplicated (escaped) - just as you would need to duplicate them when using a string to build a regex. So everything is fine.
For example:
>>> len("\\")
1
>>> len("\\n")
2
>>> len("\n")
1
>>> print "\\n"
\n
>>> print "\n"
>>>

The \ character is an escape character, that is a character that changes the meaning of the subsequent character[s]. For example the "n" character is simply an "n". But if you escape it like "\n" it becomes the "newline" character. So, if you need to use a \ literal, you need to escape it with... itself: \\

The backslashes are not duplicated. To realize this, try to do:
for element in key:
print element
And you will see this output:
\#one\
\#two\
\#some\
\#tests\
\#are\
\#done
When you have printed whole list, the python used representation where strings are printed not as they are, but they are printed as python expression (notice the quotes "", they are not in the strings)
To actually encode string containing backslash, you need to duplicate that backslash. That is it.

When you convert a list to a string (e.g. to print it), it calls repr on each object contained in the list. That's why you get the quotes and extra backslashes in your second line of output. Try this:
s = "\\a string with an escaped backslash"
print s # prints: \a string with an escaped backslash
print repr(s) # prints: '\\a string with an escaped backslash'
The repr call puts quotes around the string, and shows the backslash escapes.