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Python - Selecting data from at one specific time per day

I'm quite new to Python and have a simple question (I think). I have an array with hourly data for an entire month. I want to make a new array with only data at a specific time every day (at 00:00 UTC). How do I do this?
This is what the array looks like:
Thank you for your help!

I would go about it by first making a boolean mask representing which times satisfied that condition, and then selecting values based on that mask. If your data is truly hourly this could be done using the following:
mask = q_era5_feb.time.dt.hour == 0
result = q_era5_feb.sel(time=mask)

Pandas dataframe: summing cell data from a group of rows, storing in a new column

As a part of a treatment for a health related issue, I need to measure my liquid intake (along with some other parameters), registring the amount of liquid every time I drink. I have a dataframe, of several months of such registration.
I want to sum my daily amount in an additional column (in red, image below)
As you may see, I wish like to store it in the first column of the slice returned by df.groupby(df['Date'])., for all the days.
I tried the following:
df.groupby(df.Date).first()['Total']= df.groupby(df.Date)['Drank'].fillna(0).sum()
But seems not to be the way to do it.
Greatful for any advice.
Thanks
Michael

use fact False==0
first row of date will be where data is not equal to shift() of date
merge() to sum
## construct a data set
d = pd.date_range("1-jan-2021", "1-mar-2021", freq="2H")
A = np.random.randint(20,300,len(d)).astype(float)
A.ravel()[np.random.choice(A.size, A.size//2, replace=False)] = np.nan
df = pd.DataFrame({"datetime":d, "Drank":A})
df = df.assign(Date=df.datetime.dt.date, Time=df.datetime.dt.time).drop(columns=["datetime"]).loc[:,["Date","Time","Drank"]]
## construction done
# first row will have different date to shift
# merge Total back
df.assign(row=df.Date.eq(df.Date.shift())).merge(df.groupby("Date", as_index=False).agg(Total=("Drank","sum")).assign(row=0),
on=["Date","row"], how="left").drop(columns="row")

Assigning a value to the same dates fulfilling a condition in a more efficient way in a dataframe

I have the following dataframe called df1 that contains data for a number of regions in the column NUTS_ID:
The index, called Date has all the days of 2010. That is, for each code in NUTS_ID I have a day of 2010 (all days of the year for AT1, AT2and so on). I created a list containing the dates corresponding to non-workdays and I want to add a column that with 0 for non-workdays and 1 for workdays.
For this, I simply used a for loop that checks day by day if it's in the workday list I created:
for day in df1.index:
if day not in workdays_list:
df1.loc[day,'Workday'] = 0 # Assigning 0 to to non-workdays
else:
df1.loc[day,'Workday'] = 1 # Assigning 1 to workdays
This works well enough if the dataset is not big. But with some of the datasets I'm processing this takes a very long time. I would like to ask for ideas in order to do the process faster and more efficient. Thank you in advance for your input.
EDIT: One of the things I have thought is that maybe a groupby could be helpful, but I don't know if that is correct.

You can use np.where with isin to check if your Date (i.e. your index) is in the list you created:
import numpy as np
df1['Workday'] = np.where(df1.index.isin(workdays_list),1,0)
I can't reproduce your dataset, but something along those lines should work.

pandas inserting rows in a monotonically increasing dataframe using itertuples

I've been searching for a solution to this for a while, and I'm really stuck! I have a very large text file, imported as a panda dataframe containing just two columns but with hundreds of thousands to millions of rows. The columns contain packet dumps: one is the data of the packets formatted as ascii representations of monotonically increasing integers, and the second the packet time.
I want to go through this dataframe, and make sure that the dataframe is monotonically increasing, and if there are missing data, to insert a new rows in order to make the list monotonically increasing. i.e the 'data' column should be filled in with the appropriate value but the time should be changed to 'NaN' or 'NULL', etc.
The following is a sample of the data:
data frame_time_epoch
303030303030303000 1527986052.485855896
303030303030303100 1527986052.491020305
303030303030303200 1527986052.496127062
303030303030303300 1527986052.501301944
303030303030303400 1527986052.506439335
So I have two questions:
1) I've been trying to loop through the dataframe using itertuples to try to get the next row do a comparison with the current row and if the difference s more than the 100 to add a new row, but unfortunately I've struggled with this since, there doesn't seem to be a good way to retreive the row after the one called.
2) Is there a better way (faster) way to do this other than the way I've proposed?
This may be trivial, though I've really struggled with it. Thank you in advance for your help.

A problem at a time. You can do a verbatim check df.data.is_monotonic_increasing.
Inserting new indices: it is better to go the other way around. You already know the index you want. It is given by range(min_val, max_val+1, 100). You can create a blank DataFrame with this index and update it using your data.
This may be memory intensive so you may need to go over your data in chunks. In that case, you may need to provide index range ahead of time.
import pandas as pd
# test data
df = pd.read_csv(
pd.compat.StringIO(
"""data frame_time_epoch
303030303030303000 1527986052.485855896
303030303030303100 1527986052.491020305
303030303030303200 1527986052.496127062
303030303030303300 1527986052.501301944
303030303030303500 1527986052.506439335"""
),
sep=r" +",
)
# check if the data is increasing
assert df.data.is_monotonic_increasing
# desired index range
rng = range(df.data.iloc[0], df.data.iloc[-1] + 1, 100)
# blank frame with full index
df2 = pd.DataFrame(index=rng, columns=["frame_time_epoch"])
# update with existing data
df2.update(df.set_index("data"))
# result
# frame_time_epoch
# 303030303030303000 1.52799e+09
# 303030303030303100 1.52799e+09
# 303030303030303200 1.52799e+09
# 303030303030303300 1.52799e+09
# 303030303030303400 NaN
# 303030303030303500 1.52799e+09

Just for examination: Did you try sth like
delta = df['data'].diff()
delta[delta>0]
delta[delta<100]

Append multiple columns into two columns python

I have a csv file which contains approximately 100 columns of data. Each column represents temperature values taken every 15 minutes throughout the day for each of the 100 days. The header of each column is the date for that day. I want to convert this into two columns, the first being the date time (I will have to create this somehow), and the second being the temperatures stacked on top of each other for each day.
My attempt:
with open("original_file.csv") as ofile:
stack_vec = []
next(ofile)
for line in ofile:
columns = lineo.split(',') # get all the columns
for i in range (0,len(columns)):
stack_vec.append(columnso[i])
np.savetxt("converted.csv",stack_vec, delimiter=",", fmt='%s')
In my attempt, I am trying to create a new vector with each column appended to the end of it. However, the code is extremely slow and likely not working! Once I have this step figured out, I then need to take the date from each column and add 15 minutes to the date time for each row. Any help would be greatly appreciated.

If i got this correct you have a csv with 96 rows and 100 Columns and want to stack in into one vector day after day to a vector with 960 entries , right ?
An easy approach would be to use numpy:
import numpy as np
x = np.genfromtxt('original_file.csv', delimiter=',')
data = x.ravel(order ='F')
Note numpy is a third party library but the go-to library for math.
the first line will read the csv into a ndarray which is like matrix ( even through it behaves different for mathematical operations)
Then with ravel you vectorize it. the oder is so that it stacks rows ontop of each other instead of columns, i.e day after day. (Leave it as default / blank if you want time point after point)
For your date problem see How can I make a python numpy arange of datetime i guess i couldn't give a better example.
if you have this two array you can ensure the shape by x.reshape(960,1) and then stack them with np.concatenate([x,dates], axis = 1 ) with dates being you date vector.