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errors from api when using python requests module for file upload

when i make the following request:
curl -X POST http://localhost:8080/endpoint \
-F "file=filepath/example.zip" \
-H "Content-Type: multipart/form-data"
everything works fine.
However, when i try to do the same in python:
import requests
url = "http://localhost:8080/endpoint"
files = {"file": open("example.zip", "rb")}
headers = {"Content-Type": "multipart/form-data"}
r = requests.post(url, files=files, headers=headers)
the api gives me an error. are these two code snippets not equivalent? thanks

the issue was this:
multipart data POST using python requests: no multipart boundary was found
it seems as though setting
headers = {"Content-Type": "multipart/form-data"}
caused the issue. i removed it and it works

Retrieve answer from a python url request

I want to convert the following curl instruction into python code:
curl -X POST --insecure -H "Content-Type:audio/wav" --data-binary 'audio_test.wav' 'http://localhost:8888/file?l=atc&ac=atc'
This curl command returns: "One two five"
So, after some reseaches I decided to use the requests library. I made the following code:
import requests
url = 'http://localhost:8888/file?l=atc&ac=atc'
with open('audio_test.wav','rb') as fichier:
payload = fichier.read()
head = {'Content-Type':'audio/wav', 'Accept-Charset': 'utf-8'}
req = requests.post(url, data=payload, headers=head)
print(req)
And it gaves me: <Response [200]>. So I assume that it works.
However I don't have any ideas of how to retrieve the result ("One two five" ) from this since the curl command did it automatically.
Any suggestions ?

Convert this curl command to Python 3

How can I send this curl out using Python?
I did find similar requests, but cannot adapt my code to suite the query
I have also tried using pycurl, following this example but without luck.
$ curl -v -X GET -H "Accept: text/csv" -H "Authorization: Basic YW5kcmVhLmJvdHRpQHdzcC5jb206OWY5N2E5YTY2ZWU1MTMxZjdmNjk4MDcwZTFkODEwMjU0M2I0NTg1ZA==" "https://epc.opendatacommunities.org/api/v1/domestic/search"
Thanks

If you are using the Python Requests package the following code snippet should work:
import requests
headers = {
'Accept': 'text/csv',
'Authorization': 'Basic YW5kcmVhLmJvdHRpQHdzcC5jb206OWY5N2E5YTY2ZWU1MTMxZjdmNjk4MDcwZTFkODEwMjU0M2I0NTg1ZA==',
}
response = requests.get('https://epc.opendatacommunities.org/api/v1/domestic/search', headers=headers)
response.status_code # 200
response.text # "lmk-key,address1,address2,address3,postcode,buildi ..."
(Note: I used the https://curl.trillworks.com/ website to automatically make the conversion)

How to convert "curl -X POST -T " to Python

How do I convert
curl -X POST -T 'sample_data.json' -H "Content-Type: application/json" https://sample_url.com
to Python using requests?
Specifically, how do I provide "-T" parameter to the request?

I believe you could do something like this:
import requests
import json
requests.post('https://sample_url.com',
headers = {'Content-type': 'application/json'},
data = json.loads(open('sample_data.json').read())
}
You can check out the requests page for more details.
Or, to show a fully self-contained example without having to load the json from a file, you could do:
import requests
requests.post('https://httpbin.org/post', data = {'key':'value'})
<Response [200]>
Note, from the requests docs:
Using the json parameter in the request will change the Content-Type in the header to application/json.
So, you could just do the following instead:
r = requests.post(url, json=payload)

curl -X POST -T 'sample_data.json' \
-H 'Content-Type: application/json' \
https://sample_url.com/
is effectively equivalent to
curl -X POST \
-H 'Content-Type: application/json' \
-d "$(cat sample_data.json)" \
https://sample_url.com/sample_data.json
so using requests, it would be
with open('sample_data.json') as fh:
response = requests.post(
"https://sample_url.com/sample_data.json",
data=fh.read(),
header={'Content-Type': 'application/json'}
)

There are a couple of ways that you could do it. But the best way is to use the requests library. It's not part of the standard library (yet), but makes HTTP requests super straight-forward.
$ pip install requests
or
$ conda install requests
Then
import json
import requests
url = r"https://sample_url.com"
with open("sample_data.json", "r") as fh:
data = json.load(fh)
requests.post(url=url, data=data)

The best way is to use the Python Requests library - https://2.python-requests.org/en/master/. To be able to post a JSON payload in the message is
import Requests
import json
result = requests.post(URL,json=json.loads(open('sample_data.json').read()))
The requests library natively understands how to send your JSON data
There are some more examples of how to post messages with Form encoded payloads on this part of the page as well - https://2.python-requests.org/en/master/user/quickstart/#more-complicated-post-requests
To be able to do other verbs you just need to change the function for requests -
for a GET, requests.get(url)
for a PUT, requests.put(url,data=DATA) or requests.put(url,json=JSON)
for a DELETE, requests.delete(url)
and so on.

Trouble converting curl commands to python requests

I'm trying to grab some data from a website using API, but I'm having trouble converting the example curl command to python requests.
example curl command
curl -X POST "some_url" \
-H "accept: application/json" \
-H "Authorization: <accesstoken>" \
-d #- <<BODY
{}
BODY
My python requests that didn't work
headers = {
'Authorization': "Bearer {0}".format(access_token)
}
response = requests.request('GET', "some_url",
headers=headers, allow_redirects=False)
I get error code 400, can anyone help me figure out what was wrong?

The equivalent requests code for your curl should be:
import requests
headers = {
'accept': 'application/json',
'Authorization': '<accesstoken>',
}
data = "{} "
response = requests.post('http://some_url', headers=headers, data=data)
You can use https://curl.trillworks.com/ to convert your actual curl invocation (note that it won't handle heredocs, as in your example).
If you see different behavior between curl and your python code, dump the HTTP requests and compare:
Python requests - print entire http request (raw)?
How can I see the request headers made by curl when sending a request to the server?