Feedparser not parsing searched for description - python

I'm trying to utilize RSS to get auto notifications for specific security vulnerabilities i may be concerned with. I have gotten it functional for searching for keywords in the title and url of feed entries, but it seems to ignore the rss description.
I've verified the description field exists within the feed (I originally started with summary in place of description before discovering this) but don't understand why its not working (relatively new to python). Is it possibly a sanitation issue, or am i missing something on how the search is performed?
#!/usr/bin/env python3.6
import feedparser
#Keywords to search for in the rss feed
key_words = ['Chrome','Tomcat','linux','windows']
# get the urls we have seen prior
f = open('viewed_urls.txt', 'r')
urls = f.readlines()
urls = [url.rstrip() for url in urls]
f.close()
#Returns true if keyword is in string
def contains_wanted(in_str):
for wrd in key_words:
if wrd.lower() in in_str:
return True
return False
#Returns true if url result has not been seen before
def url_is_new(urlstr):
# returns true if the url string does not exist
# in the list of strings extracted from the text file
if urlstr in urls:
return False
else:
return True
#actual parsing phase
feed = feedparser.parse('https://nvd.nist.gov/feeds/xml/cve/misc/nvd-rss.xml')
for key in feed["entries"]:
title = key['title']
url = key['links'][0]['href']
description = key['description']
#formats and outputs the specified rss fields
if contains_wanted(title.lower()) and contains_wanted(description.lower()) and url_is_new(url):
print('{} - {} - {}\n'.format(title, url, description))
#appends reoccurring rss feeds in the viewed_urls file
with open('viewed_urls.txt', 'a') as f:
f.write('{}\n'.format(title,url))

This helped. I was unaware of the conjunction logic but have resolved it. I omitted contains_wanted(title.lower()) since this was not necessary in the statement logic as contains_wanted(description.lower()) fulfills the title statements purpose as well as its own. and am getting proper output.
Thank you pbn.

Related

Search through JSON query from Valve API in Python

I am looking to find various statistics about players in games such as CS:GO from the Steam Web API, but cannot work out how to search through the JSON returned from the query (e.g. here) in Python.
I just need to be able to get a specific part of the list that is provided, e.g. finding total_kills from the link above. If I had a way that could sort through all of the information provided and filters it down to just that specific thing (in this case total_kills) then that would help a load!
The code I have at the moment to turn it into something Python can read is:
url = "http://api.steampowered.com/IPlayerService/GetOwnedGames/v0001/?key=FE3C600EB76959F47F80C707467108F2&steamid=76561198185148697&include_appinfo=1"
data = requests.get(url).text
data = json.loads(data)
If you are looking for a way to search through the stats list then try this:
import requests
import json
def findstat(data, stat_name):
for stat in data['playerstats']['stats']:
if stat['name'] == stat_name:
return stat['value']
url = "http://api.steampowered.com/ISteamUserStats/GetUserStatsForGame/v0002/?appid=730&key=FE3C600EB76959F47F80C707467108F2&steamid=76561198185148697"
data = requests.get(url).text
data = json.loads(data)
total_kills = findstat(data, 'total_kills') # change 'total_kills' to your desired stat name
print(total_kills)

scrape text from webpage using python 2.7

I'm trying to scrape data from this website:
Death Row Information
I'm having trouble to scrape the last statements from all the executed offenders in the list because the last statement is located at another HTML page. The name of the URL is built like this: http://www.tdcj.state.tx.us/death_row/dr_info/[lastname][firstname].html. I can't think of a way of how I can scrape the last statements from these pages and put them in an Sqlite database.
All the other info (expect for "offender information", which I don't need) is already in my datbase.
Anyone who can give me a pointer to get started getting this done in Python?
Thanks
Edit2: I got a little bit further:
import sqlite3
import csv
import re
import urllib2
from urllib2 import Request, urlopen, URLError
from BeautifulSoup import BeautifulSoup
import requests
import string
URLS = []
Lastwords = {}
conn = sqlite3.connect('prison.sqlite')
conn.text_factory = str
cur = conn.cursor()
# Make some fresh tables using executescript()
cur.execute("DROP TABLE IF EXISTS prison")
cur.execute("CREATE TABLE Prison ( link1 text, link2 text,Execution text, LastName text, Firstname text, TDCJNumber text, Age integer, date text, race text, county text)")
conn.commit()
csvfile = open("prisonfile.csv","rb")
creader = csv.reader(csvfile, delimiter = ",")
for t in creader:
cur.execute('INSERT INTO Prison VALUES (?,?,?,?,?,?,?,?,?,?)', t, )
for column in cur.execute("SELECT LastName, Firstname FROM prison"):
lastname = column[0].lower()
firstname = column[1].lower()
name = lastname+firstname
CleanName = name.translate(None, ",.!-#'#$" "")
CleanName2 = CleanName.replace(" ", "")
Url = "http://www.tdcj.state.tx.us/death_row/dr_info/"
Link = Url+CleanName2+"last.html"
URLS.append(Link)
for URL in URLS:
try:
page = urllib2.urlopen(URL)
except URLError, e:
if e.code ==404:
continue
soup = BeautifulSoup(page.read())
statements = soup.findAll ('p',{ "class" : "Last Statement:" })
print statements
csvfile.close()
conn.commit()
conn.close()
The code is messy, I know. Once everything works I will clean it up. One problem though. I'm trying to get all the statements by using soup.findall, but I cannot seem to get the class right. The relevant part of the page source looks like this:
<p class="text_bold">Last Statement:</p>
<p>I don't have anything to say, you can proceed Warden Jones.</p>
However, the output of my program:
[]
[]
[]
...
What could be the problem exactly?
I will not write code that solves the problem, but will give you a simple plan for how to do it yourself:
You know that each last statement is located at the URL:
http://www.tdcj.state.tx.us/death_row/dr_info/[lastname][firstname]last.html
You say you already have all the other information. This presumably includes the list of executed prisoners. So you should generate a list of names in your python code. This will allow you to generate the URL to get to each page you need to get to.
Then make a For loop that iterates over each URL using the format I posted above.
Within the body of this for loop, write code to read the page and get the last statement. The last statement on each page is in the same format on each page, so you can use parsing to capture the part that you want:
<p class="text_bold">Last Statement:</p>
<p>D.J., Laurie, Dr. Wheat, about all I can say is goodbye, and for all the rest of you, although you don’t forgive me for my transgressions, I forgive yours against me. I am ready to begin my journey and that’s all I have to say.</p>
Once you have your list of last statements, you can push them to SQL.
So your code will look like this:
import urllib2
# Make a list of names ('Last1First1','Last2First2','Last3First3',...)
names = #some_call_to_your_database
# Make a list of URLs to each inmate's last words page
# ('URL...Last1First1last.html',URL...Last2First2last.html,...)
URLS = () # made from the 'names' list above
# Create a dictionary to hold all the last words:
LastWords = {}
# Iterate over each individual page
for eachURL in URLS:
response = urllib2.urlopen(eachURL)
html = response.read()
## Some prisoners had no last words, so those URLs will 404.
if ...: # Handle those 404s here
## Code to parse the response, hunting specifically
## for the code block I mentioned above. Once you have the
## last words as a string, save to dictionary:
LastWords['LastFirst'] = "LastFirst's last words."
# Now LastWords is a dictionary with all the last words!
# Write some more code to push the content of LastWords
# to your SQL database.

getting data from webpage with select menus with python and beautifulsoup

I am trying to collect data from a webpage which has a bunch of select lists i need to fetch
data from. Here is the page:- http://www.asusparts.eu/partfinder/Asus/All In One/E Series/
And this is what i have so far:
import glob, string
from bs4 import BeautifulSoup
import urllib2, csv
for file in glob.glob("http://www.asusparts.eu/partfinder/*"):
##-page to show all selections for the E-series-##
selected_list = 'http://www.asusparts.eu/partfinder/Asus/All In One/E Series/'
##-
page = urllib2.urlopen(selected_list)
soup = BeautifulSoup(page)
##-page which shows results after selecting one option-##
url = 'http://www.asusparts.eu/partfinder/Asus/All In One/E Series/ET10B'
##-identify the id of select list which contains the E-series-##
select = soup.find('select', id="myselectListModel")
option_tags = select.findAll('option')
##-omit first item in list as isn't part of the option-##
option_tags = option_tags[1:]
for option in option_tags:
open(url + option['value'])
html = urllib2.urlopen("http://www.asusparts.eu/partfinder/")
soup = BeautifulSoup(html)
all = soup.find('div', id="accordion")
I am not sure if i am going about the right way? As all the select menus make it confusing. Basically i need to grab
all the data from the selected results such as images,price,description,etc. They are all contained within
one div tag which contains all the results, which is named 'accordion' so would this still gather all the data?
or would i need to dig deeper to search through the tags inside this div? Also i would have prefered to search by id rather than
class as i could fetch all the data in one go. How would i do this from what i have above? Thanks. Also i am unsure about the glob function too if i am using that correctly or not?
EDIT
Here is my edited code, no errors return however i am not sure if it returns all the models for the e-series?
import string, urllib2, urllib, csv, urlparse from bs4 import
BeautifulSoup
##-page which shows results after selecting one option-##
url = 'http://www.asusparts.eu/partfinder/Asus/All In One/E Series/ET10B'
base_url = 'http://www.asusparts.eu/' + url
print base_url
##-page to show all selections for the E-series-##
selected_list = urllib.quote(base_url + '/Asus/All In One/E Series/ET10B')
print urllib.quote(base_url + '/Asus/All In One/E Series/ET10B')
#selected_list = 'http://www.asusparts.eu/partfinder/Asus/All In One/E Series/ET10B'
##-
page = urllib2.urlopen('http://www.asusparts.eu/partfinder/Asus/All%20In%20One/E%20Series')
soup = BeautifulSoup(page)
print soup
##-identify the id of select list which contains the E-series-##
select = soup.find('select', id="myselectListModel")
option_tags = select.findAll('option')
print option_tags
##-omit first item in list as isn't part of the option-##
option_tags = option_tags[1:]
print option_tags
for option in option_tags:
url + option['redirectvalue']
print " " + url + option['redirectvalue']
First of all, I'd like to point out a couple of problems you have in the code you posted. First, of all the glob module is not typically used for making HTTP requests. It is useful for iterating through a subset of files on a specified path, you can read more about it in its docs.
The second issue is that in the line:
for file in glob.glob("http://www.asusparts.eu/partfinder/*"):
you have an indentation error, because there is no indented code that follows. This will raise an error and prevent the rest of the code from being executed.
Another problem is that you are using some of python's "reserved" names for your variables. You should never use words such as all or file for variable names.
Finally when you are looping through option_tags:
for option in option_tags:
open(url + option['value'])
The open statement will try and open a local file whose path is url + option['value']. This will likely raise an error, as I doubt you'll have a file at that location. In addition, you should be aware that you aren't doing anything with this open file.
Okay, so enough with the critique. I've taken a look at the asus page and I think I have an idea of what you want to accomplish. From what I understand, you want to scrape a list of parts (images, text, price, etc..) for each computer model on the asus page. Each model has its list of parts located at a unique URL (for example: http://www.asusparts.eu/partfinder/Asus/Desktop/B%20Series/BM2220). This means that you need to be able to create this unique URL for each model. To make matters more complicated, each parts category is loaded dynamically, so for example the parts for the "Cooling" section are not loaded until you click on the link for "Cooling". This means we have a two part problem: 1) Get all of the valid (brand, type, family, model) combinations and 2) Figure out how to load all the parts for a given model.
I was kind of bored and decided to write up a simple program that will take care of most of the heavy lifting. It isn't the most elegant thing out there, but it'll get the job done. Step 1) is accomplished in get_model_information(). Step 2) is taken care of in parse_models() but is a little less obvious. Taking a look at the asus website, whenever you click on a parts subsection the JavaScript function getProductsBasedOnCategoryID() is run, which makes an ajax call to a formatted PRODUCT_URL (see below). The response is some JSON information that is used to populate the section you clicked on.
import urllib2
import json
import urlparse
from bs4 import BeautifulSoup
BASE_URL = 'http://www.asusparts.eu/partfinder/'
PRODUCTS_URL = 'http://json.zandparts.com/api/category/GetCategories/'\
'44/EUR/{model}/{family}/{accessory}/{brand}/null/'
ACCESSORIES = ['Cable', 'Cooling', 'Cover', 'HDD', 'Keyboard', 'Memory',
'Miscellaneous', 'Mouse', 'ODD', 'PS', 'Screw']
def get_options(url, select_id):
"""
Gets all the options from a select element.
"""
r = urllib2.urlopen(url)
soup = BeautifulSoup(r)
select = soup.find('select', id=select_id)
try:
options = [option for option in select.strings]
except AttributeError:
print url, select_id, select
raise
return options[1:] # The first option is the menu text
def get_model_information():
"""
Finds all the models for each family, all the families and models for each
type, and all the types, families, and models for each brand.
These are all added as tuples (brand, type, family, model) to the list
models.
"""
model_info = []
print "Getting brands"
brand_options = get_options(BASE_URL, 'mySelectList')
for brand in brand_options:
print "Getting types for {0}".format(brand)
# brand = brand.replace(' ', '%20') # URL encode spaces
brand_url = urlparse.urljoin(BASE_URL, brand.replace(' ', '%20'))
types = get_options(brand_url, 'mySelectListType')
for _type in types:
print "Getting families for {0}->{1}".format(brand, _type)
bt = '{0}/{1}'.format(brand, _type)
type_url = urlparse.urljoin(BASE_URL, bt.replace(' ', '%20'))
families = get_options(type_url, 'myselectListFamily')
for family in families:
print "Getting models for {0}->{1}->{2}".format(brand,
_type, family)
btf = '{0}/{1}'.format(bt, family)
fam_url = urlparse.urljoin(BASE_URL, btf.replace(' ', '%20'))
models = get_options(fam_url, 'myselectListModel')
model_info.extend((brand, _type, family, m) for m in models)
return model_info
def parse_models(model_information):
"""
Get all the information for each accessory type for every
(brand, type, family, model). accessory_info will be the python formatted
json results. You can parse, filter, and save this information or use
it however suits your needs.
"""
for brand, _type, family, model in model_information:
for accessory in ACCESSORIES:
r = urllib2.urlopen(PRODUCTS_URL.format(model=model, family=family,
accessory=accessory,
brand=brand,))
accessory_info = json.load(r)
# Do something with accessory_info
# ...
def main():
models = get_model_information()
parse_models(models)
if __name__ == '__main__':
main()
Finally, one side note. I have dropped urllib2 in favor of the requests library. I personally think provides much more functionality and has better semantics, but you can use whatever you would like.

Dictionary / JSON issue using Python 2.7

I'm looking at scraping some data from Facebook using Python 2.7. My code basically augments by 1 changing the Facebook profile ID to then capture details returned by the page.
An example of the page I'm looking to capture the data from is graph.facebook.com/4.
Here's my code below:
import scraperwiki
import urlparse
import simplejson
source_url = "http://graph.facebook.com/"
profile_id = 1
while True:
try:
profile_id +=1
profile_url = urlparse.urljoin(source_url, str(profile_id))
results_json = simplejson.loads(scraperwiki.scrape(profile_url))
for result in results_json['results']:
print result
data = {}
data['id'] = result['id']
data['name'] = result['name']
data['first_name'] = result['first_name']
data['last_name'] = result['last_name']
data['link'] = result['link']
data['username'] = result['username']
data['gender'] = result['gender']
data['locale'] = result['locale']
print data['id'], data['name']
scraperwiki.sqlite.save(unique_keys=['id'], data=data)
#time.sleep(3)
except:
continue
profile_id +=1
I am using the scraperwiki site to carry out this check but no data is printed back to console despite the line 'print data['id'], data['name'] used just to check the code is working
Any suggestions on what is wrong with this code? As said, for each returned profile, the unique data should be captured and printed to screen as well as populated into the sqlite database.
Thanks
Any suggestions on what is wrong with this code?
Yes. You are swallowing all of your errors. There could be a huge number of things going wrong in the block under try. If anything goes wrong in that block, you move on without printing anything.
You should only ever use a try / except block when you are looking to handle a specific error.
modify your code so that it looks like this:
while True:
profile_id +=1
profile_url = urlparse.urljoin(source_url, str(profile_id))
results_json = simplejson.loads(scraperwiki.scrape(profile_url))
for result in results_json['results']:
print result
data = {}
# ... more ...
and then you will get detailed error messages when specific things go wrong.
As for your concern in the comments:
The reason I have the error handling is because, if you look for
example at graph.facebook.com/3, this page contains no user data and
so I don't want to collate this info and skip to the next user, ie. no
4 etc
If you want to handle the case where there is no data, then find a way to handle that case specifically. It is bad practice to swallow all errors.

How to get all YouTube comments with Python's gdata module?

Looking to grab all the comments from a given video, rather than go one page at a time.
from gdata import youtube as yt
from gdata.youtube import service as yts
client = yts.YouTubeService()
client.ClientLogin(username, pwd) #the pwd might need to be application specific fyi
comments = client.GetYouTubeVideoComments(video_id='the_id')
a_comment = comments.entry[0]
The above code with let you grab a single comment, likely the most recent comment, but I'm looking for a way to grab all the comments at once. Is this possible with Python's gdata module?
The Youtube API docs for comments, the comment feed docs and the Python API docs
The following achieves what you asked for using the Python YouTube API:
from gdata.youtube import service
USERNAME = 'username#gmail.com'
PASSWORD = 'a_very_long_password'
VIDEO_ID = 'wf_IIbT8HGk'
def comments_generator(client, video_id):
comment_feed = client.GetYouTubeVideoCommentFeed(video_id=video_id)
while comment_feed is not None:
for comment in comment_feed.entry:
yield comment
next_link = comment_feed.GetNextLink()
if next_link is None:
comment_feed = None
else:
comment_feed = client.GetYouTubeVideoCommentFeed(next_link.href)
client = service.YouTubeService()
client.ClientLogin(USERNAME, PASSWORD)
for comment in comments_generator(client, VIDEO_ID):
author_name = comment.author[0].name.text
text = comment.content.text
print("{}: {}".format(author_name, text))
Unfortunately the API limits the number of entries that can be retrieved to 1000. This was the error I got when I tried a tweaked version with a hand crafted GetYouTubeVideoCommentFeed URL parameter:
gdata.service.RequestError: {'status': 400, 'body': 'You cannot request beyond item 1000.', 'reason': 'Bad Request'}
Note that the same principle should apply to retrieve entries in other feeds of the API.
If you want to hand craft the GetYouTubeVideoCommentFeed URL parameter, its format is:
'https://gdata.youtube.com/feeds/api/videos/{video_id}/comments?start-index={sta‌​rt_index}&max-results={max_results}'
The following restrictions apply: start-index <= 1000 and max-results <= 50.
The only solution I've got for now, but it's not using the API and gets slow when there's several thousand comments.
import bs4, re, urllib2
#grab the page source for vide
data = urllib2.urlopen(r'http://www.youtube.com/all_comments?v=video_id') #example XhFtHW4YB7M
#pull out comments
soup = bs4.BeautifulSoup(data)
cmnts = soup.findAll(attrs={'class': 'comment yt-tile-default'})
#do something with them, ie count them
print len(cmnts)
Note that due to 'class' being a builtin python name, you can't do regular searches for 'startwith' via regex or lambdas as seen here, since you're using a dict, over regular parameters. It also gets pretty slow due to BeautifulSoup, but it needs to get used because etree and minidom don't find matching tags for some reason. Even after prettyfying() with bs4

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